\[x \cdot \left(1 - \left(1 - y\right) \cdot z\right)
\]
↓
\[\begin{array}{l}
t_0 := \left(1 - y\right) \cdot z\\
\mathbf{if}\;t_0 \leq -\infty:\\
\;\;\;\;z \cdot \left(y \cdot x\right)\\
\mathbf{elif}\;t_0 \leq 5 \cdot 10^{+276}:\\
\;\;\;\;x - t_0 \cdot x\\
\mathbf{else}:\\
\;\;\;\;\left(y + -1\right) \cdot \left(z \cdot x\right)\\
\end{array}
\]
(FPCore (x y z) :precision binary64 (* x (- 1.0 (* (- 1.0 y) z))))
↓
(FPCore (x y z)
:precision binary64
(let* ((t_0 (* (- 1.0 y) z)))
(if (<= t_0 (- INFINITY))
(* z (* y x))
(if (<= t_0 5e+276) (- x (* t_0 x)) (* (+ y -1.0) (* z x))))))double code(double x, double y, double z) {
return x * (1.0 - ((1.0 - y) * z));
}
↓
double code(double x, double y, double z) {
double t_0 = (1.0 - y) * z;
double tmp;
if (t_0 <= -((double) INFINITY)) {
tmp = z * (y * x);
} else if (t_0 <= 5e+276) {
tmp = x - (t_0 * x);
} else {
tmp = (y + -1.0) * (z * x);
}
return tmp;
}
public static double code(double x, double y, double z) {
return x * (1.0 - ((1.0 - y) * z));
}
↓
public static double code(double x, double y, double z) {
double t_0 = (1.0 - y) * z;
double tmp;
if (t_0 <= -Double.POSITIVE_INFINITY) {
tmp = z * (y * x);
} else if (t_0 <= 5e+276) {
tmp = x - (t_0 * x);
} else {
tmp = (y + -1.0) * (z * x);
}
return tmp;
}
def code(x, y, z):
return x * (1.0 - ((1.0 - y) * z))
↓
def code(x, y, z):
t_0 = (1.0 - y) * z
tmp = 0
if t_0 <= -math.inf:
tmp = z * (y * x)
elif t_0 <= 5e+276:
tmp = x - (t_0 * x)
else:
tmp = (y + -1.0) * (z * x)
return tmp
function code(x, y, z)
return Float64(x * Float64(1.0 - Float64(Float64(1.0 - y) * z)))
end
↓
function code(x, y, z)
t_0 = Float64(Float64(1.0 - y) * z)
tmp = 0.0
if (t_0 <= Float64(-Inf))
tmp = Float64(z * Float64(y * x));
elseif (t_0 <= 5e+276)
tmp = Float64(x - Float64(t_0 * x));
else
tmp = Float64(Float64(y + -1.0) * Float64(z * x));
end
return tmp
end
function tmp = code(x, y, z)
tmp = x * (1.0 - ((1.0 - y) * z));
end
↓
function tmp_2 = code(x, y, z)
t_0 = (1.0 - y) * z;
tmp = 0.0;
if (t_0 <= -Inf)
tmp = z * (y * x);
elseif (t_0 <= 5e+276)
tmp = x - (t_0 * x);
else
tmp = (y + -1.0) * (z * x);
end
tmp_2 = tmp;
end
code[x_, y_, z_] := N[(x * N[(1.0 - N[(N[(1.0 - y), $MachinePrecision] * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_] := Block[{t$95$0 = N[(N[(1.0 - y), $MachinePrecision] * z), $MachinePrecision]}, If[LessEqual[t$95$0, (-Infinity)], N[(z * N[(y * x), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 5e+276], N[(x - N[(t$95$0 * x), $MachinePrecision]), $MachinePrecision], N[(N[(y + -1.0), $MachinePrecision] * N[(z * x), $MachinePrecision]), $MachinePrecision]]]]
x \cdot \left(1 - \left(1 - y\right) \cdot z\right)
↓
\begin{array}{l}
t_0 := \left(1 - y\right) \cdot z\\
\mathbf{if}\;t_0 \leq -\infty:\\
\;\;\;\;z \cdot \left(y \cdot x\right)\\
\mathbf{elif}\;t_0 \leq 5 \cdot 10^{+276}:\\
\;\;\;\;x - t_0 \cdot x\\
\mathbf{else}:\\
\;\;\;\;\left(y + -1\right) \cdot \left(z \cdot x\right)\\
\end{array}
Alternatives
| Alternative 1 |
|---|
| Error | 45.03% |
|---|
| Cost | 1904 |
|---|
\[\begin{array}{l}
t_0 := x \cdot \left(y \cdot z\right)\\
t_1 := y \cdot \left(z \cdot x\right)\\
t_2 := z \cdot \left(-x\right)\\
\mathbf{if}\;y \leq -3.7 \cdot 10^{+129}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq -3 \cdot 10^{+74}:\\
\;\;\;\;x\\
