?

Average Accuracy: 89.2% → 97.2%
Time: 12.2s
Precision: binary64
Cost: 1737

?

\[\frac{x \cdot 2}{y \cdot z - t \cdot z} \]
\[\begin{array}{l} t_1 := y \cdot z - z \cdot t\\ \mathbf{if}\;t_1 \leq -5 \cdot 10^{+93} \lor \neg \left(t_1 \leq 2 \cdot 10^{+250}\right):\\ \;\;\;\;\frac{\frac{x \cdot 2}{z}}{y - t}\\ \mathbf{else}:\\ \;\;\;\;\frac{x \cdot 2}{t_1}\\ \end{array} \]
(FPCore (x y z t) :precision binary64 (/ (* x 2.0) (- (* y z) (* t z))))
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (- (* y z) (* z t))))
   (if (or (<= t_1 -5e+93) (not (<= t_1 2e+250)))
     (/ (/ (* x 2.0) z) (- y t))
     (/ (* x 2.0) t_1))))
double code(double x, double y, double z, double t) {
	return (x * 2.0) / ((y * z) - (t * z));
}
double code(double x, double y, double z, double t) {
	double t_1 = (y * z) - (z * t);
	double tmp;
	if ((t_1 <= -5e+93) || !(t_1 <= 2e+250)) {
		tmp = ((x * 2.0) / z) / (y - t);
	} else {
		tmp = (x * 2.0) / t_1;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (x * 2.0d0) / ((y * z) - (t * z))
end function
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: tmp
    t_1 = (y * z) - (z * t)
    if ((t_1 <= (-5d+93)) .or. (.not. (t_1 <= 2d+250))) then
        tmp = ((x * 2.0d0) / z) / (y - t)
    else
        tmp = (x * 2.0d0) / t_1
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	return (x * 2.0) / ((y * z) - (t * z));
}
public static double code(double x, double y, double z, double t) {
	double t_1 = (y * z) - (z * t);
	double tmp;
	if ((t_1 <= -5e+93) || !(t_1 <= 2e+250)) {
		tmp = ((x * 2.0) / z) / (y - t);
	} else {
		tmp = (x * 2.0) / t_1;
	}
	return tmp;
}
def code(x, y, z, t):
	return (x * 2.0) / ((y * z) - (t * z))
def code(x, y, z, t):
	t_1 = (y * z) - (z * t)
	tmp = 0
	if (t_1 <= -5e+93) or not (t_1 <= 2e+250):
		tmp = ((x * 2.0) / z) / (y - t)
	else:
		tmp = (x * 2.0) / t_1
	return tmp
function code(x, y, z, t)
	return Float64(Float64(x * 2.0) / Float64(Float64(y * z) - Float64(t * z)))
end
function code(x, y, z, t)
	t_1 = Float64(Float64(y * z) - Float64(z * t))
	tmp = 0.0
	if ((t_1 <= -5e+93) || !(t_1 <= 2e+250))
		tmp = Float64(Float64(Float64(x * 2.0) / z) / Float64(y - t));
	else
		tmp = Float64(Float64(x * 2.0) / t_1);
	end
	return tmp
end
function tmp = code(x, y, z, t)
	tmp = (x * 2.0) / ((y * z) - (t * z));
end
function tmp_2 = code(x, y, z, t)
	t_1 = (y * z) - (z * t);
	tmp = 0.0;
	if ((t_1 <= -5e+93) || ~((t_1 <= 2e+250)))
		tmp = ((x * 2.0) / z) / (y - t);
	else
		tmp = (x * 2.0) / t_1;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := N[(N[(x * 2.0), $MachinePrecision] / N[(N[(y * z), $MachinePrecision] - N[(t * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(y * z), $MachinePrecision] - N[(z * t), $MachinePrecision]), $MachinePrecision]}, If[Or[LessEqual[t$95$1, -5e+93], N[Not[LessEqual[t$95$1, 2e+250]], $MachinePrecision]], N[(N[(N[(x * 2.0), $MachinePrecision] / z), $MachinePrecision] / N[(y - t), $MachinePrecision]), $MachinePrecision], N[(N[(x * 2.0), $MachinePrecision] / t$95$1), $MachinePrecision]]]
\frac{x \cdot 2}{y \cdot z - t \cdot z}
\begin{array}{l}
t_1 := y \cdot z - z \cdot t\\
\mathbf{if}\;t_1 \leq -5 \cdot 10^{+93} \lor \neg \left(t_1 \leq 2 \cdot 10^{+250}\right):\\
\;\;\;\;\frac{\frac{x \cdot 2}{z}}{y - t}\\

