\[ \begin{array}{c}[x, y] = \mathsf{sort}([x, y])\\ \end{array} \]
Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{x \cdot y}{\left(z \cdot z\right) \cdot \left(z + 1\right)}
\]
↓
\[\begin{array}{l}
t_0 := \frac{-\frac{x \cdot y}{z + 1}}{z \cdot \left(-z\right)}\\
t_1 := \frac{-1}{\left(z \cdot \frac{z}{x}\right) \cdot \frac{-1 - z}{y}}\\
\mathbf{if}\;x \cdot y \leq -5 \cdot 10^{+274}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;x \cdot y \leq -5 \cdot 10^{-162}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;x \cdot y \leq 4 \cdot 10^{-141}:\\
\;\;\;\;\frac{\frac{x}{z}}{z \cdot \frac{z + 1}{y}}\\
\mathbf{elif}\;x \cdot y \leq 10^{+176}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
(FPCore (x y z) :precision binary64 (/ (* x y) (* (* z z) (+ z 1.0)))) ↓
(FPCore (x y z)
:precision binary64
(let* ((t_0 (/ (- (/ (* x y) (+ z 1.0))) (* z (- z))))
(t_1 (/ -1.0 (* (* z (/ z x)) (/ (- -1.0 z) y)))))
(if (<= (* x y) -5e+274)
t_1
(if (<= (* x y) -5e-162)
t_0
(if (<= (* x y) 4e-141)
(/ (/ x z) (* z (/ (+ z 1.0) y)))
(if (<= (* x y) 1e+176) t_0 t_1)))))) double code(double x, double y, double z) {
return (x * y) / ((z * z) * (z + 1.0));
}
↓
double code(double x, double y, double z) {
double t_0 = -((x * y) / (z + 1.0)) / (z * -z);
double t_1 = -1.0 / ((z * (z / x)) * ((-1.0 - z) / y));
double tmp;
if ((x * y) <= -5e+274) {
tmp = t_1;
} else if ((x * y) <= -5e-162) {
tmp = t_0;
} else if ((x * y) <= 4e-141) {
tmp = (x / z) / (z * ((z + 1.0) / y));
} else if ((x * y) <= 1e+176) {
tmp = t_0;
} else {
tmp = t_1;
}
return tmp;
}
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
code = (x * y) / ((z * z) * (z + 1.0d0))
end function
↓
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8) :: t_0
real(8) :: t_1
real(8) :: tmp
t_0 = -((x * y) / (z + 1.0d0)) / (z * -z)
t_1 = (-1.0d0) / ((z * (z / x)) * (((-1.0d0) - z) / y))
if ((x * y) <= (-5d+274)) then
tmp = t_1
else if ((x * y) <= (-5d-162)) then
tmp = t_0
else if ((x * y) <= 4d-141) then
tmp = (x / z) / (z * ((z + 1.0d0) / y))
else if ((x * y) <= 1d+176) then
tmp = t_0
else
tmp = t_1
end if
code = tmp
end function
public static double code(double x, double y, double z) {
return (x * y) / ((z * z) * (z + 1.0));
}
↓
public static double code(double x, double y, double z) {
double t_0 = -((x * y) / (z + 1.0)) / (z * -z);
double t_1 = -1.0 / ((z * (z / x)) * ((-1.0 - z) / y));
double tmp;
if ((x * y) <= -5e+274) {
tmp = t_1;
} else if ((x * y) <= -5e-162) {
tmp = t_0;
} else if ((x * y) <= 4e-141) {
tmp = (x / z) / (z * ((z + 1.0) / y));
} else if ((x * y) <= 1e+176) {
tmp = t_0;
} else {
tmp = t_1;
}
return tmp;
}
def code(x, y, z):
return (x * y) / ((z * z) * (z + 1.0))
↓
def code(x, y, z):
t_0 = -((x * y) / (z + 1.0)) / (z * -z)
