Math FPCore C Julia Wolfram TeX \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 - a\right) + \left(b \cdot b\right) \cdot \left(3 + a\right)\right)\right) - 1
\]
↓
\[{\left(\mathsf{hypot}\left(a, b\right)\right)}^{4} + \mathsf{fma}\left(4, \mathsf{fma}\left(b \cdot b, a + 3, a \cdot a\right) - {a}^{3}, -1\right)
\]
(FPCore (a b)
:precision binary64
(-
(+
(pow (+ (* a a) (* b b)) 2.0)
(* 4.0 (+ (* (* a a) (- 1.0 a)) (* (* b b) (+ 3.0 a)))))
1.0)) ↓
(FPCore (a b)
:precision binary64
(+
(pow (hypot a b) 4.0)
(fma 4.0 (- (fma (* b b) (+ a 3.0) (* a a)) (pow a 3.0)) -1.0))) double code(double a, double b) {
return (pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 - a)) + ((b * b) * (3.0 + a))))) - 1.0;
}
↓
double code(double a, double b) {
return pow(hypot(a, b), 4.0) + fma(4.0, (fma((b * b), (a + 3.0), (a * a)) - pow(a, 3.0)), -1.0);
}
function code(a, b)
return Float64(Float64((Float64(Float64(a * a) + Float64(b * b)) ^ 2.0) + Float64(4.0 * Float64(Float64(Float64(a * a) * Float64(1.0 - a)) + Float64(Float64(b * b) * Float64(3.0 + a))))) - 1.0)
end
↓
function code(a, b)
return Float64((hypot(a, b) ^ 4.0) + fma(4.0, Float64(fma(Float64(b * b), Float64(a + 3.0), Float64(a * a)) - (a ^ 3.0)), -1.0))
end
code[a_, b_] := N[(N[(N[Power[N[(N[(a * a), $MachinePrecision] + N[(b * b), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[(4.0 * N[(N[(N[(a * a), $MachinePrecision] * N[(1.0 - a), $MachinePrecision]), $MachinePrecision] + N[(N[(b * b), $MachinePrecision] * N[(3.0 + a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision]
↓
code[a_, b_] := N[(N[Power[N[Sqrt[a ^ 2 + b ^ 2], $MachinePrecision], 4.0], $MachinePrecision] + N[(4.0 * N[(N[(N[(b * b), $MachinePrecision] * N[(a + 3.0), $MachinePrecision] + N[(a * a), $MachinePrecision]), $MachinePrecision] - N[Power[a, 3.0], $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision]), $MachinePrecision]
\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 - a\right) + \left(b \cdot b\right) \cdot \left(3 + a\right)\right)\right) - 1
↓
{\left(\mathsf{hypot}\left(a, b\right)\right)}^{4} + \mathsf{fma}\left(4, \mathsf{fma}\left(b \cdot b, a + 3, a \cdot a\right) - {a}^{3}, -1\right)
Alternatives Alternative 1 Accuracy 98.7% Cost 8328
\[\begin{array}{l}
\mathbf{if}\;a \leq -4.3 \cdot 10^{-7}:\\
\;\;\;\;\left({a}^{4} + 4 \cdot \left(a \cdot \left(a \cdot \left(1 - a\right)\right)\right)\right) + -1\\
\mathbf{elif}\;a \leq 1.05 \cdot 10^{-15}:\\
\;\;\;\;\left({b}^{4} + \left(b \cdot b\right) \cdot 12\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\left({\left(b \cdot b + a \cdot a\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 - a\right) + b \cdot \left(a \cdot b\right)\right)\right) + -1\\
\end{array}
\]
Alternative 2 Accuracy 99.7% Cost 8192
\[\left({\left(b \cdot b + a \cdot a\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 - a\right) + \left(b \cdot b\right) \cdot \left(a + 3\right)\right)\right) + -1
\]
Alternative 3 Accuracy 97.1% Cost 7561
\[\begin{array}{l}
\mathbf{if}\;a \leq -1.25 \cdot 10^{-6} \lor \neg \left(a \leq 1.05 \cdot 10^{-15}\right):\\
