?

Average Accuracy: 81.7% → 99.3%
Time: 11.2s
Precision: binary64
Cost: 60432

?

\[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
\[\begin{array}{l} t_0 := \frac{e^{-y}}{x}\\ t_1 := \log \left(\frac{x}{x + y}\right)\\ t_2 := \frac{e^{x \cdot t_1}}{x}\\ t_3 := \frac{{\left(e^{x}\right)}^{t_1}}{x}\\ \mathbf{if}\;t_2 \leq -5000:\\ \;\;\;\;t_3\\ \mathbf{elif}\;t_2 \leq -4 \cdot 10^{-308}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;t_2 \leq 0:\\ \;\;\;\;t_3\\ \mathbf{elif}\;t_2 \leq 2 \cdot 10^{-84}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]
(FPCore (x y) :precision binary64 (/ (exp (* x (log (/ x (+ x y))))) x))
(FPCore (x y)
 :precision binary64
 (let* ((t_0 (/ (exp (- y)) x))
        (t_1 (log (/ x (+ x y))))
        (t_2 (/ (exp (* x t_1)) x))
        (t_3 (/ (pow (exp x) t_1) x)))
   (if (<= t_2 -5000.0)
     t_3
     (if (<= t_2 -4e-308)
       t_0
       (if (<= t_2 0.0) t_3 (if (<= t_2 2e-84) t_0 (/ 1.0 x)))))))
double code(double x, double y) {
	return exp((x * log((x / (x + y))))) / x;
}
double code(double x, double y) {
	double t_0 = exp(-y) / x;
	double t_1 = log((x / (x + y)));
	double t_2 = exp((x * t_1)) / x;
	double t_3 = pow(exp(x), t_1) / x;
	double tmp;
	if (t_2 <= -5000.0) {
		tmp = t_3;
	} else if (t_2 <= -4e-308) {
		tmp = t_0;
	} else if (t_2 <= 0.0) {
		tmp = t_3;
	} else if (t_2 <= 2e-84) {
		tmp = t_0;
	} else {
		tmp = 1.0 / x;
	}
	return tmp;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp((x * log((x / (x + y))))) / x
end function
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8) :: t_0
    real(8) :: t_1
    real(8) :: t_2
    real(8) :: t_3
    real(8) :: tmp
    t_0 = exp(-y) / x
    t_1 = log((x / (x + y)))
    t_2 = exp((x * t_1)) / x
    t_3 = (exp(x) ** t_1) / x
    if (t_2 <= (-5000.0d0)) then
        tmp = t_3
    else if (t_2 <= (-4d-308)) then
        tmp = t_0
    else if (t_2 <= 0.0d0) then
        tmp = t_3
    else if (t_2 <= 2d-84) then
        tmp = t_0
    else
        tmp = 1.0d0 / x
    end if
    code = tmp
end function
public static double code(double x, double y) {
	return Math.exp((x * Math.log((x / (x + y))))) / x;
}
public static double code(double x, double y) {
	double t_0 = Math.exp(-y) / x;
	double t_1 = Math.log((x / (x + y)));
	double t_2 = Math.exp((x * t_1)) / x;
	double t_3 = Math.pow(Math.exp(x), t_1) / x;
	double tmp;
	if (t_2 <= -5000.0) {
		tmp = t_3;
