?

Average Accuracy: 49.4% → 89.4%
Time: 23.8s
Precision: binary64
Cost: 7044

?

\[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
\[\begin{array}{l} \mathbf{if}\;x \leq 8200:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\ \end{array} \]
(FPCore (x n)
 :precision binary64
 (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))
(FPCore (x n)
 :precision binary64
 (if (<= x 8200.0) (/ (log (/ (+ x 1.0) x)) n) (/ (/ (pow x (/ 1.0 n)) x) n)))
double code(double x, double n) {
	return pow((x + 1.0), (1.0 / n)) - pow(x, (1.0 / n));
}
double code(double x, double n) {
	double tmp;
	if (x <= 8200.0) {
		tmp = log(((x + 1.0) / x)) / n;
	} else {
		tmp = (pow(x, (1.0 / n)) / x) / n;
	}
	return tmp;
}
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    code = ((x + 1.0d0) ** (1.0d0 / n)) - (x ** (1.0d0 / n))
end function
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    real(8) :: tmp
    if (x <= 8200.0d0) then
        tmp = log(((x + 1.0d0) / x)) / n
    else
        tmp = ((x ** (1.0d0 / n)) / x) / n
    end if
    code = tmp
end function
public static double code(double x, double n) {
	return Math.pow((x + 1.0), (1.0 / n)) - Math.pow(x, (1.0 / n));
}
public static double code(double x, double n) {
	double tmp;
	if (x <= 8200.0) {
		tmp = Math.log(((x + 1.0) / x)) / n;
	} else {
		tmp = (Math.pow(x, (1.0 / n)) / x) / n;
	}
	return tmp;
}
def code(x, n):
	return math.pow((x + 1.0), (1.0 / n)) - math.pow(x, (1.0 / n))
def code(x, n):
	tmp = 0
	if x <= 8200.0:
		tmp = math.log(((x + 1.0) / x)) / n
	else:
		tmp = (math.pow(x, (1.0 / n)) / x) / n
	return tmp
function code(x, n)
	return Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - (x ^ Float64(1.0 / n)))
end
function code(x, n)
	tmp = 0.0
	if (x <= 8200.0)
		tmp = Float64(log(Float64(Float64(x + 1.0) / x)) / n);
	else
		tmp = Float64(Float64((x ^ Float64(1.0 / n)) / x) / n);
	end
	return tmp
end
function tmp = code(x, n)
	tmp = ((x + 1.0) ^ (1.0 / n)) - (x ^ (1.0 / n));
end
function tmp_2 = code(x, n)
	tmp = 0.0;
	if (x <= 8200.0)
		tmp = log(((x + 1.0) / x)) / n;
	else
		tmp = ((x ^ (1.0 / n)) / x) / n;
	end
	tmp_2 = tmp;
end
code[x_, n_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
code[x_, n_] := If[LessEqual[x, 8200.0], N[(N[Log[N[(N[(x + 1.0), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], N[(N[(N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision]]
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\begin{array}{l}
\mathbf{if}\;x \leq 8200:\\
\;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Split input into 2 regimes
  2. if x < 8200

    1. Initial program 26.9%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Taylor expanded in n around inf 77.7%

      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
    3. Simplified77.7%

      \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
      Proof

      [Start]77.7

      \[ \frac{\log \left(1 + x\right) - \log x}{n} \]

      log1p-def [=>]77.7

      \[ \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
    4. Applied egg-rr77.7%

      \[\leadsto \frac{\color{blue}{\log \left(\frac{x + 1}{x}\right)}}{n} \]
      Proof

      [Start]77.7

      \[ \frac{\mathsf{log1p}\left(x\right) - \log x}{n} \]

      add-log-exp [=>]77.7

      \[ \frac{\color{blue}{\log \left(e^{\mathsf{log1p}\left(x\right) - \log x}\right)}}{n} \]

      exp-diff [=>]77.7

      \[ \frac{\log \color{blue}{\left(\frac{e^{\mathsf{log1p}\left(x\right)}}{e^{\log x}}\right)}}{n} \]

      log1p-udef [=>]77.7

      \[ \frac{\log \left(\frac{e^{\color{blue}{\log \left(1 + x\right)}}}{e^{\log x}}\right)}{n} \]

      add-exp-log [<=]77.7

      \[ \frac{\log \left(\frac{\color{blue}{1 + x}}{e^{\log x}}\right)}{n} \]

      +-commutative [=>]77.7

      \[ \frac{\log \left(\frac{\color{blue}{x + 1}}{e^{\log x}}\right)}{n} \]

      add-exp-log [<=]77.7

      \[ \frac{\log \left(\frac{x + 1}{\color{blue}{x}}\right)}{n} \]

    if 8200 < x

    1. Initial program 68.1%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Taylor expanded in x around inf 97.6%

      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
    3. Simplified97.6%

      \[\leadsto \color{blue}{\frac{e^{\frac{\log x}{n}}}{x \cdot n}} \]
      Proof

      [Start]97.6

      \[ \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x} \]

      mul-1-neg [=>]97.6

      \[ \frac{e^{\color{blue}{-\frac{\log \left(\frac{1}{x}\right)}{n}}}}{n \cdot x} \]

      log-rec [=>]97.6

      \[ \frac{e^{-\frac{\color{blue}{-\log x}}{n}}}{n \cdot x} \]

      mul-1-neg [<=]97.6

      \[ \frac{e^{-\frac{\color{blue}{-1 \cdot \log x}}{n}}}{n \cdot x} \]

      distribute-neg-frac [=>]97.6

      \[ \frac{e^{\color{blue}{\frac{--1 \cdot \log x}{n}}}}{n \cdot x} \]

      mul-1-neg [=>]97.6

      \[ \frac{e^{\frac{-\color{blue}{\left(-\log x\right)}}{n}}}{n \cdot x} \]

      remove-double-neg [=>]97.6

      \[ \frac{e^{\frac{\color{blue}{\log x}}{n}}}{n \cdot x} \]

