?

Average Accuracy: 99.9% → 99.9%
Time: 9.2s
Precision: binary64
Cost: 704

?

\[ \begin{array}{c}[x, y] = \mathsf{sort}([x, y])\\ \end{array} \]
\[\frac{\left(x + y\right) - z}{t \cdot 2} \]
\[0.5 \cdot \left(\frac{x}{t} + \frac{y - z}{t}\right) \]
(FPCore (x y z t) :precision binary64 (/ (- (+ x y) z) (* t 2.0)))
(FPCore (x y z t) :precision binary64 (* 0.5 (+ (/ x t) (/ (- y z) t))))
double code(double x, double y, double z, double t) {
	return ((x + y) - z) / (t * 2.0);
}
double code(double x, double y, double z, double t) {
	return 0.5 * ((x / t) + ((y - z) / t));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = ((x + y) - z) / (t * 2.0d0)
end function
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = 0.5d0 * ((x / t) + ((y - z) / t))
end function
public static double code(double x, double y, double z, double t) {
	return ((x + y) - z) / (t * 2.0);
}
public static double code(double x, double y, double z, double t) {
	return 0.5 * ((x / t) + ((y - z) / t));
}
def code(x, y, z, t):
	return ((x + y) - z) / (t * 2.0)
def code(x, y, z, t):
	return 0.5 * ((x / t) + ((y - z) / t))
function code(x, y, z, t)
	return Float64(Float64(Float64(x + y) - z) / Float64(t * 2.0))
end
function code(x, y, z, t)
	return Float64(0.5 * Float64(Float64(x / t) + Float64(Float64(y - z) / t)))
end
function tmp = code(x, y, z, t)
	tmp = ((x + y) - z) / (t * 2.0);
end
function tmp = code(x, y, z, t)
	tmp = 0.5 * ((x / t) + ((y - z) / t));
end
code[x_, y_, z_, t_] := N[(N[(N[(x + y), $MachinePrecision] - z), $MachinePrecision] / N[(t * 2.0), $MachinePrecision]), $MachinePrecision]
code[x_, y_, z_, t_] := N[(0.5 * N[(N[(x / t), $MachinePrecision] + N[(N[(y - z), $MachinePrecision] / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{\left(x + y\right) - z}{t \cdot 2}
0.5 \cdot \left(\frac{x}{t} + \frac{y - z}{t}\right)

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Initial program 99.9%

    \[\frac{\left(x + y\right) - z}{t \cdot 2} \]
  2. Taylor expanded in x around 0 99.9%

    \[\leadsto \color{blue}{0.5 \cdot \frac{y - z}{t} + 0.5 \cdot \frac{x}{t}} \]
  3. Simplified99.9%

    \[\leadsto \color{blue}{0.5 \cdot \left(\frac{x}{t} + \frac{y - z}{t}\right)} \]
    Proof

    [Start]99.9

    \[ 0.5 \cdot \frac{y - z}{t} + 0.5 \cdot \frac{x}{t} \]

    +-commutative [=>]99.9

    \[ \color{blue}{0.5 \cdot \frac{x}{t} + 0.5 \cdot \frac{y - z}{t}} \]

    distribute-lft-out [=>]99.9

    \[ \color{blue}{0.5 \cdot \left(\frac{x}{t} + \frac{y - z}{t}\right)} \]
  4. Final simplification99.9%

    \[\leadsto 0.5 \cdot \left(\frac{x}{t} + \frac{y - z}{t}\right) \]