	} else if (t_2 <= -4e-308) {
		tmp = t_0;
	} else if (t_2 <= 0.0) {
		tmp = t_3;
	} else if (t_2 <= 2e-84) {
		tmp = t_0;
	} else {
		tmp = 1.0 / x;
	}
	return tmp;
}
def code(x, y):
	return math.exp((x * math.log((x / (x + y))))) / x
def code(x, y):
	t_0 = math.exp(-y) / x
	t_1 = math.log((x / (x + y)))
	t_2 = math.exp((x * t_1)) / x
	t_3 = math.pow(math.exp(x), t_1) / x
	tmp = 0
	if t_2 <= -5000.0:
		tmp = t_3
	elif t_2 <= -4e-308:
		tmp = t_0
	elif t_2 <= 0.0:
		tmp = t_3
	elif t_2 <= 2e-84:
		tmp = t_0
	else:
		tmp = 1.0 / x
	return tmp
function code(x, y)
	return Float64(exp(Float64(x * log(Float64(x / Float64(x + y))))) / x)
end
function code(x, y)
	t_0 = Float64(exp(Float64(-y)) / x)
	t_1 = log(Float64(x / Float64(x + y)))
	t_2 = Float64(exp(Float64(x * t_1)) / x)
	t_3 = Float64((exp(x) ^ t_1) / x)
	tmp = 0.0
	if (t_2 <= -5000.0)
		tmp = t_3;
	elseif (t_2 <= -4e-308)
		tmp = t_0;
	elseif (t_2 <= 0.0)
		tmp = t_3;
	elseif (t_2 <= 2e-84)
		tmp = t_0;
	else
		tmp = Float64(1.0 / x);
	end
	return tmp
end
function tmp = code(x, y)
	tmp = exp((x * log((x / (x + y))))) / x;
end
function tmp_2 = code(x, y)
	t_0 = exp(-y) / x;
	t_1 = log((x / (x + y)));
	t_2 = exp((x * t_1)) / x;
	t_3 = (exp(x) ^ t_1) / x;
	tmp = 0.0;
	if (t_2 <= -5000.0)
		tmp = t_3;
	elseif (t_2 <= -4e-308)
		tmp = t_0;
	elseif (t_2 <= 0.0)
		tmp = t_3;
	elseif (t_2 <= 2e-84)
		tmp = t_0;
	else
		tmp = 1.0 / x;
	end
	tmp_2 = tmp;
end
code[x_, y_] := N[(N[Exp[N[(x * N[Log[N[(x / N[(x + y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision]
code[x_, y_] := Block[{t$95$0 = N[(N[Exp[(-y)], $MachinePrecision] / x), $MachinePrecision]}, Block[{t$95$1 = N[Log[N[(x / N[(x + y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$2 = N[(N[Exp[N[(x * t$95$1), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision]}, Block[{t$95$3 = N[(N[Power[N[Exp[x], $MachinePrecision], t$95$1], $MachinePrecision] / x), $MachinePrecision]}, If[LessEqual[t$95$2, -5000.0], t$95$3, If[LessEqual[t$95$2, -4e-308], t$95$0, If[LessEqual[t$95$2, 0.0], t$95$3, If[LessEqual[t$95$2, 2e-84], t$95$0, N[(1.0 / x), $MachinePrecision]]]]]]]]]
\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x}
\begin{array}{l}
t_0 := \frac{e^{-y}}{x}\\
t_1 := \log \left(\frac{x}{x + y}\right)\\
t_2 := \frac{e^{x \cdot t_1}}{x}\\
t_3 := \frac{{\left(e^{x}\right)}^{t_1}}{x}\\
\mathbf{if}\;t_2 \leq -5000:\\
\;\;\;\;t_3\\

