\[ \begin{array}{c}[a, b] = \mathsf{sort}([a, b])\\ \end{array} \]
Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\log \left(e^{a} + e^{b}\right)
\]
↓
\[\begin{array}{l}
\mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\
\;\;\;\;\frac{b}{e^{a} + 1}\\
\mathbf{else}:\\
\;\;\;\;\log \left(e^{a} + e^{b}\right)\\
\end{array}
\]
(FPCore (a b) :precision binary64 (log (+ (exp a) (exp b)))) ↓
(FPCore (a b)
:precision binary64
(if (<= (exp a) 2e-322) (/ b (+ (exp a) 1.0)) (log (+ (exp a) (exp b))))) double code(double a, double b) {
return log((exp(a) + exp(b)));
}
↓
double code(double a, double b) {
double tmp;
if (exp(a) <= 2e-322) {
tmp = b / (exp(a) + 1.0);
} else {
tmp = log((exp(a) + exp(b)));
}
return tmp;
}
real(8) function code(a, b)
real(8), intent (in) :: a
real(8), intent (in) :: b
code = log((exp(a) + exp(b)))
end function
↓
real(8) function code(a, b)
real(8), intent (in) :: a
real(8), intent (in) :: b
real(8) :: tmp
if (exp(a) <= 2d-322) then
tmp = b / (exp(a) + 1.0d0)
else
tmp = log((exp(a) + exp(b)))
end if
code = tmp
end function
public static double code(double a, double b) {
return Math.log((Math.exp(a) + Math.exp(b)));
}
↓
public static double code(double a, double b) {
double tmp;
if (Math.exp(a) <= 2e-322) {
tmp = b / (Math.exp(a) + 1.0);
} else {
tmp = Math.log((Math.exp(a) + Math.exp(b)));
}
return tmp;
}
def code(a, b):
return math.log((math.exp(a) + math.exp(b)))
↓
def code(a, b):
tmp = 0
if math.exp(a) <= 2e-322:
tmp = b / (math.exp(a) + 1.0)
else:
tmp = math.log((math.exp(a) + math.exp(b)))
return tmp
function code(a, b)
return log(Float64(exp(a) + exp(b)))
end
↓
function code(a, b)
tmp = 0.0
if (exp(a) <= 2e-322)
tmp = Float64(b / Float64(exp(a) + 1.0));
else
tmp = log(Float64(exp(a) + exp(b)));
end
return tmp
end
function tmp = code(a, b)
tmp = log((exp(a) + exp(b)));
end
↓
function tmp_2 = code(a, b)
tmp = 0.0;
if (exp(a) <= 2e-322)
tmp = b / (exp(a) + 1.0);
else
tmp = log((exp(a) + exp(b)));
end
tmp_2 = tmp;
end
code[a_, b_] := N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
↓
code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 2e-322], N[(b / N[(N[Exp[a], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
\log \left(e^{a} + e^{b}\right)
↓
\begin{array}{l}
\mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\
\;\;\;\;\frac{b}{e^{a} + 1}\\
\mathbf{else}:\\
\;\;\;\;\log \left(e^{a} + e^{b}\right)\\
\end{array}
Alternatives Alternative 1 Accuracy 97.2% Cost 26056
\[\begin{array}{l}
t_0 := e^{a} + 1\\
\mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\
\;\;\;\;\frac{b}{t_0}\\
\mathbf{elif}\;e^{a} \leq 1:\\
\;\;\;\;\log t_0\\
\mathbf{else}:\\
\;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\
\end{array}
\]
Alternative 2 Accuracy 97.5% Cost 25928
\[\begin{array}{l}
\mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\
\;\;\;\;\frac{b}{e^{a} + 1}\\
\mathbf{elif}\;e^{a} \leq 1:\\
\;\;\;\;\mathsf{log1p}\left(e^{a}\right)\\
\mathbf{else}:\\
\;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\
\end{array}
\]
Alternative 3 Accuracy 97.5% Cost 19396
\[\begin{array}{l}
\mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\
\;\;\;\;\frac{b}{e^{a} + 1}\\
\mathbf{else}:\\
\;\;\;\;\mathsf{log1p}\left(e^{a}\right)\\
\end{array}
\]
Alternative 4 Accuracy 97.6% Cost 19392
\[\mathsf{log1p}\left(e^{a} + \mathsf{expm1}\left(b\right)\right)
\]
Alternative 5 Accuracy 97.2% Cost 13508
\[\begin{array}{l}
\mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\
\;\;\;\;\frac{b}{e^{a} + 1}\\
\mathbf{else}:\\
\;\;\;\;a \cdot 0.5 + \left(b \cdot 0.5 + \log 2\right)\\
\end{array}
\]
Alternative 6 Accuracy 96.5% Cost 13376
\[\mathsf{log1p}\left(e^{a} + \left(b + 0.5 \cdot \left(b \cdot b\right)\right)\right)
\]
Alternative 7 Accuracy 97.1% Cost 13252
\[\begin{array}{l}
\mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\
\;\;\;\;\frac{b}{e^{a} + 1}\\
\mathbf{else}:\\
\;\;\;\;\log \left(b + \left(a + 2\right)\right)\\
\end{array}
\]
Alternative 8 Accuracy 95.8% Cost 12992
\[\mathsf{log1p}\left(e^{a} + b\right)
\]
Alternative 9 Accuracy 49.1% Cost 6856
\[\begin{array}{l}
\mathbf{if}\;a \leq -1:\\
\;\;\;\;b \cdot \left(0.5 + a \cdot -0.25\right)\\
\mathbf{elif}\;a \leq -2 \cdot 10^{-16}:\\
\;\;\;\;\log \left(a + 2\right)\\
\mathbf{else}:\\
\;\;\;\;\log \left(b + 2\right)\\
\end{array}
\]
Alternative 10 Accuracy 49.1% Cost 6852
\[\begin{array}{l}
\mathbf{if}\;a \leq -1:\\
\;\;\;\;b \cdot \left(0.5 + a \cdot -0.25\right)\\
\mathbf{else}:\\
\;\;\;\;\log \left(b + \left(a + 2\right)\right)\\
\end{array}
\]
Alternative 11 Accuracy 48.5% Cost 6724
\[\begin{array}{l}
\mathbf{if}\;a \leq -1:\\
\;\;\;\;b \cdot \left(0.5 + a \cdot -0.25\right)\\
\mathbf{else}:\\
\;\;\;\;\log \left(a + 2\right)\\
\end{array}
\]
Alternative 12 Accuracy 48.2% Cost 6720
\[b \cdot 0.5 + \log 2
\]
Alternative 13 Accuracy 47.3% Cost 6464
\[\log 2
\]
Alternative 14 Accuracy 5.4% Cost 448
\[b \cdot \left(0.5 + a \cdot -0.25\right)
\]
Alternative 15 Accuracy 2.6% Cost 192
\[a \cdot 0.5
\]