\;\;\;\;a \cdot \left({a}^{3} + a \cdot \left(4 + a \cdot -4\right)\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\left({b}^{4} + \left(b \cdot b\right) \cdot 12\right) + -1\\
\end{array}
\]
Alternative 4 Accuracy 97.2% Cost 7561
\[\begin{array}{l}
\mathbf{if}\;a \leq -1 \cdot 10^{-7} \lor \neg \left(a \leq 1.05 \cdot 10^{-15}\right):\\
\;\;\;\;\left({a}^{4} + 4 \cdot \left(a \cdot \left(a \cdot \left(1 - a\right)\right)\right)\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\left({b}^{4} + \left(b \cdot b\right) \cdot 12\right) + -1\\
\end{array}
\]
Alternative 5 Accuracy 95.7% Cost 7433
\[\begin{array}{l}
\mathbf{if}\;a \leq -1.9 \cdot 10^{-5} \lor \neg \left(a \leq 10^{-15}\right):\\
\;\;\;\;\left({a}^{4} - 4 \cdot \left(a \cdot \left(a \cdot a\right)\right)\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\left({b}^{4} + \left(b \cdot b\right) \cdot 12\right) + -1\\
\end{array}
\]
Alternative 6 Accuracy 95.7% Cost 7305
\[\begin{array}{l}
\mathbf{if}\;a \leq -1.9 \cdot 10^{-5} \lor \neg \left(a \leq 1.05 \cdot 10^{-15}\right):\\
\;\;\;\;{a}^{3} \cdot \left(a + -4\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\left({b}^{4} + \left(b \cdot b\right) \cdot 12\right) + -1\\
\end{array}
\]
Alternative 7 Accuracy 95.6% Cost 7241
\[\begin{array}{l}
\mathbf{if}\;a \leq -1.4 \cdot 10^{-5} \lor \neg \left(a \leq 1.05 \cdot 10^{-15}\right):\\
\;\;\;\;{a}^{3} \cdot \left(a + -4\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(b \cdot b, b \cdot b + 12, -1\right)\\
\end{array}
\]
Alternative 8 Accuracy 94.2% Cost 7177
\[\begin{array}{l}
\mathbf{if}\;a \leq -1.9 \cdot 10^{-5} \lor \neg \left(a \leq 1.05 \cdot 10^{-15}\right):\\
\;\;\;\;{a}^{3} \cdot \left(a + -4\right) + -1\\
\mathbf{else}:\\
\;\;\;\;{b}^{4} + -1\\
\end{array}
\]
Alternative 9 Accuracy 80.4% Cost 6924
\[\begin{array}{l}
t_0 := \left(b \cdot b\right) \cdot 12 + \left(b \cdot b\right) \cdot \left(b \cdot b\right)\\
\mathbf{if}\;b \leq -0.28:\\
\;\;\;\;t_0\\
\mathbf{elif}\;b \leq -3.3 \cdot 10^{-131}:\\
\;\;\;\;\left(a \cdot a\right) \cdot \left(4 + a \cdot -4\right) + -1\\
\mathbf{elif}\;b \leq -1.95 \cdot 10^{-138}:\\
\;\;\;\;{a}^{4}\\
\mathbf{elif}\;b \leq 0.29:\\
\;\;\;\;a \cdot \left(a \cdot 4\right) + -1\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
Alternative 10 Accuracy 93.6% Cost 6921
\[\begin{array}{l}
\mathbf{if}\;a \leq -0.00016 \lor \neg \left(a \leq 1.05 \cdot 10^{-15}\right):\\
\;\;\;\;{a}^{4} + -1\\
\mathbf{else}:\\
\;\;\;\;{b}^{4} + -1\\
\end{array}
\]
Alternative 11 Accuracy 94.6% Cost 6916
\[\begin{array}{l}
\mathbf{if}\;b \cdot b \leq 0.04:\\
\;\;\;\;{a}^{4} + -1\\
\mathbf{else}:\\
\;\;\;\;\left(b \cdot b\right) \cdot 12 + \left(b \cdot b\right) \cdot \left(b \cdot b\right)\\
\end{array}
\]
Alternative 12 Accuracy 80.9% Cost 1097
\[\begin{array}{l}
\mathbf{if}\;b \leq -0.28 \lor \neg \left(b \leq 0.29\right):\\
\;\;\;\;\left(b \cdot b\right) \cdot 12 + \left(b \cdot b\right) \cdot \left(b \cdot b\right)\\
\mathbf{else}:\\
\;\;\;\;a \cdot \left(a \cdot 4\right) + -1\\
\end{array}
\]
Alternative 13 Accuracy 63.7% Cost 448
\[-1 + b \cdot \left(b \cdot 12\right)
\]
Alternative 14 Accuracy 62.1% Cost 64
\[-1
\]