Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
\]
↓
\[\begin{array}{l}
t_0 := \sqrt{b_2 \cdot b_2 - c \cdot a}\\
\mathbf{if}\;b_2 \leq -2.55 \cdot 10^{+64}:\\
\;\;\;\;\frac{c \cdot -0.5}{b_2}\\
\mathbf{elif}\;b_2 \leq 5 \cdot 10^{-305}:\\
\;\;\;\;\frac{\frac{\left(b_2 \cdot b_2 - b_2 \cdot b_2\right) - c \cdot a}{a}}{b_2 - t_0}\\
\mathbf{elif}\;b_2 \leq 2.1 \cdot 10^{+140}:\\
\;\;\;\;\frac{\left(-b_2\right) - t_0}{a}\\
\mathbf{else}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\end{array}
\]
(FPCore (a b_2 c)
:precision binary64
(/ (- (- b_2) (sqrt (- (* b_2 b_2) (* a c)))) a)) ↓
(FPCore (a b_2 c)
:precision binary64
(let* ((t_0 (sqrt (- (* b_2 b_2) (* c a)))))
(if (<= b_2 -2.55e+64)
(/ (* c -0.5) b_2)
(if (<= b_2 5e-305)
(/ (/ (- (- (* b_2 b_2) (* b_2 b_2)) (* c a)) a) (- b_2 t_0))
(if (<= b_2 2.1e+140) (/ (- (- b_2) t_0) a) (* -2.0 (/ b_2 a))))))) double code(double a, double b_2, double c) {
return (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a;
}
↓
double code(double a, double b_2, double c) {
double t_0 = sqrt(((b_2 * b_2) - (c * a)));
double tmp;
if (b_2 <= -2.55e+64) {
tmp = (c * -0.5) / b_2;
} else if (b_2 <= 5e-305) {
tmp = ((((b_2 * b_2) - (b_2 * b_2)) - (c * a)) / a) / (b_2 - t_0);
} else if (b_2 <= 2.1e+140) {
tmp = (-b_2 - t_0) / a;
} else {
tmp = -2.0 * (b_2 / a);
}
return tmp;
}
real(8) function code(a, b_2, c)
real(8), intent (in) :: a
real(8), intent (in) :: b_2
real(8), intent (in) :: c
code = (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a
end function
↓
real(8) function code(a, b_2, c)
real(8), intent (in) :: a
real(8), intent (in) :: b_2
real(8), intent (in) :: c
real(8) :: t_0
real(8) :: tmp
t_0 = sqrt(((b_2 * b_2) - (c * a)))
if (b_2 <= (-2.55d+64)) then
tmp = (c * (-0.5d0)) / b_2
else if (b_2 <= 5d-305) then
tmp = ((((b_2 * b_2) - (b_2 * b_2)) - (c * a)) / a) / (b_2 - t_0)
else if (b_2 <= 2.1d+140) then
tmp = (-b_2 - t_0) / a
else
tmp = (-2.0d0) * (b_2 / a)
end if
code = tmp
end function
public static double code(double a, double b_2, double c) {
return (-b_2 - Math.sqrt(((b_2 * b_2) - (a * c)))) / a;
}
↓
public static double code(double a, double b_2, double c) {
double t_0 = Math.sqrt(((b_2 * b_2) - (c * a)));
double tmp;
if (b_2 <= -2.55e+64) {
tmp = (c * -0.5) / b_2;
} else if (b_2 <= 5e-305) {
tmp = ((((b_2 * b_2) - (b_2 * b_2)) - (c * a)) / a) / (b_2 - t_0);
} else if (b_2 <= 2.1e+140) {
tmp = (-b_2 - t_0) / a;
} else {
tmp = -2.0 * (b_2 / a);
}
return tmp;
}
def code(a, b_2, c):
return (-b_2 - math.sqrt(((b_2 * b_2) - (a * c)))) / a
↓
def code(a, b_2, c):
t_0 = math.sqrt(((b_2 * b_2) - (c * a)))
tmp = 0
if b_2 <= -2.55e+64:
tmp = (c * -0.5) / b_2
elif b_2 <= 5e-305:
tmp = ((((b_2 * b_2) - (b_2 * b_2)) - (c * a)) / a) / (b_2 - t_0)
elif b_2 <= 2.1e+140:
tmp = (-b_2 - t_0) / a
else:
tmp = -2.0 * (b_2 / a)
return tmp
function code(a, b_2, c)
return Float64(Float64(Float64(-b_2) - sqrt(Float64(Float64(b_2 * b_2) - Float64(a * c)))) / a)
end
↓
function code(a, b_2, c)
t_0 = sqrt(Float64(Float64(b_2 * b_2) - Float64(c * a)))
tmp = 0.0
if (b_2 <= -2.55e+64)
tmp = Float64(Float64(c * -0.5) / b_2);
elseif (b_2 <= 5e-305)
tmp = Float64(Float64(Float64(Float64(Float64(b_2 * b_2) - Float64(b_2 * b_2)) - Float64(c * a)) / a) / Float64(b_2 - t_0));
elseif (b_2 <= 2.1e+140)
tmp = Float64(Float64(Float64(-b_2) - t_0) / a);
else
tmp = Float64(-2.0 * Float64(b_2 / a));
end
return tmp
end
function tmp = code(a, b_2, c)
tmp = (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a;
end
↓
function tmp_2 = code(a, b_2, c)
t_0 = sqrt(((b_2 * b_2) - (c * a)));
tmp = 0.0;
if (b_2 <= -2.55e+64)
tmp = (c * -0.5) / b_2;
elseif (b_2 <= 5e-305)
tmp = ((((b_2 * b_2) - (b_2 * b_2)) - (c * a)) / a) / (b_2 - t_0);
elseif (b_2 <= 2.1e+140)
tmp = (-b_2 - t_0) / a;
else
tmp = -2.0 * (b_2 / a);
end
tmp_2 = tmp;
end
code[a_, b$95$2_, c_] := N[(N[((-b$95$2) - N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(a * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / a), $MachinePrecision]
