?

Average Accuracy: 71.6% → 87.3%
Time: 20.5s
Precision: binary64
Cost: 20352

?

\[\left(\left(-2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)\right) \cdot \sqrt{1 + {\left(\frac{U}{\left(2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)}\right)}^{2}} \]
\[\begin{array}{l} t_0 := \cos \left(\frac{K}{2}\right)\\ \left(\left(-2 \cdot J\right) \cdot t_0\right) \cdot \mathsf{hypot}\left(1, \frac{U}{2 \cdot \left(J \cdot t_0\right)}\right) \end{array} \]
(FPCore (J K U)
 :precision binary64
 (*
  (* (* -2.0 J) (cos (/ K 2.0)))
  (sqrt (+ 1.0 (pow (/ U (* (* 2.0 J) (cos (/ K 2.0)))) 2.0)))))
(FPCore (J K U)
 :precision binary64
 (let* ((t_0 (cos (/ K 2.0))))
   (* (* (* -2.0 J) t_0) (hypot 1.0 (/ U (* 2.0 (* J t_0)))))))
double code(double J, double K, double U) {
	return ((-2.0 * J) * cos((K / 2.0))) * sqrt((1.0 + pow((U / ((2.0 * J) * cos((K / 2.0)))), 2.0)));
}
double code(double J, double K, double U) {
	double t_0 = cos((K / 2.0));
	return ((-2.0 * J) * t_0) * hypot(1.0, (U / (2.0 * (J * t_0))));
}
public static double code(double J, double K, double U) {
	return ((-2.0 * J) * Math.cos((K / 2.0))) * Math.sqrt((1.0 + Math.pow((U / ((2.0 * J) * Math.cos((K / 2.0)))), 2.0)));
}
public static double code(double J, double K, double U) {
	double t_0 = Math.cos((K / 2.0));
	return ((-2.0 * J) * t_0) * Math.hypot(1.0, (U / (2.0 * (J * t_0))));
}
def code(J, K, U):
	return ((-2.0 * J) * math.cos((K / 2.0))) * math.sqrt((1.0 + math.pow((U / ((2.0 * J) * math.cos((K / 2.0)))), 2.0)))
def code(J, K, U):
	t_0 = math.cos((K / 2.0))
	return ((-2.0 * J) * t_0) * math.hypot(1.0, (U / (2.0 * (J * t_0))))
function code(J, K, U)
	return Float64(Float64(Float64(-2.0 * J) * cos(Float64(K / 2.0))) * sqrt(Float64(1.0 + (Float64(U / Float64(Float64(2.0 * J) * cos(Float64(K / 2.0)))) ^ 2.0))))
end
function code(J, K, U)
	t_0 = cos(Float64(K / 2.0))
	return Float64(Float64(Float64(-2.0 * J) * t_0) * hypot(1.0, Float64(U / Float64(2.0 * Float64(J * t_0)))))
end
function tmp = code(J, K, U)
	tmp = ((-2.0 * J) * cos((K / 2.0))) * sqrt((1.0 + ((U / ((2.0 * J) * cos((K / 2.0)))) ^ 2.0)));
end
function tmp = code(J, K, U)
	t_0 = cos((K / 2.0));
	tmp = ((-2.0 * J) * t_0) * hypot(1.0, (U / (2.0 * (J * t_0))));
end
code[J_, K_, U_] := N[(N[(N[(-2.0 * J), $MachinePrecision] * N[Cos[N[(K / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[N[(1.0 + N[Power[N[(U / N[(N[(2.0 * J), $MachinePrecision] * N[Cos[N[(K / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
code[J_, K_, U_] := Block[{t$95$0 = N[Cos[N[(K / 2.0), $MachinePrecision]], $MachinePrecision]}, N[(N[(N[(-2.0 * J), $MachinePrecision] * t$95$0), $MachinePrecision] * N[Sqrt[1.0 ^ 2 + N[(U / N[(2.0 * N[(J * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]]
\left(\left(-2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)\right) \cdot \sqrt{1 + {\left(\frac{U}{\left(2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)}\right)}^{2}}
\begin{array}{l}
t_0 := \cos \left(\frac{K}{2}\right)\\
\left(\left(-2 \cdot J\right) \cdot t_0\right) \cdot \mathsf{hypot}\left(1, \frac{U}{2 \cdot \left(J \cdot t_0\right)}\right)
\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Initial program 71.6%

    \[\left(\left(-2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)\right) \cdot \sqrt{1 + {\left(\frac{U}{\left(2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)}\right)}^{2}} \]
  2. Simplified87.3%

    \[\leadsto \color{blue}{\left(\left(-2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)\right) \cdot \mathsf{hypot}\left(1, \frac{U}{2 \cdot \left(J \cdot \cos \left(\frac{K}{2}\right)\right)}\right)} \]
    Proof

