Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
\]
↓
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.15 \cdot 10^{-90}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{elif}\;b_2 \leq 1.25 \cdot 10^{+117}:\\
\;\;\;\;\frac{\sqrt{b_2 \cdot b_2 - a \cdot c}}{-a} - \frac{b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2 \cdot -2}{a}\\
\end{array}
\]
(FPCore (a b_2 c)
:precision binary64
(/ (- (- b_2) (sqrt (- (* b_2 b_2) (* a c)))) a)) ↓
(FPCore (a b_2 c)
:precision binary64
(if (<= b_2 -1.15e-90)
(* -0.5 (/ c b_2))
(if (<= b_2 1.25e+117)
(- (/ (sqrt (- (* b_2 b_2) (* a c))) (- a)) (/ b_2 a))
(/ (* b_2 -2.0) a)))) double code(double a, double b_2, double c) {
return (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a;
}
↓
double code(double a, double b_2, double c) {
double tmp;
if (b_2 <= -1.15e-90) {
tmp = -0.5 * (c / b_2);
} else if (b_2 <= 1.25e+117) {
tmp = (sqrt(((b_2 * b_2) - (a * c))) / -a) - (b_2 / a);
} else {
tmp = (b_2 * -2.0) / a;
}
return tmp;
}
real(8) function code(a, b_2, c)
real(8), intent (in) :: a
real(8), intent (in) :: b_2
real(8), intent (in) :: c
code = (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a
end function
↓
real(8) function code(a, b_2, c)
real(8), intent (in) :: a
real(8), intent (in) :: b_2
real(8), intent (in) :: c
real(8) :: tmp
if (b_2 <= (-1.15d-90)) then
tmp = (-0.5d0) * (c / b_2)
else if (b_2 <= 1.25d+117) then
tmp = (sqrt(((b_2 * b_2) - (a * c))) / -a) - (b_2 / a)
else
tmp = (b_2 * (-2.0d0)) / a
end if
code = tmp
end function
public static double code(double a, double b_2, double c) {
return (-b_2 - Math.sqrt(((b_2 * b_2) - (a * c)))) / a;
}
↓
public static double code(double a, double b_2, double c) {
double tmp;
if (b_2 <= -1.15e-90) {
tmp = -0.5 * (c / b_2);
} else if (b_2 <= 1.25e+117) {
tmp = (Math.sqrt(((b_2 * b_2) - (a * c))) / -a) - (b_2 / a);
} else {
tmp = (b_2 * -2.0) / a;
}
return tmp;
}
def code(a, b_2, c):
return (-b_2 - math.sqrt(((b_2 * b_2) - (a * c)))) / a
↓
def code(a, b_2, c):
tmp = 0
if b_2 <= -1.15e-90:
tmp = -0.5 * (c / b_2)
elif b_2 <= 1.25e+117:
tmp = (math.sqrt(((b_2 * b_2) - (a * c))) / -a) - (b_2 / a)
else:
tmp = (b_2 * -2.0) / a
return tmp
function code(a, b_2, c)
return Float64(Float64(Float64(-b_2) - sqrt(Float64(Float64(b_2 * b_2) - Float64(a * c)))) / a)
end
↓
function code(a, b_2, c)
tmp = 0.0
if (b_2 <= -1.15e-90)
tmp = Float64(-0.5 * Float64(c / b_2));
elseif (b_2 <= 1.25e+117)
tmp = Float64(Float64(sqrt(Float64(Float64(b_2 * b_2) - Float64(a * c))) / Float64(-a)) - Float64(b_2 / a));
else
tmp = Float64(Float64(b_2 * -2.0) / a);
end
return tmp
end
function tmp = code(a, b_2, c)
tmp = (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a;
end
↓
function tmp_2 = code(a, b_2, c)
tmp = 0.0;
if (b_2 <= -1.15e-90)
tmp = -0.5 * (c / b_2);
elseif (b_2 <= 1.25e+117)
tmp = (sqrt(((b_2 * b_2) - (a * c))) / -a) - (b_2 / a);
else
tmp = (b_2 * -2.0) / a;
end
tmp_2 = tmp;
end
code[a_, b$95$2_, c_] := N[(N[((-b$95$2) - N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(a * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / a), $MachinePrecision]
↓
code[a_, b$95$2_, c_] := If[LessEqual[b$95$2, -1.15e-90], N[(-0.5 * N[(c / b$95$2), $MachinePrecision]), $MachinePrecision], If[LessEqual[b$95$2, 1.25e+117], N[(N[(N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(a * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-a)), $MachinePrecision] - N[(b$95$2 / a), $MachinePrecision]), $MachinePrecision], N[(N[(b$95$2 * -2.0), $MachinePrecision] / a), $MachinePrecision]]]
\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
↓
\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.15 \cdot 10^{-90}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{elif}\;b_2 \leq 1.25 \cdot 10^{+117}:\\
\;\;\;\;\frac{\sqrt{b_2 \cdot b_2 - a \cdot c}}{-a} - \frac{b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2 \cdot -2}{a}\\
\end{array}
Alternatives Alternative 1 Error 10.5 Cost 7432
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.15 \cdot 10^{-90}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{elif}\;b_2 \leq 2.15 \cdot 10^{+116}:\\
\;\;\;\;\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2 \cdot -2}{a}\\
\end{array}
\]
Alternative 2 Error 13.6 Cost 7240
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.15 \cdot 10^{-90}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{elif}\;b_2 \leq 1.32 \cdot 10^{-73}:\\
\;\;\;\;\frac{\left(-b_2\right) - \sqrt{c \cdot \left(-a\right)}}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2}{a} \cdot -2 + 0.5 \cdot \frac{c}{b_2}\\
\end{array}
\]
Alternative 3 Error 13.9 Cost 7112
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.15 \cdot 10^{-90}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{elif}\;b_2 \leq 1.22 \cdot 10^{-73}:\\
\;\;\;\;\frac{-\sqrt{c \cdot \left(-a\right)}}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2}{a} \cdot -2 + 0.5 \cdot \frac{c}{b_2}\\
\end{array}
\]
Alternative 4 Error 20.2 Cost 6984
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -6.4 \cdot 10^{-203}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{elif}\;b_2 \leq 4.8 \cdot 10^{-178}:\\
\;\;\;\;-\sqrt{\frac{c}{-a}}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2}{a} \cdot -2 + 0.5 \cdot \frac{c}{b_2}\\
\end{array}
\]
Alternative 5 Error 22.8 Cost 836
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -5 \cdot 10^{-310}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2}{a} \cdot -2 + 0.5 \cdot \frac{c}{b_2}\\
\end{array}
\]
Alternative 6 Error 22.9 Cost 452
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -3.4 \cdot 10^{-251}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{else}:\\
\;\;\;\;b_2 \cdot \frac{-2}{a}\\
\end{array}
\]
Alternative 7 Error 22.8 Cost 452
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.7 \cdot 10^{-249}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2 \cdot -2}{a}\\
\end{array}
\]
Alternative 8 Error 39.9 Cost 320
\[-0.5 \cdot \frac{c}{b_2}
\]