?

Average Accuracy: 99.4% → 99.3%
Time: 3.5s
Precision: binary64
Cost: 448

?

\[\frac{x \cdot 100}{x + y} \]
\[\frac{100}{\frac{x + y}{x}} \]
(FPCore (x y) :precision binary64 (/ (* x 100.0) (+ x y)))
(FPCore (x y) :precision binary64 (/ 100.0 (/ (+ x y) x)))
double code(double x, double y) {
	return (x * 100.0) / (x + y);
}
double code(double x, double y) {
	return 100.0 / ((x + y) / x);
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = (x * 100.0d0) / (x + y)
end function
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = 100.0d0 / ((x + y) / x)
end function
public static double code(double x, double y) {
	return (x * 100.0) / (x + y);
}
public static double code(double x, double y) {
	return 100.0 / ((x + y) / x);
}
def code(x, y):
	return (x * 100.0) / (x + y)
def code(x, y):
	return 100.0 / ((x + y) / x)
function code(x, y)
	return Float64(Float64(x * 100.0) / Float64(x + y))
end
function code(x, y)
	return Float64(100.0 / Float64(Float64(x + y) / x))
end
function tmp = code(x, y)
	tmp = (x * 100.0) / (x + y);
end
function tmp = code(x, y)
	tmp = 100.0 / ((x + y) / x);
end
code[x_, y_] := N[(N[(x * 100.0), $MachinePrecision] / N[(x + y), $MachinePrecision]), $MachinePrecision]
code[x_, y_] := N[(100.0 / N[(N[(x + y), $MachinePrecision] / x), $MachinePrecision]), $MachinePrecision]
\frac{x \cdot 100}{x + y}
\frac{100}{\frac{x + y}{x}}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original99.4%
Target99.8%
Herbie99.3%
\[\frac{x}{1} \cdot \frac{100}{x + y} \]

Derivation?

  1. Initial program 99.4%

    \[\frac{x \cdot 100}{x + y} \]
  2. Simplified99.7%

    \[\leadsto \color{blue}{\frac{x}{\frac{x + y}{100}}} \]
    Proof

    [Start]99.4

    \[ \frac{x \cdot 100}{x + y} \]

    associate-/l* [=>]99.7

    \[ \color{blue}{\frac{x}{\frac{x + y}{100}}} \]
  3. Applied egg-rr64.6%

    \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(x \cdot \frac{100}{x + y}\right)} - 1} \]
    Proof

    [Start]99.7

    \[ \frac{x}{\frac{x + y}{100}} \]

    expm1-log1p-u [=>]98.5

    \[ \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{x}{\frac{x + y}{100}}\right)\right)} \]

    expm1-udef [=>]64.6

    \[ \color{blue}{e^{\mathsf{log1p}\left(\frac{x}{\frac{x + y}{100}}\right)} - 1} \]

    div-inv [=>]64.6

    \[ e^{\mathsf{log1p}\left(\color{blue}{x \cdot \frac{1}{\frac{x + y}{100}}}\right)} - 1 \]

    clear-num [<=]64.6

    \[ e^{\mathsf{log1p}\left(x \cdot \color{blue}{\frac{100}{x + y}}\right)} - 1 \]
  4. Simplified99.3%

    \[\leadsto \color{blue}{\frac{100}{\frac{x + y}{x}}} \]
    Proof

    [Start]64.6

    \[ e^{\mathsf{log1p}\left(x \cdot \frac{100}{x + y}\right)} - 1 \]

    expm1-def [=>]98.5

    \[ \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(x \cdot \frac{100}{x + y}\right)\right)} \]

    expm1-log1p [=>]99.8

    \[ \color{blue}{x \cdot \frac{100}{x + y}} \]

    *-commutative [=>]99.8

    \[ \color{blue}{\frac{100}{x + y} \cdot x} \]

    associate-/r/ [<=]99.3

    \[ \color{blue}{\frac{100}{\frac{x + y}{x}}} \]
  5. Final simplification99.3%

    \[\leadsto \frac{100}{\frac{x + y}{x}} \]

Alternatives

Alternative 1
Accuracy74.6%
Cost584
\[\begin{array}{l} \mathbf{if}\;x \leq -5.2 \cdot 10^{-23}:\\ \;\;\;\;100\\ \mathbf{elif}\;x \leq 5.8 \cdot 10^{+18}:\\ \;\;\;\;100 \cdot \frac{x}{y}\\ \mathbf{else}:\\ \;\;\;\;100\\ \end{array} \]
Alternative 2
Accuracy74.8%
Cost584
\[\begin{array}{l} \mathbf{if}\;x \leq -4.8 \cdot 10^{-23}:\\ \;\;\;\;100\\ \mathbf{elif}\;x \leq 1.3 \cdot 10^{+16}:\\ \;\;\;\;\frac{x}{y \cdot 0.01}\\ \mathbf{else}:\\ \;\;\;\;100\\ \end{array} \]
Alternative 3
Accuracy99.8%
Cost448
\[x \cdot \frac{100}{x + y} \]
Alternative 4
Accuracy50.3%
Cost64
\[100 \]

Error

Reproduce?

herbie shell --seed 2023138 
(FPCore (x y)
  :name "Development.Shake.Progress:message from shake-0.15.5"
  :precision binary64

  :herbie-target
  (* (/ x 1.0) (/ 100.0 (+ x y)))

  (/ (* x 100.0) (+ x y)))