?

Average Accuracy: 83.3% → 99.8%
Time: 8.8s
Precision: binary64
Cost: 840

?

\[\frac{x \cdot \left(\left(y - z\right) + 1\right)}{z} \]
\[\begin{array}{l} t_0 := 1 + \left(y - z\right)\\ \mathbf{if}\;z \leq -5800000000000:\\ \;\;\;\;\left(\frac{y}{z} + -1\right) \cdot x\\ \mathbf{elif}\;z \leq 1.6 \cdot 10^{+32}:\\ \;\;\;\;\frac{x \cdot t_0}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{\frac{z}{t_0}}\\ \end{array} \]
(FPCore (x y z) :precision binary64 (/ (* x (+ (- y z) 1.0)) z))
(FPCore (x y z)
 :precision binary64
 (let* ((t_0 (+ 1.0 (- y z))))
   (if (<= z -5800000000000.0)
     (* (+ (/ y z) -1.0) x)
     (if (<= z 1.6e+32) (/ (* x t_0) z) (/ x (/ z t_0))))))
double code(double x, double y, double z) {
	return (x * ((y - z) + 1.0)) / z;
}
double code(double x, double y, double z) {
	double t_0 = 1.0 + (y - z);
	double tmp;
	if (z <= -5800000000000.0) {
		tmp = ((y / z) + -1.0) * x;
	} else if (z <= 1.6e+32) {
		tmp = (x * t_0) / z;
	} else {
		tmp = x / (z / t_0);
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = (x * ((y - z) + 1.0d0)) / z
end function
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: t_0
    real(8) :: tmp
    t_0 = 1.0d0 + (y - z)
    if (z <= (-5800000000000.0d0)) then
        tmp = ((y / z) + (-1.0d0)) * x
    else if (z <= 1.6d+32) then
        tmp = (x * t_0) / z
    else
        tmp = x / (z / t_0)
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	return (x * ((y - z) + 1.0)) / z;
}
public static double code(double x, double y, double z) {
	double t_0 = 1.0 + (y - z);
	double tmp;
	if (z <= -5800000000000.0) {
		tmp = ((y / z) + -1.0) * x;
	} else if (z <= 1.6e+32) {
		tmp = (x * t_0) / z;
	} else {
		tmp = x / (z / t_0);
	}
	return tmp;
}
def code(x, y, z):
	return (x * ((y - z) + 1.0)) / z
def code(x, y, z):
	t_0 = 1.0 + (y - z)
	tmp = 0
	if z <= -5800000000000.0:
		tmp = ((y / z) + -1.0) * x
	elif z <= 1.6e+32:
		tmp = (x * t_0) / z
	else:
		tmp = x / (z / t_0)
	return tmp
function code(x, y, z)
	return Float64(Float64(x * Float64(Float64(y - z) + 1.0)) / z)
end
function code(x, y, z)
	t_0 = Float64(1.0 + Float64(y - z))
	tmp = 0.0
	if (z <= -5800000000000.0)
		tmp = Float64(Float64(Float64(y / z) + -1.0) * x);
	elseif (z <= 1.6e+32)
		tmp = Float64(Float64(x * t_0) / z);
	else
		tmp = Float64(x / Float64(z / t_0));
	end
	return tmp
end
function tmp = code(x, y, z)
	tmp = (x * ((y - z) + 1.0)) / z;
end
function tmp_2 = code(x, y, z)
	t_0 = 1.0 + (y - z);
	tmp = 0.0;
	if (z <= -5800000000000.0)
		tmp = ((y / z) + -1.0) * x;
	elseif (z <= 1.6e+32)
		tmp = (x * t_0) / z;
	else
		tmp = x / (z / t_0);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := N[(N[(x * N[(N[(y - z), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision] / z), $MachinePrecision]
code[x_, y_, z_] := Block[{t$95$0 = N[(1.0 + N[(y - z), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[z, -5800000000000.0], N[(N[(N[(y / z), $MachinePrecision] + -1.0), $MachinePrecision] * x), $MachinePrecision], If[LessEqual[z, 1.6e+32], N[(N[(x * t$95$0), $MachinePrecision] / z), $MachinePrecision], N[(x / N[(z / t$95$0), $MachinePrecision]), $MachinePrecision]]]]
\frac{x \cdot \left(\left(y - z\right) + 1\right)}{z}
\begin{array}{l}
t_0 := 1 + \left(y - z\right)\\
\mathbf{if}\;z \leq -5800000000000:\\
\;\;\;\;\left(\frac{y}{z} + -1\right) \cdot x\\