\mathbf{else}:\\
\;\;\;\;\frac{x \cdot 2}{t_1}\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original89.2%
Target96.5%
Herbie97.2%
\[\begin{array}{l} \mathbf{if}\;\frac{x \cdot 2}{y \cdot z - t \cdot z} < -2.559141628295061 \cdot 10^{-13}:\\ \;\;\;\;\frac{x}{\left(y - t\right) \cdot z} \cdot 2\\ \mathbf{elif}\;\frac{x \cdot 2}{y \cdot z - t \cdot z} < 1.045027827330126 \cdot 10^{-269}:\\ \;\;\;\;\frac{\frac{x}{z} \cdot 2}{y - t}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{\left(y - t\right) \cdot z} \cdot 2\\ \end{array} \]

Derivation?

  1. Split input into 2 regimes
  2. if (-.f64 (*.f64 y z) (*.f64 t z)) < -5.0000000000000001e93 or 1.9999999999999998e250 < (-.f64 (*.f64 y z) (*.f64 t z))

    1. Initial program 79.3%

      \[\frac{x \cdot 2}{y \cdot z - t \cdot z} \]
    2. Simplified97.3%

      \[\leadsto \color{blue}{\frac{\frac{x \cdot 2}{z}}{y - t}} \]
      Proof

      [Start]79.3

      \[ \frac{x \cdot 2}{y \cdot z - t \cdot z} \]

      distribute-rgt-out-- [=>]83.2

      \[ \frac{x \cdot 2}{\color{blue}{z \cdot \left(y - t\right)}} \]

      associate-/r* [=>]97.3

      \[ \color{blue}{\frac{\frac{x \cdot 2}{z}}{y - t}} \]

    if -5.0000000000000001e93 < (-.f64 (*.f64 y z) (*.f64 t z)) < 1.9999999999999998e250

    1. Initial program 97.0%

      \[\frac{x \cdot 2}{y \cdot z - t \cdot z} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification97.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot z - z \cdot t \leq -5 \cdot 10^{+93} \lor \neg \left(y \cdot z - z \cdot t \leq 2 \cdot 10^{+250}\right):\\ \;\;\;\;\frac{\frac{x \cdot 2}{z}}{y - t}\\ \mathbf{else}:\\ \;\;\;\;\frac{x \cdot 2}{y \cdot z - z \cdot t}\\ \end{array} \]

