Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1\right) \cdot \log a\right) - b}}{y}
\]
↓
\[\frac{x \cdot e^{\left(y \cdot \log z + \left(t + -1\right) \cdot \log a\right) - b}}{y}
\]
(FPCore (x y z t a b)
:precision binary64
(/ (* x (exp (- (+ (* y (log z)) (* (- t 1.0) (log a))) b))) y)) ↓
(FPCore (x y z t a b)
:precision binary64
(/ (* x (exp (- (+ (* y (log z)) (* (+ t -1.0) (log a))) b))) y)) double code(double x, double y, double z, double t, double a, double b) {
return (x * exp((((y * log(z)) + ((t - 1.0) * log(a))) - b))) / y;
}
↓
double code(double x, double y, double z, double t, double a, double b) {
return (x * exp((((y * log(z)) + ((t + -1.0) * log(a))) - b))) / y;
}
real(8) function code(x, y, z, t, a, b)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
real(8), intent (in) :: a
real(8), intent (in) :: b
code = (x * exp((((y * log(z)) + ((t - 1.0d0) * log(a))) - b))) / y
end function
↓
real(8) function code(x, y, z, t, a, b)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
real(8), intent (in) :: a
real(8), intent (in) :: b
code = (x * exp((((y * log(z)) + ((t + (-1.0d0)) * log(a))) - b))) / y
end function
public static double code(double x, double y, double z, double t, double a, double b) {
return (x * Math.exp((((y * Math.log(z)) + ((t - 1.0) * Math.log(a))) - b))) / y;
}
↓
public static double code(double x, double y, double z, double t, double a, double b) {
return (x * Math.exp((((y * Math.log(z)) + ((t + -1.0) * Math.log(a))) - b))) / y;
}
def code(x, y, z, t, a, b):
return (x * math.exp((((y * math.log(z)) + ((t - 1.0) * math.log(a))) - b))) / y
↓
def code(x, y, z, t, a, b):
return (x * math.exp((((y * math.log(z)) + ((t + -1.0) * math.log(a))) - b))) / y
function code(x, y, z, t, a, b)
return Float64(Float64(x * exp(Float64(Float64(Float64(y * log(z)) + Float64(Float64(t - 1.0) * log(a))) - b))) / y)
end
↓
function code(x, y, z, t, a, b)
return Float64(Float64(x * exp(Float64(Float64(Float64(y * log(z)) + Float64(Float64(t + -1.0) * log(a))) - b))) / y)
end
function tmp = code(x, y, z, t, a, b)
tmp = (x * exp((((y * log(z)) + ((t - 1.0) * log(a))) - b))) / y;
end
↓
function tmp = code(x, y, z, t, a, b)
tmp = (x * exp((((y * log(z)) + ((t + -1.0) * log(a))) - b))) / y;
end
code[x_, y_, z_, t_, a_, b_] := N[(N[(x * N[Exp[N[(N[(N[(y * N[Log[z], $MachinePrecision]), $MachinePrecision] + N[(N[(t - 1.0), $MachinePrecision] * N[Log[a], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - b), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / y), $MachinePrecision]
↓
code[x_, y_, z_, t_, a_, b_] := N[(N[(x * N[Exp[N[(N[(N[(y * N[Log[z], $MachinePrecision]), $MachinePrecision] + N[(N[(t + -1.0), $MachinePrecision] * N[Log[a], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - b), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / y), $MachinePrecision]
\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1\right) \cdot \log a\right) - b}}{y}
↓
\frac{x \cdot e^{\left(y \cdot \log z + \left(t + -1\right) \cdot \log a\right) - b}}{y}
Alternatives Alternative 1 Accuracy 87.6% Cost 27016
