Math FPCore C Java Python Julia MATLAB Wolfram TeX \[\frac{x \cdot \left(y + z\right)}{z}
\]
↓
\[\begin{array}{l}
t_0 := \frac{x \cdot \left(y + z\right)}{z}\\
\mathbf{if}\;t_0 \leq -\infty:\\
\;\;\;\;\left(y + z\right) \cdot \frac{x}{z}\\
\mathbf{elif}\;t_0 \leq -5 \cdot 10^{+50} \lor \neg \left(t_0 \leq 2 \cdot 10^{-77}\right) \land t_0 \leq 5 \cdot 10^{+287}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;x + \frac{x}{\frac{z}{y}}\\
\end{array}
\]
(FPCore (x y z) :precision binary64 (/ (* x (+ y z)) z)) ↓
(FPCore (x y z)
:precision binary64
(let* ((t_0 (/ (* x (+ y z)) z)))
(if (<= t_0 (- INFINITY))
(* (+ y z) (/ x z))
(if (or (<= t_0 -5e+50) (and (not (<= t_0 2e-77)) (<= t_0 5e+287)))
t_0
(+ x (/ x (/ z y))))))) double code(double x, double y, double z) {
return (x * (y + z)) / z;
}
↓
double code(double x, double y, double z) {
double t_0 = (x * (y + z)) / z;
double tmp;
if (t_0 <= -((double) INFINITY)) {
tmp = (y + z) * (x / z);
} else if ((t_0 <= -5e+50) || (!(t_0 <= 2e-77) && (t_0 <= 5e+287))) {
tmp = t_0;
} else {
tmp = x + (x / (z / y));
}
return tmp;
}
public static double code(double x, double y, double z) {
return (x * (y + z)) / z;
}
↓
public static double code(double x, double y, double z) {
double t_0 = (x * (y + z)) / z;
double tmp;
if (t_0 <= -Double.POSITIVE_INFINITY) {
tmp = (y + z) * (x / z);
} else if ((t_0 <= -5e+50) || (!(t_0 <= 2e-77) && (t_0 <= 5e+287))) {
tmp = t_0;
} else {
tmp = x + (x / (z / y));
}
return tmp;
}
def code(x, y, z):
return (x * (y + z)) / z
↓
def code(x, y, z):
t_0 = (x * (y + z)) / z
tmp = 0
if t_0 <= -math.inf:
tmp = (y + z) * (x / z)
elif (t_0 <= -5e+50) or (not (t_0 <= 2e-77) and (t_0 <= 5e+287)):
tmp = t_0
else:
tmp = x + (x / (z / y))
return tmp
function code(x, y, z)
return Float64(Float64(x * Float64(y + z)) / z)
end
↓
function code(x, y, z)
t_0 = Float64(Float64(x * Float64(y + z)) / z)
tmp = 0.0
if (t_0 <= Float64(-Inf))
tmp = Float64(Float64(y + z) * Float64(x / z));
elseif ((t_0 <= -5e+50) || (!(t_0 <= 2e-77) && (t_0 <= 5e+287)))
tmp = t_0;
else
tmp = Float64(x + Float64(x / Float64(z / y)));
end
return tmp
end
function tmp = code(x, y, z)
tmp = (x * (y + z)) / z;
end
↓
function tmp_2 = code(x, y, z)
t_0 = (x * (y + z)) / z;
tmp = 0.0;
if (t_0 <= -Inf)
tmp = (y + z) * (x / z);
elseif ((t_0 <= -5e+50) || (~((t_0 <= 2e-77)) && (t_0 <= 5e+287)))
tmp = t_0;
else
tmp = x + (x / (z / y));
end
tmp_2 = tmp;
end
code[x_, y_, z_] := N[(N[(x * N[(y + z), $MachinePrecision]), $MachinePrecision] / z), $MachinePrecision]
↓
