?

Average Error: 97.0% → 99.9%
Time: 12.2s
Precision: binary64
Cost: 7428.00

?

\[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
\[\begin{array}{l} \mathbf{if}\;k \leq 10^{+14}:\\ \;\;\;\;\frac{a \cdot {k}^{m}}{\left(1 + k \cdot 10\right) + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;{k}^{m} \cdot \frac{\frac{a}{k}}{k}\\ \end{array} \]
(FPCore (a k m)
 :precision binary64
 (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))
(FPCore (a k m)
 :precision binary64
 (if (<= k 1e+14)
   (/ (* a (pow k m)) (+ (+ 1.0 (* k 10.0)) (* k k)))
   (* (pow k m) (/ (/ a k) k))))
double code(double a, double k, double m) {
	return (a * pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
double code(double a, double k, double m) {
	double tmp;
	if (k <= 1e+14) {
		tmp = (a * pow(k, m)) / ((1.0 + (k * 10.0)) + (k * k));
	} else {
		tmp = pow(k, m) * ((a / k) / k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = (a * (k ** m)) / ((1.0d0 + (10.0d0 * k)) + (k * k))
end function
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (k <= 1d+14) then
        tmp = (a * (k ** m)) / ((1.0d0 + (k * 10.0d0)) + (k * k))
    else
        tmp = (k ** m) * ((a / k) / k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	return (a * Math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
public static double code(double a, double k, double m) {
	double tmp;
	if (k <= 1e+14) {
		tmp = (a * Math.pow(k, m)) / ((1.0 + (k * 10.0)) + (k * k));
	} else {
		tmp = Math.pow(k, m) * ((a / k) / k);
	}
	return tmp;
}
def code(a, k, m):
	return (a * math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k))
def code(a, k, m):
	tmp = 0
	if k <= 1e+14:
		tmp = (a * math.pow(k, m)) / ((1.0 + (k * 10.0)) + (k * k))
	else:
		tmp = math.pow(k, m) * ((a / k) / k)
	return tmp
function code(a, k, m)
	return Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(10.0 * k)) + Float64(k * k)))
end
function code(a, k, m)
	tmp = 0.0
	if (k <= 1e+14)
		tmp = Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(k * 10.0)) + Float64(k * k)));
	else
		tmp = Float64((k ^ m) * Float64(Float64(a / k) / k));
	end
	return tmp
end
function tmp = code(a, k, m)
	tmp = (a * (k ^ m)) / ((1.0 + (10.0 * k)) + (k * k));
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (k <= 1e+14)
		tmp = (a * (k ^ m)) / ((1.0 + (k * 10.0)) + (k * k));
	else
		tmp = (k ^ m) * ((a / k) / k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(10.0 * k), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[a_, k_, m_] := If[LessEqual[k, 1e+14], N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(k * 10.0), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[Power[k, m], $MachinePrecision] * N[(N[(a / k), $MachinePrecision] / k), $MachinePrecision]), $MachinePrecision]]
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\begin{array}{l}
\mathbf{if}\;k \leq 10^{+14}:\\
\;\;\;\;\frac{a \cdot {k}^{m}}{\left(1 + k \cdot 10\right) + k \cdot k}\\

\mathbf{else}:\\
\;\;\;\;{k}^{m} \cdot \frac{\frac{a}{k}}{k}\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Split input into 2 regimes
  2. if k < 1e14

    1. Initial program 99.9

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]

    if 1e14 < k

    1. Initial program 92.0

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Taylor expanded in k around 0 91.9

      \[\leadsto \frac{a \cdot {k}^{m}}{\color{blue}{1} + k \cdot k} \]
    3. Taylor expanded in k around inf 91.9

      \[\leadsto \color{blue}{\frac{a \cdot e^{-1 \cdot \left(\log \left(\frac{1}{k}\right) \cdot m\right)}}{{k}^{2}}} \]
    4. Simplified99.7

      \[\leadsto \color{blue}{{k}^{m} \cdot \frac{\frac{a}{k}}{k}} \]
      Proof

      [Start]91.9

      \[ \frac{a \cdot e^{-1 \cdot \left(\log \left(\frac{1}{k}\right) \cdot m\right)}}{{k}^{2}} \]

      associate-/l* [=>]91.9

      \[ \color{blue}{\frac{a}{\frac{{k}^{2}}{e^{-1 \cdot \left(\log \left(\frac{1}{k}\right) \cdot m\right)}}}} \]

      associate-/r/ [=>]91.9

      \[ \color{blue}{\frac{a}{{k}^{2}} \cdot e^{-1 \cdot \left(\log \left(\frac{1}{k}\right) \cdot m\right)}} \]

