Math FPCore C Java Python Julia MATLAB Wolfram TeX \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1
\]
↓
\[\left({\left(\mathsf{hypot}\left(a, b\right)\right)}^{4} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + \left(b \cdot b\right) \cdot \left(1 + a \cdot -3\right)\right)\right) + -1
\]
(FPCore (a b)
:precision binary64
(-
(+
(pow (+ (* a a) (* b b)) 2.0)
(* 4.0 (+ (* (* a a) (+ 1.0 a)) (* (* b b) (- 1.0 (* 3.0 a))))))
1.0)) ↓
(FPCore (a b)
:precision binary64
(+
(+
(pow (hypot a b) 4.0)
(* 4.0 (+ (* (* a a) (+ a 1.0)) (* (* b b) (+ 1.0 (* a -3.0))))))
-1.0)) double code(double a, double b) {
return (pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0;
}
↓
double code(double a, double b) {
return (pow(hypot(a, b), 4.0) + (4.0 * (((a * a) * (a + 1.0)) + ((b * b) * (1.0 + (a * -3.0)))))) + -1.0;
}
public static double code(double a, double b) {
return (Math.pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0;
}
↓
public static double code(double a, double b) {
return (Math.pow(Math.hypot(a, b), 4.0) + (4.0 * (((a * a) * (a + 1.0)) + ((b * b) * (1.0 + (a * -3.0)))))) + -1.0;
}
def code(a, b):
return (math.pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0
↓
def code(a, b):
return (math.pow(math.hypot(a, b), 4.0) + (4.0 * (((a * a) * (a + 1.0)) + ((b * b) * (1.0 + (a * -3.0)))))) + -1.0
function code(a, b)
return Float64(Float64((Float64(Float64(a * a) + Float64(b * b)) ^ 2.0) + Float64(4.0 * Float64(Float64(Float64(a * a) * Float64(1.0 + a)) + Float64(Float64(b * b) * Float64(1.0 - Float64(3.0 * a)))))) - 1.0)
end
↓
function code(a, b)
return Float64(Float64((hypot(a, b) ^ 4.0) + Float64(4.0 * Float64(Float64(Float64(a * a) * Float64(a + 1.0)) + Float64(Float64(b * b) * Float64(1.0 + Float64(a * -3.0)))))) + -1.0)
end
function tmp = code(a, b)
tmp = ((((a * a) + (b * b)) ^ 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0;
end
↓
function tmp = code(a, b)
tmp = ((hypot(a, b) ^ 4.0) + (4.0 * (((a * a) * (a + 1.0)) + ((b * b) * (1.0 + (a * -3.0)))))) + -1.0;
end
code[a_, b_] := N[(N[(N[Power[N[(N[(a * a), $MachinePrecision] + N[(b * b), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[(4.0 * N[(N[(N[(a * a), $MachinePrecision] * N[(1.0 + a), $MachinePrecision]), $MachinePrecision] + N[(N[(b * b), $MachinePrecision] * N[(1.0 - N[(3.0 * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision]
↓
code[a_, b_] := N[(N[(N[Power[N[Sqrt[a ^ 2 + b ^ 2], $MachinePrecision], 4.0], $MachinePrecision] + N[(4.0 * N[(N[(N[(a * a), $MachinePrecision] * N[(a + 1.0), $MachinePrecision]), $MachinePrecision] + N[(N[(b * b), $MachinePrecision] * N[(1.0 + N[(a * -3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision]
\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1
↓
\left({\left(\mathsf{hypot}\left(a, b\right)\right)}^{4} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + \left(b \cdot b\right) \cdot \left(1 + a \cdot -3\right)\right)\right) + -1
Alternatives Alternative 1 Accuracy 99.7% Cost 8196
\[\begin{array}{l}
\mathbf{if}\;b \cdot b \leq 2 \cdot 10^{-10}:\\
\;\;\;\;\left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + \left(b \cdot b\right) \cdot \left(1 + a \cdot -3\right)\right) + {a}^{4}\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(b \cdot b\right)\right) + -1\\
\end{array}
\]
Alternative 2 Accuracy 99.6% Cost 7936
\[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + b \cdot b\right)\right) + -1
\]
Alternative 3 Accuracy 99.6% Cost 7684
\[\begin{array}{l}
\mathbf{if}\;b \cdot b \leq 10^{-38}:\\
\;\;\;\;\left({a}^{4} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right)\right)\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(b \cdot b\right)\right) + -1\\
\end{array}
\]
Alternative 4 Accuracy 97.1% Cost 7561
\[\begin{array}{l}
\mathbf{if}\;a \leq -0.115 \lor \neg \left(a \leq 3.2 \cdot 10^{-7}\right):\\
\;\;\;\;\left({a}^{4} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right)\right)\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\left(4 \cdot \left(b \cdot b\right) + {b}^{4}\right) + -1\\
\end{array}
\]
Alternative 5 Accuracy 95.7% Cost 7305
\[\begin{array}{l}
\mathbf{if}\;a \leq -1300000000 \lor \neg \left(a \leq 1.8 \cdot 10^{-5}\right):\\
\;\;\;\;{a}^{3} \cdot \left(a + 4\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\left(4 \cdot \left(b \cdot b\right) + {b}^{4}\right) + -1\\
\end{array}
\]
Alternative 6 Accuracy 94.4% Cost 7177
\[\begin{array}{l}
\mathbf{if}\;a \leq -1300000000 \lor \neg \left(a \leq 1.8 \cdot 10^{-5}\right):\\
\;\;\;\;{a}^{3} \cdot \left(a + 4\right) + -1\\
\mathbf{else}:\\
\;\;\;\;{b}^{4} + -1\\
\end{array}
\]
Alternative 7 Accuracy 94.3% Cost 6921
\[\begin{array}{l}
\mathbf{if}\;a \leq -1300000000 \lor \neg \left(a \leq 1.8 \cdot 10^{-5}\right):\\
\;\;\;\;a \cdot \left(\left(a \cdot a\right) \cdot \left(a + 4\right)\right) + -1\\
\mathbf{else}:\\
\;\;\;\;{b}^{4} + -1\\
\end{array}
\]
Alternative 8 Accuracy 80.5% Cost 2249
\[\begin{array}{l}
\mathbf{if}\;a \leq -4 \lor \neg \left(a \leq 1.9\right):\\
\;\;\;\;a \cdot \left(\left(a \cdot a\right) \cdot \left(a + 4\right)\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + \left(b \cdot b\right) \cdot \left(1 + a \cdot -3\right)\right) + 2 \cdot \left(\left(a \cdot a\right) \cdot \left(b \cdot b\right)\right)\right) + -1\\
\end{array}
\]
Alternative 9 Accuracy 80.5% Cost 1865
\[\begin{array}{l}
\mathbf{if}\;a \leq -4 \lor \neg \left(a \leq 2.1\right):\\
\;\;\;\;a \cdot \left(\left(a \cdot a\right) \cdot \left(a + 4\right)\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + b \cdot b\right) + a \cdot \left(\left(b \cdot b\right) \cdot \left(a \cdot 2\right)\right)\right) + -1\\
\end{array}
\]
Alternative 10 Accuracy 78.8% Cost 704
\[a \cdot \left(\left(a \cdot a\right) \cdot \left(a + 4\right)\right) + -1
\]
Alternative 11 Accuracy 63.0% Cost 448
\[4 \cdot \left(b \cdot b\right) + -1
\]