?

Average Accuracy: 91.7% → 99.9%
Time: 7.9s
Precision: binary64
Cost: 448

?

\[x \cdot \left(1 + y \cdot y\right) \]
\[x + y \cdot \left(y \cdot x\right) \]
(FPCore (x y) :precision binary64 (* x (+ 1.0 (* y y))))
(FPCore (x y) :precision binary64 (+ x (* y (* y x))))
double code(double x, double y) {
	return x * (1.0 + (y * y));
}
double code(double x, double y) {
	return x + (y * (y * x));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = x * (1.0d0 + (y * y))
end function
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = x + (y * (y * x))
end function
public static double code(double x, double y) {
	return x * (1.0 + (y * y));
}
public static double code(double x, double y) {
	return x + (y * (y * x));
}
def code(x, y):
	return x * (1.0 + (y * y))
def code(x, y):
	return x + (y * (y * x))
function code(x, y)
	return Float64(x * Float64(1.0 + Float64(y * y)))
end
function code(x, y)
	return Float64(x + Float64(y * Float64(y * x)))
end
function tmp = code(x, y)
	tmp = x * (1.0 + (y * y));
end
function tmp = code(x, y)
	tmp = x + (y * (y * x));
end
code[x_, y_] := N[(x * N[(1.0 + N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[x_, y_] := N[(x + N[(y * N[(y * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
x \cdot \left(1 + y \cdot y\right)
x + y \cdot \left(y \cdot x\right)

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original91.7%
Target99.9%
Herbie99.9%
\[x + \left(x \cdot y\right) \cdot y \]

Derivation?

  1. Initial program 91.7%

    \[x \cdot \left(1 + y \cdot y\right) \]
  2. Applied egg-rr91.7%

    \[\leadsto \color{blue}{x \cdot \left(y \cdot y\right) + x} \]
    Proof

    [Start]91.7

    \[ x \cdot \left(1 + y \cdot y\right) \]

    distribute-rgt-in [=>]91.7

    \[ \color{blue}{1 \cdot x + \left(y \cdot y\right) \cdot x} \]

    *-un-lft-identity [<=]91.7

    \[ \color{blue}{x} + \left(y \cdot y\right) \cdot x \]

    +-commutative [=>]91.7

    \[ \color{blue}{\left(y \cdot y\right) \cdot x + x} \]

    *-commutative [=>]91.7

    \[ \color{blue}{x \cdot \left(y \cdot y\right)} + x \]
  3. Taylor expanded in x around 0 91.7%

    \[\leadsto \color{blue}{{y}^{2} \cdot x} + x \]
  4. Simplified99.9%

    \[\leadsto \color{blue}{y \cdot \left(y \cdot x\right)} + x \]
    Proof

    [Start]91.7

    \[ {y}^{2} \cdot x + x \]

    unpow2 [=>]91.7

    \[ \color{blue}{\left(y \cdot y\right)} \cdot x + x \]

    associate-*l* [=>]99.9

    \[ \color{blue}{y \cdot \left(y \cdot x\right)} + x \]
  5. Final simplification99.9%

    \[\leadsto x + y \cdot \left(y \cdot x\right) \]

Alternatives

Alternative 1
Accuracy99.9%
Cost708
\[\begin{array}{l} \mathbf{if}\;y \cdot y \leq 2.2 \cdot 10^{+32}:\\ \;\;\;\;x \cdot \left(y \cdot y + 1\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(y \cdot x\right)\\ \end{array} \]
Alternative 2
Accuracy99.9%
Cost708
\[\begin{array}{l} \mathbf{if}\;y \cdot y \leq 2.2 \cdot 10^{+32}:\\ \;\;\;\;x + x \cdot \left(y \cdot y\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(y \cdot x\right)\\ \end{array} \]
Alternative 3
Accuracy90.2%
Cost580
\[\begin{array}{l} \mathbf{if}\;y \cdot y \leq 1:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y \cdot y\right)\\ \end{array} \]
Alternative 4
Accuracy98.4%
Cost580
\[\begin{array}{l} \mathbf{if}\;y \cdot y \leq 5 \cdot 10^{-5}:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(y \cdot x\right)\\ \end{array} \]
Alternative 5
Accuracy67.0%
Cost64
\[x \]

Error

Reproduce?

herbie shell --seed 2023138 
(FPCore (x y)
  :name "Numeric.Integration.TanhSinh:everywhere from integration-0.2.1"
  :precision binary64

  :herbie-target
  (+ x (* (* x y) y))

  (* x (+ 1.0 (* y y))))