\[\begin{array}{l}
t_1 := \left(t + -1\right) \cdot \log a\\
t_2 := a \cdot e^{b}\\
\mathbf{if}\;t_1 \leq -635:\\
\;\;\;\;\frac{x \cdot \frac{{a}^{t}}{a}}{y}\\
\mathbf{elif}\;t_1 \leq 500:\\
\;\;\;\;\frac{x \cdot {z}^{y}}{y \cdot t_2}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{x}{t_2}}{y}\\
\end{array}
\]
Alternative 2 Accuracy 96.1% Cost 26692
\[\begin{array}{l}
\mathbf{if}\;\left(t + -1\right) \cdot \log a \leq -648:\\
\;\;\;\;\frac{x \cdot \frac{{a}^{t}}{a}}{y}\\
\mathbf{else}:\\
\;\;\;\;\frac{x \cdot e^{\left(y \cdot \log z - \log a\right) - b}}{y}\\
\end{array}
\]
Alternative 3 Accuracy 80.0% Cost 14233
\[\begin{array}{l}
t_1 := x \cdot \frac{{a}^{t}}{y \cdot a}\\
\mathbf{if}\;t \leq -1.2 \cdot 10^{+204}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq -5 \cdot 10^{+130}:\\
\;\;\;\;\frac{x}{a \cdot \left(y \cdot \left(1 + \left(b + 0.5 \cdot \left(b \cdot b\right)\right)\right)\right)}\\
\mathbf{elif}\;t \leq -4.6 \cdot 10^{+52}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq 0.0003 \lor \neg \left(t \leq 4.6 \cdot 10^{+42}\right) \land t \leq 9.5 \cdot 10^{+80}:\\
\;\;\;\;\frac{x \cdot \frac{\frac{{z}^{y}}{a}}{e^{b}}}{y}\\
\mathbf{else}:\\
\;\;\;\;\frac{x \cdot \frac{{a}^{t}}{a}}{y}\\
\end{array}
\]
Alternative 4 Accuracy 83.3% Cost 13836
\[\begin{array}{l}
\mathbf{if}\;b \leq 9.5 \cdot 10^{-91}:\\
\;\;\;\;\frac{x \cdot \frac{{a}^{t}}{a}}{y}\\
\mathbf{elif}\;b \leq 3.7 \cdot 10^{-13}:\\
\;\;\;\;\frac{x \cdot \frac{{z}^{y}}{a}}{y}\\
\mathbf{elif}\;b \leq 1000:\\
\;\;\;\;x \cdot \frac{{a}^{t}}{y \cdot \left(a \cdot e^{b}\right)}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{a \cdot \left(y \cdot e^{b}\right)}\\
\end{array}
\]
Alternative 5 Accuracy 72.4% Cost 7376
\[\begin{array}{l}
t_1 := \left(1 + \frac{x}{y \cdot a}\right) + -1\\
\mathbf{if}\;b \leq -9.2 \cdot 10^{+123}:\\
\;\;\;\;\frac{x}{0.5 \cdot \left(y \cdot \left(a \cdot \left(b \cdot b\right)\right)\right)}\\
\mathbf{elif}\;b \leq 5.8 \cdot 10^{-216}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;b \leq 9.4 \cdot 10^{-163}:\\
\;\;\;\;\frac{1}{a} \cdot \frac{1}{\frac{y}{x}}\\
\mathbf{elif}\;b \leq 4 \cdot 10^{-35}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{a \cdot \left(y \cdot e^{b}\right)}\\
\end{array}
\]
Alternative 6 Accuracy 83.1% Cost 7308
\[\begin{array}{l}
\mathbf{if}\;b \leq 7 \cdot 10^{-91}:\\
\;\;\;\;\frac{x \cdot \frac{{a}^{t}}{a}}{y}\\
\mathbf{elif}\;b \leq 1.1 \cdot 10^{-13}:\\
\;\;\;\;\frac{x \cdot \frac{{z}^{y}}{a}}{y}\\
\mathbf{elif}\;b \leq 200:\\
\;\;\;\;x \cdot \frac{{a}^{t}}{y \cdot a}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{a \cdot \left(y \cdot e^{b}\right)}\\
\end{array}
\]
Alternative 7 Accuracy 82.1% Cost 7176
\[\begin{array}{l}
\mathbf{if}\;b \leq -6.2 \cdot 10^{+119}:\\
\;\;\;\;\frac{x}{0.5 \cdot \left(y \cdot \left(a \cdot \left(b \cdot b\right)\right)\right)}\\
\mathbf{elif}\;b \leq 2.5 \cdot 10^{-20}:\\
\;\;\;\;x \cdot \frac{{a}^{t}}{y \cdot a}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{a \cdot \left(y \cdot e^{b}\right)}\\
\end{array}
\]
