\[ \begin{array}{c}[x, y, z] = \mathsf{sort}([x, y, z])\\ \end{array} \]
Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z}
\]
↓
\[\begin{array}{l}
t_0 := 2 \cdot {\left(e^{\left(\log \left(\left(-y\right) - z\right) - \log \left(\frac{-1}{x}\right)\right) \cdot 0.16666666666666666}\right)}^{3}\\
\mathbf{if}\;y \leq -1.1 \cdot 10^{+49}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq -2.6 \cdot 10^{-195}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot x + x \cdot z}\\
\mathbf{elif}\;y \leq 5.1 \cdot 10^{-256}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
\]
(FPCore (x y z)
:precision binary64
(* 2.0 (sqrt (+ (+ (* x y) (* x z)) (* y z))))) ↓
(FPCore (x y z)
:precision binary64
(let* ((t_0
(*
2.0
(pow
(exp (* (- (log (- (- y) z)) (log (/ -1.0 x))) 0.16666666666666666))
3.0))))
(if (<= y -1.1e+49)
t_0
(if (<= y -2.6e-195)
(* 2.0 (sqrt (+ (* y x) (* x z))))
(if (<= y 5.1e-256) t_0 (* 2.0 (* (sqrt z) (sqrt y)))))))) double code(double x, double y, double z) {
return 2.0 * sqrt((((x * y) + (x * z)) + (y * z)));
}
↓
double code(double x, double y, double z) {
double t_0 = 2.0 * pow(exp(((log((-y - z)) - log((-1.0 / x))) * 0.16666666666666666)), 3.0);
double tmp;
if (y <= -1.1e+49) {
tmp = t_0;
} else if (y <= -2.6e-195) {
tmp = 2.0 * sqrt(((y * x) + (x * z)));
} else if (y <= 5.1e-256) {
tmp = t_0;
} else {
tmp = 2.0 * (sqrt(z) * sqrt(y));
}
return tmp;
}
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
code = 2.0d0 * sqrt((((x * y) + (x * z)) + (y * z)))
end function
↓
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8) :: t_0
real(8) :: tmp
t_0 = 2.0d0 * (exp(((log((-y - z)) - log(((-1.0d0) / x))) * 0.16666666666666666d0)) ** 3.0d0)
if (y <= (-1.1d+49)) then
tmp = t_0
else if (y <= (-2.6d-195)) then
tmp = 2.0d0 * sqrt(((y * x) + (x * z)))
else if (y <= 5.1d-256) then
tmp = t_0
else
tmp = 2.0d0 * (sqrt(z) * sqrt(y))
end if
code = tmp
end function
public static double code(double x, double y, double z) {
return 2.0 * Math.sqrt((((x * y) + (x * z)) + (y * z)));
}
↓
public static double code(double x, double y, double z) {
double t_0 = 2.0 * Math.pow(Math.exp(((Math.log((-y - z)) - Math.log((-1.0 / x))) * 0.16666666666666666)), 3.0);
double tmp;
if (y <= -1.1e+49) {
tmp = t_0;
} else if (y <= -2.6e-195) {
tmp = 2.0 * Math.sqrt(((y * x) + (x * z)));
} else if (y <= 5.1e-256) {
tmp = t_0;
} else {
tmp = 2.0 * (Math.sqrt(z) * Math.sqrt(y));
}
return tmp;
}
def code(x, y, z):
return 2.0 * math.sqrt((((x * y) + (x * z)) + (y * z)))
↓
def code(x, y, z):
t_0 = 2.0 * math.pow(math.exp(((math.log((-y - z)) - math.log((-1.0 / x))) * 0.16666666666666666)), 3.0)
tmp = 0
if y <= -1.1e+49:
tmp = t_0
elif y <= -2.6e-195:
tmp = 2.0 * math.sqrt(((y * x) + (x * z)))
elif y <= 5.1e-256:
tmp = t_0
else:
tmp = 2.0 * (math.sqrt(z) * math.sqrt(y))
return tmp
function code(x, y, z)
return Float64(2.0 * sqrt(Float64(Float64(Float64(x * y) + Float64(x * z)) + Float64(y * z))))
end
↓
function code(x, y, z)
t_0 = Float64(2.0 * (exp(Float64(Float64(log(Float64(Float64(-y) - z)) - log(Float64(-1.0 / x))) * 0.16666666666666666)) ^ 3.0))
tmp = 0.0
if (y <= -1.1e+49)
tmp = t_0;
elseif (y <= -2.6e-195)
tmp = Float64(2.0 * sqrt(Float64(Float64(y * x) + Float64(x * z))));
elseif (y <= 5.1e-256)
tmp = t_0;
else
tmp = Float64(2.0 * Float64(sqrt(z) * sqrt(y)));
end
return tmp
end
function tmp = code(x, y, z)
tmp = 2.0 * sqrt((((x * y) + (x * z)) + (y * z)));
end
↓
function tmp_2 = code(x, y, z)
t_0 = 2.0 * (exp(((log((-y - z)) - log((-1.0 / x))) * 0.16666666666666666)) ^ 3.0);
tmp = 0.0;
if (y <= -1.1e+49)
tmp = t_0;
elseif (y <= -2.6e-195)
tmp = 2.0 * sqrt(((y * x) + (x * z)));