code[x_, y_, z_] := Block[{t$95$0 = N[(N[(x * N[(y + z), $MachinePrecision]), $MachinePrecision] / z), $MachinePrecision]}, If[LessEqual[t$95$0, (-Infinity)], N[(N[(y + z), $MachinePrecision] * N[(x / z), $MachinePrecision]), $MachinePrecision], If[Or[LessEqual[t$95$0, -5e+50], And[N[Not[LessEqual[t$95$0, 2e-77]], $MachinePrecision], LessEqual[t$95$0, 5e+287]]], t$95$0, N[(x + N[(x / N[(z / y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\frac{x \cdot \left(y + z\right)}{z}
↓
\begin{array}{l}
t_0 := \frac{x \cdot \left(y + z\right)}{z}\\
\mathbf{if}\;t_0 \leq -\infty:\\
\;\;\;\;\left(y + z\right) \cdot \frac{x}{z}\\
\mathbf{elif}\;t_0 \leq -5 \cdot 10^{+50} \lor \neg \left(t_0 \leq 2 \cdot 10^{-77}\right) \land t_0 \leq 5 \cdot 10^{+287}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;x + \frac{x}{\frac{z}{y}}\\
\end{array}
Alternatives Alternative 1 Accuracy 69.2% Cost 849
\[\begin{array}{l}
\mathbf{if}\;z \leq -2 \cdot 10^{+102}:\\
\;\;\;\;x\\
\mathbf{elif}\;z \leq -5 \cdot 10^{+56} \lor \neg \left(z \leq -5.7 \cdot 10^{+19}\right) \land z \leq 5.6 \cdot 10^{-121}:\\
\;\;\;\;y \cdot \frac{x}{z}\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 2 Accuracy 69.4% Cost 848
\[\begin{array}{l}
\mathbf{if}\;z \leq -2 \cdot 10^{+102}:\\
\;\;\;\;x\\
\mathbf{elif}\;z \leq -5 \cdot 10^{+56}:\\
\;\;\;\;\frac{x}{\frac{z}{y}}\\
\mathbf{elif}\;z \leq -6.8 \cdot 10^{+18}:\\
\;\;\;\;x\\
\mathbf{elif}\;z \leq 5.8 \cdot 10^{-121}:\\
\;\;\;\;y \cdot \frac{x}{z}\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 3 Accuracy 69.4% Cost 848
\[\begin{array}{l}
\mathbf{if}\;z \leq -2 \cdot 10^{+103}:\\
\;\;\;\;x\\
\mathbf{elif}\;z \leq -1.32 \cdot 10^{+56}:\\
\;\;\;\;\frac{x}{\frac{z}{y}}\\
\mathbf{elif}\;z \leq -6 \cdot 10^{+18}:\\
\;\;\;\;x\\
\mathbf{elif}\;z \leq 1.4 \cdot 10^{-122}:\\
\;\;\;\;\frac{y}{\frac{z}{x}}\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 4 Accuracy 68.2% Cost 848
\[\begin{array}{l}
\mathbf{if}\;z \leq -2 \cdot 10^{+102}:\\
\;\;\;\;x\\
\mathbf{elif}\;z \leq -5 \cdot 10^{+56}:\\
\;\;\;\;\frac{x}{\frac{z}{y}}\\
\mathbf{elif}\;z \leq -6.4 \cdot 10^{+18}:\\
\;\;\;\;x\\
\mathbf{elif}\;z \leq 4 \cdot 10^{-200}:\\
\;\;\;\;\frac{x \cdot y}{z}\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 5 Accuracy 94.6% Cost 713
\[\begin{array}{l}
\mathbf{if}\;z \leq -2.2 \cdot 10^{-152} \lor \neg \left(z \leq -4.2 \cdot 10^{-217}\right):\\
\;\;\;\;x \cdot \left(1 + \frac{y}{z}\right)\\
\mathbf{else}:\\
\;\;\;\;\left(y + z\right) \cdot \frac{x}{z}\\
\end{array}
\]
Alternative 6 Accuracy 95.0% Cost 713
\[\begin{array}{l}
\mathbf{if}\;z \leq -2.3 \cdot 10^{-152} \lor \neg \left(z \leq -4.8 \cdot 10^{-220}\right):\\
\;\;\;\;x + \frac{x}{\frac{z}{y}}\\
\mathbf{else}:\\
\;\;\;\;\left(y + z\right) \cdot \frac{x}{z}\\
\end{array}
\]
Alternative 7 Accuracy 94.5% Cost 448
\[x \cdot \left(1 + \frac{y}{z}\right)
\]
Alternative 8 Accuracy 61.0% Cost 64
\[x
\]