Math FPCore C Julia Wolfram TeX \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1
\]
↓
\[{\left(\mathsf{hypot}\left(a, b\right)\right)}^{4} + \mathsf{fma}\left(4, \mathsf{fma}\left(a, \mathsf{fma}\left(a, a, a\right), b \cdot \left(b \cdot \mathsf{fma}\left(a, -3, 1\right)\right)\right), -1\right)
\]
(FPCore (a b)
:precision binary64
(-
(+
(pow (+ (* a a) (* b b)) 2.0)
(* 4.0 (+ (* (* a a) (+ 1.0 a)) (* (* b b) (- 1.0 (* 3.0 a))))))
1.0)) ↓
(FPCore (a b)
:precision binary64
(+
(pow (hypot a b) 4.0)
(fma 4.0 (fma a (fma a a a) (* b (* b (fma a -3.0 1.0)))) -1.0))) double code(double a, double b) {
return (pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0;
}
↓
double code(double a, double b) {
return pow(hypot(a, b), 4.0) + fma(4.0, fma(a, fma(a, a, a), (b * (b * fma(a, -3.0, 1.0)))), -1.0);
}
function code(a, b)
return Float64(Float64((Float64(Float64(a * a) + Float64(b * b)) ^ 2.0) + Float64(4.0 * Float64(Float64(Float64(a * a) * Float64(1.0 + a)) + Float64(Float64(b * b) * Float64(1.0 - Float64(3.0 * a)))))) - 1.0)
end
↓
function code(a, b)
return Float64((hypot(a, b) ^ 4.0) + fma(4.0, fma(a, fma(a, a, a), Float64(b * Float64(b * fma(a, -3.0, 1.0)))), -1.0))
end
code[a_, b_] := N[(N[(N[Power[N[(N[(a * a), $MachinePrecision] + N[(b * b), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[(4.0 * N[(N[(N[(a * a), $MachinePrecision] * N[(1.0 + a), $MachinePrecision]), $MachinePrecision] + N[(N[(b * b), $MachinePrecision] * N[(1.0 - N[(3.0 * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision]
↓
code[a_, b_] := N[(N[Power[N[Sqrt[a ^ 2 + b ^ 2], $MachinePrecision], 4.0], $MachinePrecision] + N[(4.0 * N[(a * N[(a * a + a), $MachinePrecision] + N[(b * N[(b * N[(a * -3.0 + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision]), $MachinePrecision]
\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1
↓
{\left(\mathsf{hypot}\left(a, b\right)\right)}^{4} + \mathsf{fma}\left(4, \mathsf{fma}\left(a, \mathsf{fma}\left(a, a, a\right), b \cdot \left(b \cdot \mathsf{fma}\left(a, -3, 1\right)\right)\right), -1\right)
Alternatives Alternative 1 Accuracy 99.6% Cost 7936
\[-1 + \left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(b \cdot b + \left(a \cdot a\right) \cdot \left(a + 1\right)\right)\right)
\]
Alternative 2 Accuracy 95.9% Cost 7560
\[\begin{array}{l}
\mathbf{if}\;b \leq -1.55 \cdot 10^{-6}:\\
\;\;\;\;-1 + \left({b}^{4} + 4 \cdot \left(b \cdot b\right)\right)\\
\mathbf{elif}\;b \leq 1.8 \cdot 10^{-38}:\\
\;\;\;\;-1 + \left({a}^{4} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right)\right)\right)\\
\mathbf{else}:\\
\;\;\;\;-1 + {b}^{4}\\
\end{array}
\]
Alternative 3 Accuracy 95.8% Cost 7172
\[\begin{array}{l}
\mathbf{if}\;b \leq -5.5 \cdot 10^{-7}:\\
\;\;\;\;-1 + \left({b}^{4} + 4 \cdot \left(b \cdot b\right)\right)\\
\mathbf{elif}\;b \leq 1.8 \cdot 10^{-38}:\\
\;\;\;\;-1 + \left(a \cdot a\right) \cdot \left(4 + a \cdot \left(a + 4\right)\right)\\
\mathbf{else}:\\
\;\;\;\;-1 + {b}^{4}\\
\end{array}
\]
Alternative 4 Accuracy 95.3% Cost 6921
\[\begin{array}{l}
\mathbf{if}\;b \leq -0.056 \lor \neg \left(b \leq 5 \cdot 10^{-42}\right):\\
\;\;\;\;-1 + {b}^{4}\\
\mathbf{else}:\\
\;\;\;\;-1 + \left(a \cdot a\right) \cdot \left(4 + a \cdot \left(a + 4\right)\right)\\
\end{array}
\]
Alternative 5 Accuracy 96.4% Cost 6792
\[\begin{array}{l}
\mathbf{if}\;b \leq -85:\\
\;\;\;\;{b}^{4}\\
\mathbf{elif}\;b \leq 1.9:\\
\;\;\;\;-1 + \left(a \cdot a\right) \cdot \left(4 + a \cdot \left(a + 4\right)\right)\\
\mathbf{else}:\\
\;\;\;\;{b}^{4}\\
\end{array}
\]
Alternative 6 Accuracy 81.0% Cost 832
\[-1 + \left(a \cdot a\right) \cdot \left(4 + a \cdot \left(a + 4\right)\right)
\]
Alternative 7 Accuracy 79.0% Cost 704
\[-1 + \left(a \cdot a\right) \cdot \left(4 + a \cdot a\right)
\]
Alternative 8 Accuracy 79.5% Cost 704
\[-1 + \left(a \cdot a\right) \cdot \left(a \cdot \left(a + 4\right)\right)
\]
Alternative 9 Accuracy 78.8% Cost 576
\[-1 + \left(a \cdot a\right) \cdot \left(a \cdot a\right)
\]
Alternative 10 Accuracy 64.3% Cost 448
\[-1 + a \cdot \left(a \cdot 4\right)
\]
Alternative 11 Accuracy 63.0% Cost 64
\[-1
\]