      *-commutative [=>]97.6

      \[ \frac{e^{\frac{\log x}{n}}}{\color{blue}{x \cdot n}} \]
    4. Applied egg-rr97.1%

      \[\leadsto \color{blue}{{\left(\sqrt[3]{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}}\right)}^{3}} \]
      Proof

      [Start]97.6

      \[ \frac{e^{\frac{\log x}{n}}}{x \cdot n} \]

      add-cube-cbrt [=>]97.1

      \[ \color{blue}{\left(\sqrt[3]{\frac{e^{\frac{\log x}{n}}}{x \cdot n}} \cdot \sqrt[3]{\frac{e^{\frac{\log x}{n}}}{x \cdot n}}\right) \cdot \sqrt[3]{\frac{e^{\frac{\log x}{n}}}{x \cdot n}}} \]

      pow3 [=>]97.1

      \[ \color{blue}{{\left(\sqrt[3]{\frac{e^{\frac{\log x}{n}}}{x \cdot n}}\right)}^{3}} \]

      div-inv [=>]97.1

      \[ {\left(\sqrt[3]{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x \cdot n}}\right)}^{3} \]

      exp-to-pow [=>]97.1

      \[ {\left(\sqrt[3]{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x \cdot n}}\right)}^{3} \]
    5. Applied egg-rr99.1%

      \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
      Proof

      [Start]97.1

      \[ {\left(\sqrt[3]{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}}\right)}^{3} \]

      rem-cube-cbrt [=>]97.6

      \[ \color{blue}{\frac{{x}^{\left(\frac{1}{n}\right)}}{x \cdot n}} \]

      associate-/r* [=>]99.1

      \[ \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification89.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 8200:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\ \end{array} \]

Alternatives

Alternative 1
Accuracy89.4%
Cost7044
\[\begin{array}{l} \mathbf{if}\;x \leq 8200:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{n}}{x}\\ \end{array} \]
Alternative 2
Accuracy76.3%
Cost6980
\[\begin{array}{l} \mathbf{if}\;x \leq 800:\\ \;\;\;\;\frac{\log \left(\frac{x + 1}{x}\right)}{n}\\ \mathbf{elif}\;x \leq 3.2 \cdot 10^{+144}:\\ \;\;\;\;\frac{\frac{1}{\frac{\frac{0.041666666666666664}{x} + -0.08333333333333333}{x} + \left(x + 0.5\right)}}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{-1}{n} \cdot 0\\ \end{array} \]
Alternative 3
Accuracy75.9%
Cost6852
\[\begin{array}{l} \mathbf{if}\;x \leq 0.52:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;x \leq 3.2 \cdot 10^{+144}:\\ \;\;\;\;\frac{\frac{1}{\frac{\frac{0.041666666666666664}{x} + -0.08333333333333333}{x} + \left(x + 0.5\right)}}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{-1}{n} \cdot 0\\ \end{array} \]
Alternative 4
Accuracy73.5%
Cost6788
\[\begin{array}{l} \mathbf{if}\;x \leq 0.35:\\ \;\;\;\;\frac{-\log x}{n}\\ \mathbf{elif}\;x \leq 5 \cdot 10^{+191}:\\ \;\;\;\;\frac{\frac{1}{\frac{\frac{0.041666666666666664}{x} + -0.08333333333333333}{x} + \left(x + 0.5\right)}}{n}\\ \mathbf{else}:\\ \;\;\;\;-1 + \left(1 + \frac{1}{x \cdot n}\right)\\ \end{array} \]
Alternative 5
Accuracy75.6%
Cost6788
\[\begin{array}{l} \mathbf{if}\;x \leq 0.35:\\ \;\;\;\;\frac{-\log x}{n}\\ \mathbf{elif}\;x \leq 3.2 \cdot 10^{+144}:\\ \;\;\;\;\frac{\frac{1}{\frac{\frac{0.041666666666666664}{x} + -0.08333333333333333}{x} + \left(x + 0.5\right)}}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{-1}{n} \cdot 0\\ \end{array} \]
Alternative 6
Accuracy49.4%
Cost836
\[\begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -1000000000000:\\ \;\;\;\;-1 + \left(1 + \frac{1}{x \cdot n}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{x + 0.5}}{n}\\ \end{array} \]
Alternative 7
Accuracy42.1%
Cost448
\[\frac{\frac{1}{x + 0.5}}{n} \]
Alternative 8
Accuracy37.3%
Cost320
\[\frac{1}{x \cdot n} \]
Alternative 9
Accuracy38.1%
Cost320
\[\frac{\frac{1}{n}}{x} \]
Alternative 10
Accuracy38.1%
Cost320
\[\frac{\frac{1}{x}}{n} \]
Alternative 11
Accuracy4.6%
Cost192
\[\frac{x}{n} \]

Error

Reproduce?

herbie shell --seed 2023135 
(FPCore (x n)
  :name "2nthrt (problem 3.4.6)"
  :precision binary64
  (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))