?

Average Accuracy: 99.7% → 100.0%
Time: 11.6s
Precision: binary64
Cost: 33152

?

\[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 - a\right) + \left(b \cdot b\right) \cdot \left(3 + a\right)\right)\right) - 1 \]
\[{\left(\mathsf{hypot}\left(a, b\right)\right)}^{4} + \mathsf{fma}\left(4, \mathsf{fma}\left(b \cdot b, a + 3, a \cdot a\right) - {a}^{3}, -1\right) \]
(FPCore (a b)
 :precision binary64
 (-
  (+
   (pow (+ (* a a) (* b b)) 2.0)
   (* 4.0 (+ (* (* a a) (- 1.0 a)) (* (* b b) (+ 3.0 a)))))
  1.0))
(FPCore (a b)
 :precision binary64
 (+
  (pow (hypot a b) 4.0)
  (fma 4.0 (- (fma (* b b) (+ a 3.0) (* a a)) (pow a 3.0)) -1.0)))
double code(double a, double b) {
	return (pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 - a)) + ((b * b) * (3.0 + a))))) - 1.0;
}
double code(double a, double b) {
	return pow(hypot(a, b), 4.0) + fma(4.0, (fma((b * b), (a + 3.0), (a * a)) - pow(a, 3.0)), -1.0);
}
function code(a, b)
	return Float64(Float64((Float64(Float64(a * a) + Float64(b * b)) ^ 2.0) + Float64(4.0 * Float64(Float64(Float64(a * a) * Float64(1.0 - a)) + Float64(Float64(b * b) * Float64(3.0 + a))))) - 1.0)
end
function code(a, b)
	return Float64((hypot(a, b) ^ 4.0) + fma(4.0, Float64(fma(Float64(b * b), Float64(a + 3.0), Float64(a * a)) - (a ^ 3.0)), -1.0))
end
code[a_, b_] := N[(N[(N[Power[N[(N[(a * a), $MachinePrecision] + N[(b * b), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[(4.0 * N[(N[(N[(a * a), $MachinePrecision] * N[(1.0 - a), $MachinePrecision]), $MachinePrecision] + N[(N[(b * b), $MachinePrecision] * N[(3.0 + a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision]
code[a_, b_] := N[(N[Power[N[Sqrt[a ^ 2 + b ^ 2], $MachinePrecision], 4.0], $MachinePrecision] + N[(4.0 * N[(N[(N[(b * b), $MachinePrecision] * N[(a + 3.0), $MachinePrecision] + N[(a * a), $MachinePrecision]), $MachinePrecision] - N[Power[a, 3.0], $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision]), $MachinePrecision]
\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 - a\right) + \left(b \cdot b\right) \cdot \left(3 + a\right)\right)\right) - 1
{\left(\mathsf{hypot}\left(a, b\right)\right)}^{4} + \mathsf{fma}\left(4, \mathsf{fma}\left(b \cdot b, a + 3, a \cdot a\right) - {a}^{3}, -1\right)

Error?

Derivation?

  1. Initial program 99.7%

    \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 - a\right) + \left(b \cdot b\right) \cdot \left(3 + a\right)\right)\right) - 1 \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{{\left(\mathsf{hypot}\left(a, b\right)\right)}^{4} + \mathsf{fma}\left(4, \mathsf{fma}\left(b \cdot b, a + 3, a \cdot a\right) - {a}^{3}, -1\right)} \]
    Proof

    [Start]99.7

    \[ \left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 - a\right) + \left(b \cdot b\right) \cdot \left(3 + a\right)\right)\right) - 1 \]

    associate--l+ [=>]99.7

    \[ \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 - a\right) + \left(b \cdot b\right) \cdot \left(3 + a\right)\right) - 1\right)} \]
  3. Final simplification100.0%

    \[\leadsto {\left(\mathsf{hypot}\left(a, b\right)\right)}^{4} + \mathsf{fma}\left(4, \mathsf{fma}\left(b \cdot b, a + 3, a \cdot a\right) - {a}^{3}, -1\right) \]

