Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
\]
↓
\[\begin{array}{l}
t_0 := \sqrt{b_2 \cdot b_2 - c \cdot a}\\
\mathbf{if}\;b_2 \leq -7.2 \cdot 10^{+49}:\\
\;\;\;\;\frac{-0.5 \cdot c}{b_2}\\
\mathbf{elif}\;b_2 \leq 2 \cdot 10^{-238}:\\
\;\;\;\;\frac{\frac{c \cdot \left(-a\right)}{b_2 - t_0}}{a}\\
\mathbf{elif}\;b_2 \leq 1.85 \cdot 10^{+116}:\\
\;\;\;\;\frac{-t_0}{a} - \frac{b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2 \cdot -2}{a}\\
\end{array}
\]
(FPCore (a b_2 c)
:precision binary64
(/ (- (- b_2) (sqrt (- (* b_2 b_2) (* a c)))) a)) ↓
(FPCore (a b_2 c)
:precision binary64
(let* ((t_0 (sqrt (- (* b_2 b_2) (* c a)))))
(if (<= b_2 -7.2e+49)
(/ (* -0.5 c) b_2)
(if (<= b_2 2e-238)
(/ (/ (* c (- a)) (- b_2 t_0)) a)
(if (<= b_2 1.85e+116)
(- (/ (- t_0) a) (/ b_2 a))
(/ (* b_2 -2.0) a)))))) double code(double a, double b_2, double c) {
return (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a;
}
↓
double code(double a, double b_2, double c) {
double t_0 = sqrt(((b_2 * b_2) - (c * a)));
double tmp;
if (b_2 <= -7.2e+49) {
tmp = (-0.5 * c) / b_2;
} else if (b_2 <= 2e-238) {
tmp = ((c * -a) / (b_2 - t_0)) / a;
} else if (b_2 <= 1.85e+116) {
tmp = (-t_0 / a) - (b_2 / a);
} else {
tmp = (b_2 * -2.0) / a;
}
return tmp;
}
real(8) function code(a, b_2, c)
real(8), intent (in) :: a
real(8), intent (in) :: b_2
real(8), intent (in) :: c
code = (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a
end function
↓
real(8) function code(a, b_2, c)
real(8), intent (in) :: a
real(8), intent (in) :: b_2
real(8), intent (in) :: c
real(8) :: t_0
real(8) :: tmp
t_0 = sqrt(((b_2 * b_2) - (c * a)))
if (b_2 <= (-7.2d+49)) then
tmp = ((-0.5d0) * c) / b_2
else if (b_2 <= 2d-238) then
tmp = ((c * -a) / (b_2 - t_0)) / a
else if (b_2 <= 1.85d+116) then
tmp = (-t_0 / a) - (b_2 / a)
else
tmp = (b_2 * (-2.0d0)) / a
end if
code = tmp
end function
public static double code(double a, double b_2, double c) {
return (-b_2 - Math.sqrt(((b_2 * b_2) - (a * c)))) / a;
}
↓
public static double code(double a, double b_2, double c) {
double t_0 = Math.sqrt(((b_2 * b_2) - (c * a)));
double tmp;
if (b_2 <= -7.2e+49) {
tmp = (-0.5 * c) / b_2;
} else if (b_2 <= 2e-238) {
tmp = ((c * -a) / (b_2 - t_0)) / a;
} else if (b_2 <= 1.85e+116) {
tmp = (-t_0 / a) - (b_2 / a);
} else {
tmp = (b_2 * -2.0) / a;
}
return tmp;
}
def code(a, b_2, c):
return (-b_2 - math.sqrt(((b_2 * b_2) - (a * c)))) / a
↓
def code(a, b_2, c):
t_0 = math.sqrt(((b_2 * b_2) - (c * a)))
tmp = 0
if b_2 <= -7.2e+49:
tmp = (-0.5 * c) / b_2
elif b_2 <= 2e-238:
tmp = ((c * -a) / (b_2 - t_0)) / a
elif b_2 <= 1.85e+116:
tmp = (-t_0 / a) - (b_2 / a)
else:
tmp = (b_2 * -2.0) / a
return tmp
function code(a, b_2, c)
return Float64(Float64(Float64(-b_2) - sqrt(Float64(Float64(b_2 * b_2) - Float64(a * c)))) / a)
end
↓
function code(a, b_2, c)
t_0 = sqrt(Float64(Float64(b_2 * b_2) - Float64(c * a)))
tmp = 0.0
if (b_2 <= -7.2e+49)
tmp = Float64(Float64(-0.5 * c) / b_2);
elseif (b_2 <= 2e-238)
tmp = Float64(Float64(Float64(c * Float64(-a)) / Float64(b_2 - t_0)) / a);
elseif (b_2 <= 1.85e+116)
tmp = Float64(Float64(Float64(-t_0) / a) - Float64(b_2 / a));
else
tmp = Float64(Float64(b_2 * -2.0) / a);
end
return tmp
end
function tmp = code(a, b_2, c)
tmp = (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a;
end
↓
function tmp_2 = code(a, b_2, c)
t_0 = sqrt(((b_2 * b_2) - (c * a)));
tmp = 0.0;
if (b_2 <= -7.2e+49)
tmp = (-0.5 * c) / b_2;
elseif (b_2 <= 2e-238)
tmp = ((c * -a) / (b_2 - t_0)) / a;