      *-commutative [=>]91.9

      \[ \color{blue}{e^{-1 \cdot \left(\log \left(\frac{1}{k}\right) \cdot m\right)} \cdot \frac{a}{{k}^{2}}} \]

      mul-1-neg [=>]91.9

      \[ e^{\color{blue}{-\log \left(\frac{1}{k}\right) \cdot m}} \cdot \frac{a}{{k}^{2}} \]

      log-rec [=>]91.9

      \[ e^{-\color{blue}{\left(-\log k\right)} \cdot m} \cdot \frac{a}{{k}^{2}} \]

      distribute-lft-neg-out [=>]91.9

      \[ e^{-\color{blue}{\left(-\log k \cdot m\right)}} \cdot \frac{a}{{k}^{2}} \]

      remove-double-neg [=>]91.9

      \[ e^{\color{blue}{\log k \cdot m}} \cdot \frac{a}{{k}^{2}} \]

      exp-to-pow [=>]91.9

      \[ \color{blue}{{k}^{m}} \cdot \frac{a}{{k}^{2}} \]

      unpow2 [=>]91.9

      \[ {k}^{m} \cdot \frac{a}{\color{blue}{k \cdot k}} \]

      associate-/r* [=>]99.7

      \[ {k}^{m} \cdot \color{blue}{\frac{\frac{a}{k}}{k}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification99.9

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 10^{+14}:\\ \;\;\;\;\frac{a \cdot {k}^{m}}{\left(1 + k \cdot 10\right) + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;{k}^{m} \cdot \frac{\frac{a}{k}}{k}\\ \end{array} \]

Alternatives

Alternative 1
Error99.8%
Cost7300.00
\[\begin{array}{l} \mathbf{if}\;k \leq 10^{+14}:\\ \;\;\;\;\frac{{k}^{m}}{\frac{1 + k \cdot \left(k + 10\right)}{a}}\\ \mathbf{else}:\\ \;\;\;\;{k}^{m} \cdot \frac{\frac{a}{k}}{k}\\ \end{array} \]
Alternative 2
Error98.8%
Cost7172.00
\[\begin{array}{l} \mathbf{if}\;k \leq 1.6 \cdot 10^{-5}:\\ \;\;\;\;\left(a \cdot {k}^{m}\right) \cdot \left(1 + k \cdot -10\right)\\ \mathbf{else}:\\ \;\;\;\;{k}^{m} \cdot \frac{\frac{a}{k}}{k}\\ \end{array} \]
Alternative 3
Error98.6%
Cost7044.00
\[\begin{array}{l} \mathbf{if}\;k \leq 1.6 \cdot 10^{-5}:\\ \;\;\;\;a \cdot {k}^{m}\\ \mathbf{else}:\\ \;\;\;\;{k}^{m} \cdot \frac{\frac{a}{k}}{k}\\ \end{array} \]
Alternative 4
Error96.1%
Cost6921.00
\[\begin{array}{l} \mathbf{if}\;m \leq -0.95 \lor \neg \left(m \leq 0.0052\right):\\ \;\;\;\;a \cdot {k}^{m}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \end{array} \]
Alternative 5
Error69.6%
Cost841.00
\[\begin{array}{l} \mathbf{if}\;m \leq -0.68 \lor \neg \left(m \leq 5.2 \cdot 10^{+49}\right):\\ \;\;\;\;\left(1 + \frac{a}{k \cdot k}\right) + -1\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{1 + k \cdot k}\\ \end{array} \]
Alternative 6
Error70.7%
Cost841.00
\[\begin{array}{l} \mathbf{if}\;m \leq -1.62 \lor \neg \left(m \leq 4 \cdot 10^{+54}\right):\\ \;\;\;\;\left(1 + \frac{a}{k \cdot k}\right) + -1\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \end{array} \]
Alternative 7
Error63.0%
Cost712.00
\[\begin{array}{l} \mathbf{if}\;k \leq -0.44:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 0.098:\\ \;\;\;\;a + -10 \cdot \left(k \cdot a\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \]
Alternative 8
Error63.1%
Cost712.00
\[\begin{array}{l} \mathbf{if}\;k \leq -9.8:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 10.2:\\ \;\;\;\;\frac{a}{1 + k \cdot 10}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \]
Alternative 9
Error61.8%
Cost585.00
\[\begin{array}{l} \mathbf{if}\;k \leq -1 \lor \neg \left(k \leq 1\right):\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;a\\ \end{array} \]
Alternative 10
Error62.8%
Cost584.00
\[\begin{array}{l} \mathbf{if}\;k \leq -1:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 1:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \]
Alternative 11
Error62.8%
Cost580.00
\[\begin{array}{l} \mathbf{if}\;k \leq 300000000000:\\ \;\;\;\;\frac{a}{1 + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \]
Alternative 12
Error27.4%
Cost64.00
\[a \]

Error

Reproduce?

herbie shell --seed 2023121 
(FPCore (a k m)
  :name "Falkner and Boettcher, Appendix A"
  :precision binary64
  (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))