?

Average Error: 46.4% → 85.8%
Time: 17.1s
Precision: binary64
Cost: 7692.00

?

\[\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a} \]
\[\begin{array}{l} t_0 := \sqrt{b_2 \cdot b_2 - c \cdot a}\\ \mathbf{if}\;b_2 \leq -7.2 \cdot 10^{+49}:\\ \;\;\;\;\frac{-0.5 \cdot c}{b_2}\\ \mathbf{elif}\;b_2 \leq 2 \cdot 10^{-238}:\\ \;\;\;\;\frac{\frac{c \cdot \left(-a\right)}{b_2 - t_0}}{a}\\ \mathbf{elif}\;b_2 \leq 1.85 \cdot 10^{+116}:\\ \;\;\;\;\frac{-t_0}{a} - \frac{b_2}{a}\\ \mathbf{else}:\\ \;\;\;\;\frac{b_2 \cdot -2}{a}\\ \end{array} \]
(FPCore (a b_2 c)
 :precision binary64
 (/ (- (- b_2) (sqrt (- (* b_2 b_2) (* a c)))) a))
(FPCore (a b_2 c)
 :precision binary64
 (let* ((t_0 (sqrt (- (* b_2 b_2) (* c a)))))
   (if (<= b_2 -7.2e+49)
     (/ (* -0.5 c) b_2)
     (if (<= b_2 2e-238)
       (/ (/ (* c (- a)) (- b_2 t_0)) a)
       (if (<= b_2 1.85e+116)
         (- (/ (- t_0) a) (/ b_2 a))
         (/ (* b_2 -2.0) a))))))
double code(double a, double b_2, double c) {
	return (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a;
}
double code(double a, double b_2, double c) {
	double t_0 = sqrt(((b_2 * b_2) - (c * a)));
	double tmp;
	if (b_2 <= -7.2e+49) {
		tmp = (-0.5 * c) / b_2;
	} else if (b_2 <= 2e-238) {
		tmp = ((c * -a) / (b_2 - t_0)) / a;
	} else if (b_2 <= 1.85e+116) {
		tmp = (-t_0 / a) - (b_2 / a);
	} else {
		tmp = (b_2 * -2.0) / a;
	}
	return tmp;
}
real(8) function code(a, b_2, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_2
    real(8), intent (in) :: c
    code = (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a
end function
real(8) function code(a, b_2, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b_2
    real(8), intent (in) :: c
    real(8) :: t_0
    real(8) :: tmp
    t_0 = sqrt(((b_2 * b_2) - (c * a)))
    if (b_2 <= (-7.2d+49)) then
        tmp = ((-0.5d0) * c) / b_2
    else if (b_2 <= 2d-238) then
        tmp = ((c * -a) / (b_2 - t_0)) / a
    else if (b_2 <= 1.85d+116) then
        tmp = (-t_0 / a) - (b_2 / a)
    else
        tmp = (b_2 * (-2.0d0)) / a
    end if
    code = tmp
end function
public static double code(double a, double b_2, double c) {
	return (-b_2 - Math.sqrt(((b_2 * b_2) - (a * c)))) / a;
}
public static double code(double a, double b_2, double c) {
	double t_0 = Math.sqrt(((b_2 * b_2) - (c * a)));
	double tmp;
	if (b_2 <= -7.2e+49) {
		tmp = (-0.5 * c) / b_2;
	} else if (b_2 <= 2e-238) {
		tmp = ((c * -a) / (b_2 - t_0)) / a;
	} else if (b_2 <= 1.85e+116) {
		tmp = (-t_0 / a) - (b_2 / a);
	} else {
		tmp = (b_2 * -2.0) / a;
	}
	return tmp;
}
def code(a, b_2, c):
	return (-b_2 - math.sqrt(((b_2 * b_2) - (a * c)))) / a
def code(a, b_2, c):
	t_0 = math.sqrt(((b_2 * b_2) - (c * a)))
	tmp = 0
	if b_2 <= -7.2e+49:
		tmp = (-0.5 * c) / b_2
	elif b_2 <= 2e-238:
		tmp = ((c * -a) / (b_2 - t_0)) / a
	elif b_2 <= 1.85e+116:
		tmp = (-t_0 / a) - (b_2 / a)
	else:
		tmp = (b_2 * -2.0) / a
	return tmp
function code(a, b_2, c)
	return Float64(Float64(Float64(-b_2) - sqrt(Float64(Float64(b_2 * b_2) - Float64(a * c)))) / a)
end
function code(a, b_2, c)
	t_0 = sqrt(Float64(Float64(b_2 * b_2) - Float64(c * a)))
	tmp = 0.0
	if (b_2 <= -7.2e+49)
		tmp = Float64(Float64(-0.5 * c) / b_2);
	elseif (b_2 <= 2e-238)
		tmp = Float64(Float64(Float64(c * Float64(-a)) / Float64(b_2 - t_0)) / a);
	elseif (b_2 <= 1.85e+116)
		tmp = Float64(Float64(Float64(-t_0) / a) - Float64(b_2 / a));
	else
		tmp = Float64(Float64(b_2 * -2.0) / a);
	end
	return tmp
end
function tmp = code(a, b_2, c)
	tmp = (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a;
end
function tmp_2 = code(a, b_2, c)
	t_0 = sqrt(((b_2 * b_2) - (c * a)));
	tmp = 0.0;
	if (b_2 <= -7.2e+49)
		tmp = (-0.5 * c) / b_2;
	elseif (b_2 <= 2e-238)
		tmp = ((c * -a) / (b_2 - t_0)) / a;
	elseif (b_2 <= 1.85e+116)
		tmp = (-t_0 / a) - (b_2 / a);
	else
		tmp = (b_2 * -2.0) / a;
	end
	tmp_2 = tmp;
end
code[a_, b$95$2_, c_] := N[(N[((-b$95$2) - N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(a * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / a), $MachinePrecision]
code[a_, b$95$2_, c_] := Block[{t$95$0 = N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(c * a), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[b$95$2, -7.2e+49], N[(N[(-0.5 * c), $MachinePrecision] / b$95$2), $MachinePrecision], If[LessEqual[b$95$2, 2e-238], N[(N[(N[(c * (-a)), $MachinePrecision] / N[(b$95$2 - t$95$0), $MachinePrecision]), $MachinePrecision] / a), $MachinePrecision], If[LessEqual[b$95$2, 1.85e+116], N[(N[((-t$95$0) / a), $MachinePrecision] - N[(b$95$2 / a), $MachinePrecision]), $MachinePrecision], N[(N[(b$95$2 * -2.0), $MachinePrecision] / a), $MachinePrecision]]]]]
\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
\begin{array}{l}
t_0 := \sqrt{b_2 \cdot b_2 - c \cdot a}\\
\mathbf{if}\;b_2 \leq -7.2 \cdot 10^{+49}:\\
\;\;\;\;\frac{-0.5 \cdot c}{b_2}\\

