?

Average Accuracy: 100.0% → 100.0%
Time: 3.4s
Precision: binary64
Cost: 576

?

\[\left(\frac{x}{2} + y \cdot x\right) + z \]
\[\left(\frac{x}{2} + x \cdot y\right) + z \]
(FPCore (x y z) :precision binary64 (+ (+ (/ x 2.0) (* y x)) z))
(FPCore (x y z) :precision binary64 (+ (+ (/ x 2.0) (* x y)) z))
double code(double x, double y, double z) {
	return ((x / 2.0) + (y * x)) + z;
}
double code(double x, double y, double z) {
	return ((x / 2.0) + (x * y)) + z;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = ((x / 2.0d0) + (y * x)) + z
end function
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = ((x / 2.0d0) + (x * y)) + z
end function
public static double code(double x, double y, double z) {
	return ((x / 2.0) + (y * x)) + z;
}
public static double code(double x, double y, double z) {
	return ((x / 2.0) + (x * y)) + z;
}
def code(x, y, z):
	return ((x / 2.0) + (y * x)) + z
def code(x, y, z):
	return ((x / 2.0) + (x * y)) + z
function code(x, y, z)
	return Float64(Float64(Float64(x / 2.0) + Float64(y * x)) + z)
end
function code(x, y, z)
	return Float64(Float64(Float64(x / 2.0) + Float64(x * y)) + z)
end
function tmp = code(x, y, z)
	tmp = ((x / 2.0) + (y * x)) + z;
end
function tmp = code(x, y, z)
	tmp = ((x / 2.0) + (x * y)) + z;
end
code[x_, y_, z_] := N[(N[(N[(x / 2.0), $MachinePrecision] + N[(y * x), $MachinePrecision]), $MachinePrecision] + z), $MachinePrecision]
code[x_, y_, z_] := N[(N[(N[(x / 2.0), $MachinePrecision] + N[(x * y), $MachinePrecision]), $MachinePrecision] + z), $MachinePrecision]
\left(\frac{x}{2} + y \cdot x\right) + z
\left(\frac{x}{2} + x \cdot y\right) + z

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Initial program 100.0%

    \[\left(\frac{x}{2} + y \cdot x\right) + z \]
  2. Final simplification100.0%

    \[\leadsto \left(\frac{x}{2} + x \cdot y\right) + z \]

Alternatives

Alternative 1
Accuracy98.3%
Cost844
\[\begin{array}{l} t_0 := x \cdot y + z\\ \mathbf{if}\;y \leq -255:\\ \;\;\;\;t_0\\ \mathbf{elif}\;y \leq 2.3 \cdot 10^{-9}:\\ \;\;\;\;z + x \cdot 0.5\\ \mathbf{elif}\;y \leq 2.1 \cdot 10^{+14}:\\ \;\;\;\;x \cdot y + x \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 2
Accuracy57.2%
Cost720
\[\begin{array}{l} \mathbf{if}\;z \leq -4.1 \cdot 10^{-50}:\\ \;\;\;\;z\\ \mathbf{elif}\;z \leq -1.5 \cdot 10^{-195}:\\ \;\;\;\;x \cdot 0.5\\ \mathbf{elif}\;z \leq -9.5 \cdot 10^{-250}:\\ \;\;\;\;x \cdot y\\ \mathbf{elif}\;z \leq 8.2 \cdot 10^{-24}:\\ \;\;\;\;x \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;z\\ \end{array} \]
Alternative 3
Accuracy98.3%
Cost716
\[\begin{array}{l} t_0 := x \cdot y + z\\ \mathbf{if}\;y \leq -255:\\ \;\;\;\;t_0\\ \mathbf{elif}\;y \leq 2.3 \cdot 10^{-9}:\\ \;\;\;\;z + x \cdot 0.5\\ \mathbf{elif}\;y \leq 2.1 \cdot 10^{+14}:\\ \;\;\;\;x \cdot \left(y + 0.5\right)\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 4
Accuracy83.1%
Cost585
\[\begin{array}{l} \mathbf{if}\;z \leq -2 \cdot 10^{-48} \lor \neg \left(z \leq 5.8 \cdot 10^{-93}\right):\\ \;\;\;\;z + x \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y + 0.5\right)\\ \end{array} \]
Alternative 5
Accuracy75.1%
Cost584
\[\begin{array}{l} \mathbf{if}\;z \leq -6 \cdot 10^{-33}:\\ \;\;\;\;z\\ \mathbf{elif}\;z \leq 4.6 \cdot 10^{+26}:\\ \;\;\;\;x \cdot \left(y + 0.5\right)\\ \mathbf{else}:\\ \;\;\;\;z\\ \end{array} \]
Alternative 6
Accuracy57.5%
Cost456
\[\begin{array}{l} \mathbf{if}\;z \leq -3.5 \cdot 10^{-53}:\\ \;\;\;\;z\\ \mathbf{elif}\;z \leq 2.2 \cdot 10^{-24}:\\ \;\;\;\;x \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;z\\ \end{array} \]
Alternative 7
Accuracy100.0%
Cost448
\[z + x \cdot \left(y + 0.5\right) \]
Alternative 8
Accuracy45.1%
Cost64
\[z \]

Error

Reproduce?

herbie shell --seed 2023135 
(FPCore (x y z)
  :name "Data.Histogram.Bin.BinF:$cfromIndex from histogram-fill-0.8.4.1"
  :precision binary64
  (+ (+ (/ x 2.0) (* y x)) z))