Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{x + \frac{y \cdot z - x}{t \cdot z - x}}{x + 1}
\]
↓
\[\begin{array}{l}
t_1 := z \cdot t - x\\
t_2 := \frac{x + \frac{y \cdot z - x}{t_1}}{x + 1}\\
\mathbf{if}\;t_2 \leq -40000:\\
\;\;\;\;\frac{x + \frac{y}{\frac{t_1}{z}}}{x + 1}\\
\mathbf{elif}\;t_2 \leq 2 \cdot 10^{+226}:\\
\;\;\;\;t_2\\
\mathbf{else}:\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\end{array}
\]
(FPCore (x y z t)
:precision binary64
(/ (+ x (/ (- (* y z) x) (- (* t z) x))) (+ x 1.0))) ↓
(FPCore (x y z t)
:precision binary64
(let* ((t_1 (- (* z t) x)) (t_2 (/ (+ x (/ (- (* y z) x) t_1)) (+ x 1.0))))
(if (<= t_2 -40000.0)
(/ (+ x (/ y (/ t_1 z))) (+ x 1.0))
(if (<= t_2 2e+226) t_2 (/ (+ x (/ y t)) (+ x 1.0)))))) double code(double x, double y, double z, double t) {
return (x + (((y * z) - x) / ((t * z) - x))) / (x + 1.0);
}
↓
double code(double x, double y, double z, double t) {
double t_1 = (z * t) - x;
double t_2 = (x + (((y * z) - x) / t_1)) / (x + 1.0);
double tmp;
if (t_2 <= -40000.0) {
tmp = (x + (y / (t_1 / z))) / (x + 1.0);
} else if (t_2 <= 2e+226) {
tmp = t_2;
} else {
tmp = (x + (y / t)) / (x + 1.0);
}
return tmp;
}
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
code = (x + (((y * z) - x) / ((t * z) - x))) / (x + 1.0d0)
end function
↓
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
real(8) :: t_1
real(8) :: t_2
real(8) :: tmp
t_1 = (z * t) - x
t_2 = (x + (((y * z) - x) / t_1)) / (x + 1.0d0)
if (t_2 <= (-40000.0d0)) then
tmp = (x + (y / (t_1 / z))) / (x + 1.0d0)
else if (t_2 <= 2d+226) then
tmp = t_2
else
tmp = (x + (y / t)) / (x + 1.0d0)
end if
code = tmp
end function
public static double code(double x, double y, double z, double t) {
return (x + (((y * z) - x) / ((t * z) - x))) / (x + 1.0);
}
↓
public static double code(double x, double y, double z, double t) {
double t_1 = (z * t) - x;
double t_2 = (x + (((y * z) - x) / t_1)) / (x + 1.0);
double tmp;
if (t_2 <= -40000.0) {
tmp = (x + (y / (t_1 / z))) / (x + 1.0);
} else if (t_2 <= 2e+226) {
tmp = t_2;
} else {
tmp = (x + (y / t)) / (x + 1.0);
}
return tmp;
}
def code(x, y, z, t):
return (x + (((y * z) - x) / ((t * z) - x))) / (x + 1.0)
↓
def code(x, y, z, t):
t_1 = (z * t) - x
t_2 = (x + (((y * z) - x) / t_1)) / (x + 1.0)
tmp = 0
if t_2 <= -40000.0:
tmp = (x + (y / (t_1 / z))) / (x + 1.0)
elif t_2 <= 2e+226:
tmp = t_2
else:
tmp = (x + (y / t)) / (x + 1.0)
return tmp
function code(x, y, z, t)
return Float64(Float64(x + Float64(Float64(Float64(y * z) - x) / Float64(Float64(t * z) - x))) / Float64(x + 1.0))
end
↓
function code(x, y, z, t)
t_1 = Float64(Float64(z * t) - x)
t_2 = Float64(Float64(x + Float64(Float64(Float64(y * z) - x) / t_1)) / Float64(x + 1.0))
tmp = 0.0
if (t_2 <= -40000.0)