elseif (y <= 5.1e-256)
tmp = t_0;
else
tmp = 2.0 * (sqrt(z) * sqrt(y));
end
tmp_2 = tmp;
end
code[x_, y_, z_] := N[(2.0 * N[Sqrt[N[(N[(N[(x * y), $MachinePrecision] + N[(x * z), $MachinePrecision]), $MachinePrecision] + N[(y * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_] := Block[{t$95$0 = N[(2.0 * N[Power[N[Exp[N[(N[(N[Log[N[((-y) - z), $MachinePrecision]], $MachinePrecision] - N[Log[N[(-1.0 / x), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * 0.16666666666666666), $MachinePrecision]], $MachinePrecision], 3.0], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[y, -1.1e+49], t$95$0, If[LessEqual[y, -2.6e-195], N[(2.0 * N[Sqrt[N[(N[(y * x), $MachinePrecision] + N[(x * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], If[LessEqual[y, 5.1e-256], t$95$0, N[(2.0 * N[(N[Sqrt[z], $MachinePrecision] * N[Sqrt[y], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]]
2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z}
↓
\begin{array}{l}
t_0 := 2 \cdot {\left(e^{\left(\log \left(\left(-y\right) - z\right) - \log \left(\frac{-1}{x}\right)\right) \cdot 0.16666666666666666}\right)}^{3}\\
\mathbf{if}\;y \leq -1.1 \cdot 10^{+49}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq -2.6 \cdot 10^{-195}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot x + x \cdot z}\\
\mathbf{elif}\;y \leq 5.1 \cdot 10^{-256}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
Alternatives Alternative 1 Accuracy 93.0% Cost 26564
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.1 \cdot 10^{+49}:\\
\;\;\;\;2 \cdot {\left(e^{0.25}\right)}^{\left(2 \cdot \left(\log \left(\left(-z\right) - x\right) - \log \left(\frac{-1}{y}\right)\right)\right)}\\
\mathbf{elif}\;y \leq 4.2 \cdot 10^{-233}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right) + y \cdot x}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
\]
Alternative 2 Accuracy 92.5% Cost 26564
\[\begin{array}{l}
\mathbf{if}\;y \leq 1.6 \cdot 10^{-250}:\\
\;\;\;\;2 \cdot {\left(e^{0.25 \cdot \left(\log \left(\left(-y\right) - z\right) - \log \left(\frac{-1}{x}\right)\right)}\right)}^{2}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
\]
Alternative 3 Accuracy 82.7% Cost 13892
\[\begin{array}{l}
\mathbf{if}\;\left(y \cdot x + x \cdot z\right) + y \cdot z \leq 5 \cdot 10^{+307}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right) + y \cdot x}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
\]
Alternative 4 Accuracy 69.1% Cost 7108
\[\begin{array}{l}
\mathbf{if}\;y \leq -1 \cdot 10^{-285}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot x + x \cdot z}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right)}\\
\end{array}
\]
Alternative 5 Accuracy 69.3% Cost 7104
\[2 \cdot \sqrt{y \cdot z + x \cdot \left(y + z\right)}
\]
Alternative 6 Accuracy 69.3% Cost 7104
\[2 \cdot \sqrt{z \cdot \left(y + x\right) + y \cdot x}
\]
Alternative 7 Accuracy 67.9% Cost 6980
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.2 \cdot 10^{-285}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot x}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right)}\\
\end{array}
\]
Alternative 8 Accuracy 69.3% Cost 6980
\[\begin{array}{l}
\mathbf{if}\;y \leq -2 \cdot 10^{-307}:\\
\;\;\;\;2 \cdot \sqrt{x \cdot \left(y + z\right)}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right)}\\
\end{array}
\]
Alternative 9 Accuracy 66.8% Cost 6852
\[\begin{array}{l}
\mathbf{if}\;y \leq -5 \cdot 10^{-310}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot x}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot z}\\
\end{array}
\]
Alternative 10 Accuracy 35.3% Cost 6720
\[2 \cdot \sqrt{y \cdot x}
\]