elseif (b_2 <= 1.85e+116)
tmp = (-t_0 / a) - (b_2 / a);
else
tmp = (b_2 * -2.0) / a;
end
tmp_2 = tmp;
end
code[a_, b$95$2_, c_] := N[(N[((-b$95$2) - N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(a * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / a), $MachinePrecision]
↓
code[a_, b$95$2_, c_] := Block[{t$95$0 = N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(c * a), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[b$95$2, -7.2e+49], N[(N[(-0.5 * c), $MachinePrecision] / b$95$2), $MachinePrecision], If[LessEqual[b$95$2, 2e-238], N[(N[(N[(c * (-a)), $MachinePrecision] / N[(b$95$2 - t$95$0), $MachinePrecision]), $MachinePrecision] / a), $MachinePrecision], If[LessEqual[b$95$2, 1.85e+116], N[(N[((-t$95$0) / a), $MachinePrecision] - N[(b$95$2 / a), $MachinePrecision]), $MachinePrecision], N[(N[(b$95$2 * -2.0), $MachinePrecision] / a), $MachinePrecision]]]]]
\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
↓
\begin{array}{l}
t_0 := \sqrt{b_2 \cdot b_2 - c \cdot a}\\
\mathbf{if}\;b_2 \leq -7.2 \cdot 10^{+49}:\\
\;\;\;\;\frac{-0.5 \cdot c}{b_2}\\
\mathbf{elif}\;b_2 \leq 2 \cdot 10^{-238}:\\
\;\;\;\;\frac{\frac{c \cdot \left(-a\right)}{b_2 - t_0}}{a}\\
\mathbf{elif}\;b_2 \leq 1.85 \cdot 10^{+116}:\\
\;\;\;\;\frac{-t_0}{a} - \frac{b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2 \cdot -2}{a}\\
\end{array}
Alternatives Alternative 1 Error 83.7% Cost 7560.00
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.1 \cdot 10^{-90}:\\
\;\;\;\;\frac{-0.5 \cdot c}{b_2}\\
\mathbf{elif}\;b_2 \leq 3 \cdot 10^{+114}:\\
\;\;\;\;\frac{-\sqrt{b_2 \cdot b_2 - c \cdot a}}{a} - \frac{b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2 \cdot -2}{a}\\
\end{array}
\]
Alternative 2 Error 83.7% Cost 7432.00
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.1 \cdot 10^{-90}:\\
\;\;\;\;\frac{-0.5 \cdot c}{b_2}\\
\mathbf{elif}\;b_2 \leq 1.35 \cdot 10^{+116}:\\
\;\;\;\;\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - c \cdot a}}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2 \cdot -2}{a}\\
\end{array}
\]
Alternative 3 Error 78.7% Cost 7240.00
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1 \cdot 10^{-90}:\\
\;\;\;\;\frac{-0.5 \cdot c}{b_2}\\
\mathbf{elif}\;b_2 \leq 1.8 \cdot 10^{-73}:\\
\;\;\;\;\frac{\left(-b_2\right) - \sqrt{c \cdot \left(-a\right)}}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2}{a} \cdot -2 + 0.5 \cdot \frac{c}{b_2}\\
\end{array}
\]
Alternative 4 Error 64.3% Cost 836.00
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -5 \cdot 10^{-310}:\\
\;\;\;\;\frac{-0.5 \cdot c}{b_2}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2}{a} \cdot -2 + 0.5 \cdot \frac{c}{b_2}\\
\end{array}
\]
Alternative 5 Error 64.2% Cost 452.00
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -3.5 \cdot 10^{-251}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\mathbf{else}:\\
\;\;\;\;b_2 \cdot \frac{-2}{a}\\
\end{array}
\]
Alternative 6 Error 64.2% Cost 452.00
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -2.6 \cdot 10^{-249}:\\
\;\;\;\;\frac{-0.5 \cdot c}{b_2}\\
\mathbf{else}:\\
\;\;\;\;b_2 \cdot \frac{-2}{a}\\
\end{array}
\]
Alternative 7 Error 64.3% Cost 452.00
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.3 \cdot 10^{-250}:\\
\;\;\;\;\frac{-0.5 \cdot c}{b_2}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2 \cdot -2}{a}\\
\end{array}
\]
Alternative 8 Error 37.6% Cost 320.00
\[-0.5 \cdot \frac{c}{b_2}
\]
Alternative 9 Error 11.9% Cost 64.00
\[0
\]