Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{\left(x \cdot x + y \cdot y\right) - z \cdot z}{y \cdot 2}
\]
↓
\[\left(\left(x + z\right) \cdot \frac{z - x}{y} - y\right) \cdot -0.5
\]
(FPCore (x y z)
:precision binary64
(/ (- (+ (* x x) (* y y)) (* z z)) (* y 2.0))) ↓
(FPCore (x y z) :precision binary64 (* (- (* (+ x z) (/ (- z x) y)) y) -0.5)) double code(double x, double y, double z) {
return (((x * x) + (y * y)) - (z * z)) / (y * 2.0);
}
↓
double code(double x, double y, double z) {
return (((x + z) * ((z - x) / y)) - y) * -0.5;
}
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
code = (((x * x) + (y * y)) - (z * z)) / (y * 2.0d0)
end function
↓
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
code = (((x + z) * ((z - x) / y)) - y) * (-0.5d0)
end function
public static double code(double x, double y, double z) {
return (((x * x) + (y * y)) - (z * z)) / (y * 2.0);
}
↓
public static double code(double x, double y, double z) {
return (((x + z) * ((z - x) / y)) - y) * -0.5;
}
def code(x, y, z):
return (((x * x) + (y * y)) - (z * z)) / (y * 2.0)
↓
def code(x, y, z):
return (((x + z) * ((z - x) / y)) - y) * -0.5
function code(x, y, z)
return Float64(Float64(Float64(Float64(x * x) + Float64(y * y)) - Float64(z * z)) / Float64(y * 2.0))
end
↓
function code(x, y, z)
return Float64(Float64(Float64(Float64(x + z) * Float64(Float64(z - x) / y)) - y) * -0.5)
end
function tmp = code(x, y, z)
tmp = (((x * x) + (y * y)) - (z * z)) / (y * 2.0);
end
↓
function tmp = code(x, y, z)
tmp = (((x + z) * ((z - x) / y)) - y) * -0.5;
end
code[x_, y_, z_] := N[(N[(N[(N[(x * x), $MachinePrecision] + N[(y * y), $MachinePrecision]), $MachinePrecision] - N[(z * z), $MachinePrecision]), $MachinePrecision] / N[(y * 2.0), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_] := N[(N[(N[(N[(x + z), $MachinePrecision] * N[(N[(z - x), $MachinePrecision] / y), $MachinePrecision]), $MachinePrecision] - y), $MachinePrecision] * -0.5), $MachinePrecision]
\frac{\left(x \cdot x + y \cdot y\right) - z \cdot z}{y \cdot 2}
↓
\left(\left(x + z\right) \cdot \frac{z - x}{y} - y\right) \cdot -0.5
Alternatives Alternative 1 Accuracy 62.0% Cost 1108
\[\begin{array}{l}
t_0 := 0.5 \cdot \frac{x}{\frac{y}{x}}\\
t_1 := z \cdot \frac{-0.5}{\frac{y}{z}}\\
\mathbf{if}\;y \leq -6.2 \cdot 10^{+63}:\\
\;\;\;\;y \cdot 0.5\\
\mathbf{elif}\;y \leq -1.16 \cdot 10^{-76}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 8.4 \cdot 10^{-262}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq 4.4 \cdot 10^{-138}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 1.9 \cdot 10^{+17}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;y \cdot 0.5\\
\end{array}
\]
Alternative 2 Accuracy 61.8% Cost 1108
\[\begin{array}{l}
t_0 := 0.5 \cdot \frac{x}{\frac{y}{x}}\\
t_1 := -0.5 \cdot \frac{z}{\frac{y}{z}}\\
\mathbf{if}\;y \leq -1.25 \cdot 10^{+67}:\\
\;\;\;\;y \cdot 0.5\\
\mathbf{elif}\;y \leq -1.75 \cdot 10^{-76}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 3.25 \cdot 10^{-261}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq 9.6 \cdot 10^{-141}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 4.4 \cdot 10^{+17}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;y \cdot 0.5\\