    [Start]71.6

    \[ \left(\left(-2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)\right) \cdot \sqrt{1 + {\left(\frac{U}{\left(2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)}\right)}^{2}} \]

    unpow2 [=>]71.6

    \[ \left(\left(-2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)\right) \cdot \sqrt{1 + \color{blue}{\frac{U}{\left(2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)} \cdot \frac{U}{\left(2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)}}} \]

    hypot-1-def [=>]87.3

    \[ \left(\left(-2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)\right) \cdot \color{blue}{\mathsf{hypot}\left(1, \frac{U}{\left(2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)}\right)} \]

    associate-*l* [=>]87.3

    \[ \left(\left(-2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)\right) \cdot \mathsf{hypot}\left(1, \frac{U}{\color{blue}{2 \cdot \left(J \cdot \cos \left(\frac{K}{2}\right)\right)}}\right) \]
  3. Final simplification87.3%

    \[\leadsto \left(\left(-2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)\right) \cdot \mathsf{hypot}\left(1, \frac{U}{2 \cdot \left(J \cdot \cos \left(\frac{K}{2}\right)\right)}\right) \]

Alternatives

Alternative 1
Accuracy87.3%
Cost20352
\[\begin{array}{l} t_0 := \cos \left(\frac{K}{2}\right)\\ \left(-2 \cdot J\right) \cdot \left(t_0 \cdot \mathsf{hypot}\left(1, \frac{U}{t_0 \cdot \left(J \cdot 2\right)}\right)\right) \end{array} \]
Alternative 2
Accuracy73.2%
Cost14620
\[\begin{array}{l} t_0 := \mathsf{hypot}\left(1, \frac{U \cdot 0.5}{J}\right)\\ t_1 := \left(\left(-2 \cdot J\right) \cdot \cos \left(\frac{K}{2}\right)\right) \cdot t_0\\ \mathbf{if}\;J \leq -1.9 \cdot 10^{-259}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;J \leq 1.05 \cdot 10^{-257}:\\ \;\;\;\;U\\ \mathbf{elif}\;J \leq 6.8 \cdot 10^{-230}:\\ \;\;\;\;-U\\ \mathbf{elif}\;J \leq 1.4 \cdot 10^{-226}:\\ \;\;\;\;U\\ \mathbf{elif}\;J \leq 2.6 \cdot 10^{-140}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;J \leq 10^{-104}:\\ \;\;\;\;\left(-2 \cdot J\right) \cdot t_0\\ \mathbf{elif}\;J \leq 1.8 \cdot 10^{-99}:\\ \;\;\;\;-U\\ \mathbf{else}:\\ \;\;\;\;t_1\\ \end{array} \]
Alternative 3
Accuracy64.9%
Cost7905
\[\begin{array}{l} t_0 := \left(-2 \cdot J\right) \cdot \cos \left(K \cdot 0.5\right)\\ \mathbf{if}\;K \leq -6.3 \cdot 10^{+221}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;K \leq -3.6 \cdot 10^{+202}:\\ \;\;\;\;U\\ \mathbf{elif}\;K \leq -6.8 \cdot 10^{+152}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;K \leq -1.8 \cdot 10^{+75}:\\ \;\;\;\;U\\ \mathbf{elif}\;K \leq -3.2 \cdot 10^{-34}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;K \leq 0.00044:\\ \;\;\;\;\left(-2 \cdot J\right) \cdot \mathsf{hypot}\left(1, \frac{U \cdot 0.5}{J}\right)\\ \mathbf{elif}\;K \leq 5.7 \cdot 10^{+104} \lor \neg \left(K \leq 2.9 \cdot 10^{+164}\right):\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;-U\\ \end{array} \]