tmp = Float64(Float64(x + Float64(y / Float64(t_1 / z))) / Float64(x + 1.0));
elseif (t_2 <= 2e+226)
tmp = t_2;
else
tmp = Float64(Float64(x + Float64(y / t)) / Float64(x + 1.0));
end
return tmp
end
function tmp = code(x, y, z, t)
tmp = (x + (((y * z) - x) / ((t * z) - x))) / (x + 1.0);
end
↓
function tmp_2 = code(x, y, z, t)
t_1 = (z * t) - x;
t_2 = (x + (((y * z) - x) / t_1)) / (x + 1.0);
tmp = 0.0;
if (t_2 <= -40000.0)
tmp = (x + (y / (t_1 / z))) / (x + 1.0);
elseif (t_2 <= 2e+226)
tmp = t_2;
else
tmp = (x + (y / t)) / (x + 1.0);
end
tmp_2 = tmp;
end
code[x_, y_, z_, t_] := N[(N[(x + N[(N[(N[(y * z), $MachinePrecision] - x), $MachinePrecision] / N[(N[(t * z), $MachinePrecision] - x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(x + 1.0), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(z * t), $MachinePrecision] - x), $MachinePrecision]}, Block[{t$95$2 = N[(N[(x + N[(N[(N[(y * z), $MachinePrecision] - x), $MachinePrecision] / t$95$1), $MachinePrecision]), $MachinePrecision] / N[(x + 1.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -40000.0], N[(N[(x + N[(y / N[(t$95$1 / z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(x + 1.0), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, 2e+226], t$95$2, N[(N[(x + N[(y / t), $MachinePrecision]), $MachinePrecision] / N[(x + 1.0), $MachinePrecision]), $MachinePrecision]]]]]
\frac{x + \frac{y \cdot z - x}{t \cdot z - x}}{x + 1}
↓
\begin{array}{l}
t_1 := z \cdot t - x\\
t_2 := \frac{x + \frac{y \cdot z - x}{t_1}}{x + 1}\\
\mathbf{if}\;t_2 \leq -40000:\\
\;\;\;\;\frac{x + \frac{y}{\frac{t_1}{z}}}{x + 1}\\
\mathbf{elif}\;t_2 \leq 2 \cdot 10^{+226}:\\
\;\;\;\;t_2\\
\mathbf{else}:\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\end{array}
Alternatives Alternative 1 Accuracy 76.0% Cost 2020
\[\begin{array}{l}
t_1 := y \cdot z + \left(1 - y \cdot \frac{z}{x}\right)\\
t_2 := z \cdot t - x\\
t_3 := \frac{x - \frac{x}{t_2}}{x + 1}\\
t_4 := \frac{x + \frac{y}{t}}{x + 1}\\
t_5 := \frac{z}{x + 1} \cdot \frac{y}{t_2}\\
\mathbf{if}\;t \leq -8.5 \cdot 10^{-44}:\\
\;\;\;\;t_4\\
\mathbf{elif}\;t \leq -1.4 \cdot 10^{-110}:\\
\;\;\;\;t_3\\
\mathbf{elif}\;t \leq -1.8 \cdot 10^{-131}:\\
\;\;\;\;t_5\\
\mathbf{elif}\;t \leq -3.8 \cdot 10^{-280}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq 2.1 \cdot 10^{-307}:\\
\;\;\;\;1\\
\mathbf{elif}\;t \leq 5 \cdot 10^{-298}:\\
\;\;\;\;t_5\\
\mathbf{elif}\;t \leq 5 \cdot 10^{-251}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq 2.2 \cdot 10^{-231}:\\
\;\;\;\;\frac{x - z \cdot \frac{y}{x}}{x + 1}\\
\mathbf{elif}\;t \leq 2.7 \cdot 10^{-106}:\\
\;\;\;\;t_3\\
\mathbf{else}:\\
\;\;\;\;t_4\\
\end{array}
\]
Alternative 2 Accuracy 85.5% Cost 1356
\[\begin{array}{l}
