\[ \begin{array}{c}[x, y] = \mathsf{sort}([x, y])\\ \end{array} \]
Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{\left(x + y\right) - z}{t \cdot 2}
\]
↓
\[0.5 \cdot \frac{y}{t} + 0.5 \cdot \frac{x - z}{t}
\]
(FPCore (x y z t) :precision binary64 (/ (- (+ x y) z) (* t 2.0))) ↓
(FPCore (x y z t)
:precision binary64
(+ (* 0.5 (/ y t)) (* 0.5 (/ (- x z) t)))) double code(double x, double y, double z, double t) {
return ((x + y) - z) / (t * 2.0);
}
↓
double code(double x, double y, double z, double t) {
return (0.5 * (y / t)) + (0.5 * ((x - z) / t));
}
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
code = ((x + y) - z) / (t * 2.0d0)
end function
↓
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
code = (0.5d0 * (y / t)) + (0.5d0 * ((x - z) / t))
end function
public static double code(double x, double y, double z, double t) {
return ((x + y) - z) / (t * 2.0);
}
↓
public static double code(double x, double y, double z, double t) {
return (0.5 * (y / t)) + (0.5 * ((x - z) / t));
}
def code(x, y, z, t):
return ((x + y) - z) / (t * 2.0)
↓
def code(x, y, z, t):
return (0.5 * (y / t)) + (0.5 * ((x - z) / t))
function code(x, y, z, t)
return Float64(Float64(Float64(x + y) - z) / Float64(t * 2.0))
end
↓
function code(x, y, z, t)
return Float64(Float64(0.5 * Float64(y / t)) + Float64(0.5 * Float64(Float64(x - z) / t)))
end
function tmp = code(x, y, z, t)
tmp = ((x + y) - z) / (t * 2.0);
end
↓
function tmp = code(x, y, z, t)
tmp = (0.5 * (y / t)) + (0.5 * ((x - z) / t));
end
code[x_, y_, z_, t_] := N[(N[(N[(x + y), $MachinePrecision] - z), $MachinePrecision] / N[(t * 2.0), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_, t_] := N[(N[(0.5 * N[(y / t), $MachinePrecision]), $MachinePrecision] + N[(0.5 * N[(N[(x - z), $MachinePrecision] / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{\left(x + y\right) - z}{t \cdot 2}
↓
0.5 \cdot \frac{y}{t} + 0.5 \cdot \frac{x - z}{t}
Alternatives Alternative 1 Accuracy 89.1% Cost 972
\[\begin{array}{l}
t_1 := \frac{-0.5 \cdot \left(z - x\right)}{t}\\
\mathbf{if}\;x \leq -1.4 \cdot 10^{+57}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;x \leq -0.052:\\
\;\;\;\;0.5 \cdot \frac{y + x}{t}\\
\mathbf{elif}\;x \leq -2.9 \cdot 10^{-47}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \left(\frac{y}{t} - \frac{z}{t}\right)\\
\end{array}
\]
Alternative 2 Accuracy 89.0% Cost 844
\[\begin{array}{l}
t_1 := \frac{-0.5 \cdot \left(z - x\right)}{t}\\
\mathbf{if}\;x \leq -1.76 \cdot 10^{+59}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;x \leq -0.03:\\
\;\;\;\;0.5 \cdot \frac{y + x}{t}\\
\mathbf{elif}\;x \leq -1.7 \cdot 10^{-45}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \frac{y - z}{t}\\
\end{array}
\]
Alternative 3 Accuracy 80.1% Cost 713
\[\begin{array}{l}
\mathbf{if}\;z \leq -3.9 \cdot 10^{+93} \lor \neg \left(z \leq 5.4 \cdot 10^{+103}\right):\\
\;\;\;\;\frac{z \cdot -0.5}{t}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \frac{y + x}{t}\\
\end{array}
\]
Alternative 4 Accuracy 58.2% Cost 584
\[\begin{array}{l}
\mathbf{if}\;y \leq -9.5 \cdot 10^{-146}:\\
\;\;\;\;\frac{x}{\frac{t}{0.5}}\\
\mathbf{elif}\;y \leq 1.65 \cdot 10^{+77}:\\
\;\;\;\;\frac{z \cdot -0.5}{t}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \frac{y}{t}\\
\end{array}
\]
Alternative 5 Accuracy 85.9% Cost 580
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.3 \cdot 10^{-35}:\\
\;\;\;\;0.5 \cdot \frac{y + x}{t}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \frac{y - z}{t}\\
\end{array}
\]
Alternative 6 Accuracy 99.6% Cost 576
\[\left(z - \left(y + x\right)\right) \cdot \frac{-0.5}{t}
\]
Alternative 7 Accuracy 99.9% Cost 576
\[\frac{\left(y + x\right) - z}{t \cdot 2}
\]
Alternative 8 Accuracy 55.9% Cost 452
\[\begin{array}{l}
\mathbf{if}\;y \leq 2.5 \cdot 10^{+34}:\\
\;\;\;\;x \cdot \frac{0.5}{t}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \frac{y}{t}\\
\end{array}
\]
Alternative 9 Accuracy 56.0% Cost 452
\[\begin{array}{l}
\mathbf{if}\;y \leq 4.8 \cdot 10^{+34}:\\
\;\;\;\;\frac{x}{\frac{t}{0.5}}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \frac{y}{t}\\
\end{array}
\]
Alternative 10 Accuracy 35.9% Cost 320
\[0.5 \cdot \frac{y}{t}
\]