Alternatives

Alternative 1
Accuracy52.0%
Cost1640
\[\begin{array}{l} t_1 := z \cdot \frac{-0.5}{t}\\ t_2 := 0.5 \cdot \frac{y}{t}\\ t_3 := x \cdot \frac{0.5}{t}\\ \mathbf{if}\;z \leq -3.9 \cdot 10^{+135}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq -1.6 \cdot 10^{+119}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq -4.2 \cdot 10^{-58}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq -9.2 \cdot 10^{-133}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq -1.5 \cdot 10^{-172}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq -3.3 \cdot 10^{-271}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq 1.05 \cdot 10^{-171}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq 8.1 \cdot 10^{-131}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq 2.5 \cdot 10^{-91}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq 3.25 \cdot 10^{-18}:\\ \;\;\;\;t_3\\ \mathbf{else}:\\ \;\;\;\;t_1\\ \end{array} \]
Alternative 2
Accuracy52.1%
Cost1640
\[\begin{array}{l} t_1 := -0.5 \cdot \frac{z}{t}\\ t_2 := 0.5 \cdot \frac{y}{t}\\ t_3 := x \cdot \frac{0.5}{t}\\ \mathbf{if}\;z \leq -3.8 \cdot 10^{+135}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq -1.6 \cdot 10^{+119}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq -4.2 \cdot 10^{-58}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq -1.16 \cdot 10^{-132}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq -1.8 \cdot 10^{-172}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq -5.2 \cdot 10^{-272}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq 1.3 \cdot 10^{-171}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq 4.3 \cdot 10^{-131}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq 1.6 \cdot 10^{-91}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq 4.2 \cdot 10^{-20}:\\ \;\;\;\;t_3\\ \mathbf{else}:\\ \;\;\;\;t_1\\ \end{array} \]
Alternative 3
Accuracy52.1%
Cost1640
\[\begin{array}{l} t_1 := -0.5 \cdot \frac{z}{t}\\ t_2 := 0.5 \cdot \frac{y}{t}\\ t_3 := x \cdot \frac{0.5}{t}\\ \mathbf{if}\;z \leq -3.8 \cdot 10^{+135}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq -1.32 \cdot 10^{+119}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq -4.2 \cdot 10^{-58}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq -1.32 \cdot 10^{-132}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq -2.55 \cdot 10^{-172}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq -2.2 \cdot 10^{-272}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq 1.05 \cdot 10^{-171}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq 2.1 \cdot 10^{-131}:\\ \;\;\;\;\frac{0.5}{\frac{t}{x}}\\ \mathbf{elif}\;z \leq 1.1 \cdot 10^{-91}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq 2.6 \cdot 10^{-20}:\\ \;\;\;\;t_3\\ \mathbf{else}:\\ \;\;\;\;t_1\\ \end{array} \]
Alternative 4
Accuracy52.2%
Cost1640
\[\begin{array}{l} t_1 := -0.5 \cdot \frac{z}{t}\\ t_2 := 0.5 \cdot \frac{y}{t}\\ t_3 := \frac{0.5 \cdot x}{t}\\ \mathbf{if}\;z \leq -3.9 \cdot 10^{+135}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq -1.6 \cdot 10^{+119}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq -7.6 \cdot 10^{-59}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq -4.2 \cdot 10^{-133}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq -6.2 \cdot 10^{-171}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq -1.02 \cdot 10^{-272}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq 1.05 \cdot 10^{-171}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq 1.65 \cdot 10^{-130}:\\ \;\;\;\;t_3\\ \mathbf{elif}\;z \leq 3.7 \cdot 10^{-91}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;z \leq 2.05 \cdot 10^{-20}:\\ \;\;\;\;t_3\\ \mathbf{else}:\\ \;\;\;\;t_1\\ \end{array} \]
Alternative 5
Accuracy85.3%
Cost845
\[\begin{array}{l} \mathbf{if}\;y \leq 7.2 \cdot 10^{-6} \lor \neg \left(y \leq 1.3 \cdot 10^{+41}\right) \land y \leq 1.65 \cdot 10^{+95}:\\ \;\;\;\;0.5 \cdot \frac{x - z}{t}\\ \mathbf{else}:\\ \;\;\;\;0.5 \cdot \frac{x + y}{t}\\ \end{array} \]
Alternative 6
Accuracy89.6%
Cost845
\[\begin{array}{l} \mathbf{if}\;y \leq 2.5 \cdot 10^{-88}:\\ \;\;\;\;0.5 \cdot \frac{x - z}{t}\\ \mathbf{elif}\;y \leq 1.45 \cdot 10^{+31} \lor \neg \left(y \leq 1.85 \cdot 10^{+52}\right):\\ \;\;\;\;0.5 \cdot \frac{y - z}{t}\\ \mathbf{else}:\\ \;\;\;\;0.5 \cdot \frac{x + y}{t}\\ \end{array} \]
Alternative 7
Accuracy89.6%
Cost845
\[\begin{array}{l} \mathbf{if}\;y \leq 2.1 \cdot 10^{-88}:\\ \;\;\;\;0.5 \cdot \left(\frac{x}{t} - \frac{z}{t}\right)\\ \mathbf{elif}\;y \leq 4.8 \cdot 10^{+31} \lor \neg \left(y \leq 1.4 \cdot 10^{+52}\right):\\ \;\;\;\;0.5 \cdot \frac{y - z}{t}\\ \mathbf{else}:\\ \;\;\;\;0.5 \cdot \frac{x + y}{t}\\ \end{array} \]
Alternative 8
Accuracy52.6%
Cost717
\[\begin{array}{l} \mathbf{if}\;y \leq 0.48 \lor \neg \left(y \leq 3.9 \cdot 10^{+40}\right) \land y \leq 3.7 \cdot 10^{+96}:\\ \;\;\;\;z \cdot \frac{-0.5}{t}\\ \mathbf{else}:\\ \;\;\;\;0.5 \cdot \frac{y}{t}\\ \end{array} \]
Alternative 9
Accuracy78.2%
Cost713
\[\begin{array}{l} \mathbf{if}\;z \leq -4 \cdot 10^{+135} \lor \neg \left(z \leq 0.0275\right):\\ \;\;\;\;-0.5 \cdot \frac{z}{t}\\ \mathbf{else}:\\ \;\;\;\;0.5 \cdot \frac{x + y}{t}\\ \end{array} \]
Alternative 10
Accuracy99.6%
Cost576
\[\frac{-0.5}{t} \cdot \left(z - \left(x + y\right)\right) \]
Alternative 11
Accuracy99.9%
Cost576
\[\frac{\left(x + y\right) - z}{t \cdot 2} \]
Alternative 12
Accuracy36.4%
Cost320
\[0.5 \cdot \frac{y}{t} \]

Error

Reproduce?

herbie shell --seed 2023151 
(FPCore (x y z t)
  :name "Optimisation.CirclePacking:place from circle-packing-0.1.0.4, B"
  :precision binary64
  (/ (- (+ x y) z) (* t 2.0)))