\mathbf{elif}\;z \leq 1.6 \cdot 10^{+32}:\\
\;\;\;\;\frac{x \cdot t_0}{z}\\

\mathbf{else}:\\
\;\;\;\;\frac{x}{\frac{z}{t_0}}\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original83.3%
Target99.3%
Herbie99.8%
\[\begin{array}{l} \mathbf{if}\;x < -2.71483106713436 \cdot 10^{-162}:\\ \;\;\;\;\left(1 + y\right) \cdot \frac{x}{z} - x\\ \mathbf{elif}\;x < 3.874108816439546 \cdot 10^{-197}:\\ \;\;\;\;\left(x \cdot \left(\left(y - z\right) + 1\right)\right) \cdot \frac{1}{z}\\ \mathbf{else}:\\ \;\;\;\;\left(1 + y\right) \cdot \frac{x}{z} - x\\ \end{array} \]

Derivation?

  1. Split input into 3 regimes
  2. if z < -5.8e12

    1. Initial program 71.6%

      \[\frac{x \cdot \left(\left(y - z\right) + 1\right)}{z} \]
    2. Simplified90.3%

      \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(x, y, x\right)}{z} - x} \]
      Proof

      [Start]71.6

      \[ \frac{x \cdot \left(\left(y - z\right) + 1\right)}{z} \]

      associate-*r/ [<=]99.9

      \[ \color{blue}{x \cdot \frac{\left(y - z\right) + 1}{z}} \]

      +-commutative [=>]99.9

      \[ x \cdot \frac{\color{blue}{1 + \left(y - z\right)}}{z} \]

      associate-+r- [=>]99.9

      \[ x \cdot \frac{\color{blue}{\left(1 + y\right) - z}}{z} \]

      div-sub [=>]99.9

      \[ x \cdot \color{blue}{\left(\frac{1 + y}{z} - \frac{z}{z}\right)} \]

      *-inverses [=>]99.9

      \[ x \cdot \left(\frac{1 + y}{z} - \color{blue}{1}\right) \]

      distribute-rgt-out-- [<=]99.9

      \[ \color{blue}{\frac{1 + y}{z} \cdot x - 1 \cdot x} \]

      *-lft-identity [=>]99.9

      \[ \frac{1 + y}{z} \cdot x - \color{blue}{x} \]

      *-commutative [=>]99.9

      \[ \color{blue}{x \cdot \frac{1 + y}{z}} - x \]

      associate-*r/ [=>]90.3

      \[ \color{blue}{\frac{x \cdot \left(1 + y\right)}{z}} - x \]

      *-commutative [=>]90.3

      \[ \frac{\color{blue}{\left(1 + y\right) \cdot x}}{z} - x \]

      +-commutative [=>]90.3

      \[ \frac{\color{blue}{\left(y + 1\right)} \cdot x}{z} - x \]

      distribute-lft1-in [<=]90.3

      \[ \frac{\color{blue}{y \cdot x + x}}{z} - x \]

      *-commutative [=>]90.3

      \[ \frac{\color{blue}{x \cdot y} + x}{z} - x \]

      fma-def [=>]90.3

      \[ \frac{\color{blue}{\mathsf{fma}\left(x, y, x\right)}}{z} - x \]
    3. Taylor expanded in y around inf 90.3%

      \[\leadsto \color{blue}{\frac{y \cdot x}{z}} - x \]
    4. Simplified95.5%

      \[\leadsto \color{blue}{\frac{y}{\frac{z}{x}}} - x \]
      Proof

      [Start]90.3

      \[ \frac{y \cdot x}{z} - x \]

      associate-/l* [=>]95.5

      \[ \color{blue}{\frac{y}{\frac{z}{x}}} - x \]
    5. Taylor expanded in x around 0 99.8%

      \[\leadsto \color{blue}{\left(\frac{y}{z} - 1\right) \cdot x} \]

    if -5.8e12 < z < 1.5999999999999999e32

    1. Initial program 99.6%

      \[\frac{x \cdot \left(\left(y - z\right) + 1\right)}{z} \]

    if 1.5999999999999999e32 < z

    1. Initial program 70.7%

      \[\frac{x \cdot \left(\left(y - z\right) + 1\right)}{z} \]
    2. Simplified99.9%

      \[\leadsto \color{blue}{\frac{x}{\frac{z}{\left(y - z\right) + 1}}} \]
      Proof

      [Start]70.7

      \[ \frac{x \cdot \left(\left(y - z\right) + 1\right)}{z} \]

      associate-/l* [=>]99.9

      \[ \color{blue}{\frac{x}{\frac{z}{\left(y - z\right) + 1}}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification99.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq -5800000000000:\\ \;\;\;\;\left(\frac{y}{z} + -1\right) \cdot x\\ \mathbf{elif}\;z \leq 1.6 \cdot 10^{+32}:\\ \;\;\;\;\frac{x \cdot \left(1 + \left(y - z\right)\right)}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{\frac{z}{1 + \left(y - z\right)}}\\ \end{array} \]

