Math FPCore C Java Python Julia MATLAB Wolfram TeX \[x \cdot \left(\frac{y}{z} - \frac{t}{1 - z}\right)
\]
↓
\[\begin{array}{l}
t_1 := \frac{y}{z} - \frac{t}{1 - z}\\
t_2 := x \cdot t_1\\
\mathbf{if}\;t_1 \leq -\infty:\\
\;\;\;\;\frac{y \cdot x}{z}\\
\mathbf{elif}\;t_1 \leq -5 \cdot 10^{-276}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;t_1 \leq 2 \cdot 10^{-257}:\\
\;\;\;\;\left(y + t\right) \cdot \left(x \cdot \left(\frac{-2}{z} + \frac{3}{z}\right)\right)\\
\mathbf{else}:\\
\;\;\;\;t_2\\
\end{array}
\]
(FPCore (x y z t) :precision binary64 (* x (- (/ y z) (/ t (- 1.0 z))))) ↓
(FPCore (x y z t)
:precision binary64
(let* ((t_1 (- (/ y z) (/ t (- 1.0 z)))) (t_2 (* x t_1)))
(if (<= t_1 (- INFINITY))
(/ (* y x) z)
(if (<= t_1 -5e-276)
t_2
(if (<= t_1 2e-257) (* (+ y t) (* x (+ (/ -2.0 z) (/ 3.0 z)))) t_2))))) double code(double x, double y, double z, double t) {
return x * ((y / z) - (t / (1.0 - z)));
}
↓
double code(double x, double y, double z, double t) {
double t_1 = (y / z) - (t / (1.0 - z));
double t_2 = x * t_1;
double tmp;
if (t_1 <= -((double) INFINITY)) {
tmp = (y * x) / z;
} else if (t_1 <= -5e-276) {
tmp = t_2;
} else if (t_1 <= 2e-257) {
tmp = (y + t) * (x * ((-2.0 / z) + (3.0 / z)));
} else {
tmp = t_2;
}
return tmp;
}
public static double code(double x, double y, double z, double t) {
return x * ((y / z) - (t / (1.0 - z)));
}
↓
public static double code(double x, double y, double z, double t) {
double t_1 = (y / z) - (t / (1.0 - z));
double t_2 = x * t_1;
double tmp;
if (t_1 <= -Double.POSITIVE_INFINITY) {
tmp = (y * x) / z;
} else if (t_1 <= -5e-276) {
tmp = t_2;
} else if (t_1 <= 2e-257) {
tmp = (y + t) * (x * ((-2.0 / z) + (3.0 / z)));
} else {
tmp = t_2;
}
return tmp;
}
def code(x, y, z, t):
return x * ((y / z) - (t / (1.0 - z)))
↓
def code(x, y, z, t):
t_1 = (y / z) - (t / (1.0 - z))
t_2 = x * t_1
tmp = 0
if t_1 <= -math.inf:
tmp = (y * x) / z
elif t_1 <= -5e-276:
tmp = t_2
elif t_1 <= 2e-257:
tmp = (y + t) * (x * ((-2.0 / z) + (3.0 / z)))
else:
tmp = t_2
return tmp
function code(x, y, z, t)
return Float64(x * Float64(Float64(y / z) - Float64(t / Float64(1.0 - z))))
end
↓
function code(x, y, z, t)
t_1 = Float64(Float64(y / z) - Float64(t / Float64(1.0 - z)))
t_2 = Float64(x * t_1)
tmp = 0.0
if (t_1 <= Float64(-Inf))
tmp = Float64(Float64(y * x) / z);
elseif (t_1 <= -5e-276)
tmp = t_2;
elseif (t_1 <= 2e-257)
tmp = Float64(Float64(y + t) * Float64(x * Float64(Float64(-2.0 / z) + Float64(3.0 / z))));
else
tmp = t_2;
end
return tmp
end
function tmp = code(x, y, z, t)
tmp = x * ((y / z) - (t / (1.0 - z)));
end
↓
function tmp_2 = code(x, y, z, t)
t_1 = (y / z) - (t / (1.0 - z));
t_2 = x * t_1;
tmp = 0.0;
if (t_1 <= -Inf)
tmp = (y * x) / z;
elseif (t_1 <= -5e-276)
tmp = t_2;
elseif (t_1 <= 2e-257)
tmp = (y + t) * (x * ((-2.0 / z) + (3.0 / z)));
else
tmp = t_2;
end
tmp_2 = tmp;
end
code[x_, y_, z_, t_] := N[(x * N[(N[(y / z), $MachinePrecision] - N[(t / N[(1.0 - z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(y / z), $MachinePrecision] - N[(t / N[(1.0 - z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(x * t$95$1), $MachinePrecision]}, If[LessEqual[t$95$1, (-Infinity)], N[(N[(y * x), $MachinePrecision] / z), $MachinePrecision], If[LessEqual[t$95$1, -5e-276], t$95$2, If[LessEqual[t$95$1, 2e-257], N[(N[(y + t), $MachinePrecision] * N[(x * N[(N[(-2.0 / z), $MachinePrecision] + N[(3.0 / z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$2]]]]]
x \cdot \left(\frac{y}{z} - \frac{t}{1 - z}\right)
