?

Average Accuracy: 82.6% → 95.9%
Time: 4.5s
Precision: binary64
Cost: 2513

?

\[\frac{a1 \cdot a2}{b1 \cdot b2} \]
\[\begin{array}{l} t_0 := \frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{if}\;t_0 \leq -\infty:\\ \;\;\;\;\frac{a2}{b1 \cdot \frac{b2}{a1}}\\ \mathbf{elif}\;t_0 \leq -2 \cdot 10^{-300} \lor \neg \left(t_0 \leq 0\right) \land t_0 \leq 2 \cdot 10^{+291}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{a1}{b1} \cdot \frac{a2}{b2}\\ \end{array} \]
(FPCore (a1 a2 b1 b2) :precision binary64 (/ (* a1 a2) (* b1 b2)))
(FPCore (a1 a2 b1 b2)
 :precision binary64
 (let* ((t_0 (/ (* a1 a2) (* b1 b2))))
   (if (<= t_0 (- INFINITY))
     (/ a2 (* b1 (/ b2 a1)))
     (if (or (<= t_0 -2e-300) (and (not (<= t_0 0.0)) (<= t_0 2e+291)))
       t_0
       (* (/ a1 b1) (/ a2 b2))))))
double code(double a1, double a2, double b1, double b2) {
	return (a1 * a2) / (b1 * b2);
}
double code(double a1, double a2, double b1, double b2) {
	double t_0 = (a1 * a2) / (b1 * b2);
	double tmp;
	if (t_0 <= -((double) INFINITY)) {
		tmp = a2 / (b1 * (b2 / a1));
	} else if ((t_0 <= -2e-300) || (!(t_0 <= 0.0) && (t_0 <= 2e+291))) {
		tmp = t_0;
	} else {
		tmp = (a1 / b1) * (a2 / b2);
	}
	return tmp;
}
public static double code(double a1, double a2, double b1, double b2) {
	return (a1 * a2) / (b1 * b2);
}
public static double code(double a1, double a2, double b1, double b2) {
	double t_0 = (a1 * a2) / (b1 * b2);
	double tmp;
	if (t_0 <= -Double.POSITIVE_INFINITY) {
		tmp = a2 / (b1 * (b2 / a1));
	} else if ((t_0 <= -2e-300) || (!(t_0 <= 0.0) && (t_0 <= 2e+291))) {
		tmp = t_0;
	} else {
		tmp = (a1 / b1) * (a2 / b2);
	}
	return tmp;
}
def code(a1, a2, b1, b2):
	return (a1 * a2) / (b1 * b2)
def code(a1, a2, b1, b2):
	t_0 = (a1 * a2) / (b1 * b2)
	tmp = 0
	if t_0 <= -math.inf:
		tmp = a2 / (b1 * (b2 / a1))
	elif (t_0 <= -2e-300) or (not (t_0 <= 0.0) and (t_0 <= 2e+291)):
		tmp = t_0
	else:
		tmp = (a1 / b1) * (a2 / b2)
	return tmp
function code(a1, a2, b1, b2)
	return Float64(Float64(a1 * a2) / Float64(b1 * b2))
end
function code(a1, a2, b1, b2)
	t_0 = Float64(Float64(a1 * a2) / Float64(b1 * b2))
	tmp = 0.0
	if (t_0 <= Float64(-Inf))
		tmp = Float64(a2 / Float64(b1 * Float64(b2 / a1)));
	elseif ((t_0 <= -2e-300) || (!(t_0 <= 0.0) && (t_0 <= 2e+291)))
		tmp = t_0;
	else
		tmp = Float64(Float64(a1 / b1) * Float64(a2 / b2));
	end
	return tmp
end
function tmp = code(a1, a2, b1, b2)
	tmp = (a1 * a2) / (b1 * b2);
end
function tmp_2 = code(a1, a2, b1, b2)
	t_0 = (a1 * a2) / (b1 * b2);
	tmp = 0.0;
	if (t_0 <= -Inf)
		tmp = a2 / (b1 * (b2 / a1));
	elseif ((t_0 <= -2e-300) || (~((t_0 <= 0.0)) && (t_0 <= 2e+291)))
		tmp = t_0;
	else
		tmp = (a1 / b1) * (a2 / b2);
	end
	tmp_2 = tmp;
end
code[a1_, a2_, b1_, b2_] := N[(N[(a1 * a2), $MachinePrecision] / N[(b1 * b2), $MachinePrecision]), $MachinePrecision]
code[a1_, a2_, b1_, b2_] := Block[{t$95$0 = N[(N[(a1 * a2), $MachinePrecision] / N[(b1 * b2), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, (-Infinity)], N[(a2 / N[(b1 * N[(b2 / a1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[Or[LessEqual[t$95$0, -2e-300], And[N[Not[LessEqual[t$95$0, 0.0]], $MachinePrecision], LessEqual[t$95$0, 2e+291]]], t$95$0, N[(N[(a1 / b1), $MachinePrecision] * N[(a2 / b2), $MachinePrecision]), $MachinePrecision]]]]
\frac{a1 \cdot a2}{b1 \cdot b2}
\begin{array}{l}
t_0 := \frac{a1 \cdot a2}{b1 \cdot b2}\\
\mathbf{if}\;t_0 \leq -\infty:\\
\;\;\;\;\frac{a2}{b1 \cdot \frac{b2}{a1}}\\

