Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{x + \frac{y \cdot z - x}{t \cdot z - x}}{x + 1}
\]
↓
\[\begin{array}{l}
t_1 := \frac{x + \frac{y \cdot z - x}{z \cdot t - x}}{x + 1}\\
\mathbf{if}\;t_1 \leq -1.5 \cdot 10^{+28} \lor \neg \left(t_1 \leq 5 \cdot 10^{+31}\right):\\
\;\;\;\;\frac{x + \frac{y}{t - \frac{x}{z}}}{x + 1}\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
(FPCore (x y z t)
:precision binary64
(/ (+ x (/ (- (* y z) x) (- (* t z) x))) (+ x 1.0))) ↓
(FPCore (x y z t)
:precision binary64
(let* ((t_1 (/ (+ x (/ (- (* y z) x) (- (* z t) x))) (+ x 1.0))))
(if (or (<= t_1 -1.5e+28) (not (<= t_1 5e+31)))
(/ (+ x (/ y (- t (/ x z)))) (+ x 1.0))
t_1))) double code(double x, double y, double z, double t) {
return (x + (((y * z) - x) / ((t * z) - x))) / (x + 1.0);
}
↓
double code(double x, double y, double z, double t) {
double t_1 = (x + (((y * z) - x) / ((z * t) - x))) / (x + 1.0);
double tmp;
if ((t_1 <= -1.5e+28) || !(t_1 <= 5e+31)) {
tmp = (x + (y / (t - (x / z)))) / (x + 1.0);
} else {
tmp = t_1;
}
return tmp;
}
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
code = (x + (((y * z) - x) / ((t * z) - x))) / (x + 1.0d0)
end function
↓
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
real(8) :: t_1
real(8) :: tmp
t_1 = (x + (((y * z) - x) / ((z * t) - x))) / (x + 1.0d0)
if ((t_1 <= (-1.5d+28)) .or. (.not. (t_1 <= 5d+31))) then
tmp = (x + (y / (t - (x / z)))) / (x + 1.0d0)
else
tmp = t_1
end if
code = tmp
end function
public static double code(double x, double y, double z, double t) {
return (x + (((y * z) - x) / ((t * z) - x))) / (x + 1.0);
}
↓
public static double code(double x, double y, double z, double t) {
double t_1 = (x + (((y * z) - x) / ((z * t) - x))) / (x + 1.0);
double tmp;
if ((t_1 <= -1.5e+28) || !(t_1 <= 5e+31)) {
tmp = (x + (y / (t - (x / z)))) / (x + 1.0);
} else {
tmp = t_1;
}
return tmp;
}
def code(x, y, z, t):
return (x + (((y * z) - x) / ((t * z) - x))) / (x + 1.0)
↓
def code(x, y, z, t):
t_1 = (x + (((y * z) - x) / ((z * t) - x))) / (x + 1.0)
tmp = 0
if (t_1 <= -1.5e+28) or not (t_1 <= 5e+31):
tmp = (x + (y / (t - (x / z)))) / (x + 1.0)
else:
tmp = t_1
return tmp
function code(x, y, z, t)
return Float64(Float64(x + Float64(Float64(Float64(y * z) - x) / Float64(Float64(t * z) - x))) / Float64(x + 1.0))
end
↓
function code(x, y, z, t)
t_1 = Float64(Float64(x + Float64(Float64(Float64(y * z) - x) / Float64(Float64(z * t) - x))) / Float64(x + 1.0))
tmp = 0.0
if ((t_1 <= -1.5e+28) || !(t_1 <= 5e+31))
tmp = Float64(Float64(x + Float64(y / Float64(t - Float64(x / z)))) / Float64(x + 1.0));
else
tmp = t_1;
end
return tmp
end
function tmp = code(x, y, z, t)
tmp = (x + (((y * z) - x) / ((t * z) - x))) / (x + 1.0);
end
↓
function tmp_2 = code(x, y, z, t)
t_1 = (x + (((y * z) - x) / ((z * t) - x))) / (x + 1.0);
tmp = 0.0;