\mathbf{elif}\;t_2 \leq -4 \cdot 10^{-308}:\\
\;\;\;\;t_0\\

\mathbf{elif}\;t_2 \leq 0:\\
\;\;\;\;t_3\\

\mathbf{elif}\;t_2 \leq 2 \cdot 10^{-84}:\\
\;\;\;\;t_0\\

\mathbf{else}:\\
\;\;\;\;\frac{1}{x}\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original81.7%
Target87.3%
Herbie99.3%
\[\begin{array}{l} \mathbf{if}\;y < -3.7311844206647956 \cdot 10^{+94}:\\ \;\;\;\;\frac{e^{\frac{-1}{y}}}{x}\\ \mathbf{elif}\;y < 2.817959242728288 \cdot 10^{+37}:\\ \;\;\;\;\frac{{\left(\frac{x}{y + x}\right)}^{x}}{x}\\ \mathbf{elif}\;y < 2.347387415166998 \cdot 10^{+178}:\\ \;\;\;\;\log \left(e^{\frac{{\left(\frac{x}{y + x}\right)}^{x}}{x}}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{e^{\frac{-1}{y}}}{x}\\ \end{array} \]

Derivation?

  1. Split input into 3 regimes
  2. if (/.f64 (exp.f64 (*.f64 x (log.f64 (/.f64 x (+.f64 x y))))) x) < -5e3 or -4.00000000000000013e-308 < (/.f64 (exp.f64 (*.f64 x (log.f64 (/.f64 x (+.f64 x y))))) x) < 0.0

    1. Initial program 74.2%

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Simplified99.8%

      \[\leadsto \color{blue}{\frac{{\left(e^{x}\right)}^{\log \left(\frac{x}{x + y}\right)}}{x}} \]
      Proof

      [Start]74.2

      \[ \frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]

      exp-prod [=>]99.8

      \[ \frac{\color{blue}{{\left(e^{x}\right)}^{\log \left(\frac{x}{x + y}\right)}}}{x} \]

    if -5e3 < (/.f64 (exp.f64 (*.f64 x (log.f64 (/.f64 x (+.f64 x y))))) x) < -4.00000000000000013e-308 or 0.0 < (/.f64 (exp.f64 (*.f64 x (log.f64 (/.f64 x (+.f64 x y))))) x) < 2.0000000000000001e-84

    1. Initial program 78.1%

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Simplified78.1%

      \[\leadsto \color{blue}{\frac{{\left(\frac{x}{x + y}\right)}^{x}}{x}} \]
      Proof

      [Start]78.1

      \[ \frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]

      *-commutative [=>]78.1

      \[ \frac{e^{\color{blue}{\log \left(\frac{x}{x + y}\right) \cdot x}}}{x} \]

      exp-to-pow [=>]78.1

      \[ \frac{\color{blue}{{\left(\frac{x}{x + y}\right)}^{x}}}{x} \]
    3. Taylor expanded in x around inf 99.9%

      \[\leadsto \frac{\color{blue}{e^{-1 \cdot y}}}{x} \]
    4. Simplified99.9%

      \[\leadsto \frac{\color{blue}{e^{-y}}}{x} \]
      Proof

      [Start]99.9

      \[ \frac{e^{-1 \cdot y}}{x} \]

      mul-1-neg [=>]99.9

      \[ \frac{e^{\color{blue}{-y}}}{x} \]

    if 2.0000000000000001e-84 < (/.f64 (exp.f64 (*.f64 x (log.f64 (/.f64 x (+.f64 x y))))) x)

    1. Initial program 98.7%

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Simplified98.4%

      \[\leadsto \color{blue}{\frac{{\left(e^{x}\right)}^{\log \left(\frac{x}{x + y}\right)}}{x}} \]
      Proof

      [Start]98.7

      \[ \frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]

      exp-prod [=>]98.4

      \[ \frac{\color{blue}{{\left(e^{x}\right)}^{\log \left(\frac{x}{x + y}\right)}}}{x} \]
    3. Taylor expanded in x around 0 97.6%

      \[\leadsto \frac{\color{blue}{1}}{x} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification99.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \leq -5000:\\ \;\;\;\;\frac{{\left(e^{x}\right)}^{\log \left(\frac{x}{x + y}\right)}}{x}\\ \mathbf{elif}\;\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \leq -4 \cdot 10^{-308}:\\ \;\;\;\;\frac{e^{-y}}{x}\\ \mathbf{elif}\;\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \leq 0:\\ \;\;\;\;\frac{{\left(e^{x}\right)}^{\log \left(\frac{x}{x + y}\right)}}{x}\\ \mathbf{elif}\;\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \leq 2 \cdot 10^{-84}:\\ \;\;\;\;\frac{e^{-y}}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]

Alternatives

Alternative 1
Accuracy99.3%
Cost6921
\[\begin{array}{l} \mathbf{if}\;x \leq -14600000000 \lor \neg \left(x \leq 4.4 \cdot 10^{-14}\right):\\ \;\;\;\;\frac{e^{-y}}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]
Alternative 2
Accuracy91.6%
Cost713
\[\begin{array}{l} \mathbf{if}\;x \leq -100000000000 \lor \neg \left(x \leq 4.4 \cdot 10^{-14}\right):\\ \;\;\;\;\frac{1}{x + x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]
Alternative 3
Accuracy86.8%
Cost584
\[\begin{array}{l} \mathbf{if}\;y \leq 18000:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{elif}\;y \leq 4 \cdot 10^{+185}:\\ \;\;\;\;\frac{x}{x \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]
Alternative 4
Accuracy84.3%
Cost192
\[\frac{1}{x} \]

Error

Reproduce?

herbie shell --seed 2023140 
(FPCore (x y)
  :name "Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, F"
  :precision binary64

  :herbie-target
  (if (< y -3.7311844206647956e+94) (/ (exp (/ -1.0 y)) x) (if (< y 2.817959242728288e+37) (/ (pow (/ x (+ y x)) x) x) (if (< y 2.347387415166998e+178) (log (exp (/ (pow (/ x (+ y x)) x) x))) (/ (exp (/ -1.0 y)) x))))

  (/ (exp (* x (log (/ x (+ x y))))) x))