\[\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot \sin \left(\lambda_1 - \lambda_2\right)}{\cos \phi_1 + \cos \phi_2 \cdot \cos \left(\lambda_1 - \lambda_2\right)}
\]
↓
\[\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot \sin \left(\lambda_1 - \lambda_2\right)}{\mathsf{fma}\left(\cos \phi_2, \cos \left(\lambda_1 - \lambda_2\right), \cos \phi_1\right)}
\]
(FPCore (lambda1 lambda2 phi1 phi2)
:precision binary64
(+
lambda1
(atan2
(* (cos phi2) (sin (- lambda1 lambda2)))
(+ (cos phi1) (* (cos phi2) (cos (- lambda1 lambda2)))))))
↓
(FPCore (lambda1 lambda2 phi1 phi2)
:precision binary64
(+
lambda1
(atan2
(* (cos phi2) (sin (- lambda1 lambda2)))
(fma (cos phi2) (cos (- lambda1 lambda2)) (cos phi1)))))
double code(double lambda1, double lambda2, double phi1, double phi2) {
return lambda1 + atan2((cos(phi2) * sin((lambda1 - lambda2))), (cos(phi1) + (cos(phi2) * cos((lambda1 - lambda2)))));
}
↓
double code(double lambda1, double lambda2, double phi1, double phi2) {
return lambda1 + atan2((cos(phi2) * sin((lambda1 - lambda2))), fma(cos(phi2), cos((lambda1 - lambda2)), cos(phi1)));
}
function code(lambda1, lambda2, phi1, phi2)
return Float64(lambda1 + atan(Float64(cos(phi2) * sin(Float64(lambda1 - lambda2))), Float64(cos(phi1) + Float64(cos(phi2) * cos(Float64(lambda1 - lambda2))))))
end
↓
function code(lambda1, lambda2, phi1, phi2)
return Float64(lambda1 + atan(Float64(cos(phi2) * sin(Float64(lambda1 - lambda2))), fma(cos(phi2), cos(Float64(lambda1 - lambda2)), cos(phi1))))
end
code[lambda1_, lambda2_, phi1_, phi2_] := N[(lambda1 + N[ArcTan[N[(N[Cos[phi2], $MachinePrecision] * N[Sin[N[(lambda1 - lambda2), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(N[Cos[phi1], $MachinePrecision] + N[(N[Cos[phi2], $MachinePrecision] * N[Cos[N[(lambda1 - lambda2), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
↓
code[lambda1_, lambda2_, phi1_, phi2_] := N[(lambda1 + N[ArcTan[N[(N[Cos[phi2], $MachinePrecision] * N[Sin[N[(lambda1 - lambda2), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(N[Cos[phi2], $MachinePrecision] * N[Cos[N[(lambda1 - lambda2), $MachinePrecision]], $MachinePrecision] + N[Cos[phi1], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot \sin \left(\lambda_1 - \lambda_2\right)}{\cos \phi_1 + \cos \phi_2 \cdot \cos \left(\lambda_1 - \lambda_2\right)}
↓
\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot \sin \left(\lambda_1 - \lambda_2\right)}{\mathsf{fma}\left(\cos \phi_2, \cos \left(\lambda_1 - \lambda_2\right), \cos \phi_1\right)}
Alternatives
| Alternative 1 |
|---|
| Accuracy | 89.9% |
|---|
| Cost | 45960 |
|---|
\[\begin{array}{l}
t_0 := \cos \left(\lambda_1 - \lambda_2\right)\\
t_1 := \cos \phi_2 \cdot \sin \left(\lambda_1 - \lambda_2\right)\\
\mathbf{if}\;\cos \phi_1 \leq 0.73:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_1}{\cos \phi_1 + t_0 \cdot \left(1 + -0.5 \cdot \left(\phi_2 \cdot \phi_2\right)\right)}\\
\mathbf{elif}\;\cos \phi_1 \leq 0.999999:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_1}{\cos \phi_2 + \cos \phi_1}\\
\mathbf{else}:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_1}{1 + \cos \phi_2 \cdot t_0}\\
\end{array}
\]
| Alternative 2 |
|---|
| Accuracy | 98.8% |
|---|
| Cost | 39296 |
|---|
\[\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot \sin \left(\lambda_1 - \lambda_2\right)}{\cos \phi_1 + \cos \phi_2 \cdot \cos \left(\lambda_1 - \lambda_2\right)}
\]
| Alternative 3 |
|---|
| Accuracy | 98.2% |
|---|
| Cost | 39168 |
|---|
\[\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot \sin \left(\lambda_1 - \lambda_2\right)}{\cos \phi_1 + \cos \phi_2 \cdot \cos \lambda_2}
\]
| Alternative 4 |
|---|
| Accuracy | 85.2% |
|---|
| Cost | 33156 |
|---|
\[\begin{array}{l}
t_0 := \sin \left(\lambda_1 - \lambda_2\right)\\
\mathbf{if}\;\cos \phi_2 \leq 0.967:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot t_0}{1 + \left(\cos \phi_2 + -0.5 \cdot \left(\phi_1 \cdot \phi_1\right)\right)}\\
\mathbf{else}:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_0}{\cos \phi_1 + \cos \left(\lambda_2 - \lambda_1\right)}\\
\end{array}
\]
| Alternative 5 |
|---|
| Accuracy | 88.0% |
|---|
| Cost | 33033 |
|---|
\[\begin{array}{l}