Alternatives

Alternative 1
Accuracy99.7%
Cost8192
\[\left({\left(b \cdot b + a \cdot a\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 - a\right) + \left(b \cdot b\right) \cdot \left(a + 3\right)\right)\right) + -1 \]
Alternative 2
Accuracy97.9%
Cost7936
\[\left({\left(b \cdot b + a \cdot a\right)}^{2} + 4 \cdot \left(a \cdot a + \left(b \cdot b\right) \cdot \left(a + 3\right)\right)\right) + -1 \]
Alternative 3
Accuracy97.3%
Cost7561
\[\begin{array}{l} \mathbf{if}\;b \leq -0.00013 \lor \neg \left(b \leq 0.102\right):\\ \;\;\;\;\left(\left(b \cdot b\right) \cdot 12 + {b}^{4}\right) + -1\\ \mathbf{else}:\\ \;\;\;\;\left({a}^{4} + 4 \cdot \left(a \cdot \left(a \cdot \left(1 - a\right)\right)\right)\right) + -1\\ \end{array} \]
Alternative 4
Accuracy95.9%
Cost7433
\[\begin{array}{l} \mathbf{if}\;b \leq -2 \cdot 10^{-8} \lor \neg \left(b \leq 0.102\right):\\ \;\;\;\;\left(\left(b \cdot b\right) \cdot 12 + {b}^{4}\right) + -1\\ \mathbf{else}:\\ \;\;\;\;\left({a}^{4} - 4 \cdot \left(a \cdot \left(a \cdot a\right)\right)\right) + -1\\ \end{array} \]
Alternative 5
Accuracy97.6%
Cost7424
\[\left({\left(b \cdot b + a \cdot a\right)}^{2} + \left(b \cdot b\right) \cdot 12\right) + -1 \]
Alternative 6
Accuracy95.9%
Cost7305
\[\begin{array}{l} \mathbf{if}\;b \leq -2.75 \cdot 10^{-6} \lor \neg \left(b \leq 0.102\right):\\ \;\;\;\;\left(\left(b \cdot b\right) \cdot 12 + {b}^{4}\right) + -1\\ \mathbf{else}:\\ \;\;\;\;{a}^{3} \cdot \left(a + -4\right) + -1\\ \end{array} \]
Alternative 7
Accuracy95.8%
Cost7241
\[\begin{array}{l} \mathbf{if}\;b \leq -1.15 \cdot 10^{-7} \lor \neg \left(b \leq 0.102\right):\\ \;\;\;\;b \cdot \left(b \cdot \mathsf{fma}\left(b, b, 12\right)\right) + -1\\ \mathbf{else}:\\ \;\;\;\;{a}^{3} \cdot \left(a + -4\right) + -1\\ \end{array} \]
Alternative 8
Accuracy95.8%
Cost7176
\[\begin{array}{l} \mathbf{if}\;b \leq -2.7 \cdot 10^{-6}:\\ \;\;\;\;\left(\left(b \cdot b\right) \cdot 12 + \left(b \cdot b\right) \cdot \left(b \cdot b\right)\right) + -1\\ \mathbf{elif}\;b \leq 0.102:\\ \;\;\;\;{a}^{3} \cdot \left(a + -4\right) + -1\\ \mathbf{else}:\\ \;\;\;\;\left(b \cdot b\right) \cdot \left(b \cdot b + 12\right) + -1\\ \end{array} \]
Alternative 9
Accuracy95.1%
Cost6920
\[\begin{array}{l} \mathbf{if}\;b \leq -9.8 \cdot 10^{-8}:\\ \;\;\;\;\left(\left(b \cdot b\right) \cdot 12 + \left(b \cdot b\right) \cdot \left(b \cdot b\right)\right) + -1\\ \mathbf{elif}\;b \leq 0.102:\\ \;\;\;\;{a}^{4} + -1\\ \mathbf{else}:\\ \;\;\;\;\left(b \cdot b\right) \cdot \left(b \cdot b + 12\right) + -1\\ \end{array} \]
Alternative 10
Accuracy95.3%
Cost6793
\[\begin{array}{l} \mathbf{if}\;a \leq -10000000000000 \lor \neg \left(a \leq 740\right):\\ \;\;\;\;{a}^{4}\\ \mathbf{else}:\\ \;\;\;\;\left(b \cdot b\right) \cdot \left(b \cdot b + 12\right) + -1\\ \end{array} \]
Alternative 11
Accuracy81.6%
Cost704
\[\left(b \cdot b\right) \cdot \left(b \cdot b + 12\right) + -1 \]
Alternative 12
Accuracy64.8%
Cost448
\[4 \cdot \left(a \cdot a\right) + -1 \]
Alternative 13
Accuracy65.0%
Cost448
\[\left(b \cdot b\right) \cdot 12 + -1 \]

Error

Reproduce?

herbie shell --seed 2023144 
(FPCore (a b)
  :name "Bouland and Aaronson, Equation (24)"
  :precision binary64
  (- (+ (pow (+ (* a a) (* b b)) 2.0) (* 4.0 (+ (* (* a a) (- 1.0 a)) (* (* b b) (+ 3.0 a))))) 1.0))