\mathbf{elif}\;y \leq -5.5 \cdot 10^{+53}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq -4.4 \cdot 10^{+26}:\\
\;\;\;\;x\\
\mathbf{elif}\;y \leq -16500000:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq -1.35 \cdot 10^{-80}:\\
\;\;\;\;x\\
\mathbf{elif}\;y \leq -4.9 \cdot 10^{-181}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;y \leq -4.4 \cdot 10^{-287}:\\
\;\;\;\;x\\
\mathbf{elif}\;y \leq 4.6 \cdot 10^{-200}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;y \leq 1.15 \cdot 10^{-105}:\\
\;\;\;\;x\\
\mathbf{elif}\;y \leq 1.18 \cdot 10^{-51}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;y \leq 3100000000000:\\
\;\;\;\;x\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
| Alternative 2 |
|---|
| Error | 0.15% |
|---|
| Cost | 1352 |
|---|
\[\begin{array}{l}
t_0 := \left(1 - y\right) \cdot z\\
\mathbf{if}\;t_0 \leq -\infty:\\
\;\;\;\;z \cdot \left(y \cdot x\right)\\
\mathbf{elif}\;t_0 \leq 5 \cdot 10^{+276}:\\
\;\;\;\;x \cdot \left(1 - t_0\right)\\
\mathbf{else}:\\
\;\;\;\;\left(y + -1\right) \cdot \left(z \cdot x\right)\\
\end{array}
\]
| Alternative 3 |
|---|
| Error | 18.75% |
|---|
| Cost | 1112 |
|---|
\[\begin{array}{l}
t_0 := x \cdot \left(y \cdot z\right)\\
t_1 := y \cdot \left(z \cdot x\right)\\
t_2 := x \cdot \left(1 - z\right)\\
\mathbf{if}\;y \leq -2.05 \cdot 10^{+131}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq -4.5 \cdot 10^{+73}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;y \leq -2.9 \cdot 10^{+54}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq -2.75 \cdot 10^{+26}:\\
\;\;\;\;x\\
\mathbf{elif}\;y \leq -16500000:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq 3100000000000:\\
\;\;\;\;t_2\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
| Alternative 4 |
|---|
| Error | 18.72% |
|---|
| Cost | 1112 |
|---|
\[\begin{array}{l}
t_0 := y \cdot \left(z \cdot x\right)\\
t_1 := x \cdot \left(1 - z\right)\\
\mathbf{if}\;y \leq -9.2 \cdot 10^{+137}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;y \leq -2.7 \cdot 10^{+73}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;y \leq -1.2 \cdot 10^{+54}:\\
\;\;\;\;x \cdot \left(y \cdot z\right)\\
\mathbf{elif}\;y \leq -2.65 \cdot 10^{+26}:\\
\;\;\;\;x\\
\mathbf{elif}\;y \leq -15500000:\\
\;\;\;\;x \cdot \left(z \cdot \left(y + -1\right)\right)\\
\mathbf{elif}\;y \leq 5900000000000:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
| Alternative 5 |
|---|
| Error | 14.47% |
|---|
| Cost | 713 |
|---|
\[\begin{array}{l}
\mathbf{if}\;z \leq -19000 \lor \neg \left(z \leq 1.9 \cdot 10^{-14}\right):\\
\;\;\;\;\left(y + -1\right) \cdot \left(z \cdot x\right)\\
\mathbf{else}:\\
\;\;\;\;x \cdot \left(1 - z\right)\\
\end{array}
\]
| Alternative 6 |
|---|
| Error | 2.11% |
|---|
| Cost | 713 |
|---|
\[\begin{array}{l}
\mathbf{if}\;z \leq -1 \lor \neg \left(z \leq 1.9 \cdot 10^{-14}\right):\\
\;\;\;\;\left(y + -1\right) \cdot \left(z \cdot x\right)\\
\mathbf{else}:\\
\;\;\;\;x + x \cdot \left(y \cdot z\right)\\
\end{array}
\]
| Alternative 7 |
|---|
| Error | 31.35% |
|---|
| Cost | 521 |
|---|
\[\begin{array}{l}
\mathbf{if}\;z \leq -1 \lor \neg \left(z \leq 1.9 \cdot 10^{-14}\right):\\
\;\;\;\;z \cdot \left(-x\right)\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
| Alternative 8 |
|---|
| Error | 52.47% |
|---|
| Cost | 64 |
|---|
\[x
\]