Alternatives

Alternative 1
Accuracy99.6%
Cost841
\[\begin{array}{l} \mathbf{if}\;z \leq -0.0034 \lor \neg \left(z \leq 1.7 \cdot 10^{-24}\right):\\ \;\;\;\;\frac{x}{\frac{z}{1 + \left(y - z\right)}}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{z} \cdot \left(y + 1\right)\\ \end{array} \]
Alternative 2
Accuracy93.5%
Cost713
\[\begin{array}{l} \mathbf{if}\;y \leq -1 \lor \neg \left(y \leq 0.02\right):\\ \;\;\;\;\left(\frac{y}{z} + -1\right) \cdot x\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{z} - x\\ \end{array} \]
Alternative 3
Accuracy98.6%
Cost713
\[\begin{array}{l} \mathbf{if}\;z \leq -0.95 \lor \neg \left(z \leq 1\right):\\ \;\;\;\;\left(\frac{y}{z} + -1\right) \cdot x\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{z} \cdot \left(y + 1\right)\\ \end{array} \]
Alternative 4
Accuracy98.6%
Cost712
\[\begin{array}{l} \mathbf{if}\;z \leq -0.98:\\ \;\;\;\;\left(\frac{y}{z} + -1\right) \cdot x\\ \mathbf{elif}\;z \leq 1:\\ \;\;\;\;\frac{x}{z} \cdot \left(y + 1\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{y}{z} \cdot x - x\\ \end{array} \]
Alternative 5
Accuracy69.0%
Cost588
\[\begin{array}{l} \mathbf{if}\;z \leq -3.5 \cdot 10^{+31}:\\ \;\;\;\;-x\\ \mathbf{elif}\;z \leq -1.07 \cdot 10^{-47}:\\ \;\;\;\;y \cdot \frac{x}{z}\\ \mathbf{elif}\;z \leq 1:\\ \;\;\;\;\frac{x}{z}\\ \mathbf{else}:\\ \;\;\;\;-x\\ \end{array} \]
Alternative 6
Accuracy69.0%
Cost588
\[\begin{array}{l} \mathbf{if}\;z \leq -3.5 \cdot 10^{+31}:\\ \;\;\;\;-x\\ \mathbf{elif}\;z \leq -7.6 \cdot 10^{-45}:\\ \;\;\;\;\frac{y}{z} \cdot x\\ \mathbf{elif}\;z \leq 1:\\ \;\;\;\;\frac{x}{z}\\ \mathbf{else}:\\ \;\;\;\;-x\\ \end{array} \]
Alternative 7
Accuracy82.3%
Cost585
\[\begin{array}{l} \mathbf{if}\;y \leq -8.6 \cdot 10^{+61} \lor \neg \left(y \leq 2.3 \cdot 10^{+59}\right):\\ \;\;\;\;y \cdot \frac{x}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{z} - x\\ \end{array} \]
Alternative 8
Accuracy81.9%
Cost584
\[\begin{array}{l} \mathbf{if}\;y \leq -9.2 \cdot 10^{+61}:\\ \;\;\;\;\frac{y \cdot x}{z}\\ \mathbf{elif}\;y \leq 3.3 \cdot 10^{+59}:\\ \;\;\;\;\frac{x}{z} - x\\ \mathbf{else}:\\ \;\;\;\;y \cdot \frac{x}{z}\\ \end{array} \]
Alternative 9
Accuracy69.0%
Cost456
\[\begin{array}{l} \mathbf{if}\;z \leq -1.1 \cdot 10^{-18}:\\ \;\;\;\;-x\\ \mathbf{elif}\;z \leq 1:\\ \;\;\;\;\frac{x}{z}\\ \mathbf{else}:\\ \;\;\;\;-x\\ \end{array} \]
Alternative 10
Accuracy48.5%
Cost128
\[-x \]
Alternative 11
Accuracy3.0%
Cost64
\[x \]

Error

Reproduce?

herbie shell --seed 2023133 
(FPCore (x y z)
  :name "Diagrams.TwoD.Segment.Bernstein:evaluateBernstein from diagrams-lib-1.3.0.3"
  :precision binary64

  :herbie-target
  (if (< x -2.71483106713436e-162) (- (* (+ 1.0 y) (/ x z)) x) (if (< x 3.874108816439546e-197) (* (* x (+ (- y z) 1.0)) (/ 1.0 z)) (- (* (+ 1.0 y) (/ x z)) x)))

  (/ (* x (+ (- y z) 1.0)) z))