?

Average Accuracy: 52.3% → 98.5%
Time: 18.1s
Precision: binary64
Cost: 25924

?

\[ \begin{array}{c}[a, b] = \mathsf{sort}([a, b])\\ \end{array} \]
\[\log \left(e^{a} + e^{b}\right) \]
\[\begin{array}{l} \mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\log \left(e^{a} + e^{b}\right)\\ \end{array} \]
(FPCore (a b) :precision binary64 (log (+ (exp a) (exp b))))
(FPCore (a b)
 :precision binary64
 (if (<= (exp a) 2e-322) (/ b (+ (exp a) 1.0)) (log (+ (exp a) (exp b)))))
double code(double a, double b) {
	return log((exp(a) + exp(b)));
}
double code(double a, double b) {
	double tmp;
	if (exp(a) <= 2e-322) {
		tmp = b / (exp(a) + 1.0);
	} else {
		tmp = log((exp(a) + exp(b)));
	}
	return tmp;
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = log((exp(a) + exp(b)))
end function
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if (exp(a) <= 2d-322) then
        tmp = b / (exp(a) + 1.0d0)
    else
        tmp = log((exp(a) + exp(b)))
    end if
    code = tmp
end function
public static double code(double a, double b) {
	return Math.log((Math.exp(a) + Math.exp(b)));
}
public static double code(double a, double b) {
	double tmp;
	if (Math.exp(a) <= 2e-322) {
		tmp = b / (Math.exp(a) + 1.0);
	} else {
		tmp = Math.log((Math.exp(a) + Math.exp(b)));
	}
	return tmp;
}
def code(a, b):
	return math.log((math.exp(a) + math.exp(b)))
def code(a, b):
	tmp = 0
	if math.exp(a) <= 2e-322:
		tmp = b / (math.exp(a) + 1.0)
	else:
		tmp = math.log((math.exp(a) + math.exp(b)))
	return tmp
function code(a, b)
	return log(Float64(exp(a) + exp(b)))
end
function code(a, b)
	tmp = 0.0
	if (exp(a) <= 2e-322)
		tmp = Float64(b / Float64(exp(a) + 1.0));
	else
		tmp = log(Float64(exp(a) + exp(b)));
	end
	return tmp
end
function tmp = code(a, b)
	tmp = log((exp(a) + exp(b)));
end
function tmp_2 = code(a, b)
	tmp = 0.0;
	if (exp(a) <= 2e-322)
		tmp = b / (exp(a) + 1.0);
	else
		tmp = log((exp(a) + exp(b)));
	end
	tmp_2 = tmp;
end
code[a_, b_] := N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 2e-322], N[(b / N[(N[Exp[a], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
\log \left(e^{a} + e^{b}\right)
\begin{array}{l}
\mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\
\;\;\;\;\frac{b}{e^{a} + 1}\\

\mathbf{else}:\\
\;\;\;\;\log \left(e^{a} + e^{b}\right)\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Split input into 2 regimes
  2. if (exp.f64 a) < 1.97626e-322

    1. Initial program 8.9%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Taylor expanded in b around 0 7.2%

      \[\leadsto \log \color{blue}{\left(1 + \left(e^{a} + b\right)\right)} \]
    3. Simplified7.2%

      \[\leadsto \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
      Proof

      [Start]7.2

      \[ \log \left(1 + \left(e^{a} + b\right)\right) \]

      associate-+r+ [=>]7.2

      \[ \log \color{blue}{\left(\left(1 + e^{a}\right) + b\right)} \]

      +-commutative [=>]7.2

      \[ \log \left(\color{blue}{\left(e^{a} + 1\right)} + b\right) \]

      associate-+l+ [=>]7.2

      \[ \log \color{blue}{\left(e^{a} + \left(1 + b\right)\right)} \]
    4. Taylor expanded in b around 0 100.0%

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    5. Simplified100.0%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right) + \frac{b}{2 + \mathsf{expm1}\left(a\right)}} \]
      Proof

      [Start]100.0

      \[ \log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}} \]

      log1p-def [=>]100.0

      \[ \color{blue}{\mathsf{log1p}\left(e^{a}\right)} + \frac{b}{1 + e^{a}} \]

      +-commutative [<=]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{\color{blue}{e^{a} + 1}} \]

      +-commutative [=>]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{\color{blue}{1 + e^{a}}} \]

      metadata-eval [<=]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{\color{blue}{\left(2 - 1\right)} + e^{a}} \]

      associate--r- [<=]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{\color{blue}{2 - \left(1 - e^{a}\right)}} \]

      metadata-eval [<=]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{\color{blue}{\left(2 + 0\right)} - \left(1 - e^{a}\right)} \]

      associate-+r- [<=]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{\color{blue}{2 + \left(0 - \left(1 - e^{a}\right)\right)}} \]

      associate--r- [=>]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{2 + \color{blue}{\left(\left(0 - 1\right) + e^{a}\right)}} \]

      metadata-eval [=>]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{2 + \left(\color{blue}{-1} + e^{a}\right)} \]