↓
\begin{array}{l}
t_1 := \frac{y}{z} - \frac{t}{1 - z}\\
t_2 := x \cdot t_1\\
\mathbf{if}\;t_1 \leq -\infty:\\
\;\;\;\;\frac{y \cdot x}{z}\\
\mathbf{elif}\;t_1 \leq -5 \cdot 10^{-276}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;t_1 \leq 2 \cdot 10^{-257}:\\
\;\;\;\;\left(y + t\right) \cdot \left(x \cdot \left(\frac{-2}{z} + \frac{3}{z}\right)\right)\\
\mathbf{else}:\\
\;\;\;\;t_2\\
\end{array}
Alternatives Alternative 1 Error 1.9 Cost 2636
\[\begin{array}{l}
t_1 := \frac{y}{z} - \frac{t}{1 - z}\\
t_2 := x \cdot t_1\\
\mathbf{if}\;t_1 \leq -\infty:\\
\;\;\;\;\frac{y \cdot x}{z}\\
\mathbf{elif}\;t_1 \leq -1 \cdot 10^{-166}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;t_1 \leq 5 \cdot 10^{-252}:\\
\;\;\;\;\left(y + t\right) \cdot \frac{x}{z}\\
\mathbf{else}:\\
\;\;\;\;t_2\\
\end{array}
\]
Alternative 2 Error 16.8 Cost 1240
\[\begin{array}{l}
t_1 := x \cdot \frac{t}{z + -1}\\
\mathbf{if}\;t \leq -4.9 \cdot 10^{+113}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq -1.2 \cdot 10^{+15}:\\
\;\;\;\;x \cdot \left(\frac{y}{z} - t\right)\\
\mathbf{elif}\;t \leq -95000000000:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq 2 \cdot 10^{-242}:\\
\;\;\;\;x \cdot \frac{y}{z}\\
\mathbf{elif}\;t \leq 2.2 \cdot 10^{+40}:\\
\;\;\;\;\frac{y \cdot x}{z}\\
\mathbf{elif}\;t \leq 3.35 \cdot 10^{+69}:\\
\;\;\;\;y \cdot \frac{x}{z}\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
Alternative 3 Error 19.8 Cost 980
\[\begin{array}{l}
t_1 := x \cdot \frac{t}{z}\\
t_2 := x \cdot \frac{y}{z}\\
\mathbf{if}\;z \leq -36000000:\\
\;\;\;\;t_1\\
\mathbf{elif}\;z \leq 1.25 \cdot 10^{+39}:\\
\;\;\;\;x \cdot \left(\frac{y}{z} - t\right)\\
\mathbf{elif}\;z \leq 5 \cdot 10^{+46}:\\
\;\;\;\;t \cdot \frac{x}{z}\\
\mathbf{elif}\;z \leq 6 \cdot 10^{+160}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;z \leq 9.6 \cdot 10^{+209}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;t_2\\
\end{array}
\]
Alternative 4 Error 22.1 Cost 848
\[\begin{array}{l}
t_1 := x \cdot \frac{t}{z}\\
\mathbf{if}\;t \leq -1.55 \cdot 10^{+120}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq 4.3 \cdot 10^{-242}:\\
\;\;\;\;x \cdot \frac{y}{z}\\
\mathbf{elif}\;t \leq 3.2 \cdot 10^{+41}:\\
\;\;\;\;\frac{y \cdot x}{z}\\
\mathbf{elif}\;t \leq 1.02 \cdot 10^{+70}:\\
\;\;\;\;y \cdot \frac{x}{z}\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
Alternative 5 Error 5.2 Cost 712
\[\begin{array}{l}
t_1 := x \cdot \frac{y + t}{z}\\
\mathbf{if}\;z \leq -7800000:\\
\;\;\;\;t_1\\
\mathbf{elif}\;z \leq 0.006:\\
\;\;\;\;x \cdot \left(\frac{y}{z} - t\right)\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
Alternative 6 Error 35.7 Cost 584
\[\begin{array}{l}
t_1 := t \cdot \frac{x}{z}\\
\mathbf{if}\;z \leq -1:\\
\;\;\;\;t_1\\
\mathbf{elif}\;z \leq 1:\\
\;\;\;\;x \cdot \left(-t\right)\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
Alternative 7 Error 33.9 Cost 584
\[\begin{array}{l}
t_1 := x \cdot \frac{t}{z}\\
\mathbf{if}\;z \leq -1:\\
\;\;\;\;t_1\\
\mathbf{elif}\;z \leq 1:\\
\;\;\;\;x \cdot \left(-t\right)\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
Alternative 8 Error 21.7 Cost 584
\[\begin{array}{l}
t_1 := x \cdot \frac{t}{z}\\
\mathbf{if}\;t \leq -1.4 \cdot 10^{+124}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t \leq 9.5 \cdot 10^{+73}:\\
\;\;\;\;x \cdot \frac{y}{z}\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
Alternative 9 Error 50.8 Cost 256
\[x \cdot \left(-t\right)
\]