?

Average Error: 2.8 → 1.8
Time: 13.5s
Precision: binary64
Cost: 708

?

\[\frac{x}{y - z \cdot t} \]
\[\begin{array}{l} \mathbf{if}\;z \cdot t \leq 10^{+193}:\\ \;\;\;\;\frac{x}{y - z \cdot t}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{x}{-z}}{t}\\ \end{array} \]
(FPCore (x y z t) :precision binary64 (/ x (- y (* z t))))
(FPCore (x y z t)
 :precision binary64
 (if (<= (* z t) 1e+193) (/ x (- y (* z t))) (/ (/ x (- z)) t)))
double code(double x, double y, double z, double t) {
	return x / (y - (z * t));
}
double code(double x, double y, double z, double t) {
	double tmp;
	if ((z * t) <= 1e+193) {
		tmp = x / (y - (z * t));
	} else {
		tmp = (x / -z) / t;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = x / (y - (z * t))
end function
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if ((z * t) <= 1d+193) then
        tmp = x / (y - (z * t))
    else
        tmp = (x / -z) / t
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	return x / (y - (z * t));
}
public static double code(double x, double y, double z, double t) {
	double tmp;
	if ((z * t) <= 1e+193) {
		tmp = x / (y - (z * t));
	} else {
		tmp = (x / -z) / t;
	}
	return tmp;
}
def code(x, y, z, t):
	return x / (y - (z * t))
def code(x, y, z, t):
	tmp = 0
	if (z * t) <= 1e+193:
		tmp = x / (y - (z * t))
	else:
		tmp = (x / -z) / t
	return tmp
function code(x, y, z, t)
	return Float64(x / Float64(y - Float64(z * t)))
end
function code(x, y, z, t)
	tmp = 0.0
	if (Float64(z * t) <= 1e+193)
		tmp = Float64(x / Float64(y - Float64(z * t)));
	else
		tmp = Float64(Float64(x / Float64(-z)) / t);
	end
	return tmp
end
function tmp = code(x, y, z, t)
	tmp = x / (y - (z * t));
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if ((z * t) <= 1e+193)
		tmp = x / (y - (z * t));
	else
		tmp = (x / -z) / t;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := N[(x / N[(y - N[(z * t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[x_, y_, z_, t_] := If[LessEqual[N[(z * t), $MachinePrecision], 1e+193], N[(x / N[(y - N[(z * t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(x / (-z)), $MachinePrecision] / t), $MachinePrecision]]
\frac{x}{y - z \cdot t}
\begin{array}{l}
\mathbf{if}\;z \cdot t \leq 10^{+193}:\\
\;\;\;\;\frac{x}{y - z \cdot t}\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{x}{-z}}{t}\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original2.8
Target1.9
Herbie1.8
\[\begin{array}{l} \mathbf{if}\;x < -1.618195973607049 \cdot 10^{+50}:\\ \;\;\;\;\frac{1}{\frac{y}{x} - \frac{z}{x} \cdot t}\\ \mathbf{elif}\;x < 2.1378306434876444 \cdot 10^{+131}:\\ \;\;\;\;\frac{x}{y - z \cdot t}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\frac{y}{x} - \frac{z}{x} \cdot t}\\ \end{array} \]

Derivation?

  1. Split input into 2 regimes
  2. if (*.f64 z t) < 1.00000000000000007e193

    1. Initial program 1.7

      \[\frac{x}{y - z \cdot t} \]

    if 1.00000000000000007e193 < (*.f64 z t)

    1. Initial program 11.0

      \[\frac{x}{y - z \cdot t} \]
    2. Taylor expanded in y around 0 13.1

      \[\leadsto \color{blue}{-1 \cdot \frac{x}{t \cdot z}} \]
    3. Simplified13.1

      \[\leadsto \color{blue}{\frac{-x}{t \cdot z}} \]
      Proof

      [Start]13.1

      \[ -1 \cdot \frac{x}{t \cdot z} \]

      rational_best-simplify-1 [<=]13.1

      \[ -1 \cdot \frac{x}{\color{blue}{z \cdot t}} \]

      rational_best-simplify-62 [=>]13.1

      \[ \color{blue}{\frac{x \cdot -1}{z \cdot t}} \]

      rational_best-simplify-11 [<=]13.1

      \[ \frac{\color{blue}{-x}}{z \cdot t} \]

      rational_best-simplify-1 [=>]13.1

      \[ \frac{-x}{\color{blue}{t \cdot z}} \]
    4. Applied egg-rr2.5

      \[\leadsto \color{blue}{\frac{x}{z} \cdot \frac{-1}{t}} \]
    5. Applied egg-rr2.5

      \[\leadsto \color{blue}{\frac{\frac{x}{-z}}{t}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification1.8

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \cdot t \leq 10^{+193}:\\ \;\;\;\;\frac{x}{y - z \cdot t}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{x}{-z}}{t}\\ \end{array} \]

Alternatives

Alternative 1
Error19.1
Cost1044
\[\begin{array}{l} t_1 := \frac{\frac{x}{-t}}{z}\\ \mathbf{if}\;y \leq -6.5 \cdot 10^{+30}:\\ \;\;\;\;\frac{x}{y}\\ \mathbf{elif}\;y \leq -6.4 \cdot 10^{-9}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;y \leq -4.8 \cdot 10^{-136}:\\ \;\;\;\;\frac{x}{y}\\ \mathbf{elif}\;y \leq -5.5 \cdot 10^{-228}:\\ \;\;\;\;\frac{-x}{t \cdot z}\\ \mathbf{elif}\;y \leq 6.8 \cdot 10^{-43}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y}\\ \end{array} \]
Alternative 2
Error18.1
Cost912
\[\begin{array}{l} t_1 := \frac{-x}{t \cdot z}\\ \mathbf{if}\;y \leq -6.5 \cdot 10^{+30}:\\ \;\;\;\;\frac{x}{y}\\ \mathbf{elif}\;y \leq -9.2 \cdot 10^{-88}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;y \leq -4.8 \cdot 10^{-136}:\\ \;\;\;\;\frac{x}{y}\\ \mathbf{elif}\;y \leq 1.12 \cdot 10^{-42}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y}\\ \end{array} \]
Alternative 3
Error19.1
Cost912
\[\begin{array}{l} t_1 := \frac{\frac{x}{-z}}{t}\\ \mathbf{if}\;y \leq -5.1 \cdot 10^{+28}:\\ \;\;\;\;\frac{x}{y}\\ \mathbf{elif}\;y \leq -2.6 \cdot 10^{-88}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;y \leq -4.8 \cdot 10^{-136}:\\ \;\;\;\;\frac{x}{y}\\ \mathbf{elif}\;y \leq 1.15 \cdot 10^{-42}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{y}\\ \end{array} \]
Alternative 4
Error30.1
Cost192
\[\frac{x}{y} \]

Error

Reproduce?

herbie shell --seed 2023101 
(FPCore (x y z t)
  :name "Diagrams.Solve.Tridiagonal:solveTriDiagonal from diagrams-solve-0.1, B"
  :precision binary64

  :herbie-target
  (if (< x -1.618195973607049e+50) (/ 1.0 (- (/ y x) (* (/ z x) t))) (if (< x 2.1378306434876444e+131) (/ x (- y (* z t))) (/ 1.0 (- (/ y x) (* (/ z x) t)))))

  (/ x (- y (* z t))))