t_1 = -1.0 / ((z * (z / x)) * ((-1.0 - z) / y))
tmp = 0
if (x * y) <= -5e+274:
tmp = t_1
elif (x * y) <= -5e-162:
tmp = t_0
elif (x * y) <= 4e-141:
tmp = (x / z) / (z * ((z + 1.0) / y))
elif (x * y) <= 1e+176:
tmp = t_0
else:
tmp = t_1
return tmp
function code(x, y, z)
return Float64(Float64(x * y) / Float64(Float64(z * z) * Float64(z + 1.0)))
end
↓
function code(x, y, z)
t_0 = Float64(Float64(-Float64(Float64(x * y) / Float64(z + 1.0))) / Float64(z * Float64(-z)))
t_1 = Float64(-1.0 / Float64(Float64(z * Float64(z / x)) * Float64(Float64(-1.0 - z) / y)))
tmp = 0.0
if (Float64(x * y) <= -5e+274)
tmp = t_1;
elseif (Float64(x * y) <= -5e-162)
tmp = t_0;
elseif (Float64(x * y) <= 4e-141)
tmp = Float64(Float64(x / z) / Float64(z * Float64(Float64(z + 1.0) / y)));
elseif (Float64(x * y) <= 1e+176)
tmp = t_0;
else
tmp = t_1;
end
return tmp
end
function tmp = code(x, y, z)
tmp = (x * y) / ((z * z) * (z + 1.0));
end
↓
function tmp_2 = code(x, y, z)
t_0 = -((x * y) / (z + 1.0)) / (z * -z);
t_1 = -1.0 / ((z * (z / x)) * ((-1.0 - z) / y));
tmp = 0.0;
if ((x * y) <= -5e+274)
tmp = t_1;
elseif ((x * y) <= -5e-162)
tmp = t_0;
elseif ((x * y) <= 4e-141)
tmp = (x / z) / (z * ((z + 1.0) / y));
elseif ((x * y) <= 1e+176)
tmp = t_0;
else
tmp = t_1;
end
tmp_2 = tmp;
end
code[x_, y_, z_] := N[(N[(x * y), $MachinePrecision] / N[(N[(z * z), $MachinePrecision] * N[(z + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_] := Block[{t$95$0 = N[((-N[(N[(x * y), $MachinePrecision] / N[(z + 1.0), $MachinePrecision]), $MachinePrecision]) / N[(z * (-z)), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(-1.0 / N[(N[(z * N[(z / x), $MachinePrecision]), $MachinePrecision] * N[(N[(-1.0 - z), $MachinePrecision] / y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(x * y), $MachinePrecision], -5e+274], t$95$1, If[LessEqual[N[(x * y), $MachinePrecision], -5e-162], t$95$0, If[LessEqual[N[(x * y), $MachinePrecision], 4e-141], N[(N[(x / z), $MachinePrecision] / N[(z * N[(N[(z + 1.0), $MachinePrecision] / y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(x * y), $MachinePrecision], 1e+176], t$95$0, t$95$1]]]]]]
\frac{x \cdot y}{\left(z \cdot z\right) \cdot \left(z + 1\right)}
↓
\begin{array}{l}
t_0 := \frac{-\frac{x \cdot y}{z + 1}}{z \cdot \left(-z\right)}\\
t_1 := \frac{-1}{\left(z \cdot \frac{z}{x}\right) \cdot \frac{-1 - z}{y}}\\
\mathbf{if}\;x \cdot y \leq -5 \cdot 10^{+274}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;x \cdot y \leq -5 \cdot 10^{-162}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;x \cdot y \leq 4 \cdot 10^{-141}:\\
\;\;\;\;\frac{\frac{x}{z}}{z \cdot \frac{z + 1}{y}}\\
\mathbf{elif}\;x \cdot y \leq 10^{+176}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
Alternatives Alternative 1 Accuracy 97.6% Cost 3792