t_1 := \frac{x + y \cdot \frac{z}{z \cdot t - x}}{x + 1}\\
\mathbf{if}\;t \leq -2 \cdot 10^{-278}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq 2.7 \cdot 10^{-205}:\\
\;\;\;\;\frac{x + \frac{x - y \cdot z}{x}}{x + 1}\\
\mathbf{elif}\;t \leq 4 \cdot 10^{+34}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\end{array}
\]
Alternative 3 Accuracy 85.6% Cost 1356
\[\begin{array}{l}
t_1 := \frac{x + \frac{y}{\frac{z \cdot t - x}{z}}}{x + 1}\\
\mathbf{if}\;t \leq -3.2 \cdot 10^{-278}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq 5.3 \cdot 10^{-202}:\\
\;\;\;\;\frac{x + \frac{x - y \cdot z}{x}}{x + 1}\\
\mathbf{elif}\;t \leq 1.45 \cdot 10^{+35}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\end{array}
\]
Alternative 4 Accuracy 81.6% Cost 1097
\[\begin{array}{l}
\mathbf{if}\;t \leq -2.25 \cdot 10^{-73} \lor \neg \left(t \leq 6.1 \cdot 10^{-106}\right):\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\mathbf{else}:\\
\;\;\;\;\frac{x + \frac{x - y \cdot z}{x}}{x + 1}\\
\end{array}
\]
Alternative 5 Accuracy 81.6% Cost 1097
\[\begin{array}{l}
\mathbf{if}\;t \leq -2.85 \cdot 10^{-73} \lor \neg \left(t \leq 2.3 \cdot 10^{-106}\right):\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\mathbf{else}:\\
\;\;\;\;\frac{1 + \left(x - \frac{y \cdot z}{x}\right)}{x + 1}\\
\end{array}
\]
Alternative 6 Accuracy 75.3% Cost 969
\[\begin{array}{l}
\mathbf{if}\;t \leq -8.5 \cdot 10^{-146} \lor \neg \left(t \leq 1.3 \cdot 10^{-109}\right):\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\mathbf{else}:\\
\;\;\;\;y \cdot z + \left(1 - y \cdot \frac{z}{x}\right)\\
\end{array}
\]
Alternative 7 Accuracy 67.6% Cost 848
\[\begin{array}{l}
\mathbf{if}\;x \leq -6 \cdot 10^{-53}:\\
\;\;\;\;1\\
\mathbf{elif}\;x \leq 2 \cdot 10^{-156}:\\
\;\;\;\;\frac{y}{t}\\
\mathbf{elif}\;x \leq 4.3 \cdot 10^{-57}:\\
\;\;\;\;x - \frac{x}{z \cdot t}\\
\mathbf{elif}\;x \leq 6.5 \cdot 10^{-20}:\\
\;\;\;\;1\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{x + 1}\\
\end{array}
\]
Alternative 8 Accuracy 75.7% Cost 841
\[\begin{array}{l}
\mathbf{if}\;z \leq -8.2 \cdot 10^{-47} \lor \neg \left(z \leq 3.1 \cdot 10^{-133}\right):\\
\;\;\;\;\frac{x + \frac{y}{t}}{x + 1}\\
\mathbf{else}:\\
\;\;\;\;1\\
\end{array}
\]
Alternative 9 Accuracy 67.2% Cost 584
\[\begin{array}{l}
\mathbf{if}\;x \leq -9.6 \cdot 10^{-53}:\\
\;\;\;\;1\\
\mathbf{elif}\;x \leq 4.9 \cdot 10^{-157}:\\
\;\;\;\;\frac{y}{t}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{x + 1}\\
\end{array}
\]
Alternative 10 Accuracy 67.6% Cost 456
\[\begin{array}{l}
\mathbf{if}\;x \leq -2.4 \cdot 10^{-53}:\\
\;\;\;\;1\\
\mathbf{elif}\;x \leq 5.6 \cdot 10^{-60}:\\
\;\;\;\;\frac{y}{t}\\
\mathbf{else}:\\
\;\;\;\;1\\
\end{array}
\]
Alternative 11 Accuracy 55.4% Cost 64
\[1
\]