Math FPCore C Java Python Julia MATLAB Wolfram TeX \[\frac{x \cdot 2}{y \cdot z - t \cdot z}
\]
↓
\[\begin{array}{l}
t_1 := y \cdot z - z \cdot t\\
\mathbf{if}\;t_1 \leq -\infty:\\
\;\;\;\;\frac{\frac{2}{z}}{\frac{y - t}{x}}\\
\mathbf{elif}\;t_1 \leq -2 \cdot 10^{-57}:\\
\;\;\;\;\frac{2 \cdot x}{t_1}\\
\mathbf{elif}\;t_1 \leq 0 \lor \neg \left(t_1 \leq 4 \cdot 10^{+243}\right):\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{\frac{z \cdot \left(y - t\right)}{2}}\\
\end{array}
\]
(FPCore (x y z t) :precision binary64 (/ (* x 2.0) (- (* y z) (* t z)))) ↓
(FPCore (x y z t)
:precision binary64
(let* ((t_1 (- (* y z) (* z t))))
(if (<= t_1 (- INFINITY))
(/ (/ 2.0 z) (/ (- y t) x))
(if (<= t_1 -2e-57)
(/ (* 2.0 x) t_1)
(if (or (<= t_1 0.0) (not (<= t_1 4e+243)))
(* 2.0 (/ (/ x z) (- y t)))
(/ x (/ (* z (- y t)) 2.0))))))) double code(double x, double y, double z, double t) {
return (x * 2.0) / ((y * z) - (t * z));
}
↓
double code(double x, double y, double z, double t) {
double t_1 = (y * z) - (z * t);
double tmp;
if (t_1 <= -((double) INFINITY)) {
tmp = (2.0 / z) / ((y - t) / x);
} else if (t_1 <= -2e-57) {
tmp = (2.0 * x) / t_1;
} else if ((t_1 <= 0.0) || !(t_1 <= 4e+243)) {
tmp = 2.0 * ((x / z) / (y - t));
} else {
tmp = x / ((z * (y - t)) / 2.0);
}
return tmp;
}
public static double code(double x, double y, double z, double t) {
return (x * 2.0) / ((y * z) - (t * z));
}
↓
public static double code(double x, double y, double z, double t) {
double t_1 = (y * z) - (z * t);
double tmp;
if (t_1 <= -Double.POSITIVE_INFINITY) {
tmp = (2.0 / z) / ((y - t) / x);
} else if (t_1 <= -2e-57) {
tmp = (2.0 * x) / t_1;
} else if ((t_1 <= 0.0) || !(t_1 <= 4e+243)) {
tmp = 2.0 * ((x / z) / (y - t));
} else {
tmp = x / ((z * (y - t)) / 2.0);
}
return tmp;
}
def code(x, y, z, t):
return (x * 2.0) / ((y * z) - (t * z))
↓
def code(x, y, z, t):
t_1 = (y * z) - (z * t)
tmp = 0
if t_1 <= -math.inf:
tmp = (2.0 / z) / ((y - t) / x)
elif t_1 <= -2e-57:
tmp = (2.0 * x) / t_1
elif (t_1 <= 0.0) or not (t_1 <= 4e+243):
tmp = 2.0 * ((x / z) / (y - t))
else:
tmp = x / ((z * (y - t)) / 2.0)
return tmp
function code(x, y, z, t)
return Float64(Float64(x * 2.0) / Float64(Float64(y * z) - Float64(t * z)))
end
↓
function code(x, y, z, t)
t_1 = Float64(Float64(y * z) - Float64(z * t))
tmp = 0.0
if (t_1 <= Float64(-Inf))
tmp = Float64(Float64(2.0 / z) / Float64(Float64(y - t) / x));
elseif (t_1 <= -2e-57)
tmp = Float64(Float64(2.0 * x) / t_1);
elseif ((t_1 <= 0.0) || !(t_1 <= 4e+243))
tmp = Float64(2.0 * Float64(Float64(x / z) / Float64(y - t)));
else
tmp = Float64(x / Float64(Float64(z * Float64(y - t)) / 2.0));
end
return tmp
end
function tmp = code(x, y, z, t)
tmp = (x * 2.0) / ((y * z) - (t * z));
end
↓
function tmp_2 = code(x, y, z, t)
t_1 = (y * z) - (z * t);
tmp = 0.0;