\mathbf{elif}\;t_0 \leq -2 \cdot 10^{-300} \lor \neg \left(t_0 \leq 0\right) \land t_0 \leq 2 \cdot 10^{+291}:\\
\;\;\;\;t_0\\

\mathbf{else}:\\
\;\;\;\;\frac{a1}{b1} \cdot \frac{a2}{b2}\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original82.6%
Target81.4%
Herbie95.9%
\[\frac{a1}{b1} \cdot \frac{a2}{b2} \]

Derivation?

  1. Split input into 3 regimes
  2. if (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -inf.0

    1. Initial program 0.0%

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]
    2. Simplified51.8%

      \[\leadsto \color{blue}{a2 \cdot \frac{a1}{b1 \cdot b2}} \]
      Proof

      [Start]0.0

      \[ \frac{a1 \cdot a2}{b1 \cdot b2} \]

      associate-*l/ [<=]51.8

      \[ \color{blue}{\frac{a1}{b1 \cdot b2} \cdot a2} \]

      *-commutative [=>]51.8

      \[ \color{blue}{a2 \cdot \frac{a1}{b1 \cdot b2}} \]
    3. Applied egg-rr74.6%

      \[\leadsto \color{blue}{\frac{a2}{\frac{b2}{a1} \cdot b1}} \]

    if -inf.0 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -2.00000000000000005e-300 or -0.0 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < 1.9999999999999999e291

    1. Initial program 98.6%

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]

    if -2.00000000000000005e-300 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -0.0 or 1.9999999999999999e291 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2))

    1. Initial program 66.0%

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]
    2. Simplified93.8%

      \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
      Proof

      [Start]66.0

      \[ \frac{a1 \cdot a2}{b1 \cdot b2} \]

      times-frac [=>]93.8

      \[ \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification95.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -\infty:\\ \;\;\;\;\frac{a2}{b1 \cdot \frac{b2}{a1}}\\ \mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -2 \cdot 10^{-300} \lor \neg \left(\frac{a1 \cdot a2}{b1 \cdot b2} \leq 0\right) \land \frac{a1 \cdot a2}{b1 \cdot b2} \leq 2 \cdot 10^{+291}:\\ \;\;\;\;\frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{else}:\\ \;\;\;\;\frac{a1}{b1} \cdot \frac{a2}{b2}\\ \end{array} \]

Alternatives

Alternative 1
Accuracy92.0%
Cost1490
\[\begin{array}{l} \mathbf{if}\;b1 \cdot b2 \leq -1 \cdot 10^{+224} \lor \neg \left(b1 \cdot b2 \leq -4 \cdot 10^{-228} \lor \neg \left(b1 \cdot b2 \leq 5 \cdot 10^{-236}\right) \land b1 \cdot b2 \leq 2 \cdot 10^{+229}\right):\\ \;\;\;\;\frac{a1}{b1} \cdot \frac{a2}{b2}\\ \mathbf{else}:\\ \;\;\;\;a2 \cdot \frac{a1}{b1 \cdot b2}\\ \end{array} \]
Alternative 2
Accuracy91.4%
Cost1490
\[\begin{array}{l} \mathbf{if}\;b1 \cdot b2 \leq -\infty \lor \neg \left(b1 \cdot b2 \leq -2 \cdot 10^{-157} \lor \neg \left(b1 \cdot b2 \leq 5 \cdot 10^{-309}\right) \land b1 \cdot b2 \leq 5 \cdot 10^{+259}\right):\\ \;\;\;\;\frac{a1}{b1} \cdot \frac{a2}{b2}\\ \mathbf{else}:\\ \;\;\;\;a1 \cdot \frac{a2}{b1 \cdot b2}\\ \end{array} \]
Alternative 3
Accuracy82.9%
Cost448
\[a2 \cdot \frac{a1}{b1 \cdot b2} \]

Error

Reproduce?

herbie shell --seed 2023129 
(FPCore (a1 a2 b1 b2)
  :name "Quotient of products"
  :precision binary64

  :herbie-target
  (* (/ a1 b1) (/ a2 b2))

  (/ (* a1 a2) (* b1 b2)))