Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{x \cdot 2}{y \cdot z - t \cdot z}
\]
↓
\[\begin{array}{l}
t_1 := y \cdot z - z \cdot t\\
\mathbf{if}\;t_1 \leq -5 \cdot 10^{+279}:\\
\;\;\;\;\frac{2}{\frac{z}{x} \cdot \left(y - t\right)}\\
\mathbf{elif}\;t_1 \leq -5 \cdot 10^{-250} \lor \neg \left(t_1 \leq 0\right) \land t_1 \leq 10^{+108}:\\
\;\;\;\;\frac{2 \cdot x}{z \cdot \left(y - t\right)}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\end{array}
\]
(FPCore (x y z t) :precision binary64 (/ (* x 2.0) (- (* y z) (* t z)))) ↓
(FPCore (x y z t)
:precision binary64
(let* ((t_1 (- (* y z) (* z t))))
(if (<= t_1 -5e+279)
(/ 2.0 (* (/ z x) (- y t)))
(if (or (<= t_1 -5e-250) (and (not (<= t_1 0.0)) (<= t_1 1e+108)))
(/ (* 2.0 x) (* z (- y t)))
(* 2.0 (/ (/ x z) (- y t))))))) double code(double x, double y, double z, double t) {
return (x * 2.0) / ((y * z) - (t * z));
}
↓
double code(double x, double y, double z, double t) {
double t_1 = (y * z) - (z * t);
double tmp;
if (t_1 <= -5e+279) {
tmp = 2.0 / ((z / x) * (y - t));
} else if ((t_1 <= -5e-250) || (!(t_1 <= 0.0) && (t_1 <= 1e+108))) {
tmp = (2.0 * x) / (z * (y - t));
} else {
tmp = 2.0 * ((x / z) / (y - t));
}
return tmp;
}
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
code = (x * 2.0d0) / ((y * z) - (t * z))
end function
↓
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
real(8) :: t_1
real(8) :: tmp
t_1 = (y * z) - (z * t)
if (t_1 <= (-5d+279)) then
tmp = 2.0d0 / ((z / x) * (y - t))
else if ((t_1 <= (-5d-250)) .or. (.not. (t_1 <= 0.0d0)) .and. (t_1 <= 1d+108)) then
tmp = (2.0d0 * x) / (z * (y - t))
else
tmp = 2.0d0 * ((x / z) / (y - t))
end if
code = tmp
end function
public static double code(double x, double y, double z, double t) {
return (x * 2.0) / ((y * z) - (t * z));
}
↓
public static double code(double x, double y, double z, double t) {
double t_1 = (y * z) - (z * t);
double tmp;
if (t_1 <= -5e+279) {
tmp = 2.0 / ((z / x) * (y - t));
} else if ((t_1 <= -5e-250) || (!(t_1 <= 0.0) && (t_1 <= 1e+108))) {
tmp = (2.0 * x) / (z * (y - t));
} else {
tmp = 2.0 * ((x / z) / (y - t));
}
return tmp;
}
def code(x, y, z, t):
return (x * 2.0) / ((y * z) - (t * z))
↓
def code(x, y, z, t):
t_1 = (y * z) - (z * t)
tmp = 0
if t_1 <= -5e+279:
tmp = 2.0 / ((z / x) * (y - t))
elif (t_1 <= -5e-250) or (not (t_1 <= 0.0) and (t_1 <= 1e+108)):
tmp = (2.0 * x) / (z * (y - t))
else:
tmp = 2.0 * ((x / z) / (y - t))
return tmp
function code(x, y, z, t)
return Float64(Float64(x * 2.0) / Float64(Float64(y * z) - Float64(t * z)))
end
↓
function code(x, y, z, t)
t_1 = Float64(Float64(y * z) - Float64(z * t))
tmp = 0.0
if (t_1 <= -5e+279)
tmp = Float64(2.0 / Float64(Float64(z / x) * Float64(y - t)));
elseif ((t_1 <= -5e-250) || (!(t_1 <= 0.0) && (t_1 <= 1e+108)))
tmp = Float64(Float64(2.0 * x) / Float64(z * Float64(y - t)));
else
tmp = Float64(2.0 * Float64(Float64(x / z) / Float64(y - t)));
end
return tmp
end
function tmp = code(x, y, z, t)
tmp = (x * 2.0) / ((y * z) - (t * z));
end
↓
function tmp_2 = code(x, y, z, t)
t_1 = (y * z) - (z * t);
tmp = 0.0;
if (t_1 <= -5e+279)
tmp = 2.0 / ((z / x) * (y - t));
elseif ((t_1 <= -5e-250) || (~((t_1 <= 0.0)) && (t_1 <= 1e+108)))
tmp = (2.0 * x) / (z * (y - t));
else
tmp = 2.0 * ((x / z) / (y - t));
end
tmp_2 = tmp;
end
