Math FPCore C Java Python Julia MATLAB Wolfram TeX \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}
\]
↓
\[\begin{array}{l}
t_0 := \frac{-c}{b}\\
t_1 := \frac{\sqrt{b \cdot b + c \cdot \left(a \cdot -4\right)} - b}{a \cdot 2}\\
\mathbf{if}\;t_1 \leq -\infty:\\
\;\;\;\;t_0\\
\mathbf{elif}\;t_1 \leq -1 \cdot 10^{-258}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t_1 \leq 0:\\
\;\;\;\;t_0\\
\mathbf{elif}\;t_1 \leq 5 \cdot 10^{+266}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t_1 \leq \infty:\\
\;\;\;\;\frac{0.5}{\frac{a}{\mathsf{hypot}\left(b, \sqrt{c \cdot -4} \cdot \sqrt{a}\right) - b}}\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
(FPCore (a b c)
:precision binary64
(/ (+ (- b) (sqrt (- (* b b) (* (* 4.0 a) c)))) (* 2.0 a))) ↓
(FPCore (a b c)
:precision binary64
(let* ((t_0 (/ (- c) b))
(t_1 (/ (- (sqrt (+ (* b b) (* c (* a -4.0)))) b) (* a 2.0))))
(if (<= t_1 (- INFINITY))
t_0
(if (<= t_1 -1e-258)
t_1
(if (<= t_1 0.0)
t_0
(if (<= t_1 5e+266)
t_1
(if (<= t_1 INFINITY)
(/ 0.5 (/ a (- (hypot b (* (sqrt (* c -4.0)) (sqrt a))) b)))
t_0))))))) double code(double a, double b, double c) {
return (-b + sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a);
}
↓
double code(double a, double b, double c) {
double t_0 = -c / b;
double t_1 = (sqrt(((b * b) + (c * (a * -4.0)))) - b) / (a * 2.0);
double tmp;
if (t_1 <= -((double) INFINITY)) {
tmp = t_0;
} else if (t_1 <= -1e-258) {
tmp = t_1;
} else if (t_1 <= 0.0) {
tmp = t_0;
} else if (t_1 <= 5e+266) {
tmp = t_1;
} else if (t_1 <= ((double) INFINITY)) {
tmp = 0.5 / (a / (hypot(b, (sqrt((c * -4.0)) * sqrt(a))) - b));
} else {
tmp = t_0;
}
return tmp;
}
public static double code(double a, double b, double c) {
return (-b + Math.sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a);
}
↓
public static double code(double a, double b, double c) {
double t_0 = -c / b;
double t_1 = (Math.sqrt(((b * b) + (c * (a * -4.0)))) - b) / (a * 2.0);
double tmp;
if (t_1 <= -Double.POSITIVE_INFINITY) {
tmp = t_0;
} else if (t_1 <= -1e-258) {
tmp = t_1;
} else if (t_1 <= 0.0) {
tmp = t_0;
} else if (t_1 <= 5e+266) {
tmp = t_1;
} else if (t_1 <= Double.POSITIVE_INFINITY) {
tmp = 0.5 / (a / (Math.hypot(b, (Math.sqrt((c * -4.0)) * Math.sqrt(a))) - b));
} else {
tmp = t_0;
}
return tmp;
}
def code(a, b, c):
return (-b + math.sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a)
↓
def code(a, b, c):
t_0 = -c / b
t_1 = (math.sqrt(((b * b) + (c * (a * -4.0)))) - b) / (a * 2.0)
tmp = 0
if t_1 <= -math.inf:
tmp = t_0
elif t_1 <= -1e-258:
tmp = t_1
elif t_1 <= 0.0:
tmp = t_0
elif t_1 <= 5e+266:
tmp = t_1
elif t_1 <= math.inf:
tmp = 0.5 / (a / (math.hypot(b, (math.sqrt((c * -4.0)) * math.sqrt(a))) - b))
else:
tmp = t_0
return tmp
function code(a, b, c)
return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(4.0 * a) * c)))) / Float64(2.0 * a))
end
↓
function code(a, b, c)
t_0 = Float64(Float64(-c) / b)
t_1 = Float64(Float64(sqrt(Float64(Float64(b * b) + Float64(c * Float64(a * -4.0)))) - b) / Float64(a * 2.0))
tmp = 0.0
if (t_1 <= Float64(-Inf))
tmp = t_0;
elseif (t_1 <= -1e-258)
tmp = t_1;
elseif (t_1 <= 0.0)
tmp = t_0;
elseif (t_1 <= 5e+266)
tmp = t_1;
elseif (t_1 <= Inf)
tmp = Float64(0.5 / Float64(a / Float64(hypot(b, Float64(sqrt(Float64(c * -4.0)) * sqrt(a))) - b)));
else
tmp = t_0;
end
return tmp
end
function tmp = code(a, b, c)
tmp = (-b + sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a);
end
↓
function tmp_2 = code(a, b, c)
t_0 = -c / b;
t_1 = (sqrt(((b * b) + (c * (a * -4.0)))) - b) / (a * 2.0);