      +-commutative [<=]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{2 + \color{blue}{\left(e^{a} + -1\right)}} \]

      metadata-eval [<=]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{2 + \left(e^{a} + \color{blue}{\left(-1\right)}\right)} \]

      sub-neg [<=]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{2 + \color{blue}{\left(e^{a} - 1\right)}} \]

      expm1-def [=>]100.0

      \[ \mathsf{log1p}\left(e^{a}\right) + \frac{b}{2 + \color{blue}{\mathsf{expm1}\left(a\right)}} \]
    6. Taylor expanded in b around inf 100.0%

      \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} \]

    if 1.97626e-322 < (exp.f64 a)

    1. Initial program 96.9%

      \[\log \left(e^{a} + e^{b}\right) \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\log \left(e^{a} + e^{b}\right)\\ \end{array} \]

Alternatives

Alternative 1
Accuracy97.2%
Cost26056
\[\begin{array}{l} t_0 := e^{a} + 1\\ \mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\ \;\;\;\;\frac{b}{t_0}\\ \mathbf{elif}\;e^{a} \leq 1:\\ \;\;\;\;\log t_0\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\ \end{array} \]
Alternative 2
Accuracy97.5%
Cost25928
\[\begin{array}{l} \mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{elif}\;e^{a} \leq 1:\\ \;\;\;\;\mathsf{log1p}\left(e^{a}\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\ \end{array} \]
Alternative 3
Accuracy97.5%
Cost19396
\[\begin{array}{l} \mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{a}\right)\\ \end{array} \]
Alternative 4
Accuracy97.6%
Cost19392
\[\mathsf{log1p}\left(e^{a} + \mathsf{expm1}\left(b\right)\right) \]
Alternative 5
Accuracy97.2%
Cost13508
\[\begin{array}{l} \mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;a \cdot 0.5 + \left(b \cdot 0.5 + \log 2\right)\\ \end{array} \]
Alternative 6
Accuracy96.5%
Cost13376
\[\mathsf{log1p}\left(e^{a} + \left(b + 0.5 \cdot \left(b \cdot b\right)\right)\right) \]
Alternative 7
Accuracy97.1%
Cost13252
\[\begin{array}{l} \mathbf{if}\;e^{a} \leq 2 \cdot 10^{-322}:\\ \;\;\;\;\frac{b}{e^{a} + 1}\\ \mathbf{else}:\\ \;\;\;\;\log \left(b + \left(a + 2\right)\right)\\ \end{array} \]
Alternative 8
Accuracy95.8%
Cost12992
\[\mathsf{log1p}\left(e^{a} + b\right) \]
Alternative 9
Accuracy49.1%
Cost6856
\[\begin{array}{l} \mathbf{if}\;a \leq -1:\\ \;\;\;\;b \cdot \left(0.5 + a \cdot -0.25\right)\\ \mathbf{elif}\;a \leq -2 \cdot 10^{-16}:\\ \;\;\;\;\log \left(a + 2\right)\\ \mathbf{else}:\\ \;\;\;\;\log \left(b + 2\right)\\ \end{array} \]
Alternative 10
Accuracy49.1%
Cost6852
\[\begin{array}{l} \mathbf{if}\;a \leq -1:\\ \;\;\;\;b \cdot \left(0.5 + a \cdot -0.25\right)\\ \mathbf{else}:\\ \;\;\;\;\log \left(b + \left(a + 2\right)\right)\\ \end{array} \]
Alternative 11
Accuracy48.5%
Cost6724
\[\begin{array}{l} \mathbf{if}\;a \leq -1:\\ \;\;\;\;b \cdot \left(0.5 + a \cdot -0.25\right)\\ \mathbf{else}:\\ \;\;\;\;\log \left(a + 2\right)\\ \end{array} \]
Alternative 12
Accuracy48.2%
Cost6720
\[b \cdot 0.5 + \log 2 \]
Alternative 13
Accuracy47.3%
Cost6464
\[\log 2 \]
Alternative 14
Accuracy5.4%
Cost448
\[b \cdot \left(0.5 + a \cdot -0.25\right) \]
Alternative 15
Accuracy2.6%
Cost192
\[a \cdot 0.5 \]

Error

Reproduce?

herbie shell --seed 2023135 
(FPCore (a b)
  :name "symmetry log of sum of exp"
  :precision binary64
  (log (+ (exp a) (exp b))))