\mathbf{elif}\;b_2 \leq 2 \cdot 10^{-238}:\\
\;\;\;\;\frac{\frac{c \cdot \left(-a\right)}{b_2 - t_0}}{a}\\

\mathbf{elif}\;b_2 \leq 1.85 \cdot 10^{+116}:\\
\;\;\;\;\frac{-t_0}{a} - \frac{b_2}{a}\\

\mathbf{else}:\\
\;\;\;\;\frac{b_2 \cdot -2}{a}\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Split input into 4 regimes
  2. if b_2 < -7.19999999999999993e49

    1. Initial program 11.7

      \[\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a} \]
    2. Taylor expanded in b_2 around -inf 94.0

      \[\leadsto \color{blue}{-0.5 \cdot \frac{c}{b_2}} \]
    3. Applied egg-rr94.0

      \[\leadsto \color{blue}{\frac{-0.5 \cdot c}{b_2}} \]

    if -7.19999999999999993e49 < b_2 < 2e-238

    1. Initial program 56.7

      \[\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a} \]
    2. Applied egg-rr73.3

      \[\leadsto \frac{\color{blue}{\frac{-\left(a \cdot c + \left(b_2 \cdot b_2 - b_2 \cdot b_2\right)\right)}{b_2 - \sqrt{b_2 \cdot b_2 - a \cdot c}}}}{a} \]
    3. Simplified73.3

      \[\leadsto \frac{\color{blue}{\frac{c \cdot \left(-a\right)}{b_2 - \sqrt{b_2 \cdot b_2 - c \cdot a}}}}{a} \]
      Proof

