expq2 (section 3.11)

Average Accuracy: 34.9% → 99.3%

Time: 3.4s

Precision: binary64

Cost: 12992

Math

\[\frac{e^{x}}{e^{x} - 1} \]

↓

\[\frac{e^{x}}{\mathsf{expm1}\left(x\right)} \]

FPCore

(FPCore (x) :precision binary64 (/ (exp x) (- (exp x) 1.0)))

↓

(FPCore (x) :precision binary64 (/ (exp x) (expm1 x)))

C

double code(double x) {
	return exp(x) / (exp(x) - 1.0);
}

↓

double code(double x) {
	return exp(x) / expm1(x);
}

Java

public static double code(double x) {
	return Math.exp(x) / (Math.exp(x) - 1.0);
}

↓

public static double code(double x) {
	return Math.exp(x) / Math.expm1(x);
}

Python

def code(x):
	return math.exp(x) / (math.exp(x) - 1.0)

↓

def code(x):
	return math.exp(x) / math.expm1(x)

Julia

function code(x)
	return Float64(exp(x) / Float64(exp(x) - 1.0))
end

↓

function code(x)
	return Float64(exp(x) / expm1(x))
end

Wolfram

code[x_] := N[(N[Exp[x], $MachinePrecision] / N[(N[Exp[x], $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision]

↓

code[x_] := N[(N[Exp[x], $MachinePrecision] / N[(Exp[x] - 1), $MachinePrecision]), $MachinePrecision]

Target

Original	34.9%
Target	35.6%
Herbie	99.3%

\[\frac{1}{1 - e^{-x}} \]

Derivation

1. Initial program 34.9%

   \[\frac{e^{x}}{e^{x} - 1} \]

2. Simplified 99.3%

   \[\leadsto \color{blue}{\frac{e^{x}}{\mathsf{expm1}\left(x\right)}} \]
   Proof

   [Start] 34.9	\[ \frac{e^{x}}{e^{x} - 1} \]
   expm1-def [=>] 99.3	\[ \frac{e^{x}}{\color{blue}{\mathsf{expm1}\left(x\right)}} \]

3. Final simplification 99.3%

   \[\leadsto \frac{e^{x}}{\mathsf{expm1}\left(x\right)} \]

Alternatives

Alternative 1
Accuracy	98.8%
Cost	13828

\[\begin{array}{l} \mathbf{if}\;e^{x} \leq 0:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;0.5 + \left(-0.001388888888888889 \cdot {x}^{3} + \left(x \cdot 0.08333333333333333 + \frac{1}{x}\right)\right)\\ \end{array} \]

Alternative 2
Accuracy	98.8%
Cost	12996

\[\begin{array}{l} \mathbf{if}\;e^{x} \leq 0:\\ \;\;\;\;e^{x}\\ \mathbf{else}:\\ \;\;\;\;0.5 + \left(x \cdot 0.08333333333333333 + \frac{1}{x}\right)\\ \end{array} \]

Alternative 3
Accuracy	67.2%
Cost	576

\[0.5 + \left(x \cdot 0.08333333333333333 + \frac{1}{x}\right) \]

Alternative 4
Accuracy	67.2%
Cost	320

\[0.5 + \frac{1}{x} \]

Alternative 5
Accuracy	67.1%
Cost	192

\[\frac{1}{x} \]

Reproduce

herbie shell --seed 2023147 
(FPCore (x)
  :name "expq2 (section 3.11)"
  :precision binary64

  :herbie-target
  (/ 1.0 (- 1.0 (exp (- x))))

  (/ (exp x) (- (exp x) 1.0)))