tmp = 0.0;
if (t_1 <= -Inf)
tmp = t_0;
elseif (t_1 <= -1e-258)
tmp = t_1;
elseif (t_1 <= 0.0)
tmp = t_0;
elseif (t_1 <= 5e+266)
tmp = t_1;
elseif (t_1 <= Inf)
tmp = 0.5 / (a / (hypot(b, (sqrt((c * -4.0)) * sqrt(a))) - b));
else
tmp = t_0;
end
tmp_2 = tmp;
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(4.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]
↓
code[a_, b_, c_] := Block[{t$95$0 = N[((-c) / b), $MachinePrecision]}, Block[{t$95$1 = N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] + N[(c * N[(a * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, (-Infinity)], t$95$0, If[LessEqual[t$95$1, -1e-258], t$95$1, If[LessEqual[t$95$1, 0.0], t$95$0, If[LessEqual[t$95$1, 5e+266], t$95$1, If[LessEqual[t$95$1, Infinity], N[(0.5 / N[(a / N[(N[Sqrt[b ^ 2 + N[(N[Sqrt[N[(c * -4.0), $MachinePrecision]], $MachinePrecision] * N[Sqrt[a], $MachinePrecision]), $MachinePrecision] ^ 2], $MachinePrecision] - b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$0]]]]]]]
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}
↓
\begin{array}{l}
t_0 := \frac{-c}{b}\\
t_1 := \frac{\sqrt{b \cdot b + c \cdot \left(a \cdot -4\right)} - b}{a \cdot 2}\\
\mathbf{if}\;t_1 \leq -\infty:\\
\;\;\;\;t_0\\
\mathbf{elif}\;t_1 \leq -1 \cdot 10^{-258}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t_1 \leq 0:\\
\;\;\;\;t_0\\
\mathbf{elif}\;t_1 \leq 5 \cdot 10^{+266}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t_1 \leq \infty:\\
\;\;\;\;\frac{0.5}{\frac{a}{\mathsf{hypot}\left(b, \sqrt{c \cdot -4} \cdot \sqrt{a}\right) - b}}\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
Alternatives Alternative 1 Accuracy 84.0% Cost 7624
\[\begin{array}{l}
\mathbf{if}\;b \leq -5.7 \cdot 10^{+57}:\\
\;\;\;\;\frac{c}{b} - \frac{b}{a}\\
\mathbf{elif}\;b \leq 8.8 \cdot 10^{-67}:\\
\;\;\;\;\left(\sqrt{b \cdot b + a \cdot \left(c \cdot -4\right)} - b\right) \cdot \frac{0.5}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{-c}{b}\\
\end{array}
\]
Alternative 2 Accuracy 84.0% Cost 7624
\[\begin{array}{l}
\mathbf{if}\;b \leq -2.8 \cdot 10^{+57}:\\
\;\;\;\;\frac{c}{b} - \frac{b}{a}\\
\mathbf{elif}\;b \leq 9 \cdot 10^{-67}:\\
\;\;\;\;\frac{\sqrt{b \cdot b + c \cdot \left(a \cdot -4\right)} - b}{a \cdot 2}\\
\mathbf{else}:\\
\;\;\;\;\frac{-c}{b}\\
\end{array}
\]
Alternative 3 Accuracy 79.0% Cost 7368
\[\begin{array}{l}
\mathbf{if}\;b \leq -3.8 \cdot 10^{-42}:\\
\;\;\;\;\frac{c}{b} - \frac{b}{a}\\
\mathbf{elif}\;b \leq 9 \cdot 10^{-67}:\\
\;\;\;\;\frac{0.5}{a} \cdot \left(\sqrt{c \cdot \left(a \cdot -4\right)} - b\right)\\
\mathbf{else}:\\
\;\;\;\;\frac{-c}{b}\\
\end{array}
\]
Alternative 4 Accuracy 79.0% Cost 7368
\[\begin{array}{l}
\mathbf{if}\;b \leq -1.06 \cdot 10^{-41}:\\
\;\;\;\;\frac{c}{b} - \frac{b}{a}\\
\mathbf{elif}\;b \leq 5 \cdot 10^{-67}:\\
\;\;\;\;\frac{\sqrt{c \cdot \left(a \cdot -4\right)} - b}{a \cdot 2}\\
\mathbf{else}:\\
\;\;\;\;\frac{-c}{b}\\
\end{array}
\]
Alternative 5 Accuracy 65.7% Cost 580
\[\begin{array}{l}
\mathbf{if}\;b \leq -4.1 \cdot 10^{-300}:\\
\;\;\;\;\frac{c}{b} - \frac{b}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{-c}{b}\\
\end{array}
\]
Alternative 6 Accuracy 38.9% Cost 388
\[\begin{array}{l}
\mathbf{if}\;b \leq -5 \cdot 10^{-310}:\\
\;\;\;\;\frac{-b}{a}\\
\mathbf{else}:\\
\;\;\;\;0\\
\end{array}
\]
Alternative 7 Accuracy 65.5% Cost 388
\[\begin{array}{l}
\mathbf{if}\;b \leq 7.1 \cdot 10^{-202}:\\
\;\;\;\;\frac{-b}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{-c}{b}\\
\end{array}
\]
Alternative 8 Accuracy 11.8% Cost 64
\[0
\]