?

Average Error: 26.12% → 1.23%
Time: 10.5s
Precision: binary64
Cost: 33097

?

\[\pi \cdot \ell - \frac{1}{F \cdot F} \cdot \tan \left(\pi \cdot \ell\right) \]
\[\begin{array}{l} \mathbf{if}\;\pi \cdot \ell \leq -1 \cdot 10^{+22} \lor \neg \left(\pi \cdot \ell \leq 0.001\right):\\ \;\;\;\;\pi \cdot \ell\\ \mathbf{else}:\\ \;\;\;\;\pi \cdot \ell - \frac{\frac{1}{F}}{\frac{F}{\tan \left(\pi \cdot \ell\right)}}\\ \end{array} \]
(FPCore (F l)
 :precision binary64
 (- (* PI l) (* (/ 1.0 (* F F)) (tan (* PI l)))))
(FPCore (F l)
 :precision binary64
 (if (or (<= (* PI l) -1e+22) (not (<= (* PI l) 0.001)))
   (* PI l)
   (- (* PI l) (/ (/ 1.0 F) (/ F (tan (* PI l)))))))
double code(double F, double l) {
	return (((double) M_PI) * l) - ((1.0 / (F * F)) * tan((((double) M_PI) * l)));
}
double code(double F, double l) {
	double tmp;
	if (((((double) M_PI) * l) <= -1e+22) || !((((double) M_PI) * l) <= 0.001)) {
		tmp = ((double) M_PI) * l;
	} else {
		tmp = (((double) M_PI) * l) - ((1.0 / F) / (F / tan((((double) M_PI) * l))));
	}
	return tmp;
}
public static double code(double F, double l) {
	return (Math.PI * l) - ((1.0 / (F * F)) * Math.tan((Math.PI * l)));
}
public static double code(double F, double l) {
	double tmp;
	if (((Math.PI * l) <= -1e+22) || !((Math.PI * l) <= 0.001)) {
		tmp = Math.PI * l;
	} else {
		tmp = (Math.PI * l) - ((1.0 / F) / (F / Math.tan((Math.PI * l))));
	}
	return tmp;
}
def code(F, l):
	return (math.pi * l) - ((1.0 / (F * F)) * math.tan((math.pi * l)))
def code(F, l):
	tmp = 0
	if ((math.pi * l) <= -1e+22) or not ((math.pi * l) <= 0.001):
		tmp = math.pi * l
	else:
		tmp = (math.pi * l) - ((1.0 / F) / (F / math.tan((math.pi * l))))
	return tmp
function code(F, l)
	return Float64(Float64(pi * l) - Float64(Float64(1.0 / Float64(F * F)) * tan(Float64(pi * l))))
end
function code(F, l)
	tmp = 0.0
	if ((Float64(pi * l) <= -1e+22) || !(Float64(pi * l) <= 0.001))
		tmp = Float64(pi * l);
	else
		tmp = Float64(Float64(pi * l) - Float64(Float64(1.0 / F) / Float64(F / tan(Float64(pi * l)))));
	end
	return tmp
end
function tmp = code(F, l)
	tmp = (pi * l) - ((1.0 / (F * F)) * tan((pi * l)));
end
function tmp_2 = code(F, l)
	tmp = 0.0;
	if (((pi * l) <= -1e+22) || ~(((pi * l) <= 0.001)))
		tmp = pi * l;
	else
		tmp = (pi * l) - ((1.0 / F) / (F / tan((pi * l))));
	end
	tmp_2 = tmp;
end
code[F_, l_] := N[(N[(Pi * l), $MachinePrecision] - N[(N[(1.0 / N[(F * F), $MachinePrecision]), $MachinePrecision] * N[Tan[N[(Pi * l), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[F_, l_] := If[Or[LessEqual[N[(Pi * l), $MachinePrecision], -1e+22], N[Not[LessEqual[N[(Pi * l), $MachinePrecision], 0.001]], $MachinePrecision]], N[(Pi * l), $MachinePrecision], N[(N[(Pi * l), $MachinePrecision] - N[(N[(1.0 / F), $MachinePrecision] / N[(F / N[Tan[N[(Pi * l), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\pi \cdot \ell - \frac{1}{F \cdot F} \cdot \tan \left(\pi \cdot \ell\right)
\begin{array}{l}
\mathbf{if}\;\pi \cdot \ell \leq -1 \cdot 10^{+22} \lor \neg \left(\pi \cdot \ell \leq 0.001\right):\\
\;\;\;\;\pi \cdot \ell\\

\mathbf{else}:\\
\;\;\;\;\pi \cdot \ell - \frac{\frac{1}{F}}{\frac{F}{\tan \left(\pi \cdot \ell\right)}}\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Split input into 2 regimes
  2. if (*.f64 (PI.f64) l) < -1e22 or 1e-3 < (*.f64 (PI.f64) l)

