\[ \begin{array}{c}[y, z] = \mathsf{sort}([y, z])\\ \end{array} \]
Math FPCore C Julia Wolfram TeX \[x \cdot \left(1 - y \cdot z\right)
\]
↓
\[\begin{array}{l}
\mathbf{if}\;y \cdot z \leq -\infty:\\
\;\;\;\;z \cdot \left(y \cdot \left(-x\right)\right)\\
\mathbf{elif}\;y \cdot z \leq 5 \cdot 10^{+148}:\\
\;\;\;\;x \cdot \mathsf{fma}\left(z, -y, 1\right)\\
\mathbf{else}:\\
\;\;\;\;\left(-y\right) \cdot \left(z \cdot x\right)\\
\end{array}
\]
(FPCore (x y z) :precision binary64 (* x (- 1.0 (* y z)))) ↓
(FPCore (x y z)
:precision binary64
(if (<= (* y z) (- INFINITY))
(* z (* y (- x)))
(if (<= (* y z) 5e+148) (* x (fma z (- y) 1.0)) (* (- y) (* z x))))) double code(double x, double y, double z) {
return x * (1.0 - (y * z));
}
↓
double code(double x, double y, double z) {
double tmp;
if ((y * z) <= -((double) INFINITY)) {
tmp = z * (y * -x);
} else if ((y * z) <= 5e+148) {
tmp = x * fma(z, -y, 1.0);
} else {
tmp = -y * (z * x);
}
return tmp;
}
function code(x, y, z)
return Float64(x * Float64(1.0 - Float64(y * z)))
end
↓
function code(x, y, z)
tmp = 0.0
if (Float64(y * z) <= Float64(-Inf))
tmp = Float64(z * Float64(y * Float64(-x)));
elseif (Float64(y * z) <= 5e+148)
tmp = Float64(x * fma(z, Float64(-y), 1.0));
else
tmp = Float64(Float64(-y) * Float64(z * x));
end
return tmp
end
code[x_, y_, z_] := N[(x * N[(1.0 - N[(y * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_] := If[LessEqual[N[(y * z), $MachinePrecision], (-Infinity)], N[(z * N[(y * (-x)), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(y * z), $MachinePrecision], 5e+148], N[(x * N[(z * (-y) + 1.0), $MachinePrecision]), $MachinePrecision], N[((-y) * N[(z * x), $MachinePrecision]), $MachinePrecision]]]
x \cdot \left(1 - y \cdot z\right)
↓
\begin{array}{l}
\mathbf{if}\;y \cdot z \leq -\infty:\\
\;\;\;\;z \cdot \left(y \cdot \left(-x\right)\right)\\
\mathbf{elif}\;y \cdot z \leq 5 \cdot 10^{+148}:\\
\;\;\;\;x \cdot \mathsf{fma}\left(z, -y, 1\right)\\
\mathbf{else}:\\
\;\;\;\;\left(-y\right) \cdot \left(z \cdot x\right)\\
\end{array}
Alternatives Alternative 1 Accuracy 99.8% Cost 1224
\[\begin{array}{l}
t_0 := 1 - y \cdot z\\
\mathbf{if}\;t_0 \leq -4 \cdot 10^{+285}:\\
\;\;\;\;\left(-y\right) \cdot \left(z \cdot x\right)\\
\mathbf{elif}\;t_0 \leq 2 \cdot 10^{+290}:\\
\;\;\;\;x \cdot t_0\\
\mathbf{else}:\\
\;\;\;\;z \cdot \left(y \cdot \left(-x\right)\right)\\
\end{array}
\]
Alternative 2 Accuracy 99.4% Cost 968
\[\begin{array}{l}
\mathbf{if}\;y \cdot z \leq -\infty:\\
\;\;\;\;z \cdot \left(y \cdot \left(-x\right)\right)\\
\mathbf{elif}\;y \cdot z \leq 5 \cdot 10^{+148}:\\
\;\;\;\;x - \left(y \cdot z\right) \cdot x\\
\mathbf{else}:\\
\;\;\;\;\left(-y\right) \cdot \left(z \cdot x\right)\\
\end{array}
\]
Alternative 3 Accuracy 70.3% Cost 914
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.2 \cdot 10^{+136} \lor \neg \left(y \leq -1.95 \cdot 10^{+73}\right) \land \left(y \leq -6.8 \cdot 10^{+47} \lor \neg \left(y \leq 9 \cdot 10^{-20}\right)\right):\\
\;\;\;\;\left(y \cdot z\right) \cdot \left(-x\right)\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 4 Accuracy 72.6% Cost 912
\[\begin{array}{l}
t_0 := z \cdot \left(y \cdot \left(-x\right)\right)\\
\mathbf{if}\;y \leq -9.8 \cdot 10^{+132}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq -4 \cdot 10^{+72}:\\
\;\;\;\;x\\
\mathbf{elif}\;y \leq -4.2 \cdot 10^{+48}:\\
\;\;\;\;\left(y \cdot z\right) \cdot \left(-x\right)\\
\mathbf{elif}\;y \leq 9.5 \cdot 10^{-25}:\\
\;\;\;\;x\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
Alternative 5 Accuracy 72.3% Cost 912
\[\begin{array}{l}
\mathbf{if}\;y \leq -3.8 \cdot 10^{+133}:\\
\;\;\;\;z \cdot \left(y \cdot \left(-x\right)\right)\\
\mathbf{elif}\;y \leq -4.7 \cdot 10^{+73}:\\
\;\;\;\;x\\
\mathbf{elif}\;y \leq -8.2 \cdot 10^{+46}:\\
\;\;\;\;\left(y \cdot z\right) \cdot \left(-x\right)\\
\mathbf{elif}\;y \leq 1.28 \cdot 10^{-21}:\\
\;\;\;\;x\\
\mathbf{else}:\\
\;\;\;\;\left(-y\right) \cdot \left(z \cdot x\right)\\
\end{array}
\]
Alternative 6 Accuracy 60.2% Cost 64
\[x
\]