?

Average Accuracy: 4.2% → 100.0%
Time: 15.8s
Precision: binary64
Cost: 19520

?

\[-1 < x \land x < 1\]
\[\frac{\log \left(1 - x\right)}{\log \left(1 + x\right)} \]
\[{\left(\frac{\mathsf{log1p}\left(x\right)}{\mathsf{log1p}\left(-x\right)}\right)}^{-1} \]
(FPCore (x) :precision binary64 (/ (log (- 1.0 x)) (log (+ 1.0 x))))
(FPCore (x) :precision binary64 (pow (/ (log1p x) (log1p (- x))) -1.0))
double code(double x) {
	return log((1.0 - x)) / log((1.0 + x));
}
double code(double x) {
	return pow((log1p(x) / log1p(-x)), -1.0);
}
public static double code(double x) {
	return Math.log((1.0 - x)) / Math.log((1.0 + x));
}
public static double code(double x) {
	return Math.pow((Math.log1p(x) / Math.log1p(-x)), -1.0);
}
def code(x):
	return math.log((1.0 - x)) / math.log((1.0 + x))
def code(x):
	return math.pow((math.log1p(x) / math.log1p(-x)), -1.0)
function code(x)
	return Float64(log(Float64(1.0 - x)) / log(Float64(1.0 + x)))
end
function code(x)
	return Float64(log1p(x) / log1p(Float64(-x))) ^ -1.0
end
code[x_] := N[(N[Log[N[(1.0 - x), $MachinePrecision]], $MachinePrecision] / N[Log[N[(1.0 + x), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
code[x_] := N[Power[N[(N[Log[1 + x], $MachinePrecision] / N[Log[1 + (-x)], $MachinePrecision]), $MachinePrecision], -1.0], $MachinePrecision]
\frac{\log \left(1 - x\right)}{\log \left(1 + x\right)}
{\left(\frac{\mathsf{log1p}\left(x\right)}{\mathsf{log1p}\left(-x\right)}\right)}^{-1}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original4.2%
Target99.5%
Herbie100.0%
\[-\left(\left(\left(1 + x\right) + \frac{x \cdot x}{2}\right) + 0.4166666666666667 \cdot {x}^{3}\right) \]

Derivation?

  1. Initial program 4.2%

    \[\frac{\log \left(1 - x\right)}{\log \left(1 + x\right)} \]
  2. Applied egg-rr100.0%

    \[\leadsto \color{blue}{{\left(\frac{\mathsf{log1p}\left(x\right)}{\mathsf{log1p}\left(-x\right)}\right)}^{-1}} \]
    Proof

    [Start]4.2

    \[ \frac{\log \left(1 - x\right)}{\log \left(1 + x\right)} \]

    clear-num [=>]4.1

    \[ \color{blue}{\frac{1}{\frac{\log \left(1 + x\right)}{\log \left(1 - x\right)}}} \]

    inv-pow [=>]4.1

    \[ \color{blue}{{\left(\frac{\log \left(1 + x\right)}{\log \left(1 - x\right)}\right)}^{-1}} \]

    log1p-def [=>]6.2

    \[ {\left(\frac{\color{blue}{\mathsf{log1p}\left(x\right)}}{\log \left(1 - x\right)}\right)}^{-1} \]

    sub-neg [=>]6.2

    \[ {\left(\frac{\mathsf{log1p}\left(x\right)}{\log \color{blue}{\left(1 + \left(-x\right)\right)}}\right)}^{-1} \]

    log1p-def [=>]100.0

    \[ {\left(\frac{\mathsf{log1p}\left(x\right)}{\color{blue}{\mathsf{log1p}\left(-x\right)}}\right)}^{-1} \]
  3. Final simplification100.0%

    \[\leadsto {\left(\frac{\mathsf{log1p}\left(x\right)}{\mathsf{log1p}\left(-x\right)}\right)}^{-1} \]

Alternatives

Alternative 1
Accuracy100.0%
Cost13056
\[\frac{\mathsf{log1p}\left(-x\right)}{\mathsf{log1p}\left(x\right)} \]
Alternative 2
Accuracy99.3%
Cost576
\[\left(-1 - x\right) + -0.5 \cdot \left(x \cdot x\right) \]
Alternative 3
Accuracy98.9%
Cost192
\[-1 - x \]
Alternative 4
Accuracy97.8%
Cost64
\[-1 \]

Error

Reproduce?

herbie shell --seed 2023126 
(FPCore (x)
  :name "qlog (example 3.10)"
  :precision binary64
  :pre (and (< -1.0 x) (< x 1.0))

  :herbie-target
  (- (+ (+ (+ 1.0 x) (/ (* x x) 2.0)) (* 0.4166666666666667 (pow x 3.0))))

  (/ (log (- 1.0 x)) (log (+ 1.0 x))))