Math FPCore C Java Python Julia MATLAB Wolfram TeX \[x \cdot \left(\frac{y}{z} - \frac{t}{1 - z}\right)
\]
↓
\[\begin{array}{l}
t_1 := x \cdot \left(\frac{y}{z} - \frac{t}{1 - z}\right)\\
\mathbf{if}\;t_1 \leq -\infty:\\
\;\;\;\;\frac{x \cdot y}{z}\\
\mathbf{elif}\;t_1 \leq 4 \cdot 10^{+295}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;\frac{y}{\frac{z}{x}} - x \cdot t\\
\end{array}
\]
(FPCore (x y z t) :precision binary64 (* x (- (/ y z) (/ t (- 1.0 z))))) ↓
(FPCore (x y z t)
:precision binary64
(let* ((t_1 (* x (- (/ y z) (/ t (- 1.0 z))))))
(if (<= t_1 (- INFINITY))
(/ (* x y) z)
(if (<= t_1 4e+295) t_1 (- (/ y (/ z x)) (* x t)))))) double code(double x, double y, double z, double t) {
return x * ((y / z) - (t / (1.0 - z)));
}
↓
double code(double x, double y, double z, double t) {
double t_1 = x * ((y / z) - (t / (1.0 - z)));
double tmp;
if (t_1 <= -((double) INFINITY)) {
tmp = (x * y) / z;
} else if (t_1 <= 4e+295) {
tmp = t_1;
} else {
tmp = (y / (z / x)) - (x * t);
}
return tmp;
}
public static double code(double x, double y, double z, double t) {
return x * ((y / z) - (t / (1.0 - z)));
}
↓
public static double code(double x, double y, double z, double t) {
double t_1 = x * ((y / z) - (t / (1.0 - z)));
double tmp;
if (t_1 <= -Double.POSITIVE_INFINITY) {
tmp = (x * y) / z;
} else if (t_1 <= 4e+295) {
tmp = t_1;
} else {
tmp = (y / (z / x)) - (x * t);
}
return tmp;
}
def code(x, y, z, t):
return x * ((y / z) - (t / (1.0 - z)))
↓
def code(x, y, z, t):
t_1 = x * ((y / z) - (t / (1.0 - z)))
tmp = 0
if t_1 <= -math.inf:
tmp = (x * y) / z
elif t_1 <= 4e+295:
tmp = t_1
else:
tmp = (y / (z / x)) - (x * t)
return tmp
function code(x, y, z, t)
return Float64(x * Float64(Float64(y / z) - Float64(t / Float64(1.0 - z))))
end
↓
function code(x, y, z, t)
t_1 = Float64(x * Float64(Float64(y / z) - Float64(t / Float64(1.0 - z))))
tmp = 0.0
if (t_1 <= Float64(-Inf))
tmp = Float64(Float64(x * y) / z);
elseif (t_1 <= 4e+295)
tmp = t_1;
else
tmp = Float64(Float64(y / Float64(z / x)) - Float64(x * t));
end
return tmp
end
function tmp = code(x, y, z, t)
tmp = x * ((y / z) - (t / (1.0 - z)));
end
↓
function tmp_2 = code(x, y, z, t)
t_1 = x * ((y / z) - (t / (1.0 - z)));
tmp = 0.0;
if (t_1 <= -Inf)
tmp = (x * y) / z;
elseif (t_1 <= 4e+295)
tmp = t_1;
else
tmp = (y / (z / x)) - (x * t);
end
tmp_2 = tmp;
end
code[x_, y_, z_, t_] := N[(x * N[(N[(y / z), $MachinePrecision] - N[(t / N[(1.0 - z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(x * N[(N[(y / z), $MachinePrecision] - N[(t / N[(1.0 - z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, (-Infinity)], N[(N[(x * y), $MachinePrecision] / z), $MachinePrecision], If[LessEqual[t$95$1, 4e+295], t$95$1, N[(N[(y / N[(z / x), $MachinePrecision]), $MachinePrecision] - N[(x * t), $MachinePrecision]), $MachinePrecision]]]]
x \cdot \left(\frac{y}{z} - \frac{t}{1 - z}\right)
↓
\begin{array}{l}
t_1 := x \cdot \left(\frac{y}{z} - \frac{t}{1 - z}\right)\\
\mathbf{if}\;t_1 \leq -\infty:\\
\;\;\;\;\frac{x \cdot y}{z}\\
\mathbf{elif}\;t_1 \leq 4 \cdot 10^{+295}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;\frac{y}{\frac{z}{x}} - x \cdot t\\
\end{array}
Alternatives Alternative 1 Accuracy 56.4% Cost 850
\[\begin{array}{l}
\mathbf{if}\;z \leq -6.2 \cdot 10^{+48} \lor \neg \left(z \leq 3.8 \cdot 10^{+34}\right) \land \left(z \leq 1.35 \cdot 10^{+60} \lor \neg \left(z \leq 2.7 \cdot 10^{+125}\right)\right):\\
