Math FPCore C Julia Wolfram TeX \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\]
↓
\[\begin{array}{l}
\mathbf{if}\;k \leq 2 \cdot 10^{+37}:\\
\;\;\;\;a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{{k}^{m}}{k}}{\frac{k}{a}}\\
\end{array}
\]
(FPCore (a k m)
:precision binary64
(/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k)))) ↓
(FPCore (a k m)
:precision binary64
(if (<= k 2e+37)
(* a (/ (pow k m) (fma k (+ k 10.0) 1.0)))
(/ (/ (pow k m) k) (/ k a)))) double code(double a, double k, double m) {
return (a * pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
↓
double code(double a, double k, double m) {
double tmp;
if (k <= 2e+37) {
tmp = a * (pow(k, m) / fma(k, (k + 10.0), 1.0));
} else {
tmp = (pow(k, m) / k) / (k / a);
}
return tmp;
}
function code(a, k, m)
return Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(10.0 * k)) + Float64(k * k)))
end
↓
function code(a, k, m)
tmp = 0.0
if (k <= 2e+37)
tmp = Float64(a * Float64((k ^ m) / fma(k, Float64(k + 10.0), 1.0)));
else
tmp = Float64(Float64((k ^ m) / k) / Float64(k / a));
end
return tmp
end
code[a_, k_, m_] := N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(10.0 * k), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[a_, k_, m_] := If[LessEqual[k, 2e+37], N[(a * N[(N[Power[k, m], $MachinePrecision] / N[(k * N[(k + 10.0), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(N[Power[k, m], $MachinePrecision] / k), $MachinePrecision] / N[(k / a), $MachinePrecision]), $MachinePrecision]]
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
↓
\begin{array}{l}
\mathbf{if}\;k \leq 2 \cdot 10^{+37}:\\
\;\;\;\;a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{{k}^{m}}{k}}{\frac{k}{a}}\\
\end{array}
Alternatives Alternative 1 Accuracy 99.8% Cost 7428
\[\begin{array}{l}
\mathbf{if}\;k \leq 6.5 \cdot 10^{+14}:\\
\;\;\;\;\frac{a}{\frac{1 + \left(k \cdot k + k \cdot 10\right)}{{k}^{m}}}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{{k}^{m}}{k}}{\frac{k}{a}}\\
\end{array}
\]
Alternative 2 Accuracy 99.8% Cost 7428
\[\begin{array}{l}
\mathbf{if}\;k \leq 2 \cdot 10^{+22}:\\
\;\;\;\;\frac{a \cdot {k}^{m}}{\left(1 + k \cdot 10\right) + k \cdot k}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{{k}^{m}}{k}}{\frac{k}{a}}\\
\end{array}
\]
Alternative 3 Accuracy 95.7% Cost 7176
\[\begin{array}{l}
\mathbf{if}\;k \leq 10^{-17}:\\
\;\;\;\;a \cdot {k}^{m}\\
\mathbf{elif}\;k \leq 5.4 \cdot 10^{+146}:\\
\;\;\;\;a \cdot \frac{{k}^{m}}{k \cdot k}\\
\mathbf{elif}\;k \leq 2 \cdot 10^{+205}:\\
\;\;\;\;\frac{\frac{a}{k}}{k}\\
\mathbf{else}:\\
\;\;\;\;\frac{a}{k \cdot k}\\
\end{array}
\]
Alternative 4 Accuracy 95.7% Cost 7176
\[\begin{array}{l}
t_0 := a \cdot {k}^{m}\\
\mathbf{if}\;k \leq 10^{-17}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;k \leq 5.4 \cdot 10^{+146}:\\
\;\;\;\;\frac{t_0}{k \cdot k}\\
\mathbf{elif}\;k \leq 1.55 \cdot 10^{+205}:\\
\;\;\;\;\frac{\frac{a}{k}}{k}\\
\mathbf{else}:\\
\;\;\;\;\frac{a}{k \cdot k}\\
\end{array}
\]
Alternative 5 Accuracy 98.1% Cost 7044
\[\begin{array}{l}
\mathbf{if}\;k \leq 10^{-17}:\\
\;\;\;\;a \cdot {k}^{m}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{{k}^{m}}{k}}{\frac{k}{a}}\\
\end{array}
\]
Alternative 6 Accuracy 96.1% Cost 6921
\[\begin{array}{l}
\mathbf{if}\;m \leq -0.25 \lor \neg \left(m \leq 2.1 \cdot 10^{-6}\right):\\
\;\;\;\;a \cdot {k}^{m}\\
\mathbf{else}:\\
\;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\
