Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{\cosh x \cdot \frac{y}{x}}{z}
\]
↓
\[\begin{array}{l}
t_0 := \frac{\cosh x \cdot \frac{y}{x}}{z}\\
\mathbf{if}\;t_0 \leq -5 \cdot 10^{-25}:\\
\;\;\;\;\frac{\frac{1}{x} + x \cdot 0.5}{\frac{z}{y}}\\
\mathbf{elif}\;t_0 \leq 2 \cdot 10^{+221}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{y}{z}}{x}\\
\end{array}
\]
(FPCore (x y z) :precision binary64 (/ (* (cosh x) (/ y x)) z)) ↓
(FPCore (x y z)
:precision binary64
(let* ((t_0 (/ (* (cosh x) (/ y x)) z)))
(if (<= t_0 -5e-25)
(/ (+ (/ 1.0 x) (* x 0.5)) (/ z y))
(if (<= t_0 2e+221) t_0 (/ (/ y z) x))))) double code(double x, double y, double z) {
return (cosh(x) * (y / x)) / z;
}
↓
double code(double x, double y, double z) {
double t_0 = (cosh(x) * (y / x)) / z;
double tmp;
if (t_0 <= -5e-25) {
tmp = ((1.0 / x) + (x * 0.5)) / (z / y);
} else if (t_0 <= 2e+221) {
tmp = t_0;
} else {
tmp = (y / z) / x;
}
return tmp;
}
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
code = (cosh(x) * (y / x)) / z
end function
↓
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8) :: t_0
real(8) :: tmp
t_0 = (cosh(x) * (y / x)) / z
if (t_0 <= (-5d-25)) then
tmp = ((1.0d0 / x) + (x * 0.5d0)) / (z / y)
else if (t_0 <= 2d+221) then
tmp = t_0
else
tmp = (y / z) / x
end if
code = tmp
end function
public static double code(double x, double y, double z) {
return (Math.cosh(x) * (y / x)) / z;
}
↓
public static double code(double x, double y, double z) {
double t_0 = (Math.cosh(x) * (y / x)) / z;
double tmp;
if (t_0 <= -5e-25) {
tmp = ((1.0 / x) + (x * 0.5)) / (z / y);
} else if (t_0 <= 2e+221) {
tmp = t_0;
} else {
tmp = (y / z) / x;
}
return tmp;
}
def code(x, y, z):
return (math.cosh(x) * (y / x)) / z
↓
def code(x, y, z):
t_0 = (math.cosh(x) * (y / x)) / z
tmp = 0
if t_0 <= -5e-25:
tmp = ((1.0 / x) + (x * 0.5)) / (z / y)
elif t_0 <= 2e+221:
tmp = t_0
else:
tmp = (y / z) / x
return tmp
function code(x, y, z)
return Float64(Float64(cosh(x) * Float64(y / x)) / z)
end
↓
function code(x, y, z)
t_0 = Float64(Float64(cosh(x) * Float64(y / x)) / z)
tmp = 0.0
if (t_0 <= -5e-25)
tmp = Float64(Float64(Float64(1.0 / x) + Float64(x * 0.5)) / Float64(z / y));
elseif (t_0 <= 2e+221)
tmp = t_0;
else
tmp = Float64(Float64(y / z) / x);
end
return tmp
end
function tmp = code(x, y, z)
tmp = (cosh(x) * (y / x)) / z;
end
↓
function tmp_2 = code(x, y, z)
t_0 = (cosh(x) * (y / x)) / z;
tmp = 0.0;
if (t_0 <= -5e-25)
tmp = ((1.0 / x) + (x * 0.5)) / (z / y);
elseif (t_0 <= 2e+221)
tmp = t_0;
else
tmp = (y / z) / x;
end
tmp_2 = tmp;
end
code[x_, y_, z_] := N[(N[(N[Cosh[x], $MachinePrecision] * N[(y / x), $MachinePrecision]), $MachinePrecision] / z), $MachinePrecision]
↓
code[x_, y_, z_] := Block[{t$95$0 = N[(N[(N[Cosh[x], $MachinePrecision] * N[(y / x), $MachinePrecision]), $MachinePrecision] / z), $MachinePrecision]}, If[LessEqual[t$95$0, -5e-25], N[(N[(N[(1.0 / x), $MachinePrecision] + N[(x * 0.5), $MachinePrecision]), $MachinePrecision] / N[(z / y), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 2e+221], t$95$0, N[(N[(y / z), $MachinePrecision] / x), $MachinePrecision]]]]
\frac{\cosh x \cdot \frac{y}{x}}{z}
↓
\begin{array}{l}
t_0 := \frac{\cosh x \cdot \frac{y}{x}}{z}\\