      [Start]73.3

      \[ \frac{\frac{-\left(a \cdot c + \left(b_2 \cdot b_2 - b_2 \cdot b_2\right)\right)}{b_2 - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a} \]

      neg-sub0 [=>]73.3

      \[ \frac{\frac{\color{blue}{0 - \left(a \cdot c + \left(b_2 \cdot b_2 - b_2 \cdot b_2\right)\right)}}{b_2 - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a} \]

      +-commutative [=>]73.3

      \[ \frac{\frac{0 - \color{blue}{\left(\left(b_2 \cdot b_2 - b_2 \cdot b_2\right) + a \cdot c\right)}}{b_2 - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a} \]

      +-inverses [=>]73.3

      \[ \frac{\frac{0 - \left(\color{blue}{0} + a \cdot c\right)}{b_2 - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a} \]

      associate--r+ [=>]73.3

      \[ \frac{\frac{\color{blue}{\left(0 - 0\right) - a \cdot c}}{b_2 - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a} \]

      metadata-eval [=>]73.3

      \[ \frac{\frac{\color{blue}{0} - a \cdot c}{b_2 - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a} \]

      neg-sub0 [<=]73.3

      \[ \frac{\frac{\color{blue}{-a \cdot c}}{b_2 - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a} \]

      distribute-lft-neg-in [=>]73.3

      \[ \frac{\frac{\color{blue}{\left(-a\right) \cdot c}}{b_2 - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a} \]

      *-commutative [=>]73.3

      \[ \frac{\frac{\color{blue}{c \cdot \left(-a\right)}}{b_2 - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a} \]

      *-commutative [=>]73.3

      \[ \frac{\frac{c \cdot \left(-a\right)}{b_2 - \sqrt{b_2 \cdot b_2 - \color{blue}{c \cdot a}}}}{a} \]

    if 2e-238 < b_2 < 1.8500000000000001e116

    1. Initial program 86.8

      \[\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a} \]
    2. Applied egg-rr86.8

      \[\leadsto \color{blue}{\frac{0}{a} - \left(\frac{b_2}{a} + \frac{\sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\right)} \]
    3. Simplified86.8

      \[\leadsto \color{blue}{\frac{-\sqrt{b_2 \cdot b_2 - c \cdot a}}{a} - \frac{b_2}{a}} \]
      Proof

      [Start]86.8

      \[ \frac{0}{a} - \left(\frac{b_2}{a} + \frac{\sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\right) \]

      div0 [=>]86.8

      \[ \color{blue}{0} - \left(\frac{b_2}{a} + \frac{\sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\right) \]

      +-commutative [=>]86.8

      \[ 0 - \color{blue}{\left(\frac{\sqrt{b_2 \cdot b_2 - a \cdot c}}{a} + \frac{b_2}{a}\right)} \]

      associate--r+ [=>]86.8

      \[ \color{blue}{\left(0 - \frac{\sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\right) - \frac{b_2}{a}} \]

      neg-sub0 [<=]86.8

      \[ \color{blue}{\left(-\frac{\sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\right)} - \frac{b_2}{a} \]

      distribute-neg-frac [=>]86.8

      \[ \color{blue}{\frac{-\sqrt{b_2 \cdot b_2 - a \cdot c}}{a}} - \frac{b_2}{a} \]

      *-commutative [=>]86.8

      \[ \frac{-\sqrt{b_2 \cdot b_2 - \color{blue}{c \cdot a}}}{a} - \frac{b_2}{a} \]

    if 1.8500000000000001e116 < b_2

    1. Initial program 18.9

      \[\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a} \]
    2. Taylor expanded in b_2 around inf 94.1

      \[\leadsto \frac{\color{blue}{-2 \cdot b_2}}{a} \]
    3. Simplified94.1

      \[\leadsto \frac{\color{blue}{b_2 \cdot -2}}{a} \]
      Proof

      [Start]94.1

      \[ \frac{-2 \cdot b_2}{a} \]