code[x_, y_, z_, t_] := N[(N[(x * 2.0), $MachinePrecision] / N[(N[(y * z), $MachinePrecision] - N[(t * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(y * z), $MachinePrecision] - N[(z * t), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -5e+279], N[(2.0 / N[(N[(z / x), $MachinePrecision] * N[(y - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[Or[LessEqual[t$95$1, -5e-250], And[N[Not[LessEqual[t$95$1, 0.0]], $MachinePrecision], LessEqual[t$95$1, 1e+108]]], N[(N[(2.0 * x), $MachinePrecision] / N[(z * N[(y - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(2.0 * N[(N[(x / z), $MachinePrecision] / N[(y - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\frac{x \cdot 2}{y \cdot z - t \cdot z}
↓
\begin{array}{l}
t_1 := y \cdot z - z \cdot t\\
\mathbf{if}\;t_1 \leq -5 \cdot 10^{+279}:\\
\;\;\;\;\frac{2}{\frac{z}{x} \cdot \left(y - t\right)}\\
\mathbf{elif}\;t_1 \leq -5 \cdot 10^{-250} \lor \neg \left(t_1 \leq 0\right) \land t_1 \leq 10^{+108}:\\
\;\;\;\;\frac{2 \cdot x}{z \cdot \left(y - t\right)}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\end{array}
Alternatives Alternative 1 Accuracy 71.6% Cost 976
\[\begin{array}{l}
t_1 := \frac{x}{z} \cdot \frac{2}{y}\\
\mathbf{if}\;y \leq -1.15 \cdot 10^{-116}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 4.3 \cdot 10^{-202}:\\
\;\;\;\;\frac{-2}{\frac{z \cdot t}{x}}\\
\mathbf{elif}\;y \leq 4.8 \cdot 10^{+46}:\\
\;\;\;\;\frac{x}{t} \cdot \frac{-2}{z}\\
\mathbf{elif}\;y \leq 2.2 \cdot 10^{+65}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{\frac{2}{z}}{y}\\
\end{array}
\]
Alternative 2 Accuracy 71.5% Cost 976
\[\begin{array}{l}
t_1 := \frac{2}{y \cdot \frac{z}{x}}\\
\mathbf{if}\;y \leq -1.1 \cdot 10^{-116}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 3.9 \cdot 10^{-202}:\\
\;\;\;\;\frac{-2}{\frac{z \cdot t}{x}}\\
\mathbf{elif}\;y \leq 9.2 \cdot 10^{+49}:\\
\;\;\;\;\frac{x}{t} \cdot \frac{-2}{z}\\
\mathbf{elif}\;y \leq 7 \cdot 10^{+65}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{\frac{2}{z}}{y}\\
\end{array}
\]
Alternative 3 Accuracy 71.7% Cost 976
\[\begin{array}{l}
t_1 := \frac{2}{y \cdot \frac{z}{x}}\\
\mathbf{if}\;y \leq -8.6 \cdot 10^{-117}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 4.6 \cdot 10^{-202}:\\
\;\;\;\;\frac{x \cdot -2}{z \cdot t}\\
\mathbf{elif}\;y \leq 4.8 \cdot 10^{+46}:\\
\;\;\;\;\frac{x}{t} \cdot \frac{-2}{z}\\
\mathbf{elif}\;y \leq 10^{+67}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{\frac{2}{z}}{y}\\
\end{array}
\]
Alternative 4 Accuracy 95.4% Cost 841
\[\begin{array}{l}
\mathbf{if}\;z \leq -3 \cdot 10^{+99} \lor \neg \left(z \leq 2 \cdot 10^{-146}\right):\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{2}{z \cdot \left(y - t\right)}\\
\end{array}
\]
Alternative 5 Accuracy 72.1% Cost 713
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.15 \cdot 10^{-116} \lor \neg \left(y \leq 9.6 \cdot 10^{-30}\right):\\
\;\;\;\;x \cdot \frac{\frac{2}{z}}{y}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{t} \cdot \frac{-2}{z}\\
\end{array}
\]
Alternative 6 Accuracy 71.8% Cost 713
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.15 \cdot 10^{-116} \lor \neg \left(y \leq 9.5 \cdot 10^{-30}\right):\\
\;\;\;\;x \cdot \frac{\frac{2}{z}}{y}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{z} \cdot \frac{-2}{t}\\
\end{array}
\]
Alternative 7 Accuracy 72.0% Cost 712
\[\begin{array}{l}
\mathbf{if}\;y \leq -3.1 \cdot 10^{-115}:\\
\;\;\;\;\frac{x}{z} \cdot \frac{2}{y}\\
\mathbf{elif}\;y \leq 6.3 \cdot 10^{-30}:\\
\;\;\;\;\frac{x}{z} \cdot \frac{-2}{t}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{\frac{2}{z}}{y}\\
\end{array}
\]
Alternative 8 Accuracy 90.7% Cost 576
\[2 \cdot \frac{\frac{x}{z}}{y - t}
\]
Alternative 9 Accuracy 51.3% Cost 448
\[x \cdot \frac{\frac{2}{y}}{z}
\]
Alternative 10 Accuracy 51.3% Cost 448
\[x \cdot \frac{\frac{2}{z}}{y}
\]