if ((t_1 <= -1.5e+28) || ~((t_1 <= 5e+31)))
tmp = (x + (y / (t - (x / z)))) / (x + 1.0);
else
tmp = t_1;
end
tmp_2 = tmp;
end
code[x_, y_, z_, t_] := N[(N[(x + N[(N[(N[(y * z), $MachinePrecision] - x), $MachinePrecision] / N[(N[(t * z), $MachinePrecision] - x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(x + 1.0), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(x + N[(N[(N[(y * z), $MachinePrecision] - x), $MachinePrecision] / N[(N[(z * t), $MachinePrecision] - x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(x + 1.0), $MachinePrecision]), $MachinePrecision]}, If[Or[LessEqual[t$95$1, -1.5e+28], N[Not[LessEqual[t$95$1, 5e+31]], $MachinePrecision]], N[(N[(x + N[(y / N[(t - N[(x / z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(x + 1.0), $MachinePrecision]), $MachinePrecision], t$95$1]]
\frac{x + \frac{y \cdot z - x}{t \cdot z - x}}{x + 1}
↓
\begin{array}{l}
t_1 := \frac{x + \frac{y \cdot z - x}{z \cdot t - x}}{x + 1}\\
\mathbf{if}\;t_1 \leq -1.5 \cdot 10^{+28} \lor \neg \left(t_1 \leq 5 \cdot 10^{+31}\right):\\
\;\;\;\;\frac{x + \frac{y}{t - \frac{x}{z}}}{x + 1}\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
Alternatives Alternative 1 Accuracy 98.6% Cost 2628
\[\begin{array}{l}
t_1 := z \cdot t - x\\
\mathbf{if}\;\frac{x + \frac{y \cdot z - x}{t_1}}{x + 1} \leq 2 \cdot 10^{+33}:\\
\;\;\;\;\frac{y \cdot \frac{z}{t_1} + \left(x - \frac{x}{t_1}\right)}{x + 1}\\
\mathbf{else}:\\
\;\;\;\;\frac{x + \frac{y}{t - \frac{x}{z}}}{x + 1}\\
\end{array}
\]
Alternative 2 Accuracy 75.1% Cost 1368
\[\begin{array}{l}
t_1 := 1 - \frac{z}{x} \cdot \frac{y}{x}\\
t_2 := \frac{x + \frac{y}{t}}{x + 1}\\
t_3 := \frac{y}{\frac{x}{z}}\\
\mathbf{if}\;t \leq -3.6 \cdot 10^{-62}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;t \leq -5.4 \cdot 10^{-300}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq 1.5 \cdot 10^{-289}:\\
\;\;\;\;\frac{1 - t_3}{x + 1}\\
\mathbf{elif}\;t \leq 2.4 \cdot 10^{-144}:\\
\;\;\;\;1 - \frac{t_3}{x}\\
\mathbf{elif}\;t \leq 3.6 \cdot 10^{-98}:\\
\;\;\;\;\frac{y}{\left(x + 1\right) \cdot \left(t - \frac{x}{z}\right)}\\
\mathbf{elif}\;t \leq 6.8 \cdot 10^{-40}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;t_2\\
\end{array}
\]
Alternative 3 Accuracy 75.1% Cost 1368
\[\begin{array}{l}
t_1 := 1 - \frac{z}{x} \cdot \frac{y}{x}\\
t_2 := \frac{y}{\frac{x}{z}}\\
\mathbf{if}\;t \leq -8.6 \cdot 10^{-67}:\\
\;\;\;\;\frac{x}{x + 1} + \frac{\frac{y}{t}}{x + 1}\\
\mathbf{elif}\;t \leq -7.5 \cdot 10^{-301}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq 7.8 \cdot 10^{-290}:\\
\;\;\;\;\frac{1 - t_2}{x + 1}\\
\mathbf{elif}\;t \leq 2.9 \cdot 10^{-144}:\\
\;\;\;\;1 - \frac{t_2}{x}\\
\mathbf{elif}\;t \leq 3.6 \cdot 10^{-98}:\\
\;\;\;\;\frac{y}{\left(x + 1\right) \cdot \left(t - \frac{x}{z}\right)}\\
\mathbf{elif}\;t \leq 1.5 \cdot 10^{-40}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\end{array}