Alternative 4
Accuracy59.6%
Cost7640
\[\begin{array}{l} t_0 := \left(-2 \cdot J\right) \cdot \frac{J}{U} - U\\ t_1 := \left(-2 \cdot J\right) \cdot \cos \left(K \cdot 0.5\right)\\ \mathbf{if}\;J \leq -2.5 \cdot 10^{-121}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;J \leq -1.8 \cdot 10^{-160}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;J \leq -2.8 \cdot 10^{-178}:\\ \;\;\;\;U\\ \mathbf{elif}\;J \leq -8.2 \cdot 10^{-219}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;J \leq 4 \cdot 10^{-256}:\\ \;\;\;\;U\\ \mathbf{elif}\;J \leq 1.1 \cdot 10^{-49}:\\ \;\;\;\;-U\\ \mathbf{else}:\\ \;\;\;\;t_1\\ \end{array} \]
Alternative 5
Accuracy40.2%
Cost1496
\[\begin{array}{l} t_0 := \left(-2 \cdot J\right) \cdot \frac{J}{U} - U\\ \mathbf{if}\;J \leq -5.5 \cdot 10^{-92}:\\ \;\;\;\;-2 \cdot J\\ \mathbf{elif}\;J \leq -8.5 \cdot 10^{-161}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;J \leq -3.6 \cdot 10^{-178}:\\ \;\;\;\;U\\ \mathbf{elif}\;J \leq -4.6 \cdot 10^{-219}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;J \leq 9.5 \cdot 10^{-258}:\\ \;\;\;\;U\\ \mathbf{elif}\;J \leq 1.25 \cdot 10^{+51}:\\ \;\;\;\;-U\\ \mathbf{else}:\\ \;\;\;\;-2 \cdot J + U \cdot \frac{U \cdot -0.25}{J}\\ \end{array} \]
Alternative 6
Accuracy40.3%
Cost1104
\[\begin{array}{l} t_0 := \left(-2 \cdot J\right) \cdot \frac{J}{U} - U\\ \mathbf{if}\;J \leq -7.5 \cdot 10^{-92}:\\ \;\;\;\;-2 \cdot J\\ \mathbf{elif}\;J \leq -1.8 \cdot 10^{-160}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;J \leq -3.6 \cdot 10^{-178}:\\ \;\;\;\;U\\ \mathbf{elif}\;J \leq -9.5 \cdot 10^{-218}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;J \leq 9.2 \cdot 10^{-256}:\\ \;\;\;\;U\\ \mathbf{elif}\;J \leq 9.5 \cdot 10^{+50}:\\ \;\;\;\;-U\\ \mathbf{else}:\\ \;\;\;\;-2 \cdot J\\ \end{array} \]
Alternative 7
Accuracy40.2%
Cost852
\[\begin{array}{l} \mathbf{if}\;U \leq -4 \cdot 10^{+142}:\\ \;\;\;\;-U\\ \mathbf{elif}\;U \leq -3.9 \cdot 10^{+49}:\\ \;\;\;\;U\\ \mathbf{elif}\;U \leq 1.25 \cdot 10^{-12}:\\ \;\;\;\;-2 \cdot J\\ \mathbf{elif}\;U \leq 5.1 \cdot 10^{+169}:\\ \;\;\;\;U\\ \mathbf{elif}\;U \leq 3.2 \cdot 10^{+182}:\\ \;\;\;\;-2 \cdot J\\ \mathbf{else}:\\ \;\;\;\;-U\\ \end{array} \]
Alternative 8
Accuracy26.9%
Cost524
\[\begin{array}{l} \mathbf{if}\;K \leq -6.3 \cdot 10^{+35}:\\ \;\;\;\;U\\ \mathbf{elif}\;K \leq -4.8 \cdot 10^{-72}:\\ \;\;\;\;-U\\ \mathbf{elif}\;K \leq 1.4 \cdot 10^{-289}:\\ \;\;\;\;U\\ \mathbf{else}:\\ \;\;\;\;-U\\ \end{array} \]
Alternative 9
Accuracy27.1%
Cost64
\[U \]

Error

Reproduce?

herbie shell --seed 2023138 
(FPCore (J K U)
  :name "Maksimov and Kolovsky, Equation (3)"
  :precision binary64
  (* (* (* -2.0 J) (cos (/ K 2.0))) (sqrt (+ 1.0 (pow (/ U (* (* 2.0 J) (cos (/ K 2.0)))) 2.0)))))