?

Average Accuracy: 6.4% → 99.4%
Time: 12.1s
Precision: binary64
Cost: 6912

?

\[-0.026 < x \land x < 0.026\]
\[\frac{1}{x} - \frac{1}{\tan x} \]
\[0.3333333333333333 \cdot x + 0.022222222222222223 \cdot {x}^{3} \]
(FPCore (x) :precision binary64 (- (/ 1.0 x) (/ 1.0 (tan x))))
(FPCore (x)
 :precision binary64
 (+ (* 0.3333333333333333 x) (* 0.022222222222222223 (pow x 3.0))))
double code(double x) {
	return (1.0 / x) - (1.0 / tan(x));
}
double code(double x) {
	return (0.3333333333333333 * x) + (0.022222222222222223 * pow(x, 3.0));
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = (1.0d0 / x) - (1.0d0 / tan(x))
end function
real(8) function code(x)
    real(8), intent (in) :: x
    code = (0.3333333333333333d0 * x) + (0.022222222222222223d0 * (x ** 3.0d0))
end function
public static double code(double x) {
	return (1.0 / x) - (1.0 / Math.tan(x));
}
public static double code(double x) {
	return (0.3333333333333333 * x) + (0.022222222222222223 * Math.pow(x, 3.0));
}
def code(x):
	return (1.0 / x) - (1.0 / math.tan(x))
def code(x):
	return (0.3333333333333333 * x) + (0.022222222222222223 * math.pow(x, 3.0))
function code(x)
	return Float64(Float64(1.0 / x) - Float64(1.0 / tan(x)))
end
function code(x)
	return Float64(Float64(0.3333333333333333 * x) + Float64(0.022222222222222223 * (x ^ 3.0)))
end
function tmp = code(x)
	tmp = (1.0 / x) - (1.0 / tan(x));
end
function tmp = code(x)
	tmp = (0.3333333333333333 * x) + (0.022222222222222223 * (x ^ 3.0));
end
code[x_] := N[(N[(1.0 / x), $MachinePrecision] - N[(1.0 / N[Tan[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[x_] := N[(N[(0.3333333333333333 * x), $MachinePrecision] + N[(0.022222222222222223 * N[Power[x, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{1}{x} - \frac{1}{\tan x}
0.3333333333333333 \cdot x + 0.022222222222222223 \cdot {x}^{3}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original6.4%
Target99.9%
Herbie99.4%
\[\begin{array}{l} \mathbf{if}\;\left|x\right| < 0.026:\\ \;\;\;\;\frac{x}{3} \cdot \left(1 + \frac{x \cdot x}{15}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x} - \frac{1}{\tan x}\\ \end{array} \]

Derivation?

  1. Initial program 6.4%

    \[\frac{1}{x} - \frac{1}{\tan x} \]
  2. Taylor expanded in x around 0 99.4%

    \[\leadsto \color{blue}{0.3333333333333333 \cdot x + 0.022222222222222223 \cdot {x}^{3}} \]
  3. Final simplification99.4%

    \[\leadsto 0.3333333333333333 \cdot x + 0.022222222222222223 \cdot {x}^{3} \]

Alternatives

Alternative 1
Accuracy99.2%
Cost576
\[\left(x \cdot 0.1111111111111111\right) \cdot \frac{x}{0.3333333333333333 \cdot x} \]
Alternative 2
Accuracy99.1%
Cost320
\[\frac{0.037037037037037035}{\frac{0.1111111111111111}{x}} \]
Alternative 3
Accuracy98.9%
Cost192
\[0.3333333333333333 \cdot x \]

Error

Reproduce?

herbie shell --seed 2023137 
(FPCore (x)
  :name "invcot (example 3.9)"
  :precision binary64
  :pre (and (< -0.026 x) (< x 0.026))

  :herbie-target
  (if (< (fabs x) 0.026) (* (/ x 3.0) (+ 1.0 (/ (* x x) 15.0))) (- (/ 1.0 x) (/ 1.0 (tan x))))

  (- (/ 1.0 x) (/ 1.0 (tan x))))