\[ \begin{array}{c}[x, y, z] = \mathsf{sort}([x, y, z])\\ \end{array} \]
Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z}
\]
↓
\[\begin{array}{l}
\mathbf{if}\;y \leq -2 \cdot 10^{-310}:\\
\;\;\;\;2 \cdot \frac{\sqrt{\left(-z\right) - x}}{\sqrt{\frac{-1}{y}}}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
\]
(FPCore (x y z)
:precision binary64
(* 2.0 (sqrt (+ (+ (* x y) (* x z)) (* y z))))) ↓
(FPCore (x y z)
:precision binary64
(if (<= y -2e-310)
(* 2.0 (/ (sqrt (- (- z) x)) (sqrt (/ -1.0 y))))
(* 2.0 (* (sqrt z) (sqrt y))))) double code(double x, double y, double z) {
return 2.0 * sqrt((((x * y) + (x * z)) + (y * z)));
}
↓
double code(double x, double y, double z) {
double tmp;
if (y <= -2e-310) {
tmp = 2.0 * (sqrt((-z - x)) / sqrt((-1.0 / y)));
} else {
tmp = 2.0 * (sqrt(z) * sqrt(y));
}
return tmp;
}
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
code = 2.0d0 * sqrt((((x * y) + (x * z)) + (y * z)))
end function
↓
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8) :: tmp
if (y <= (-2d-310)) then
tmp = 2.0d0 * (sqrt((-z - x)) / sqrt(((-1.0d0) / y)))
else
tmp = 2.0d0 * (sqrt(z) * sqrt(y))
end if
code = tmp
end function
public static double code(double x, double y, double z) {
return 2.0 * Math.sqrt((((x * y) + (x * z)) + (y * z)));
}
↓
public static double code(double x, double y, double z) {
double tmp;
if (y <= -2e-310) {
tmp = 2.0 * (Math.sqrt((-z - x)) / Math.sqrt((-1.0 / y)));
} else {
tmp = 2.0 * (Math.sqrt(z) * Math.sqrt(y));
}
return tmp;
}
def code(x, y, z):
return 2.0 * math.sqrt((((x * y) + (x * z)) + (y * z)))
↓
def code(x, y, z):
tmp = 0
if y <= -2e-310:
tmp = 2.0 * (math.sqrt((-z - x)) / math.sqrt((-1.0 / y)))
else:
tmp = 2.0 * (math.sqrt(z) * math.sqrt(y))
return tmp
function code(x, y, z)
return Float64(2.0 * sqrt(Float64(Float64(Float64(x * y) + Float64(x * z)) + Float64(y * z))))
end
↓
function code(x, y, z)
tmp = 0.0
if (y <= -2e-310)
tmp = Float64(2.0 * Float64(sqrt(Float64(Float64(-z) - x)) / sqrt(Float64(-1.0 / y))));
else
tmp = Float64(2.0 * Float64(sqrt(z) * sqrt(y)));
end
return tmp
end
function tmp = code(x, y, z)
tmp = 2.0 * sqrt((((x * y) + (x * z)) + (y * z)));
end
↓
function tmp_2 = code(x, y, z)
tmp = 0.0;
if (y <= -2e-310)
tmp = 2.0 * (sqrt((-z - x)) / sqrt((-1.0 / y)));
else
tmp = 2.0 * (sqrt(z) * sqrt(y));
end
tmp_2 = tmp;
end
code[x_, y_, z_] := N[(2.0 * N[Sqrt[N[(N[(N[(x * y), $MachinePrecision] + N[(x * z), $MachinePrecision]), $MachinePrecision] + N[(y * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_] := If[LessEqual[y, -2e-310], N[(2.0 * N[(N[Sqrt[N[((-z) - x), $MachinePrecision]], $MachinePrecision] / N[Sqrt[N[(-1.0 / y), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(2.0 * N[(N[Sqrt[z], $MachinePrecision] * N[Sqrt[y], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z}
↓
\begin{array}{l}
\mathbf{if}\;y \leq -2 \cdot 10^{-310}:\\
\;\;\;\;2 \cdot \frac{\sqrt{\left(-z\right) - x}}{\sqrt{\frac{-1}{y}}}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
Alternatives Alternative 1 Accuracy 82.4% Cost 14148
\[\begin{array}{l}
\mathbf{if}\;\left(y \cdot x + z \cdot x\right) + y \cdot z \leq 2 \cdot 10^{+306}:\\
\;\;\;\;2 \cdot \sqrt{\mathsf{fma}\left(x, y, z \cdot \left(y + x\right)\right)}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \frac{\sqrt{z + x}}{{y}^{-0.5}}\\
\end{array}
\]
Alternative 2 Accuracy 82.4% Cost 14084
\[\begin{array}{l}
\mathbf{if}\;\left(y \cdot x + z \cdot x\right) + y \cdot z \leq 2 \cdot 10^{+306}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot z + x \cdot \left(y + z\right)}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \frac{\sqrt{z + x}}{{y}^{-0.5}}\\
\end{array}
\]
Alternative 3 Accuracy 82.4% Cost 13892
\[\begin{array}{l}
\mathbf{if}\;\left(y \cdot x + z \cdot x\right) + y \cdot z \leq 2 \cdot 10^{+306}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot z + x \cdot \left(y + z\right)}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
\]
Alternative 4 Accuracy 68.7% Cost 7104
\[2 \cdot \sqrt{y \cdot z + x \cdot \left(y + z\right)}
\]
Alternative 5 Accuracy 67.0% Cost 6980
\[\begin{array}{l}
\mathbf{if}\;y \leq -3.4 \cdot 10^{-254}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot x}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right)}\\
\end{array}
\]
Alternative 6 Accuracy 68.3% Cost 6980
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.55 \cdot 10^{-267}:\\
\;\;\;\;2 \cdot \sqrt{x \cdot \left(y + z\right)}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right)}\\
\end{array}
\]
Alternative 7 Accuracy 66.1% Cost 6852
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.55 \cdot 10^{-267}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot x}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot z}\\
\end{array}
\]
Alternative 8 Accuracy 33.8% Cost 6720
\[2 \cdot \sqrt{y \cdot x}
\]