    1. Initial program 35.93

      \[\pi \cdot \ell - \frac{1}{F \cdot F} \cdot \tan \left(\pi \cdot \ell\right) \]
    2. Simplified35.93

      \[\leadsto \color{blue}{\pi \cdot \ell - \frac{\tan \left(\pi \cdot \ell\right)}{F \cdot F}} \]
      Proof

      [Start]35.93

      \[ \pi \cdot \ell - \frac{1}{F \cdot F} \cdot \tan \left(\pi \cdot \ell\right) \]

      associate-*l/ [=>]35.93

      \[ \pi \cdot \ell - \color{blue}{\frac{1 \cdot \tan \left(\pi \cdot \ell\right)}{F \cdot F}} \]

      *-lft-identity [=>]35.93

      \[ \pi \cdot \ell - \frac{\color{blue}{\tan \left(\pi \cdot \ell\right)}}{F \cdot F} \]
    3. Taylor expanded in l around inf 1.1

      \[\leadsto \color{blue}{\ell \cdot \pi} \]

    if -1e22 < (*.f64 (PI.f64) l) < 1e-3

    1. Initial program 15.82

      \[\pi \cdot \ell - \frac{1}{F \cdot F} \cdot \tan \left(\pi \cdot \ell\right) \]
    2. Applied egg-rr1.38

      \[\leadsto \pi \cdot \ell - \color{blue}{\frac{\frac{1}{F}}{\frac{F}{\tan \left(\pi \cdot \ell\right)}}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification1.23

    \[\leadsto \begin{array}{l} \mathbf{if}\;\pi \cdot \ell \leq -1 \cdot 10^{+22} \lor \neg \left(\pi \cdot \ell \leq 0.001\right):\\ \;\;\;\;\pi \cdot \ell\\ \mathbf{else}:\\ \;\;\;\;\pi \cdot \ell - \frac{\frac{1}{F}}{\frac{F}{\tan \left(\pi \cdot \ell\right)}}\\ \end{array} \]

Alternatives

Alternative 1
Error1.2%
Cost32969
\[\begin{array}{l} \mathbf{if}\;\pi \cdot \ell \leq -1 \cdot 10^{+22} \lor \neg \left(\pi \cdot \ell \leq 0.001\right):\\ \;\;\;\;\pi \cdot \ell\\ \mathbf{else}:\\ \;\;\;\;\pi \cdot \ell - \frac{\frac{\tan \left(\pi \cdot \ell\right)}{F}}{F}\\ \end{array} \]
Alternative 2
Error1.51%
Cost26569
\[\begin{array}{l} \mathbf{if}\;\pi \cdot \ell \leq -1 \cdot 10^{+22} \lor \neg \left(\pi \cdot \ell \leq 0.001\right):\\ \;\;\;\;\pi \cdot \ell\\ \mathbf{else}:\\ \;\;\;\;\pi \cdot \ell - \frac{\pi}{F} \cdot \frac{\ell}{F}\\ \end{array} \]
Alternative 3
Error8.46%
Cost13513
\[\begin{array}{l} \mathbf{if}\;\ell \leq -2 \cdot 10^{+19} \lor \neg \left(\ell \leq 560\right):\\ \;\;\;\;\pi \cdot \ell\\ \mathbf{else}:\\ \;\;\;\;\ell \cdot \left(\pi - \frac{\pi}{F \cdot F}\right)\\ \end{array} \]
Alternative 4
Error22.16%
Cost7888
\[\begin{array}{l} t_0 := -\frac{\ell}{F}\\ t_1 := \left(\pi \cdot \ell + 1\right) + -1\\ \mathbf{if}\;F \cdot F \leq 2 \cdot 10^{-320}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;F \cdot F \leq 2 \cdot 10^{-257}:\\ \;\;\;\;\frac{\pi}{F} \cdot t_0\\ \mathbf{elif}\;F \cdot F \leq 5 \cdot 10^{-190}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;F \cdot F \leq 4 \cdot 10^{-130}:\\ \;\;\;\;\pi \cdot \frac{t_0}{F}\\ \mathbf{else}:\\ \;\;\;\;\pi \cdot \ell\\ \end{array} \]
Alternative 5
Error21.83%
Cost7113
\[\begin{array}{l} \mathbf{if}\;F \leq -1.35 \cdot 10^{-65} \lor \neg \left(F \leq -1.25 \cdot 10^{-108}\right):\\ \;\;\;\;\pi \cdot \ell\\ \mathbf{else}:\\ \;\;\;\;\frac{\pi}{F} \cdot \left(-\frac{\ell}{F}\right)\\ \end{array} \]
Alternative 6
Error21.81%
Cost6528
\[\pi \cdot \ell \]

Error

Reproduce?

herbie shell --seed 2023102 
(FPCore (F l)
  :name "VandenBroeck and Keller, Equation (6)"
  :precision binary64
  (- (* PI l) (* (/ 1.0 (* F F)) (tan (* PI l)))))