\[\begin{array}{l}
t_0 := \frac{\frac{x}{z}}{z \cdot \frac{z + 1}{y}}\\
t_1 := \frac{x \cdot y}{\left(z + 1\right) \cdot \left(z \cdot z\right)}\\
\mathbf{if}\;t_1 \leq -\infty:\\
\;\;\;\;t_0\\
\mathbf{elif}\;t_1 \leq -1 \cdot 10^{-290}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t_1 \leq 0:\\
\;\;\;\;\frac{y \cdot \frac{\frac{x}{z}}{z}}{z + 1}\\
\mathbf{elif}\;t_1 \leq 2 \cdot 10^{+228}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
Alternative 2 Accuracy 95.2% Cost 1736
\[\begin{array}{l}
t_0 := \left(z + 1\right) \cdot \left(z \cdot z\right)\\
\mathbf{if}\;t_0 \leq -5 \cdot 10^{+78}:\\
\;\;\;\;\frac{x \cdot \frac{\frac{y}{z}}{z}}{z}\\
\mathbf{elif}\;t_0 \leq 2 \cdot 10^{+36}:\\
\;\;\;\;\frac{y \cdot \frac{x}{z}}{z + z \cdot z}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{\frac{x}{z}}{\frac{z}{y}}}{z}\\
\end{array}
\]
Alternative 3 Accuracy 94.9% Cost 1736
\[\begin{array}{l}
t_0 := \left(z + 1\right) \cdot \left(z \cdot z\right)\\
\mathbf{if}\;t_0 \leq 2 \cdot 10^{-277}:\\
\;\;\;\;\frac{\frac{x}{z \cdot \frac{z + 1}{y}}}{z}\\
\mathbf{elif}\;t_0 \leq 2 \cdot 10^{+36}:\\
\;\;\;\;\frac{x \cdot y}{t_0}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{\frac{x}{z}}{\frac{z}{y}}}{z}\\
\end{array}
\]
Alternative 4 Accuracy 95.6% Cost 1232
\[\begin{array}{l}
t_0 := \frac{x}{z \cdot z} \cdot \frac{y}{z + 1}\\
\mathbf{if}\;z \leq -86000000000000:\\
\;\;\;\;\frac{x \cdot \frac{\frac{y}{z}}{z}}{z}\\
\mathbf{elif}\;z \leq -5 \cdot 10^{-17}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;z \leq 5.5 \cdot 10^{-19}:\\
\;\;\;\;\frac{\frac{y}{\frac{z}{x}}}{z}\\
\mathbf{elif}\;z \leq 3 \cdot 10^{+72}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{\frac{x}{z}}{\frac{z}{y}}}{z}\\
\end{array}
\]
Alternative 5 Accuracy 96.0% Cost 1232
\[\begin{array}{l}
t_0 := \frac{\frac{\frac{x}{z}}{\frac{z}{y}}}{z}\\
\mathbf{if}\;z \leq -4 \cdot 10^{+88}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;z \leq -7.8 \cdot 10^{-17}:\\
\;\;\;\;\frac{x}{z \cdot \left(z \cdot \frac{z + 1}{y}\right)}\\
\mathbf{elif}\;z \leq 1.7 \cdot 10^{-18}:\\
\;\;\;\;\frac{\frac{y}{\frac{z}{x}}}{z}\\
\mathbf{elif}\;z \leq 3.9 \cdot 10^{+71}:\\
\;\;\;\;\frac{x}{z \cdot z} \cdot \frac{y}{z + 1}\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
Alternative 6 Accuracy 95.4% Cost 1232
\[\begin{array}{l}
t_0 := \frac{x \cdot y}{\left(z + 1\right) \cdot \left(z \cdot z\right)}\\
t_1 := \frac{\frac{x}{z}}{\frac{z}{y}}\\
t_2 := \frac{t_1}{z}\\
\mathbf{if}\;z \leq -9 \cdot 10^{+60}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;z \leq -9.2 \cdot 10^{-89}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;z \leq 7.5 \cdot 10^{-123}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;z \leq 3.7 \cdot 10^{+21}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;t_2\\