Alternative 8 Accuracy 83.2% Cost 7044
\[\begin{array}{l}
\mathbf{if}\;b \leq 2.5 \cdot 10^{-20}:\\
\;\;\;\;\frac{x \cdot \frac{{a}^{t}}{a}}{y}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{a \cdot \left(y \cdot e^{b}\right)}\\
\end{array}
\]
Alternative 9 Accuracy 60.4% Cost 1232
\[\begin{array}{l}
t_1 := \left(1 + \frac{x}{y \cdot a}\right) + -1\\
t_2 := \frac{2}{y} \cdot \frac{x}{b \cdot \left(a \cdot b\right)}\\
\mathbf{if}\;b \leq -1.7 \cdot 10^{+20}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;b \leq 5.05 \cdot 10^{-216}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;b \leq 9.4 \cdot 10^{-163}:\\
\;\;\;\;\frac{1}{a} \cdot \frac{1}{\frac{y}{x}}\\
\mathbf{elif}\;b \leq 5.5 \cdot 10^{+23}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;t_2\\
\end{array}
\]
Alternative 10 Accuracy 63.9% Cost 1232
\[\begin{array}{l}
t_1 := \left(1 + \frac{x}{y \cdot a}\right) + -1\\
t_2 := \frac{x}{0.5 \cdot \left(y \cdot \left(a \cdot \left(b \cdot b\right)\right)\right)}\\
\mathbf{if}\;b \leq -4.5 \cdot 10^{+121}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;b \leq 5.8 \cdot 10^{-216}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;b \leq 9.4 \cdot 10^{-163}:\\
\;\;\;\;\frac{1}{a} \cdot \frac{1}{\frac{y}{x}}\\
\mathbf{elif}\;b \leq 5.5 \cdot 10^{+23}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;t_2\\
\end{array}
\]
Alternative 11 Accuracy 52.9% Cost 972
\[\begin{array}{l}
t_1 := \left(1 + \frac{x}{y \cdot a}\right) + -1\\
\mathbf{if}\;b \leq 5.7 \cdot 10^{-216}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;b \leq 1.02 \cdot 10^{-162}:\\
\;\;\;\;\frac{1}{a} \cdot \frac{1}{\frac{y}{x}}\\
\mathbf{elif}\;b \leq 3.3 \cdot 10^{+202}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{a \cdot \left(y \cdot b\right)}\\
\end{array}
\]
Alternative 12 Accuracy 46.0% Cost 841
\[\begin{array}{l}
\mathbf{if}\;b \leq -1.05 \lor \neg \left(b \leq 0.0036\right):\\
\;\;\;\;\frac{x}{a \cdot \left(y \cdot b\right)}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{a} \cdot \frac{1}{\frac{y}{x}}\\
\end{array}
\]
Alternative 13 Accuracy 56.1% Cost 841
\[\begin{array}{l}
\mathbf{if}\;y \leq -1 \cdot 10^{+35} \lor \neg \left(y \leq 4 \cdot 10^{-26}\right):\\
\;\;\;\;\left(1 + \frac{x}{y \cdot a}\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\frac{\left(1 + \frac{x}{a}\right) + -1}{y}\\
\end{array}
\]
Alternative 14 Accuracy 45.8% Cost 713
\[\begin{array}{l}
\mathbf{if}\;b \leq -1 \lor \neg \left(b \leq 0.0065\right):\\
\;\;\;\;\frac{x}{a \cdot \left(y \cdot b\right)}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{x}{y}}{a}\\
\end{array}
\]
Alternative 15 Accuracy 34.9% Cost 452
\[\begin{array}{l}
\mathbf{if}\;y \leq 10^{-54}:\\
\;\;\;\;\frac{\frac{x}{a}}{y}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{y \cdot a}\\
\end{array}
\]
Alternative 16 Accuracy 39.2% Cost 452
\[\begin{array}{l}
\mathbf{if}\;a \leq 7.5 \cdot 10^{-67}:\\
\;\;\;\;\frac{\frac{x}{y}}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{y \cdot a}\\
\end{array}
\]
Alternative 17 Accuracy 34.3% Cost 320
\[\frac{x}{y \cdot a}
\]