t_0 := \cos \phi_2 \cdot \sin \left(\lambda_1 - \lambda_2\right)\\
\mathbf{if}\;\phi_2 \leq -5300 \lor \neg \left(\phi_2 \leq 3100000000\right):\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_0}{\cos \phi_2 + \cos \phi_1}\\
\mathbf{else}:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_0}{\cos \phi_1 + \cos \left(\lambda_2 - \lambda_1\right)}\\
\end{array}
\]
| Alternative 6 |
|---|
| Accuracy | 88.2% |
|---|
| Cost | 32905 |
|---|
\[\begin{array}{l}
t_0 := \sin \left(\lambda_1 - \lambda_2\right)\\
\mathbf{if}\;\phi_2 \leq -12.8 \lor \neg \left(\phi_2 \leq 16000\right):\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot t_0}{\cos \phi_2 + \cos \phi_1}\\
\mathbf{else}:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_0}{\cos \phi_1 + \cos \left(\lambda_2 - \lambda_1\right)}\\
\end{array}
\]
| Alternative 7 |
|---|
| Accuracy | 78.2% |
|---|
| Cost | 32772 |
|---|
\[\begin{array}{l}
t_0 := \sin \left(\lambda_1 - \lambda_2\right)\\
\mathbf{if}\;\cos \phi_2 \leq 0.6:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot t_0}{\cos \phi_1 + 1}\\
\mathbf{else}:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_0}{\cos \phi_1 + \cos \left(\lambda_2 - \lambda_1\right)}\\
\end{array}
\]
| Alternative 8 |
|---|
| Accuracy | 82.5% |
|---|
| Cost | 32772 |
|---|
\[\begin{array}{l}
t_0 := \sin \left(\lambda_1 - \lambda_2\right)\\
\mathbf{if}\;\cos \phi_2 \leq 0.967:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot t_0}{\cos \phi_2 + 1}\\
\mathbf{else}:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_0}{\cos \phi_1 + \cos \left(\lambda_2 - \lambda_1\right)}\\
\end{array}
\]
| Alternative 9 |
|---|
| Accuracy | 84.4% |
|---|
| Cost | 32708 |
|---|
\[\begin{array}{l}
t_0 := \sin \left(\lambda_1 - \lambda_2\right)\\
\mathbf{if}\;\phi_2 \leq -57:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot \sin \left(-\lambda_2\right)}{\cos \phi_2 + \cos \phi_1}\\
\mathbf{elif}\;\phi_2 \leq 2.5 \cdot 10^{+15}:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_0}{\cos \phi_1 + \cos \left(\lambda_2 - \lambda_1\right)}\\
\mathbf{else}:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{\cos \phi_2 \cdot t_0}{1 + \left(\cos \phi_2 + -0.5 \cdot \left(\phi_1 \cdot \phi_1\right)\right)}\\
\end{array}
\]
| Alternative 10 |
|---|
| Accuracy | 70.7% |
|---|
| Cost | 32644 |
|---|
\[\begin{array}{l}
t_0 := \sin \left(\lambda_1 - \lambda_2\right)\\
\mathbf{if}\;\cos \phi_1 \leq 0.893:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_0}{\cos \phi_1 + \cos \lambda_1}\\
\mathbf{else}:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{t_0}{1 + \cos \left(\lambda_2 - \lambda_1\right)}\\
\end{array}
\]
| Alternative 11 |
|---|
| Accuracy | 66.6% |
|---|
| Cost | 26377 |
|---|
\[\begin{array}{l}
t_0 := \cos \left(\lambda_2 - \lambda_1\right)\\
\mathbf{if}\;\lambda_2 \leq -1.22 \cdot 10^{-263} \lor \neg \left(\lambda_2 \leq 9.5 \cdot 10^{-121}\right):\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{\sin \left(\lambda_1 - \lambda_2\right)}{1 + t_0}\\
\mathbf{else}:\\
\;\;\;\;\lambda_1 + \tan^{-1}_* \frac{\sin \lambda_1}{\cos \phi_1 + t_0}\\
\end{array}
\]
| Alternative 12 |
|---|
| Accuracy | 76.6% |
|---|
| Cost | 26240 |
|---|
\[\lambda_1 + \tan^{-1}_* \frac{\sin \left(\lambda_1 - \lambda_2\right)}{\cos \phi_1 + \cos \left(\lambda_2 - \lambda_1\right)}
\]
| Alternative 13 |
|---|
| Accuracy | 76.3% |
|---|
| Cost | 26112 |
|---|
\[\lambda_1 + \tan^{-1}_* \frac{\sin \left(\lambda_1 - \lambda_2\right)}{\cos \phi_1 + \cos \lambda_2}
\]
| Alternative 14 |
|---|
| Accuracy | 66.1% |
|---|
| Cost | 19840 |
|---|
\[\lambda_1 + \tan^{-1}_* \frac{\sin \left(\lambda_1 - \lambda_2\right)}{1 + \cos \left(\lambda_2 - \lambda_1\right)}
\]
| Alternative 15 |
|---|
| Accuracy | 54.7% |
|---|
| Cost | 19712 |
|---|
\[\lambda_1 + \tan^{-1}_* \frac{\sin \lambda_1}{1 + \cos \left(\lambda_2 - \lambda_1\right)}
\]
| Alternative 16 |
|---|
| Accuracy | 61.3% |
|---|
| Cost | 19712 |
|---|
\[\lambda_1 + \tan^{-1}_* \frac{\sin \left(\lambda_1 - \lambda_2\right)}{1 + \cos \lambda_1}
\]
| Alternative 17 |
|---|
| Accuracy | 65.9% |
|---|
| Cost | 19712 |
|---|
\[\lambda_1 + \tan^{-1}_* \frac{\sin \left(\lambda_1 - \lambda_2\right)}{\cos \lambda_2 + 1}
\]