Alternatives

Alternative 1
Accuracy71.9%
Cost978
\[\begin{array}{l} \mathbf{if}\;t \leq -2.9 \cdot 10^{+33} \lor \neg \left(t \leq 1.6 \cdot 10^{-92}\right) \land \left(t \leq 1.1 \cdot 10^{-42} \lor \neg \left(t \leq 4.1 \cdot 10^{+54}\right)\right):\\ \;\;\;\;x \cdot \frac{-2}{z \cdot t}\\ \mathbf{else}:\\ \;\;\;\;x \cdot \frac{2}{y \cdot z}\\ \end{array} \]
Alternative 2
Accuracy72.1%
Cost976
\[\begin{array}{l} t_1 := x \cdot \frac{2}{y \cdot z}\\ t_2 := x \cdot \frac{-2}{z \cdot t}\\ \mathbf{if}\;t \leq -5.5 \cdot 10^{+33}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;t \leq 1.6 \cdot 10^{-92}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;t \leq 1.1 \cdot 10^{-42}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;t \leq 4.5 \cdot 10^{+50}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;x \cdot \frac{\frac{-2}{t}}{z}\\ \end{array} \]
Alternative 3
Accuracy72.2%
Cost976
\[\begin{array}{l} t_1 := x \cdot \frac{2}{y \cdot z}\\ t_2 := x \cdot \frac{-2}{z \cdot t}\\ \mathbf{if}\;t \leq -2.6 \cdot 10^{+33}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;t \leq 1.6 \cdot 10^{-92}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;t \leq 1.45 \cdot 10^{-42}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;t \leq 2.35 \cdot 10^{+48}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{t} \cdot \frac{-2}{z}\\ \end{array} \]
Alternative 4
Accuracy72.4%
Cost976
\[\begin{array}{l} t_1 := x \cdot \frac{-2}{z \cdot t}\\ \mathbf{if}\;t \leq -1.85 \cdot 10^{+33}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;t \leq 1.55 \cdot 10^{-92}:\\ \;\;\;\;\frac{x}{z} \cdot \frac{2}{y}\\ \mathbf{elif}\;t \leq 1.1 \cdot 10^{-42}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;t \leq 8 \cdot 10^{+49}:\\ \;\;\;\;x \cdot \frac{2}{y \cdot z}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{t} \cdot \frac{-2}{z}\\ \end{array} \]
Alternative 5
Accuracy72.2%
Cost976
\[\begin{array}{l} t_1 := x \cdot \frac{-2}{z \cdot t}\\ \mathbf{if}\;t \leq -6 \cdot 10^{+33}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;t \leq 1.6 \cdot 10^{-92}:\\ \;\;\;\;\frac{x}{z} \cdot \frac{2}{y}\\ \mathbf{elif}\;t \leq 5.8 \cdot 10^{-43}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;t \leq 4.1 \cdot 10^{+54}:\\ \;\;\;\;x \cdot \frac{\frac{2}{y}}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{t} \cdot \frac{-2}{z}\\ \end{array} \]
Alternative 6
Accuracy72.2%
Cost976
\[\begin{array}{l} t_1 := x \cdot \frac{-2}{z \cdot t}\\ \mathbf{if}\;t \leq -1.95 \cdot 10^{+33}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;t \leq 2.7 \cdot 10^{-95}:\\ \;\;\;\;\frac{x}{z} \cdot \frac{2}{y}\\ \mathbf{elif}\;t \leq 5.6 \cdot 10^{-43}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;t \leq 4.4 \cdot 10^{+51}:\\ \;\;\;\;\frac{2}{\frac{y \cdot z}{x}}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{t} \cdot \frac{-2}{z}\\ \end{array} \]
Alternative 7
Accuracy72.1%
Cost976
\[\begin{array}{l} t_1 := \frac{\frac{x \cdot -2}{z}}{t}\\ \mathbf{if}\;t \leq -4.5 \cdot 10^{+33}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;t \leq 6.6 \cdot 10^{-93}:\\ \;\;\;\;\frac{x}{z} \cdot \frac{2}{y}\\ \mathbf{elif}\;t \leq 5.6 \cdot 10^{-43}:\\ \;\;\;\;x \cdot \frac{-2}{z \cdot t}\\ \mathbf{elif}\;t \leq 5.5 \cdot 10^{+48}:\\ \;\;\;\;\frac{2}{\frac{y \cdot z}{x}}\\ \mathbf{else}:\\ \;\;\;\;t_1\\ \end{array} \]
Alternative 8
Accuracy96.2%
Cost841
\[\begin{array}{l} \mathbf{if}\;z \leq -1.1 \cdot 10^{+52} \lor \neg \left(z \leq 3.9 \cdot 10^{-44}\right):\\ \;\;\;\;\frac{\frac{x \cdot 2}{z}}{y - t}\\ \mathbf{else}:\\ \;\;\;\;x \cdot \frac{\frac{2}{z}}{y - t}\\ \end{array} \]
Alternative 9
Accuracy90.7%
Cost576
\[x \cdot \frac{2}{z \cdot \left(y - t\right)} \]
Alternative 10
Accuracy91.2%
Cost576
\[x \cdot \frac{\frac{2}{z}}{y - t} \]
Alternative 11
Accuracy51.2%
Cost448
\[x \cdot \frac{-2}{z \cdot t} \]

Error

Reproduce?

herbie shell --seed 2023135 
(FPCore (x y z t)
  :name "Linear.Projection:infinitePerspective from linear-1.19.1.3, A"
  :precision binary64

  :herbie-target
  (if (< (/ (* x 2.0) (- (* y z) (* t z))) -2.559141628295061e-13) (* (/ x (* (- y t) z)) 2.0) (if (< (/ (* x 2.0) (- (* y z) (* t z))) 1.045027827330126e-269) (/ (* (/ x z) 2.0) (- y t)) (* (/ x (* (- y t) z)) 2.0)))

  (/ (* x 2.0) (- (* y z) (* t z))))