?

Average Accuracy: 99.3% → 99.3%
Time: 11.7s
Precision: binary64
Cost: 13120

?

\[\log \left(1 + e^{x}\right) - x \cdot y \]
\[\mathsf{log1p}\left(e^{x}\right) - x \cdot y \]
(FPCore (x y) :precision binary64 (- (log (+ 1.0 (exp x))) (* x y)))
(FPCore (x y) :precision binary64 (- (log1p (exp x)) (* x y)))
double code(double x, double y) {
	return log((1.0 + exp(x))) - (x * y);
}
double code(double x, double y) {
	return log1p(exp(x)) - (x * y);
}
public static double code(double x, double y) {
	return Math.log((1.0 + Math.exp(x))) - (x * y);
}
public static double code(double x, double y) {
	return Math.log1p(Math.exp(x)) - (x * y);
}
def code(x, y):
	return math.log((1.0 + math.exp(x))) - (x * y)
def code(x, y):
	return math.log1p(math.exp(x)) - (x * y)
function code(x, y)
	return Float64(log(Float64(1.0 + exp(x))) - Float64(x * y))
end
function code(x, y)
	return Float64(log1p(exp(x)) - Float64(x * y))
end
code[x_, y_] := N[(N[Log[N[(1.0 + N[Exp[x], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - N[(x * y), $MachinePrecision]), $MachinePrecision]
code[x_, y_] := N[(N[Log[1 + N[Exp[x], $MachinePrecision]], $MachinePrecision] - N[(x * y), $MachinePrecision]), $MachinePrecision]
\log \left(1 + e^{x}\right) - x \cdot y
\mathsf{log1p}\left(e^{x}\right) - x \cdot y

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original99.3%
Target99.9%
Herbie99.3%
\[\begin{array}{l} \mathbf{if}\;x \leq 0:\\ \;\;\;\;\log \left(1 + e^{x}\right) - x \cdot y\\ \mathbf{else}:\\ \;\;\;\;\log \left(1 + e^{-x}\right) - \left(-x\right) \cdot \left(1 - y\right)\\ \end{array} \]

Derivation?

  1. Initial program 99.3%

    \[\log \left(1 + e^{x}\right) - x \cdot y \]
  2. Simplified99.3%

    \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{x}\right) - x \cdot y} \]
    Proof

    [Start]99.3

    \[ \log \left(1 + e^{x}\right) - x \cdot y \]

    log1p-def [=>]99.3

    \[ \color{blue}{\mathsf{log1p}\left(e^{x}\right)} - x \cdot y \]
  3. Final simplification99.3%

    \[\leadsto \mathsf{log1p}\left(e^{x}\right) - x \cdot y \]

Alternatives

Alternative 1
Accuracy98.6%
Cost7108
\[\begin{array}{l} \mathbf{if}\;x \leq -1400000000:\\ \;\;\;\;x \cdot \left(-y\right)\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot 0.5 + \log 2\right) - x \cdot y\\ \end{array} \]
Alternative 2
Accuracy80.8%
Cost6852
\[\begin{array}{l} \mathbf{if}\;x \leq -9.5 \cdot 10^{-35}:\\ \;\;\;\;x \cdot \left(-y\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot 0.5 + \log 2\\ \end{array} \]
Alternative 3
Accuracy98.3%
Cost6852
\[\begin{array}{l} \mathbf{if}\;x \leq -1400000000:\\ \;\;\;\;x \cdot \left(-y\right)\\ \mathbf{else}:\\ \;\;\;\;\log 2 - x \cdot y\\ \end{array} \]
Alternative 4
Accuracy80.6%
Cost6596
\[\begin{array}{l} \mathbf{if}\;x \leq -1.1 \cdot 10^{-34}:\\ \;\;\;\;x \cdot \left(-y\right)\\ \mathbf{else}:\\ \;\;\;\;\log 2\\ \end{array} \]
Alternative 5
Accuracy46.4%
Cost256
\[x \cdot \left(-y\right) \]
Alternative 6
Accuracy3.5%
Cost192
\[x \cdot 0.5 \]

Error

Reproduce?

herbie shell --seed 2023122 
(FPCore (x y)
  :name "Logistic regression 2"
  :precision binary64

  :herbie-target
  (if (<= x 0.0) (- (log (+ 1.0 (exp x))) (* x y)) (- (log (+ 1.0 (exp (- x)))) (* (- x) (- 1.0 y))))

  (- (log (+ 1.0 (exp x))) (* x y)))