?

Average Accuracy: 100.0% → 100.0%
Time: 2.5s
Precision: binary64
Cost: 6720

?

\[x \cdot y + z \cdot t \]
\[\mathsf{fma}\left(x, y, z \cdot t\right) \]
(FPCore (x y z t) :precision binary64 (+ (* x y) (* z t)))
(FPCore (x y z t) :precision binary64 (fma x y (* z t)))
double code(double x, double y, double z, double t) {
	return (x * y) + (z * t);
}
double code(double x, double y, double z, double t) {
	return fma(x, y, (z * t));
}
function code(x, y, z, t)
	return Float64(Float64(x * y) + Float64(z * t))
end
function code(x, y, z, t)
	return fma(x, y, Float64(z * t))
end
code[x_, y_, z_, t_] := N[(N[(x * y), $MachinePrecision] + N[(z * t), $MachinePrecision]), $MachinePrecision]
code[x_, y_, z_, t_] := N[(x * y + N[(z * t), $MachinePrecision]), $MachinePrecision]
x \cdot y + z \cdot t
\mathsf{fma}\left(x, y, z \cdot t\right)

Error?

Derivation?

  1. Initial program 100.0%

    \[x \cdot y + z \cdot t \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, z \cdot t\right)} \]
    Proof

    [Start]100.0

    \[ x \cdot y + z \cdot t \]

    fma-def [=>]100.0

    \[ \color{blue}{\mathsf{fma}\left(x, y, z \cdot t\right)} \]
  3. Final simplification100.0%

    \[\leadsto \mathsf{fma}\left(x, y, z \cdot t\right) \]

Alternatives

Alternative 1
Accuracy63.1%
Cost722
\[\begin{array}{l} \mathbf{if}\;t \leq -4.1 \cdot 10^{-189} \lor \neg \left(t \leq 1.5 \cdot 10^{+30}\right) \land \left(t \leq 2 \cdot 10^{+68} \lor \neg \left(t \leq 3.4 \cdot 10^{+95}\right)\right):\\ \;\;\;\;z \cdot t\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \]
Alternative 2
Accuracy100.0%
Cost448
\[z \cdot t + x \cdot y \]
Alternative 3
Accuracy51.1%
Cost192
\[z \cdot t \]

Error

Reproduce?

herbie shell --seed 2023151 
(FPCore (x y z t)
  :name "Linear.V2:$cdot from linear-1.19.1.3, A"
  :precision binary64
  (+ (* x y) (* z t)))