Numeric.SpecFunctions:choose from math-functions-0.1.5.2

Average Accuracy: 81.0% → 99.5%

Time: 5.5s

Precision: binary64

Cost: 2512

Math

\[\frac{x \cdot \left(y + z\right)}{z} \]

↓

\[\begin{array}{l} t_0 := \frac{x \cdot \left(y + z\right)}{z}\\ t_1 := x \cdot \frac{y + z}{z}\\ \mathbf{if}\;t_0 \leq -\infty:\\ \;\;\;\;t_1\\ \mathbf{elif}\;t_0 \leq -2 \cdot 10^{+80}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;t_0 \leq 2 \cdot 10^{-81}:\\ \;\;\;\;\frac{x}{\frac{z}{y + z}}\\ \mathbf{elif}\;t_0 \leq 2 \cdot 10^{+305}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;t_1\\ \end{array} \]

FPCore

(FPCore (x y z) :precision binary64 (/ (* x (+ y z)) z))

↓

(FPCore (x y z)
 :precision binary64
 (let* ((t_0 (/ (* x (+ y z)) z)) (t_1 (* x (/ (+ y z) z))))
   (if (<= t_0 (- INFINITY))
     t_1
     (if (<= t_0 -2e+80)
       t_0
       (if (<= t_0 2e-81) (/ x (/ z (+ y z))) (if (<= t_0 2e+305) t_0 t_1))))))

C

double code(double x, double y, double z) {
	return (x * (y + z)) / z;
}

↓

double code(double x, double y, double z) {
	double t_0 = (x * (y + z)) / z;
	double t_1 = x * ((y + z) / z);
	double tmp;
	if (t_0 <= -((double) INFINITY)) {
		tmp = t_1;
	} else if (t_0 <= -2e+80) {
		tmp = t_0;
	} else if (t_0 <= 2e-81) {
		tmp = x / (z / (y + z));
	} else if (t_0 <= 2e+305) {
		tmp = t_0;
	} else {
		tmp = t_1;
	}
	return tmp;
}

Java

public static double code(double x, double y, double z) {
	return (x * (y + z)) / z;
}

↓

public static double code(double x, double y, double z) {
	double t_0 = (x * (y + z)) / z;
	double t_1 = x * ((y + z) / z);
	double tmp;
	if (t_0 <= -Double.POSITIVE_INFINITY) {
		tmp = t_1;
	} else if (t_0 <= -2e+80) {
		tmp = t_0;
	} else if (t_0 <= 2e-81) {
		tmp = x / (z / (y + z));
	} else if (t_0 <= 2e+305) {
		tmp = t_0;
	} else {
		tmp = t_1;
	}
	return tmp;
}

Python

def code(x, y, z):
	return (x * (y + z)) / z

↓

def code(x, y, z):
	t_0 = (x * (y + z)) / z
	t_1 = x * ((y + z) / z)
	tmp = 0
	if t_0 <= -math.inf:
		tmp = t_1
	elif t_0 <= -2e+80:
		tmp = t_0
	elif t_0 <= 2e-81:
		tmp = x / (z / (y + z))
	elif t_0 <= 2e+305:
		tmp = t_0
	else:
		tmp = t_1
	return tmp

Julia

function code(x, y, z)
	return Float64(Float64(x * Float64(y + z)) / z)
end

↓

function code(x, y, z)
	t_0 = Float64(Float64(x * Float64(y + z)) / z)
	t_1 = Float64(x * Float64(Float64(y + z) / z))
	tmp = 0.0
	if (t_0 <= Float64(-Inf))
		tmp = t_1;
	elseif (t_0 <= -2e+80)
		tmp = t_0;
	elseif (t_0 <= 2e-81)
		tmp = Float64(x / Float64(z / Float64(y + z)));
	elseif (t_0 <= 2e+305)
		tmp = t_0;
	else
		tmp = t_1;
	end
	return tmp
end

MATLAB

function tmp = code(x, y, z)
	tmp = (x * (y + z)) / z;
end

↓

function tmp_2 = code(x, y, z)
	t_0 = (x * (y + z)) / z;
	t_1 = x * ((y + z) / z);
	tmp = 0.0;
	if (t_0 <= -Inf)
		tmp = t_1;
	elseif (t_0 <= -2e+80)
		tmp = t_0;
	elseif (t_0 <= 2e-81)
		tmp = x / (z / (y + z));
	elseif (t_0 <= 2e+305)
		tmp = t_0;
	else
		tmp = t_1;
	end
	tmp_2 = tmp;
end

Wolfram

code[x_, y_, z_] := N[(N[(x * N[(y + z), $MachinePrecision]), $MachinePrecision] / z), $MachinePrecision]

↓

code[x_, y_, z_] := Block[{t$95$0 = N[(N[(x * N[(y + z), $MachinePrecision]), $MachinePrecision] / z), $MachinePrecision]}, Block[{t$95$1 = N[(x * N[(N[(y + z), $MachinePrecision] / z), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, (-Infinity)], t$95$1, If[LessEqual[t$95$0, -2e+80], t$95$0, If[LessEqual[t$95$0, 2e-81], N[(x / N[(z / N[(y + z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 2e+305], t$95$0, t$95$1]]]]]]

Target

Original	81.0%
Target	95.3%
Herbie	99.5%

\[\frac{x}{\frac{z}{y + z}} \]