\end{array}
\]
Alternative 3 Accuracy 62.0% Cost 1108
\[\begin{array}{l}
t_0 := -0.5 \cdot \frac{z}{\frac{y}{z}}\\
\mathbf{if}\;y \leq -6.2 \cdot 10^{+63}:\\
\;\;\;\;y \cdot 0.5\\
\mathbf{elif}\;y \leq -2.05 \cdot 10^{-76}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq 1.78 \cdot 10^{-261}:\\
\;\;\;\;x \cdot \frac{x \cdot 0.5}{y}\\
\mathbf{elif}\;y \leq 3.3 \cdot 10^{-139}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq 2.2 \cdot 10^{+14}:\\
\;\;\;\;0.5 \cdot \frac{x}{\frac{y}{x}}\\
\mathbf{else}:\\
\;\;\;\;y \cdot 0.5\\
\end{array}
\]
Alternative 4 Accuracy 61.8% Cost 1108
\[\begin{array}{l}
\mathbf{if}\;y \leq -6.2 \cdot 10^{+63}:\\
\;\;\;\;y \cdot 0.5\\
\mathbf{elif}\;y \leq -1.4 \cdot 10^{-76}:\\
\;\;\;\;-0.5 \cdot \frac{z}{\frac{y}{z}}\\
\mathbf{elif}\;y \leq 7.7 \cdot 10^{-262}:\\
\;\;\;\;x \cdot \frac{x \cdot 0.5}{y}\\
\mathbf{elif}\;y \leq 3.8 \cdot 10^{-141}:\\
\;\;\;\;\frac{-0.5}{\frac{y}{z \cdot z}}\\
\mathbf{elif}\;y \leq 2.6 \cdot 10^{+14}:\\
\;\;\;\;0.5 \cdot \frac{x}{\frac{y}{x}}\\
\mathbf{else}:\\
\;\;\;\;y \cdot 0.5\\
\end{array}
\]
Alternative 5 Accuracy 61.8% Cost 1108
\[\begin{array}{l}
\mathbf{if}\;y \leq -6.2 \cdot 10^{+63}:\\
\;\;\;\;y \cdot 0.5\\
\mathbf{elif}\;y \leq -2.05 \cdot 10^{-76}:\\
\;\;\;\;-0.5 \cdot \frac{z}{\frac{y}{z}}\\
\mathbf{elif}\;y \leq 3.6 \cdot 10^{-261}:\\
\;\;\;\;x \cdot \frac{x \cdot 0.5}{y}\\
\mathbf{elif}\;y \leq 2.3 \cdot 10^{-139}:\\
\;\;\;\;\frac{-0.5}{\frac{y}{z \cdot z}}\\
\mathbf{elif}\;y \leq 1.9 \cdot 10^{+17}:\\
\;\;\;\;\frac{x \cdot \left(x \cdot 0.5\right)}{y}\\
\mathbf{else}:\\
\;\;\;\;y \cdot 0.5\\
\end{array}
\]
Alternative 6 Accuracy 77.0% Cost 1105
\[\begin{array}{l}
t_0 := -0.5 \cdot \left(\frac{z}{\frac{y}{z}} - y\right)\\
\mathbf{if}\;y \leq -1.8 \cdot 10^{-77}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq -7.2 \cdot 10^{-140}:\\
\;\;\;\;x \cdot \frac{x \cdot 0.5}{y}\\
\mathbf{elif}\;y \leq 4.6 \cdot 10^{-138} \lor \neg \left(y \leq 1.6 \cdot 10^{-85}\right):\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;\frac{x \cdot \left(x \cdot 0.5\right)}{y}\\
\end{array}
\]
Alternative 7 Accuracy 90.0% Cost 968
\[\begin{array}{l}
\mathbf{if}\;x \leq -6.9 \cdot 10^{-57}:\\
\;\;\;\;-0.5 \cdot \left(x \cdot \frac{-x}{y} - y\right)\\
\mathbf{elif}\;x \leq 1.15 \cdot 10^{-14}:\\
\;\;\;\;-0.5 \cdot \left(\frac{z}{\frac{y}{z}} - y\right)\\
\mathbf{else}:\\
\;\;\;\;-0.5 \cdot \left(\left(z - x\right) \cdot \frac{x}{y} - y\right)\\
\end{array}
\]
Alternative 8 Accuracy 90.0% Cost 905
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.4 \cdot 10^{-55} \lor \neg \left(x \leq 4.3 \cdot 10^{-18}\right):\\
\;\;\;\;-0.5 \cdot \left(x \cdot \frac{-x}{y} - y\right)\\
\mathbf{else}:\\
\;\;\;\;-0.5 \cdot \left(\frac{z}{\frac{y}{z}} - y\right)\\
\end{array}
\]
Alternative 9 Accuracy 63.6% Cost 712
\[\begin{array}{l}
\mathbf{if}\;y \leq -3.1 \cdot 10^{-42}:\\
\;\;\;\;y \cdot 0.5\\
\mathbf{elif}\;y \leq 2.2 \cdot 10^{+14}:\\
\;\;\;\;0.5 \cdot \frac{x}{\frac{y}{x}}\\
\mathbf{else}:\\
\;\;\;\;y \cdot 0.5\\
\end{array}
\]
Alternative 10 Accuracy 57.2% Cost 192
\[y \cdot 0.5
\]