if (t_1 <= -Inf)
tmp = (2.0 / z) / ((y - t) / x);
elseif (t_1 <= -2e-57)
tmp = (2.0 * x) / t_1;
elseif ((t_1 <= 0.0) || ~((t_1 <= 4e+243)))
tmp = 2.0 * ((x / z) / (y - t));
else
tmp = x / ((z * (y - t)) / 2.0);
end
tmp_2 = tmp;
end
code[x_, y_, z_, t_] := N[(N[(x * 2.0), $MachinePrecision] / N[(N[(y * z), $MachinePrecision] - N[(t * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(y * z), $MachinePrecision] - N[(z * t), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, (-Infinity)], N[(N[(2.0 / z), $MachinePrecision] / N[(N[(y - t), $MachinePrecision] / x), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, -2e-57], N[(N[(2.0 * x), $MachinePrecision] / t$95$1), $MachinePrecision], If[Or[LessEqual[t$95$1, 0.0], N[Not[LessEqual[t$95$1, 4e+243]], $MachinePrecision]], N[(2.0 * N[(N[(x / z), $MachinePrecision] / N[(y - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(x / N[(N[(z * N[(y - t), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision]), $MachinePrecision]]]]]
\frac{x \cdot 2}{y \cdot z - t \cdot z}
↓
\begin{array}{l}
t_1 := y \cdot z - z \cdot t\\
\mathbf{if}\;t_1 \leq -\infty:\\
\;\;\;\;\frac{\frac{2}{z}}{\frac{y - t}{x}}\\
\mathbf{elif}\;t_1 \leq -2 \cdot 10^{-57}:\\
\;\;\;\;\frac{2 \cdot x}{t_1}\\
\mathbf{elif}\;t_1 \leq 0 \lor \neg \left(t_1 \leq 4 \cdot 10^{+243}\right):\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{\frac{z \cdot \left(y - t\right)}{2}}\\
\end{array}
Alternatives Alternative 1 Accuracy 72.8% Cost 976
\[\begin{array}{l}
t_1 := \frac{-2}{t \cdot \frac{z}{x}}\\
t_2 := 2 \cdot \frac{\frac{x}{y}}{z}\\
\mathbf{if}\;y \leq -5.7 \cdot 10^{+33}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;y \leq 2.8 \cdot 10^{+14}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 2.5 \cdot 10^{+90}:\\
\;\;\;\;x \cdot \frac{2}{y \cdot z}\\
\mathbf{elif}\;y \leq 1.8 \cdot 10^{+96}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;t_2\\
\end{array}
\]
Alternative 2 Accuracy 72.9% Cost 976
\[\begin{array}{l}
t_1 := \frac{-2}{t \cdot \frac{z}{x}}\\
t_2 := 2 \cdot \frac{\frac{x}{y}}{z}\\
\mathbf{if}\;y \leq -6.2 \cdot 10^{+32}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;y \leq 4.7 \cdot 10^{-7}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 2.5 \cdot 10^{+90}:\\
\;\;\;\;\frac{2}{\frac{y \cdot z}{x}}\\
\mathbf{elif}\;y \leq 7.2 \cdot 10^{+95}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;t_2\\
\end{array}
\]
Alternative 3 Accuracy 73.0% Cost 976
\[\begin{array}{l}
t_1 := 2 \cdot \frac{\frac{x}{y}}{z}\\
\mathbf{if}\;y \leq -1 \cdot 10^{+34}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 9.5 \cdot 10^{-10}:\\
\;\;\;\;\frac{-2}{t \cdot \frac{z}{x}}\\
\mathbf{elif}\;y \leq 2.5 \cdot 10^{+90}:\\
\;\;\;\;\frac{2}{\frac{y \cdot z}{x}}\\
\mathbf{elif}\;y \leq 7.2 \cdot 10^{+95}:\\