\;\;\;\;t \cdot \frac{x}{z}\\
\mathbf{else}:\\
\;\;\;\;y \cdot \frac{x}{z}\\
\end{array}
\]
Alternative 2 Accuracy 58.6% Cost 850
\[\begin{array}{l}
\mathbf{if}\;z \leq -4 \cdot 10^{+49} \lor \neg \left(z \leq 7.8 \cdot 10^{+34} \lor \neg \left(z \leq 3.3 \cdot 10^{+72}\right) \land z \leq 3.1 \cdot 10^{+125}\right):\\
\;\;\;\;x \cdot \frac{t}{z}\\
\mathbf{else}:\\
\;\;\;\;y \cdot \frac{x}{z}\\
\end{array}
\]
Alternative 3 Accuracy 58.9% Cost 849
\[\begin{array}{l}
t_1 := x \cdot \frac{t}{z}\\
\mathbf{if}\;z \leq -2.15 \cdot 10^{+49}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;z \leq 6.8 \cdot 10^{+34}:\\
\;\;\;\;y \cdot \frac{x}{z}\\
\mathbf{elif}\;z \leq 4.8 \cdot 10^{+72} \lor \neg \left(z \leq 2.7 \cdot 10^{+125}\right):\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{y}{z}\\
\end{array}
\]
Alternative 4 Accuracy 58.8% Cost 848
\[\begin{array}{l}
t_1 := x \cdot \frac{t}{z}\\
\mathbf{if}\;z \leq -1.75 \cdot 10^{+49}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;z \leq 7 \cdot 10^{+34}:\\
\;\;\;\;y \cdot \frac{x}{z}\\
\mathbf{elif}\;z \leq 3.3 \cdot 10^{+72}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;z \leq 2.7 \cdot 10^{+125}:\\
\;\;\;\;x \cdot \frac{y}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{\frac{z}{t}}\\
\end{array}
\]
Alternative 5 Accuracy 59.2% Cost 848
\[\begin{array}{l}
\mathbf{if}\;z \leq -8.6 \cdot 10^{+48}:\\
\;\;\;\;x \cdot \frac{t}{z}\\
\mathbf{elif}\;z \leq -2.85 \cdot 10^{-285}:\\
\;\;\;\;y \cdot \frac{x}{z}\\
\mathbf{elif}\;z \leq 6.6 \cdot 10^{-100}:\\
\;\;\;\;\frac{x \cdot y}{z}\\
\mathbf{elif}\;z \leq 2.7 \cdot 10^{+125}:\\
\;\;\;\;\frac{x}{\frac{z}{y}}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{\frac{z}{t}}\\
\end{array}
\]
Alternative 6 Accuracy 68.6% Cost 848
\[\begin{array}{l}
t_1 := x \cdot \frac{t}{z}\\
\mathbf{if}\;z \leq -7.2 \cdot 10^{+48}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;z \leq 5.2 \cdot 10^{+35}:\\
\;\;\;\;x \cdot \left(\frac{y}{z} - t\right)\\
\mathbf{elif}\;z \leq 3.1 \cdot 10^{+72}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;z \leq 2.9 \cdot 10^{+125}:\\
\;\;\;\;x \cdot \frac{y}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{\frac{z}{t}}\\
\end{array}
\]
Alternative 7 Accuracy 90.9% Cost 841
\[\begin{array}{l}
\mathbf{if}\;z \leq -1 \lor \neg \left(z \leq 1\right):\\
\;\;\;\;x \cdot \frac{y + t}{z}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{y}{z} - x \cdot t\\
\end{array}
\]
Alternative 8 Accuracy 93.4% Cost 841
\[\begin{array}{l}
\mathbf{if}\;z \leq -1.05 \lor \neg \left(z \leq 1\right):\\
\;\;\;\;x \cdot \frac{y + t}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{y}{\frac{z}{x}} - x \cdot t\\
\end{array}
\]
Alternative 9 Accuracy 90.9% Cost 713
\[\begin{array}{l}
\mathbf{if}\;z \leq -1 \lor \neg \left(z \leq 1\right):\\
\;\;\;\;x \cdot \frac{y + t}{z}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \left(\frac{y}{z} - t\right)\\
\end{array}
\]
Alternative 10 Accuracy 44.6% Cost 585
\[\begin{array}{l}
\mathbf{if}\;z \leq -1 \lor \neg \left(z \leq 1\right):\\
\;\;\;\;t \cdot \frac{x}{z}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \left(-t\right)\\
\end{array}
\]
Alternative 11 Accuracy 20.5% Cost 256
\[x \cdot \left(-t\right)
\]