Kahan's exp quotient

Average Error: 36.6% → 100.0%

Time: 3.1s

Precision: binary64

Cost: 6720.00

Math

\[\frac{e^{x} - 1}{x} \]

↓

\[\frac{1}{\frac{x}{\mathsf{expm1}\left(x\right)}} \]

FPCore

(FPCore (x) :precision binary64 (/ (- (exp x) 1.0) x))

↓

(FPCore (x) :precision binary64 (/ 1.0 (/ x (expm1 x))))

C

double code(double x) {
	return (exp(x) - 1.0) / x;
}

↓

double code(double x) {
	return 1.0 / (x / expm1(x));
}

Java

public static double code(double x) {
	return (Math.exp(x) - 1.0) / x;
}

↓

public static double code(double x) {
	return 1.0 / (x / Math.expm1(x));
}

Python

def code(x):
	return (math.exp(x) - 1.0) / x

↓

def code(x):
	return 1.0 / (x / math.expm1(x))

Julia

function code(x)
	return Float64(Float64(exp(x) - 1.0) / x)
end

↓

function code(x)
	return Float64(1.0 / Float64(x / expm1(x)))
end

Wolfram

code[x_] := N[(N[(N[Exp[x], $MachinePrecision] - 1.0), $MachinePrecision] / x), $MachinePrecision]

↓

code[x_] := N[(1.0 / N[(x / N[(Exp[x] - 1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]

Target

Original	36.6%
Target	36.1%
Herbie	100.0%

\[\begin{array}{l} \mathbf{if}\;x < 1 \land x > -1:\\ \;\;\;\;\frac{e^{x} - 1}{\log \left(e^{x}\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{e^{x} - 1}{x}\\ \end{array} \]

Derivation

1. Initial program 36.6

   \[\frac{e^{x} - 1}{x} \]

2. Simplified 100.0

   \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(x\right)}{x}} \]
   Proof

   [Start] 36.6	\[ \frac{e^{x} - 1}{x} \]
   expm1-def [=>] 100.0	\[ \frac{\color{blue}{\mathsf{expm1}\left(x\right)}}{x} \]

3. Applied egg-rr 100.0

   \[\leadsto \color{blue}{{\left(\frac{x}{\mathsf{expm1}\left(x\right)}\right)}^{-1}} \]

4. Applied egg-rr 100.0

   \[\leadsto \color{blue}{\frac{1}{\frac{x}{\mathsf{expm1}\left(x\right)}}} \]

5. Final simplification 100.0

   \[\leadsto \frac{1}{\frac{x}{\mathsf{expm1}\left(x\right)}} \]

Alternatives

Alternative 1
Error	100.0%
Cost	6592.00

\[\frac{\mathsf{expm1}\left(x\right)}{x} \]

Alternative 2
Error	73.0%
Cost	452.00

\[\begin{array}{l} \mathbf{if}\;x \leq -1.55:\\ \;\;\;\;\frac{-2}{x}\\ \mathbf{else}:\\ \;\;\;\;1 + x \cdot 0.5\\ \end{array} \]

Alternative 3
Error	73.0%
Cost	448.00

\[\frac{1}{1 + x \cdot -0.5} \]

Alternative 4
Error	72.2%
Cost	324.00

\[\begin{array}{l} \mathbf{if}\;x \leq -2:\\ \;\;\;\;\frac{-2}{x}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \]

Alternative 5
Error	68.0%
Cost	64.00

\[1 \]

Reproduce

herbie shell --seed 2023097 
(FPCore (x)
  :name "Kahan's exp quotient"
  :precision binary64

  :herbie-target
  (if (and (< x 1.0) (> x -1.0)) (/ (- (exp x) 1.0) (log (exp x))) (/ (- (exp x) 1.0) x))

  (/ (- (exp x) 1.0) x))