↓
code[a_, b$95$2_, c_] := Block[{t$95$0 = N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(c * a), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[b$95$2, -2.55e+64], N[(N[(c * -0.5), $MachinePrecision] / b$95$2), $MachinePrecision], If[LessEqual[b$95$2, 5e-305], N[(N[(N[(N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(b$95$2 * b$95$2), $MachinePrecision]), $MachinePrecision] - N[(c * a), $MachinePrecision]), $MachinePrecision] / a), $MachinePrecision] / N[(b$95$2 - t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[b$95$2, 2.1e+140], N[(N[((-b$95$2) - t$95$0), $MachinePrecision] / a), $MachinePrecision], N[(-2.0 * N[(b$95$2 / a), $MachinePrecision]), $MachinePrecision]]]]]
\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
↓
\begin{array}{l}
t_0 := \sqrt{b_2 \cdot b_2 - c \cdot a}\\
\mathbf{if}\;b_2 \leq -2.55 \cdot 10^{+64}:\\
\;\;\;\;\frac{c \cdot -0.5}{b_2}\\
\mathbf{elif}\;b_2 \leq 5 \cdot 10^{-305}:\\
\;\;\;\;\frac{\frac{\left(b_2 \cdot b_2 - b_2 \cdot b_2\right) - c \cdot a}{a}}{b_2 - t_0}\\
\mathbf{elif}\;b_2 \leq 2.1 \cdot 10^{+140}:\\
\;\;\;\;\frac{\left(-b_2\right) - t_0}{a}\\
\mathbf{else}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\end{array}
Alternatives Alternative 1 Accuracy 84.5% Cost 7696
\[\begin{array}{l}
t_0 := \sqrt{b_2 \cdot b_2 - c \cdot a}\\
\mathbf{if}\;b_2 \leq -6.2 \cdot 10^{+17}:\\
\;\;\;\;\frac{c \cdot -0.5}{b_2}\\
\mathbf{elif}\;b_2 \leq -2.6 \cdot 10^{-92}:\\
\;\;\;\;\frac{c \cdot \left(-a\right)}{a \cdot \left(b_2 - t_0\right)}\\
\mathbf{elif}\;b_2 \leq -2.2 \cdot 10^{-138}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{elif}\;b_2 \leq 2 \cdot 10^{+134}:\\
\;\;\;\;\frac{\left(-b_2\right) - t_0}{a}\\
\mathbf{else}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\end{array}
\]
Alternative 2 Accuracy 86.0% Cost 7688
\[\begin{array}{l}
t_0 := \sqrt{b_2 \cdot b_2 - c \cdot a}\\
\mathbf{if}\;b_2 \leq -1.15 \cdot 10^{+52}:\\
\;\;\;\;\frac{c \cdot -0.5}{b_2}\\
\mathbf{elif}\;b_2 \leq -5 \cdot 10^{-134}:\\
\;\;\;\;\frac{\frac{c \cdot \left(-a\right)}{b_2 - t_0}}{a}\\
\mathbf{elif}\;b_2 \leq 2.85 \cdot 10^{+140}:\\
\;\;\;\;\frac{\left(-b_2\right) - t_0}{a}\\
\mathbf{else}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\end{array}
\]
Alternative 3 Accuracy 83.7% Cost 7432
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -6.5 \cdot 10^{-18}:\\
\;\;\;\;\frac{c \cdot -0.5}{b_2}\\
\mathbf{elif}\;b_2 \leq 2 \cdot 10^{+140}:\\
\;\;\;\;\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - c \cdot a}}{a}\\
\mathbf{else}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\end{array}
\]
Alternative 4 Accuracy 78.2% Cost 7240
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -2.4 \cdot 10^{-18}:\\
\;\;\;\;\frac{c \cdot -0.5}{b_2}\\
\mathbf{elif}\;b_2 \leq 3.5 \cdot 10^{-40}:\\
\;\;\;\;\frac{\left(-b_2\right) - \sqrt{c \cdot \left(-a\right)}}{a}\\
\mathbf{else}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a} + \frac{c}{b_2} \cdot 0.5\\
\end{array}
\]
Alternative 5 Accuracy 38.5% Cost 452
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -5 \cdot 10^{-310}:\\
\;\;\;\;0\\
\mathbf{else}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\end{array}
\]
Alternative 6 Accuracy 64.4% Cost 452
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.9 \cdot 10^{-242}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{else}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\end{array}
\]
Alternative 7 Accuracy 64.3% Cost 452
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.5 \cdot 10^{-231}:\\
\;\;\;\;\frac{c \cdot -0.5}{b_2}\\
\mathbf{else}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\end{array}
\]
Alternative 8 Accuracy 16.9% Cost 388
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -5 \cdot 10^{-310}:\\
\;\;\;\;0\\
\mathbf{else}:\\
\;\;\;\;\frac{-b_2}{a}\\
\end{array}
\]
Alternative 9 Accuracy 12.2% Cost 64
\[0
\]