\mathbf{if}\;t_0 \leq -5 \cdot 10^{-25}:\\
\;\;\;\;\frac{\frac{1}{x} + x \cdot 0.5}{\frac{z}{y}}\\
\mathbf{elif}\;t_0 \leq 2 \cdot 10^{+221}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{y}{z}}{x}\\
\end{array}
Alternatives Alternative 1 Accuracy 98.1% Cost 7113
\[\begin{array}{l}
\mathbf{if}\;z \leq -9.6 \cdot 10^{-115} \lor \neg \left(z \leq 1.1 \cdot 10^{-55}\right):\\
\;\;\;\;\cosh x \cdot \frac{y}{x \cdot z}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{1}{x} + x \cdot 0.5}{\frac{z}{y}}\\
\end{array}
\]
Alternative 2 Accuracy 98.6% Cost 7113
\[\begin{array}{l}
\mathbf{if}\;z \leq -7.5 \cdot 10^{-103} \lor \neg \left(z \leq 2 \cdot 10^{-59}\right):\\
\;\;\;\;\cosh x \cdot \frac{y}{x \cdot z}\\
\mathbf{else}:\\
\;\;\;\;\cosh x \cdot \frac{\frac{y}{z}}{x}\\
\end{array}
\]
Alternative 3 Accuracy 97.2% Cost 1097
\[\begin{array}{l}
\mathbf{if}\;z \leq -9.6 \cdot 10^{-115} \lor \neg \left(z \leq 1.8 \cdot 10^{-57}\right):\\
\;\;\;\;\frac{y}{x \cdot z} + 0.5 \cdot \frac{x \cdot y}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{1}{x} + x \cdot 0.5}{\frac{z}{y}}\\
\end{array}
\]
Alternative 4 Accuracy 97.6% Cost 969
\[\begin{array}{l}
\mathbf{if}\;z \leq -4.6 \cdot 10^{+53} \lor \neg \left(z \leq 1.42 \cdot 10^{-55}\right):\\
\;\;\;\;\frac{y}{x \cdot z}\\
\mathbf{else}:\\
\;\;\;\;\left(\frac{1}{x} + x \cdot 0.5\right) \cdot \frac{y}{z}\\
\end{array}
\]
Alternative 5 Accuracy 97.0% Cost 968
\[\begin{array}{l}
t_0 := \frac{1}{x} + x \cdot 0.5\\
\mathbf{if}\;z \leq -9.6 \cdot 10^{-115}:\\
\;\;\;\;\frac{y}{\frac{z}{t_0}}\\
\mathbf{elif}\;z \leq 1.5 \cdot 10^{-55}:\\
\;\;\;\;t_0 \cdot \frac{y}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{y}{x \cdot z}\\
\end{array}
\]
Alternative 6 Accuracy 97.7% Cost 968
\[\begin{array}{l}
t_0 := \frac{1}{x} + x \cdot 0.5\\
\mathbf{if}\;z \leq -4.5 \cdot 10^{+53}:\\
\;\;\;\;\frac{y}{\frac{z}{t_0}}\\
\mathbf{elif}\;z \leq 1.5 \cdot 10^{-55}:\\
\;\;\;\;\frac{t_0}{\frac{z}{y}}\\
\mathbf{else}:\\
\;\;\;\;\frac{y}{x \cdot z}\\
\end{array}
\]
Alternative 7 Accuracy 97.8% Cost 968
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.8 \cdot 10^{-15}:\\
\;\;\;\;\frac{y}{x \cdot z}\\
\mathbf{elif}\;y \leq 1.1 \cdot 10^{+58}:\\
\;\;\;\;\frac{\frac{y}{x} + y \cdot \left(x \cdot 0.5\right)}{z}\\
\mathbf{else}:\\
\;\;\;\;\frac{y}{\frac{z}{\frac{1}{x} + x \cdot 0.5}}\\
\end{array}
\]
Alternative 8 Accuracy 96.6% Cost 713
\[\begin{array}{l}
\mathbf{if}\;z \leq -1.2 \cdot 10^{-103} \lor \neg \left(z \leq 3 \cdot 10^{-61}\right):\\
\;\;\;\;\frac{y}{x \cdot z}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{x \cdot \frac{z}{y}}\\
\end{array}
\]
Alternative 9 Accuracy 96.6% Cost 585
\[\begin{array}{l}
\mathbf{if}\;z \leq -4.3 \cdot 10^{-112} \lor \neg \left(z \leq 1.8 \cdot 10^{-49}\right):\\
\;\;\;\;\frac{y}{x \cdot z}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{y}{x}}{z}\\
\end{array}
\]
Alternative 10 Accuracy 96.7% Cost 585
\[\begin{array}{l}
\mathbf{if}\;z \leq -1.2 \cdot 10^{-103} \lor \neg \left(z \leq 2 \cdot 10^{-59}\right):\\
\;\;\;\;\frac{y}{x \cdot z}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{y}{z}}{x}\\
\end{array}
\]
Alternative 11 Accuracy 87.2% Cost 320
\[\frac{y}{x \cdot z}
\]