\end{array}
\]
Alternative 7 Accuracy 95.8% Cost 6920
\[\begin{array}{l}
\mathbf{if}\;m \leq -4.8 \cdot 10^{-20}:\\
\;\;\;\;a \cdot {k}^{\left(m + -2\right)}\\
\mathbf{elif}\;m \leq 5.6 \cdot 10^{-6}:\\
\;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\
\mathbf{else}:\\
\;\;\;\;a \cdot {k}^{m}\\
\end{array}
\]
Alternative 8 Accuracy 69.9% Cost 841
\[\begin{array}{l}
\mathbf{if}\;m \leq -1.5 \lor \neg \left(m \leq 4 \cdot 10^{+19}\right):\\
\;\;\;\;\left(1 + a \cdot \frac{0.1}{k}\right) + -1\\
\mathbf{else}:\\
\;\;\;\;\frac{a}{1 + k \cdot k}\\
\end{array}
\]
Alternative 9 Accuracy 72.9% Cost 840
\[\begin{array}{l}
\mathbf{if}\;m \leq -0.4:\\
\;\;\;\;\left(1 + \frac{a}{k \cdot k}\right) + -1\\
\mathbf{elif}\;m \leq 4 \cdot 10^{+19}:\\
\;\;\;\;\frac{a}{1 + k \cdot k}\\
\mathbf{else}:\\
\;\;\;\;\left(1 + a \cdot \frac{0.1}{k}\right) + -1\\
\end{array}
\]
Alternative 10 Accuracy 74.0% Cost 840
\[\begin{array}{l}
\mathbf{if}\;m \leq -0.52:\\
\;\;\;\;\left(1 + \frac{a}{k \cdot k}\right) + -1\\
\mathbf{elif}\;m \leq 4 \cdot 10^{+19}:\\
\;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\
\mathbf{else}:\\
\;\;\;\;\left(1 + a \cdot \frac{0.1}{k}\right) + -1\\
\end{array}
\]
Alternative 11 Accuracy 63.0% Cost 716
\[\begin{array}{l}
t_0 := \frac{a}{k \cdot k}\\
\mathbf{if}\;k \leq -1:\\
\;\;\;\;t_0\\
\mathbf{elif}\;k \leq 1:\\
\;\;\;\;a\\
\mathbf{elif}\;k \leq 5.2 \cdot 10^{+206}:\\
\;\;\;\;\frac{\frac{a}{k}}{k}\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
Alternative 12 Accuracy 63.3% Cost 716
\[\begin{array}{l}
t_0 := \frac{a}{k \cdot k}\\
\mathbf{if}\;k \leq -0.43:\\
\;\;\;\;t_0\\
\mathbf{elif}\;k \leq 0.1:\\
\;\;\;\;a + -10 \cdot \left(k \cdot a\right)\\
\mathbf{elif}\;k \leq 5.2 \cdot 10^{+206}:\\
\;\;\;\;\frac{\frac{a}{k}}{k}\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
Alternative 13 Accuracy 63.2% Cost 716
\[\begin{array}{l}
t_0 := \frac{a}{k \cdot k}\\
\mathbf{if}\;k \leq -0.43:\\
\;\;\;\;t_0\\
\mathbf{elif}\;k \leq 0.1:\\
\;\;\;\;a + a \cdot \left(k \cdot -10\right)\\
\mathbf{elif}\;k \leq 1.2 \cdot 10^{+205}:\\
\;\;\;\;\frac{\frac{a}{k}}{k}\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
Alternative 14 Accuracy 62.9% Cost 713
\[\begin{array}{l}
\mathbf{if}\;k \leq -0.062 \lor \neg \left(k \leq 0.075\right):\\
\;\;\;\;\frac{a}{k \cdot \left(k + 10\right)}\\
\mathbf{else}:\\
\;\;\;\;a + a \cdot \left(k \cdot -10\right)\\
\end{array}
\]
Alternative 15 Accuracy 63.3% Cost 712
\[\begin{array}{l}
\mathbf{if}\;k \leq 0.1:\\
\;\;\;\;\frac{a}{1 + k \cdot k}\\
\mathbf{elif}\;k \leq 5.2 \cdot 10^{+206}:\\
\;\;\;\;\frac{\frac{a}{k}}{k + 10}\\
\mathbf{else}:\\
\;\;\;\;\frac{a}{k \cdot k}\\
\end{array}
\]
Alternative 16 Accuracy 39.1% Cost 585
\[\begin{array}{l}
\mathbf{if}\;k \leq -0.1 \lor \neg \left(k \leq 0.1\right):\\
\;\;\;\;\frac{a}{k \cdot 10}\\
\mathbf{else}:\\
\;\;\;\;a\\
\end{array}
\]
Alternative 17 Accuracy 62.3% Cost 585
\[\begin{array}{l}
\mathbf{if}\;k \leq -1 \lor \neg \left(k \leq 1\right):\\
\;\;\;\;\frac{a}{k \cdot k}\\
\mathbf{else}:\\
\;\;\;\;a\\
\end{array}
\]
Alternative 18 Accuracy 63.0% Cost 584
\[\begin{array}{l}
\mathbf{if}\;k \leq 2 \cdot 10^{+37}:\\
\;\;\;\;\frac{a}{1 + k \cdot k}\\
\mathbf{elif}\;k \leq 1.1 \cdot 10^{+206}:\\
\;\;\;\;\frac{\frac{a}{k}}{k}\\
\mathbf{else}:\\
\;\;\;\;\frac{a}{k \cdot k}\\
\end{array}
\]
Alternative 19 Accuracy 26.7% Cost 64
\[a
\]