\[\left(\left(1.1102230246251565 \cdot 10^{-16} < a \land a < 9007199254740992\right) \land \left(1.1102230246251565 \cdot 10^{-16} < b \land b < 9007199254740992\right)\right) \land \left(1.1102230246251565 \cdot 10^{-16} < c \land c < 9007199254740992\right)\]
Math FPCore C Julia Wolfram TeX \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
\]
↓
\[\mathsf{fma}\left(-0.5, \frac{c}{b}, \mathsf{fma}\left(\frac{-0.16666666666666666}{a}, \frac{{\left(c \cdot a\right)}^{4} \cdot 6.328125}{{b}^{7}}, \mathsf{fma}\left(-0.375, \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right), -0.5625 \cdot \left(\frac{a}{{b}^{5}} \cdot \left(a \cdot {c}^{3}\right)\right)\right)\right)\right)
\]
(FPCore (a b c)
:precision binary64
(/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a))) ↓
(FPCore (a b c)
:precision binary64
(fma
-0.5
(/ c b)
(fma
(/ -0.16666666666666666 a)
(/ (* (pow (* c a) 4.0) 6.328125) (pow b 7.0))
(fma
-0.375
(* (/ a (pow b 3.0)) (* c c))
(* -0.5625 (* (/ a (pow b 5.0)) (* a (pow c 3.0)))))))) double code(double a, double b, double c) {
return (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
↓
double code(double a, double b, double c) {
return fma(-0.5, (c / b), fma((-0.16666666666666666 / a), ((pow((c * a), 4.0) * 6.328125) / pow(b, 7.0)), fma(-0.375, ((a / pow(b, 3.0)) * (c * c)), (-0.5625 * ((a / pow(b, 5.0)) * (a * pow(c, 3.0)))))));
}
function code(a, b, c)
return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c)))) / Float64(3.0 * a))
end
↓
function code(a, b, c)
return fma(-0.5, Float64(c / b), fma(Float64(-0.16666666666666666 / a), Float64(Float64((Float64(c * a) ^ 4.0) * 6.328125) / (b ^ 7.0)), fma(-0.375, Float64(Float64(a / (b ^ 3.0)) * Float64(c * c)), Float64(-0.5625 * Float64(Float64(a / (b ^ 5.0)) * Float64(a * (c ^ 3.0)))))))
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision]
↓
code[a_, b_, c_] := N[(-0.5 * N[(c / b), $MachinePrecision] + N[(N[(-0.16666666666666666 / a), $MachinePrecision] * N[(N[(N[Power[N[(c * a), $MachinePrecision], 4.0], $MachinePrecision] * 6.328125), $MachinePrecision] / N[Power[b, 7.0], $MachinePrecision]), $MachinePrecision] + N[(-0.375 * N[(N[(a / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision] * N[(c * c), $MachinePrecision]), $MachinePrecision] + N[(-0.5625 * N[(N[(a / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision] * N[(a * N[Power[c, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
↓
\mathsf{fma}\left(-0.5, \frac{c}{b}, \mathsf{fma}\left(\frac{-0.16666666666666666}{a}, \frac{{\left(c \cdot a\right)}^{4} \cdot 6.328125}{{b}^{7}}, \mathsf{fma}\left(-0.375, \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right), -0.5625 \cdot \left(\frac{a}{{b}^{5}} \cdot \left(a \cdot {c}^{3}\right)\right)\right)\right)\right)
Alternatives Alternative 1 Accuracy 95.7% Cost 47296
\[\mathsf{fma}\left(-0.5625, \left(c \cdot c\right) \cdot \left(c \cdot \frac{a \cdot a}{{b}^{5}}\right), \mathsf{fma}\left(-0.16666666666666666, \frac{{\left(c \cdot a\right)}^{4}}{\frac{a \cdot {b}^{7}}{6.328125}}, \mathsf{fma}\left(-0.5, \frac{c}{b}, -0.375 \cdot \frac{a \cdot \left(c \cdot c\right)}{{b}^{3}}\right)\right)\right)
\]
Alternative 2 Accuracy 94.0% Cost 33536
\[\mathsf{fma}\left(-0.5625, a \cdot \left(a \cdot \frac{{c}^{3}}{{b}^{5}}\right), \mathsf{fma}\left(-0.375, \frac{a \cdot \left(c \cdot c\right)}{{b}^{3}}, \frac{-0.5}{\frac{b}{c}}\right)\right)
\]
Alternative 3 Accuracy 94.3% Cost 33536
\[\mathsf{fma}\left(-0.5625, \frac{{c}^{3}}{\frac{{b}^{5}}{a \cdot a}}, \mathsf{fma}\left(-0.5, \frac{c}{b}, -0.375 \cdot \frac{c \cdot c}{\frac{{b}^{3}}{a}}\right)\right)
\]
Alternative 4 Accuracy 91.1% Cost 13696
\[\mathsf{fma}\left(-0.375, a \cdot \frac{c \cdot c}{{b}^{3}}, -0.5 \cdot \frac{c}{b}\right)
\]
Alternative 5 Accuracy 90.8% Cost 1600
\[\frac{-0.5 \cdot \frac{c \cdot a}{b} + -0.375 \cdot \left(\frac{c \cdot c}{b \cdot b} \cdot \frac{a \cdot a}{b}\right)}{a}
\]
Alternative 6 Accuracy 81.5% Cost 320
\[c \cdot \frac{-0.5}{b}
\]
Alternative 7 Accuracy 81.5% Cost 320
\[\frac{-0.5}{\frac{b}{c}}
\]
Alternative 8 Accuracy 81.7% Cost 320
\[\frac{-0.5 \cdot c}{b}
\]