\[\left(\left(1.1102230246251565 \cdot 10^{-16} < a \land a < 9007199254740992\right) \land \left(1.1102230246251565 \cdot 10^{-16} < b \land b < 9007199254740992\right)\right) \land \left(1.1102230246251565 \cdot 10^{-16} < c \land c < 9007199254740992\right)\]
Math FPCore C Julia Wolfram TeX \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}
\]
↓
\[\frac{\frac{-4 \cdot \left(c \cdot a\right)}{b + \sqrt{\mathsf{fma}\left(b, b, c \cdot \left(-4 \cdot a\right)\right)}}}{a \cdot 2}
\]
(FPCore (a b c)
:precision binary64
(/ (+ (- b) (sqrt (- (* b b) (* (* 4.0 a) c)))) (* 2.0 a))) ↓
(FPCore (a b c)
:precision binary64
(/ (/ (* -4.0 (* c a)) (+ b (sqrt (fma b b (* c (* -4.0 a)))))) (* a 2.0))) double code(double a, double b, double c) {
return (-b + sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a);
}
↓
double code(double a, double b, double c) {
return ((-4.0 * (c * a)) / (b + sqrt(fma(b, b, (c * (-4.0 * a)))))) / (a * 2.0);
}
function code(a, b, c)
return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(4.0 * a) * c)))) / Float64(2.0 * a))
end
↓
function code(a, b, c)
return Float64(Float64(Float64(-4.0 * Float64(c * a)) / Float64(b + sqrt(fma(b, b, Float64(c * Float64(-4.0 * a)))))) / Float64(a * 2.0))
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(4.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]
↓
code[a_, b_, c_] := N[(N[(N[(-4.0 * N[(c * a), $MachinePrecision]), $MachinePrecision] / N[(b + N[Sqrt[N[(b * b + N[(c * N[(-4.0 * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}
↓
\frac{\frac{-4 \cdot \left(c \cdot a\right)}{b + \sqrt{\mathsf{fma}\left(b, b, c \cdot \left(-4 \cdot a\right)\right)}}}{a \cdot 2}
Alternatives Alternative 1 Accuracy 91.4% Cost 14788
\[\begin{array}{l}
t_0 := \frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)} - b}{a \cdot 2}\\
\mathbf{if}\;t_0 \leq -10000000:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;\frac{-c}{b} - a \cdot \frac{c \cdot c}{{b}^{3}}\\
\end{array}
\]
Alternative 2 Accuracy 94.1% Cost 8448
\[\frac{\frac{-4 \cdot \left(c \cdot a\right)}{b + \left(b + -2 \cdot \left(\frac{c}{\frac{b}{a}} + \frac{c \cdot c}{\frac{\frac{{b}^{3}}{a}}{a}}\right)\right)}}{a \cdot 2}
\]
Alternative 3 Accuracy 91.1% Cost 7616
\[\frac{-4 \cdot c}{a \cdot 2} \cdot \frac{a}{\mathsf{fma}\left(-2, c \cdot \frac{a}{b}, b \cdot 2\right)}
\]
Alternative 4 Accuracy 91.1% Cost 7488
\[c \cdot \frac{a \cdot \frac{-2}{a}}{\mathsf{fma}\left(-2, c \cdot \frac{a}{b}, b \cdot 2\right)}
\]
Alternative 5 Accuracy 91.1% Cost 7232
\[\frac{-c}{b} - a \cdot \frac{c \cdot c}{{b}^{3}}
\]
Alternative 6 Accuracy 91.1% Cost 1344
\[\frac{\frac{-4 \cdot \left(c \cdot a\right)}{b + \left(b + -2 \cdot \frac{c \cdot a}{b}\right)}}{a \cdot 2}
\]
Alternative 7 Accuracy 91.1% Cost 1344
\[\frac{\frac{-4 \cdot \left(c \cdot a\right)}{-2 \cdot \frac{c \cdot a}{b} + b \cdot 2}}{a \cdot 2}
\]
Alternative 8 Accuracy 90.9% Cost 1088
\[\frac{\left(a \cdot \frac{c}{b}\right) \cdot \left(-1 - \frac{a}{b} \cdot \frac{c}{b}\right)}{a}
\]
Alternative 9 Accuracy 81.6% Cost 256
\[\frac{-c}{b}
\]
Alternative 10 Accuracy 1.6% Cost 192
\[\frac{b}{a}
\]