      *-commutative [=>]94.1

      \[ \frac{\color{blue}{b_2 \cdot -2}}{a} \]
  3. Recombined 4 regimes into one program.
  4. Final simplification85.8

    \[\leadsto \begin{array}{l} \mathbf{if}\;b_2 \leq -7.2 \cdot 10^{+49}:\\ \;\;\;\;\frac{-0.5 \cdot c}{b_2}\\ \mathbf{elif}\;b_2 \leq 2 \cdot 10^{-238}:\\ \;\;\;\;\frac{\frac{c \cdot \left(-a\right)}{b_2 - \sqrt{b_2 \cdot b_2 - c \cdot a}}}{a}\\ \mathbf{elif}\;b_2 \leq 1.85 \cdot 10^{+116}:\\ \;\;\;\;\frac{-\sqrt{b_2 \cdot b_2 - c \cdot a}}{a} - \frac{b_2}{a}\\ \mathbf{else}:\\ \;\;\;\;\frac{b_2 \cdot -2}{a}\\ \end{array} \]

Alternatives

Alternative 1
Error83.7%
Cost7560.00
\[\begin{array}{l} \mathbf{if}\;b_2 \leq -1.1 \cdot 10^{-90}:\\ \;\;\;\;\frac{-0.5 \cdot c}{b_2}\\ \mathbf{elif}\;b_2 \leq 3 \cdot 10^{+114}:\\ \;\;\;\;\frac{-\sqrt{b_2 \cdot b_2 - c \cdot a}}{a} - \frac{b_2}{a}\\ \mathbf{else}:\\ \;\;\;\;\frac{b_2 \cdot -2}{a}\\ \end{array} \]
Alternative 2
Error83.7%
Cost7432.00
\[\begin{array}{l} \mathbf{if}\;b_2 \leq -1.1 \cdot 10^{-90}:\\ \;\;\;\;\frac{-0.5 \cdot c}{b_2}\\ \mathbf{elif}\;b_2 \leq 1.35 \cdot 10^{+116}:\\ \;\;\;\;\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - c \cdot a}}{a}\\ \mathbf{else}:\\ \;\;\;\;\frac{b_2 \cdot -2}{a}\\ \end{array} \]
Alternative 3
Error78.7%
Cost7240.00
\[\begin{array}{l} \mathbf{if}\;b_2 \leq -1 \cdot 10^{-90}:\\ \;\;\;\;\frac{-0.5 \cdot c}{b_2}\\ \mathbf{elif}\;b_2 \leq 1.8 \cdot 10^{-73}:\\ \;\;\;\;\frac{\left(-b_2\right) - \sqrt{c \cdot \left(-a\right)}}{a}\\ \mathbf{else}:\\ \;\;\;\;\frac{b_2}{a} \cdot -2 + 0.5 \cdot \frac{c}{b_2}\\ \end{array} \]
Alternative 4
Error64.3%
Cost836.00
\[\begin{array}{l} \mathbf{if}\;b_2 \leq -5 \cdot 10^{-310}:\\ \;\;\;\;\frac{-0.5 \cdot c}{b_2}\\ \mathbf{else}:\\ \;\;\;\;\frac{b_2}{a} \cdot -2 + 0.5 \cdot \frac{c}{b_2}\\ \end{array} \]
Alternative 5
Error64.2%
Cost452.00
\[\begin{array}{l} \mathbf{if}\;b_2 \leq -3.5 \cdot 10^{-251}:\\ \;\;\;\;-0.5 \cdot \frac{c}{b_2}\\ \mathbf{else}:\\ \;\;\;\;b_2 \cdot \frac{-2}{a}\\ \end{array} \]
Alternative 6
Error64.2%
Cost452.00
\[\begin{array}{l} \mathbf{if}\;b_2 \leq -2.6 \cdot 10^{-249}:\\ \;\;\;\;\frac{-0.5 \cdot c}{b_2}\\ \mathbf{else}:\\ \;\;\;\;b_2 \cdot \frac{-2}{a}\\ \end{array} \]
Alternative 7
Error64.3%
Cost452.00
\[\begin{array}{l} \mathbf{if}\;b_2 \leq -1.3 \cdot 10^{-250}:\\ \;\;\;\;\frac{-0.5 \cdot c}{b_2}\\ \mathbf{else}:\\ \;\;\;\;\frac{b_2 \cdot -2}{a}\\ \end{array} \]
Alternative 8
Error37.6%
Cost320.00
\[-0.5 \cdot \frac{c}{b_2} \]
Alternative 9
Error11.9%
Cost64.00
\[0 \]

Error

Reproduce?

herbie shell --seed 2023097 
(FPCore (a b_2 c)
  :name "quad2m (problem 3.2.1, negative)"
  :precision binary64
  (/ (- (- b_2) (sqrt (- (* b_2 b_2) (* a c)))) a))