\;\;\;\;\frac{x \cdot -2}{z \cdot t}\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
Alternative 4 Accuracy 73.1% Cost 976
\[\begin{array}{l}
t_1 := 2 \cdot \frac{\frac{x}{y}}{z}\\
\mathbf{if}\;y \leq -7 \cdot 10^{+33}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 950000000000:\\
\;\;\;\;\frac{\frac{-2}{t}}{\frac{z}{x}}\\
\mathbf{elif}\;y \leq 2.5 \cdot 10^{+90}:\\
\;\;\;\;x \cdot \frac{2}{y \cdot z}\\
\mathbf{elif}\;y \leq 8 \cdot 10^{+95}:\\
\;\;\;\;\frac{x \cdot -2}{z \cdot t}\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
Alternative 5 Accuracy 72.8% Cost 976
\[\begin{array}{l}
t_1 := 2 \cdot \frac{\frac{x}{y}}{z}\\
\mathbf{if}\;y \leq -3.5 \cdot 10^{+32}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq 5.6 \cdot 10^{+14}:\\
\;\;\;\;\frac{\frac{x}{z}}{t \cdot -0.5}\\
\mathbf{elif}\;y \leq 2.1 \cdot 10^{+88}:\\
\;\;\;\;x \cdot \frac{2}{y \cdot z}\\
\mathbf{elif}\;y \leq 7.2 \cdot 10^{+95}:\\
\;\;\;\;\frac{x \cdot -2}{z \cdot t}\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
Alternative 6 Accuracy 96.1% Cost 841
\[\begin{array}{l}
\mathbf{if}\;z \leq -7.5 \cdot 10^{+86} \lor \neg \left(z \leq 5.1 \cdot 10^{-48}\right):\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{2}{z \cdot \left(y - t\right)}\\
\end{array}
\]
Alternative 7 Accuracy 96.2% Cost 841
\[\begin{array}{l}
\mathbf{if}\;z \leq -4.5 \cdot 10^{+86} \lor \neg \left(z \leq 5 \cdot 10^{-45}\right):\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{\frac{2}{z}}{y - t}\\
\end{array}
\]
Alternative 8 Accuracy 96.2% Cost 841
\[\begin{array}{l}
\mathbf{if}\;z \leq -5.6 \cdot 10^{+91} \lor \neg \left(z \leq 2 \cdot 10^{-49}\right):\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{\frac{z \cdot \left(y - t\right)}{2}}\\
\end{array}
\]
Alternative 9 Accuracy 72.3% Cost 713
\[\begin{array}{l}
\mathbf{if}\;y \leq -5.1 \cdot 10^{+33} \lor \neg \left(y \leq 3500000\right):\\
\;\;\;\;2 \cdot \frac{\frac{x}{y}}{z}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{\frac{-2}{t}}{z}\\
\end{array}
\]
Alternative 10 Accuracy 72.1% Cost 713
\[\begin{array}{l}
\mathbf{if}\;y \leq -6.2 \cdot 10^{+32} \lor \neg \left(y \leq 6500000\right):\\
\;\;\;\;2 \cdot \frac{\frac{x}{y}}{z}\\
\mathbf{else}:\\
\;\;\;\;-2 \cdot \frac{\frac{x}{t}}{z}\\
\end{array}
\]
Alternative 11 Accuracy 89.7% Cost 708
\[\begin{array}{l}
\mathbf{if}\;y \leq -5.5 \cdot 10^{+125}:\\
\;\;\;\;2 \cdot \frac{\frac{x}{y}}{z}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\end{array}
\]
Alternative 12 Accuracy 50.8% Cost 580
\[\begin{array}{l}
\mathbf{if}\;y \leq 4.6 \cdot 10^{+82}:\\
\;\;\;\;x \cdot \frac{2}{y \cdot z}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \frac{\frac{x}{y}}{z}\\
\end{array}
\]
Alternative 13 Accuracy 50.6% Cost 448
\[2 \cdot \frac{\frac{x}{y}}{z}
\]