\]
Alternative 4 Accuracy 75.7% Cost 1104
\[\begin{array}{l}
t_1 := 1 - \frac{z}{x} \cdot \frac{y}{x}\\
t_2 := \frac{x + \frac{y}{t}}{x + 1}\\
\mathbf{if}\;t \leq -5 \cdot 10^{-65}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;t \leq 2.9 \cdot 10^{-144}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq 3.6 \cdot 10^{-98}:\\
\;\;\;\;\frac{y}{\left(x + 1\right) \cdot \left(t - \frac{x}{z}\right)}\\
\mathbf{elif}\;t \leq 8.6 \cdot 10^{-40}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;t_2\\
\end{array}
\]
Alternative 5 Accuracy 89.6% Cost 1097
\[\begin{array}{l}
\mathbf{if}\;z \leq -8.2 \cdot 10^{-125} \lor \neg \left(z \leq 1.35 \cdot 10^{-118}\right):\\
\;\;\;\;\frac{x + \frac{y}{t - \frac{x}{z}}}{x + 1}\\
\mathbf{else}:\\
\;\;\;\;\frac{\left(x - \frac{y \cdot z}{x}\right) + 1}{x + 1}\\
\end{array}
\]
Alternative 6 Accuracy 90.3% Cost 1097
\[\begin{array}{l}
\mathbf{if}\;y \leq -5.8 \cdot 10^{-41} \lor \neg \left(y \leq 3.3 \cdot 10^{-187}\right):\\
\;\;\;\;\frac{x + \frac{y}{t - \frac{x}{z}}}{x + 1}\\
\mathbf{else}:\\
\;\;\;\;\frac{x - \frac{x}{z \cdot t - x}}{x + 1}\\
\end{array}
\]
Alternative 7 Accuracy 82.6% Cost 1096
\[\begin{array}{l}
\mathbf{if}\;t \leq -5 \cdot 10^{-43}:\\
\;\;\;\;\frac{x}{x + 1} + \frac{\frac{y}{t}}{x + 1}\\
\mathbf{elif}\;t \leq 6.8 \cdot 10^{-40}:\\
\;\;\;\;\frac{\left(x - \frac{y}{\frac{x}{z}}\right) + 1}{x + 1}\\
\mathbf{else}:\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\end{array}
\]
Alternative 8 Accuracy 60.4% Cost 841
\[\begin{array}{l}
\mathbf{if}\;x \leq -4 \cdot 10^{-50} \lor \neg \left(x \leq 1.5 \cdot 10^{-103}\right):\\
\;\;\;\;1 - \frac{\frac{y}{\frac{x}{z}}}{x}\\
\mathbf{else}:\\
\;\;\;\;x - \frac{x}{z \cdot t}\\
\end{array}
\]
Alternative 9 Accuracy 76.6% Cost 841
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.7 \cdot 10^{+38} \lor \neg \left(x \leq 1.75 \cdot 10^{+59}\right):\\
\;\;\;\;1 - \frac{\frac{y}{\frac{x}{z}}}{x}\\
\mathbf{else}:\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\end{array}
\]
Alternative 10 Accuracy 76.8% Cost 841
\[\begin{array}{l}
\mathbf{if}\;x \leq -2.1 \cdot 10^{+38} \lor \neg \left(x \leq 5 \cdot 10^{+65}\right):\\
\;\;\;\;1 - \frac{z}{x} \cdot \frac{y}{x}\\
\mathbf{else}:\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\end{array}
\]
Alternative 11 Accuracy 63.1% Cost 585
\[\begin{array}{l}
\mathbf{if}\;z \leq -4.6 \cdot 10^{-121} \lor \neg \left(z \leq 7 \cdot 10^{-76}\right):\\
\;\;\;\;\frac{x}{x + 1}\\
\mathbf{else}:\\
\;\;\;\;1\\
\end{array}
\]
Alternative 12 Accuracy 57.7% Cost 328
\[\begin{array}{l}
\mathbf{if}\;x \leq -2.15 \cdot 10^{-219}:\\
\;\;\;\;1\\
\mathbf{elif}\;x \leq 5.3 \cdot 10^{-101}:\\
\;\;\;\;x\\
\mathbf{else}:\\
\;\;\;\;1\\
\end{array}
\]
Alternative 13 Accuracy 56.1% Cost 64
\[1
\]