Derivation

1. Split input into 3 regimes

2. if (/.f64 (*.f64 x (+.f64 y z)) z) < -inf.0 or 1.9999999999999999e305 < (/.f64 (*.f64 x (+.f64 y z)) z)

   1. Initial program 0.7%

      \[\frac{x \cdot \left(y + z\right)}{z} \]

   2. Simplified 99.7%

      \[\leadsto \color{blue}{x \cdot \frac{y + z}{z}} \]
      Proof

      [Start] 0.7	\[ \frac{x \cdot \left(y + z\right)}{z} \]
      associate-*r/ [<=] 99.7	\[ \color{blue}{x \cdot \frac{y + z}{z}} \]

   if -inf.0 < (/.f64 (*.f64 x (+.f64 y z)) z) < -2e80 or 1.9999999999999999e-81 < (/.f64 (*.f64 x (+.f64 y z)) z) < 1.9999999999999999e305

   1. Initial program 99.6%

      \[\frac{x \cdot \left(y + z\right)}{z} \]

   if -2e80 < (/.f64 (*.f64 x (+.f64 y z)) z) < 1.9999999999999999e-81

   1. Initial program 90.4%

      \[\frac{x \cdot \left(y + z\right)}{z} \]

   2. Simplified 99.3%

      \[\leadsto \color{blue}{\frac{x}{\frac{z}{y + z}}} \]
      Proof

      [Start] 90.4	\[ \frac{x \cdot \left(y + z\right)}{z} \]
      associate-/l* [=>] 99.3	\[ \color{blue}{\frac{x}{\frac{z}{y + z}}} \]

3. Recombined 3 regimes into one program.

4. Final simplification 99.5%

   \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x \cdot \left(y + z\right)}{z} \leq -\infty:\\ \;\;\;\;x \cdot \frac{y + z}{z}\\ \mathbf{elif}\;\frac{x \cdot \left(y + z\right)}{z} \leq -2 \cdot 10^{+80}:\\ \;\;\;\;\frac{x \cdot \left(y + z\right)}{z}\\ \mathbf{elif}\;\frac{x \cdot \left(y + z\right)}{z} \leq 2 \cdot 10^{-81}:\\ \;\;\;\;\frac{x}{\frac{z}{y + z}}\\ \mathbf{elif}\;\frac{x \cdot \left(y + z\right)}{z} \leq 2 \cdot 10^{+305}:\\ \;\;\;\;\frac{x \cdot \left(y + z\right)}{z}\\ \mathbf{else}:\\ \;\;\;\;x \cdot \frac{y + z}{z}\\ \end{array} \]

Alternatives

Alternative 1
Accuracy	94.5%
Cost	713

\[\begin{array}{l} \mathbf{if}\;y \leq 1.18 \cdot 10^{+219} \lor \neg \left(y \leq 4.8 \cdot 10^{+277}\right):\\ \;\;\;\;x \cdot \frac{y + z}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{x \cdot y}{z}\\ \end{array} \]

Alternative 2
Accuracy	94.9%
Cost	713

\[\begin{array}{l} \mathbf{if}\;y \leq 3.8 \cdot 10^{+179} \lor \neg \left(y \leq 2.2 \cdot 10^{+280}\right):\\ \;\;\;\;x \cdot \frac{y + z}{z}\\ \mathbf{else}:\\ \;\;\;\;\left(y + z\right) \cdot \frac{x}{z}\\ \end{array} \]

Alternative 3
Accuracy	95.3%
Cost	712

\[\begin{array}{l} \mathbf{if}\;y \leq 1.7 \cdot 10^{+180}:\\ \;\;\;\;\frac{x}{\frac{z}{y + z}}\\ \mathbf{elif}\;y \leq 9.5 \cdot 10^{+277}:\\ \;\;\;\;\left(y + z\right) \cdot \frac{x}{z}\\ \mathbf{else}:\\ \;\;\;\;x \cdot \frac{y + z}{z}\\ \end{array} \]

Alternative 4
Accuracy	71.1%
Cost	585

\[\begin{array}{l} \mathbf{if}\;y \leq -1.75 \cdot 10^{+35} \lor \neg \left(y \leq 2.75 \cdot 10^{+72}\right):\\ \;\;\;\;y \cdot \frac{x}{z}\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \]

Alternative 5
Accuracy	70.6%
Cost	584

\[\begin{array}{l} \mathbf{if}\;z \leq -7.8 \cdot 10^{+37}:\\ \;\;\;\;x\\ \mathbf{elif}\;z \leq 1.02 \cdot 10^{-38}:\\ \;\;\;\;\frac{y}{\frac{z}{x}}\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \]

Alternative 6
Accuracy	70.8%
Cost	584

\[\begin{array}{l} \mathbf{if}\;z \leq -1.05 \cdot 10^{+38}:\\ \;\;\;\;x\\ \mathbf{elif}\;z \leq 1.9 \cdot 10^{-36}:\\ \;\;\;\;\frac{x \cdot y}{z}\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \]

Alternative 7
Accuracy	60.4%
Cost	64

\[x \]

Reproduce

herbie shell --seed 2023133 
(FPCore (x y z)
  :name "Numeric.SpecFunctions:choose from math-functions-0.1.5.2"
  :precision binary64

  :herbie-target
  (/ x (/ z (+ y z)))

  (/ (* x (+ y z)) z))