\[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th
\]
↓
\[\frac{\sin th}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin ky}}
\]
(FPCore (kx ky th)
:precision binary64
(* (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) (sin th)))
↓
(FPCore (kx ky th)
:precision binary64
(/ (sin th) (/ (hypot (sin ky) (sin kx)) (sin ky))))
double code(double kx, double ky, double th) {
return (sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) * sin(th);
}
↓
double code(double kx, double ky, double th) {
return sin(th) / (hypot(sin(ky), sin(kx)) / sin(ky));
}
public static double code(double kx, double ky, double th) {
return (Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) * Math.sin(th);
}
↓
public static double code(double kx, double ky, double th) {
return Math.sin(th) / (Math.hypot(Math.sin(ky), Math.sin(kx)) / Math.sin(ky));
}
def code(kx, ky, th):
return (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) * math.sin(th)
↓
def code(kx, ky, th):
return math.sin(th) / (math.hypot(math.sin(ky), math.sin(kx)) / math.sin(ky))
function code(kx, ky, th)
return Float64(Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th))
end
↓
function code(kx, ky, th)
return Float64(sin(th) / Float64(hypot(sin(ky), sin(kx)) / sin(ky)))
end
function tmp = code(kx, ky, th)
tmp = (sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th);
end
↓
function tmp = code(kx, ky, th)
tmp = sin(th) / (hypot(sin(ky), sin(kx)) / sin(ky));
end
code[kx_, ky_, th_] := N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]
↓
code[kx_, ky_, th_] := N[(N[Sin[th], $MachinePrecision] / N[(N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision] / N[Sin[ky], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th
↓
\frac{\sin th}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin ky}}
Alternatives
| Alternative 1 |
|---|
| Accuracy | 52.8% |
|---|
| Cost | 45516 |
|---|
\[\begin{array}{l}
\mathbf{if}\;\sin ky \leq -2 \cdot 10^{-54}:\\
\;\;\;\;\left|\sin th\right|\\
\mathbf{elif}\;\sin ky \leq -5 \cdot 10^{-307}:\\
\;\;\;\;\frac{ky}{\frac{\sin kx}{\sin th}}\\
\mathbf{elif}\;\sin ky \leq 2 \cdot 10^{-116}:\\
\;\;\;\;\sin th \cdot \left|\frac{\sin ky}{\sin kx}\right|\\
\mathbf{else}:\\
\;\;\;\;\sin th\\
\end{array}
\]
| Alternative 2 |
|---|
| Accuracy | 73.9% |
|---|
| Cost | 39049 |
|---|
\[\begin{array}{l}
t_1 := \mathsf{hypot}\left(\sin ky, \sin kx\right)\\
\mathbf{if}\;\sin th \leq -0.0005 \lor \neg \left(\sin th \leq 10^{-6}\right):\\
\;\;\;\;\frac{\sin th \cdot ky}{t_1}\\
\mathbf{else}:\\
\;\;\;\;th \cdot \frac{\sin ky}{t_1}\\
\end{array}
\]
| Alternative 3 |
|---|
| Accuracy | 57.6% |
|---|
| Cost | 38984 |
|---|
\[\begin{array}{l}
\mathbf{if}\;\sin ky \leq 2 \cdot 10^{-302}:\\
\;\;\;\;\sin ky \cdot \frac{th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\
\mathbf{elif}\;\sin ky \leq 2 \cdot 10^{-116}:\\
\;\;\;\;\sin th \cdot \left|\frac{\sin ky}{\sin kx}\right|\\
\mathbf{else}:\\
\;\;\;\;\sin th\\
\end{array}
\]
| Alternative 4 |
|---|
| Accuracy | 57.7% |
|---|
| Cost | 38984 |
|---|
\[\begin{array}{l}
\mathbf{if}\;\sin ky \leq 2 \cdot 10^{-302}:\\
\;\;\;\;th \cdot \frac{\sin ky}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\
\mathbf{elif}\;\sin ky \leq 2 \cdot 10^{-116}:\\
\;\;\;\;\sin th \cdot \left|\frac{\sin ky}{\sin kx}\right|\\
\mathbf{else}:\\
\;\;\;\;\sin th\\
\end{array}
\]
| Alternative 5 |
|---|
| Accuracy | 99.7% |
|---|
| Cost | 32384 |
|---|
\[\sin th \cdot \frac{\sin ky}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}
\]
| Alternative 6 |
|---|
| Accuracy | 48.4% |
|---|
| Cost | 26184 |
|---|
\[\begin{array}{l}
\mathbf{if}\;\sin ky \leq -2 \cdot 10^{-54}:\\
\;\;\;\;\left|\sin th\right|\\
\mathbf{elif}\;\sin ky \leq 2 \cdot 10^{-116}:\\
\;\;\;\;\sin th \cdot \frac{ky}{\sin kx}\\
\mathbf{else}:\\
\;\;\;\;\sin th\\
\end{array}
\]
| Alternative 7 |
|---|
| Accuracy | 35.3% |
|---|
| Cost | 19784 |
|---|
\[\begin{array}{l}
\mathbf{if}\;\sin ky \leq -1 \cdot 10^{-12}:\\
\;\;\;\;\sqrt{th \cdot th}\\
\mathbf{elif}\;\sin ky \leq 5 \cdot 10^{-134}:\\
\;\;\;\;th \cdot \frac{ky}{\sin kx}\\
\mathbf{else}:\\
\;\;\;\;\sin th\\
\end{array}
\]
| Alternative 8 |
|---|
| Accuracy | 40.6% |
|---|
| Cost | 19784 |
|---|
\[\begin{array}{l}
\mathbf{if}\;\sin ky \leq -2 \cdot 10^{-154}:\\
\;\;\;\;\left|\sin th\right|\\
\mathbf{elif}\;\sin ky \leq 5 \cdot 10^{-134}:\\
\;\;\;\;th \cdot \frac{ky}{\sin kx}\\
\mathbf{else}:\\
\;\;\;\;\sin th\\
\end{array}
\]
| Alternative 9 |
|---|
| Accuracy | 31.6% |
|---|
| Cost | 6728 |
|---|
\[\begin{array}{l}
\mathbf{if}\;ky \leq -0.84:\\
\;\;\;\;\sin th\\
\mathbf{elif}\;ky \leq 4.2 \cdot 10^{-134}:\\
\;\;\;\;th \cdot \frac{ky}{kx}\\
\mathbf{else}:\\
\;\;\;\;\sin th\\
\end{array}
\]
| Alternative 10 |
|---|
| Accuracy | 22.1% |
|---|
| Cost | 584 |
|---|
\[\begin{array}{l}
\mathbf{if}\;ky \leq -6 \cdot 10^{-35}:\\
\;\;\;\;th\\
\mathbf{elif}\;ky \leq 4.2 \cdot 10^{-116}:\\
\;\;\;\;th \cdot \frac{ky}{kx}\\
\mathbf{else}:\\
\;\;\;\;th\\
\end{array}
\]
| Alternative 11 |
|---|
| Accuracy | 13.7% |
|---|
| Cost | 64 |
|---|
\[th
\]