\end{array}
\]
Alternative 7 Accuracy 90.5% Cost 841
\[\begin{array}{l}
\mathbf{if}\;z \leq -1 \lor \neg \left(z \leq 1\right):\\
\;\;\;\;\frac{y}{z} \cdot \frac{x}{z \cdot z}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{y}{\frac{z}{x}}}{z}\\
\end{array}
\]
Alternative 8 Accuracy 93.0% Cost 841
\[\begin{array}{l}
\mathbf{if}\;z \leq -1 \lor \neg \left(z \leq 1\right):\\
\;\;\;\;\frac{y \cdot \frac{\frac{x}{z}}{z}}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{y}{\frac{z}{x}}}{z}\\
\end{array}
\]
Alternative 9 Accuracy 93.0% Cost 841
\[\begin{array}{l}
\mathbf{if}\;z \leq -1 \lor \neg \left(z \leq 1\right):\\
\;\;\;\;\frac{x \cdot \frac{\frac{y}{z}}{z}}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{y}{\frac{z}{x}}}{z}\\
\end{array}
\]
Alternative 10 Accuracy 90.2% Cost 840
\[\begin{array}{l}
\mathbf{if}\;z \leq -1:\\
\;\;\;\;\frac{y}{z \cdot \left(z \cdot \frac{z}{x}\right)}\\
\mathbf{elif}\;z \leq 1:\\
\;\;\;\;\frac{\frac{y}{\frac{z}{x}}}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{y}{z} \cdot \frac{x}{z \cdot z}\\
\end{array}
\]
Alternative 11 Accuracy 90.4% Cost 840
\[\begin{array}{l}
\mathbf{if}\;z \leq -1:\\
\;\;\;\;\frac{x \cdot \frac{y}{z}}{z \cdot z}\\
\mathbf{elif}\;z \leq 1:\\
\;\;\;\;\frac{\frac{y}{\frac{z}{x}}}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{y}{z} \cdot \frac{x}{z \cdot z}\\
\end{array}
\]
Alternative 12 Accuracy 93.0% Cost 840
\[\begin{array}{l}
\mathbf{if}\;z \leq -1:\\
\;\;\;\;\frac{x \cdot \frac{\frac{y}{z}}{z}}{z}\\
\mathbf{elif}\;z \leq 1:\\
\;\;\;\;\frac{\frac{y}{\frac{z}{x}}}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{\frac{x}{z}}{z}}{\frac{z}{y}}\\
\end{array}
\]
Alternative 13 Accuracy 93.3% Cost 840
\[\begin{array}{l}
\mathbf{if}\;z \leq -1:\\
\;\;\;\;\frac{x \cdot \frac{\frac{y}{z}}{z}}{z}\\
\mathbf{elif}\;z \leq 1:\\
\;\;\;\;\frac{\frac{y}{\frac{z}{x}}}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{\frac{x}{z}}{\frac{z}{y}}}{z}\\
\end{array}
\]
Alternative 14 Accuracy 70.6% Cost 580
\[\begin{array}{l}
\mathbf{if}\;y \leq 4 \cdot 10^{+19}:\\
\;\;\;\;\frac{x}{z} \cdot \frac{y}{z}\\
\mathbf{else}:\\
\;\;\;\;y \cdot \frac{\frac{x}{z}}{z}\\
\end{array}
\]
Alternative 15 Accuracy 72.7% Cost 580
\[\begin{array}{l}
\mathbf{if}\;y \leq 9.5 \cdot 10^{-47}:\\
\;\;\;\;\frac{x}{z \cdot \frac{z}{y}}\\
\mathbf{else}:\\
\;\;\;\;y \cdot \frac{\frac{x}{z}}{z}\\
\end{array}
\]
Alternative 16 Accuracy 73.1% Cost 580
\[\begin{array}{l}
\mathbf{if}\;y \leq 3.9 \cdot 10^{-45}:\\
\;\;\;\;\frac{x}{z \cdot \frac{z}{y}}\\
\mathbf{else}:\\
\;\;\;\;\frac{y}{z \cdot \frac{z}{x}}\\
\end{array}
\]
Alternative 17 Accuracy 64.3% Cost 448
\[y \cdot \frac{\frac{x}{z}}{z}
\]